An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of $45 \times {10^{ - 2}}{\rm{A}}.$ The maximum energy of a photon in the radiation in eV is $h = 6.62 \times {10^{ - 34}}$ Js , $c = 3 \times {10^8}\;{\rm{m}}{{\rm{s}}^{ - 1}})$

JEE PHYSICS MCQ: ATOMS

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An X-ray tube produces a continuous spectrum of radiation with its shortest wavelength of

45 \times {10^{ - 2}}\mathrm{A}.

The maximum energy of a photon in the radiation in eV is

h = 6.62 \times {10^{ - 34}}

Js ,

c = 3 \times {10^8}\;\mathrm{m}{\mathrm{s}^{ - 1}})

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Correct option: A

27500

Option A (27500) is correct because the maximum energy of a photon is inversely proportional to the shortest wavelength, and the calculation yields approximately 27500 eV.

JEE PHYSICS MCQ: ATOMS

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