Skip to main content
Back to ATOMS

Your Progress

0 / 257 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • ATOMS

Atoms practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 151-180 of 257 questions

Preparing practice and saved progress…

151 Medium
151 of 257
Understanding +4 | -1
Assertion (A): In Rutherford experiment only few α−\alpha- particles get rebounded.

Reason (R): Most of the atomic space is empty.
View answer and explanation
Correct option: B
Both (A) and (R) are true and (R) is not the correct explanation of (A)
Option B is correct. Both the assertion and the reason are true, but the reason doesn't directly explain why only a few alpha particles rebound. The concentration of mass at the center is the correct explanation.
152 Medium
152 of 257
Application +4 | -1
In hydrogen atom, for which transition minimum energy is emitted?
View answer and explanation
Correct option: D
n1=4,n2=5n_1=4, n_2=5
Option D (n1=4,n2=5n_1=4, n_2=5) is correct because the energy difference between these levels is the smallest among the given options, leading to minimum energy emission.
153 Medium
153 of 257
Remembering +4 | -1
The value of structure constant is
View answer and explanation
Correct option: A
1137\frac{1}{137}
Option A (1137\frac{1}{137}) is correct because the fine-structure constant is approximately equal to 1/137.
154 Medium
154 of 257
Application +4 | -1
Find the largest and shortest wavelengths in the Lyman series for hydrogen. In what region of the electromagnetic spectrum does each series lie?
View answer and explanation
Correct option: A
911Ao911 \mathop {\text{A}}\limits^{\text{o}}
Option A (911Ao911 \mathop {\text{A}}\limits^{\text{o}}) is correct because the shortest wavelength in the Lyman series is 911 Angstroms.
155 Medium
155 of 257
Understanding +4 | -1
The potential difference applied to an XX-ray tube is increased. As a result, in the emitted radiation
View answer and explanation
Correct option: D
The minimum wavelength decreases
Option D (The minimum wavelength decreases) is correct because increasing the potential difference in an X-ray tube decreases the minimum wavelength of the emitted radiation.
156 Medium
156 of 257
Application +4 | -1
In Bohr’s model, if the atomic radius of the first orbit is r0{r_0}, then the radius of the fourth orbit is
View answer and explanation
Correct option: D
16 r016\,{r_0}
Option D (16,r016\\,{r_0}) is correct because the radius of the nth orbit in Bohr's model is proportional to n², so the radius of the fourth orbit is 16 times the radius of the first orbit.
157 Medium
157 of 257
Understanding +4 | -1
White X-rays are called white due to the fact that
View answer and explanation
Correct option: C
they have a continuous wavelength range.
Option C is correct because white X-rays are characterized by a continuous range of wavelengths, similar to white light having a continuous spectrum of colors.
158 Easy
158 of 257
Application +4 | -1
The ratio of the magnitude of the kinetic energy to the potential energy of an electron in the 5th 5^{\text {th }} excited state of a hydrogen atom is :
View answer and explanation
Correct option: D
12\frac{1}{2}
Option D (12\frac{1}{2}) is correct because the kinetic energy is half the magnitude of the potential energy for an electron in any orbit of a hydrogen atom.
159 Medium
159 of 257
Application +4 | -1
H+,  He+   and   O++{H^ + },\,\,H{e^ + }\,\,\,\mathrm{and}\,\,\,{O^{ + + }} ions having same kinetic energy pass through a region of space filled with uniform magnetic field B directed perpendicular to the velocity of ions. The masses of the ions H+,  He+   and   O++{H^ + },\,\,H{e^ + }\,\,\,\mathrm{and}\,\,\,{O^{ + + }} are respectively in the ratio 1:4:16. As a result
A)H+{H^ + } ions willbedeflected most
B) O++{O^{ + + }} ions willbedeflectedleast
C) He+   and   O++H{e^ + }\,\,\,\mathrm{and}\,\,\,{O^{ + + }} ions will suffer samedeflection
D) All ions will suffer thesamedeflection
View answer and explanation
Correct option: A
A, C
Options A and C are correct. The radius of the circular path depends on mass and charge, and the deflection is inversely proportional to the radius. H+ and He++ have the same deflection.
160 Medium
160 of 257
Analyzing +4 | -1
Statement-1: When hydrogen atom is raised from the ground state to an excited state the kinetic energy increases.
