JEE PHYSICS MCQ: ATOMS

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In a hypothetical Bohr hydrogen, the mass of the electron is doubled. The energy

{E_0}

and the radius

{r_0}

of the first orbit will be (

{a_0}

is the Bohr radius)

View answer and explanation

Correct option: A

{E_0} = - 27.2\,\,eV;\,\,{r_0} = {a_0}/2

Option A (

{E_0} = - 27.2\,\,eV;\,\,{r_0} = {a_0}/2

) is correct because the energy is directly proportional to the mass and the radius is inversely proportional to the mass of the electron.

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n

=2

{n}=1

\lambda_0

\lambda_0

{R_H} = 1.097\,\, \times \,\,{10^7}\,\,m