Statement-2: The velocity of electron in a quantum state is inversely proportional to the quantum number of the state.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Statement-1 is false because when a hydrogen atom is raised to an excited state, the kinetic energy decreases. Statement-2 is true because the velocity of an electron is inversely proportional to the principal quantum number.
161 Medium
161 of 257
Application +4 | -1
In a coolidge tube experiment, the minimum wavelength of the continuous X-ray spectrum equal to 66.3 pm.
View answer and explanation
Correct option: B
Electrons accelerate through a potential difference of 18.75 kV in the coolidge tube
The correct answer is Electrons accelerate through a potential difference of 18.75 kV in the coolidge tube because the minimum wavelength is related to the accelerating potential by eV=hc/λeV = hc/\lambda.
162 Medium
162 of 257
Understanding +4 | -1
An electron moving around the nucleus with an angular momentum ll has a magnetic moment
View answer and explanation
Correct option: B
e2ml\frac{e}{{2m}}l
Option B (e2ml\frac{{e}}{{2m}}l) is correct because the magnetic moment of an electron is proportional to its angular momentum, with the constant of proportionality being e2m\frac{{e}}{{2m}}.
163 Medium
163 of 257
Understanding +4 | -1
Statement I: The different lines of emission spectra (like Lyman,Balmer, etc) of atomic hydrogen gas are produced by different atoms.
Statement II: The sample of atomic hydrogen gas consists of millions of atoms.
View answer and explanation
Correct option: B
Statement I is true; Statement II is true; Statement II is not the correct explanation for Statement I
Option D (Statement I is true; Statement II is true; Statement II is not the correct explanation for Statement I) is correct because different lines are produced by different atoms, and the sample consists of millions of atoms, but the latter doesn't explain the former.
164 Medium
164 of 257
Application +4 | -1
Hydrogen atom is excited from ground state to another state with principal quantum number equal to 4\mathrm{4}. Then the number of spectral lines in the emission spectra will be
View answer and explanation
Correct option: D
6\mathrm{6}
Option D (6\mathrm{6}) is correct because the number of spectral lines is given by n(n-1)/2.
165 Medium
165 of 257
Understanding +4 | -1
The continuous X-rays spectrum produced by an X-ray machine at constant voltage has
View answer and explanation
Correct option: B
A minimum wavelength
Option B is correct because the continuous X-ray spectrum has a definite short wavelength limit, hence a minimum wavelength.
166 Medium
166 of 257
Application +4 | -1
An electron is accelerated through a potential difference of 64 volts. What is the de-Broglie wavelength associated with it? To which part of the electromagnetic spectrum does this value of wavelength correspond?
View answer and explanation
Correct option: A
1.53 A∘,X1.53 ~\mathop {\text{A}}\limits^ \circ, X-rays
Option A (1.53 A∘,X1.53 ~\mathop {\text{A}}\limits^ \circ, X-rays) is correct because it is calculated using the de-Broglie wavelength formula and the resulting wavelength corresponds to the X-ray part of the electromagnetic spectrum.
167 Medium
167 of 257
Application +4 | -1
An electron in the hydrogen atom jumps excited state nn to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75  eV.2.75\;eV. If the stopping potential of the photoelectron is 10  eV,10\;eV, then the value of nn is
View answer and explanation
Correct option: D
4
Option D (4) is correct because the energy difference between the excited state n and the ground state corresponds to the energy of the emitted photon, which can be calculated from the work function and stopping potential.
168 Medium
168 of 257
Application +4 | -1
If accelerating voltage of X\mathrm{X}-ray tube is 13 kV13 \mathrm{~kV} find minimum wavelength of X\mathrm{X}-ray,
View answer and explanation
Correct option: C
0.95 A∘0.95 \,\mathop {\text{A}}\limits^ \circ
Option C (0.95 A∘0.95 \,\mathop {\text{A}}\limits^ \circ) is correct because it is the minimum wavelength calculated using the accelerating voltage and the formula relating wavelength to voltage in an X-ray tube.
169 Medium
169 of 257
Application +4 | -1
If the series limit of Lymen series for Hydrogen atom is equal to the series limit of Balmer series for a hydrogen like atom, then atomic number of this hydrogen like atom will be
View answer and explanation
Correct option: B
2
Option B (2) is correct because the atomic number Z is found to be 2 by equating the series limits of the Lyman series for Hydrogen and the Balmer series for the hydrogen-like atom.
170 Easy
170 of 257
Understanding +4 | -1
E1E_1 is energy of KαK_\alpha photon of aluminium, E2E_2 is energy of KβK_\beta photon of aluminium and E3E_3 is energy of KαK_\alpha photon from sodium, then the correct order of energies is given:
View answer and explanation
Correct option: D
E2>E1>E3E_2 > E_1 > E_3
Option D (E2>E1>E3E_2 > E_1 > E_3) is correct because KβK_\beta photons have higher energy than KαK_\alpha photons for the same element, and the energy of KαK_\alpha photons increases with atomic number.
171 Medium
171 of 257
Application +4 | -1
The ratio between total acceleration of the electron in singly ionized helium atom and hydrogen atom (ground state) is
View answer and explanation
Correct option: B
8
Option B (8) is correct because the total acceleration is proportional to Z cubed, where Z is the atomic number.
172 Medium
172 of 257
Understanding +4 | -1
If the ionization potential of helium atom is 24.6 volt, the energy required to ionize it will be
View answer and explanation
Correct option: A
24.6  eV24.6\,\,eV
Option A (24.6  eV24.6\,\,eV) is correct because the ionization potential in volts is numerically equal to the ionization energy in electron volts.
173 Medium
173 of 257
Application +4 | -1
What will be the angular momentum of an electron, if energy of this electron in HH-atom is −1.5  eV- 1.5\,\,eV (in JJ-ss)
View answer and explanation
Correct option: C
3.15  ×10−343.15\,\, \times {10^{ - 34}}
Option C (3.15 ×10−343.15\, \times {10^{ - 34}}) is correct because the angular momentum is calculated using the energy level and the formula L=nh2πL = n\frac{h}{{2\pi }}.
174 Medium
174 of 257
Understanding +4 | -1
If λ1{\lambda _1} and λ2{\lambda _2} are the wavelengths of characteristic X-rays and gamma rays respectively, then the relation between them is
View answer and explanation
Correct option: C
λ1>λ2{\lambda _1} > {\lambda _2}
Option C (λ1>λ2{\lambda _1} > {\lambda _2}) is correct because X-rays generally have longer wavelengths than gamma rays.
175 Medium
175 of 257
Application +4 | -1
According to Bohr’s theory, the ratio of the times taken by the electron in a hydrogen atom to complete one revolution in orbits corresponding to ground and first excited state is.
View answer and explanation
Correct option: C
0.047222222
Option C (0.2 eV) is correct because the maximum kinetic energy is the difference between the photon energy and the work function.
176 Medium
176 of 257
Remembering +4 | -1
In Raman effect, Stoke’s lines are spectral lines having
View answer and explanation
Correct option: D
Wavelength greater than that of the original line
Option D (Wavelength greater than that of the original line) is correct because Stoke's lines in Raman scattering have lower energy and thus longer wavelengths.
177 Medium
177 of 257
Understanding +4 | -1
The ratio of the kinetic energy to the total energy of an electron in a Bohr orbit is
View answer and explanation
Correct option: A
−1- 1
Option A (-1) is correct because the kinetic energy is the negative of the total energy in a Bohr orbit.
178 Medium
178 of 257
Remembering +4 | -1
For principal quantum number n=3n = 3, the possible values of orbital quantum number ′l′'l' are
View answer and explanation
Correct option: C
0,1,2\mathrm{0, 1, 2}
Option C (0,1,2\mathrm{0, 1, 2}) is correct because for n=3n=3, the possible values of ll are 0 to n−1n-1, which are 0, 1, and 2.
179 Medium
179 of 257
Understanding +4 | -1
For characteristic XX-ray of some material
View answer and explanation
Correct option: C
λ(Kγ)<λ(Kβ)<λ(Kα)\lambda \left( {{K_\gamma }} \right) < \lambda \left( {{K_\beta }} \right) < \lambda \left( {{K_\alpha }} \right)
Option D is incorrect, Option C is correct because energy and wavelength are inversely proportional, and the energy of Kα\alpha is less than Kβ\beta and Kγ\gamma.
180 Medium
180 of 257
Application +4 | -1
An electron in hydrogen atom first jumps from second excited state to first excited state and then from first excited state to ground state. Let the ratio of wavelength, momentum and energy of photons emitted in these two cases be a,ba, b and cc respectively. Then,
View answer and explanation
Correct option: D
c=1ac=\frac{1}{a}
Option D (c=1ac=\frac{1}{a}) is correct because the ratio of energies is the inverse of the ratio of wavelengths, and the ratio of momenta is equal to the ratio of energies.
Revision notes and key takeaways

Review ATOMS in your textbook or class notes, then use this set to check your understanding.

Showing 151-180 of 257 questions

Your practice

0 / 257 answered · 257 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.