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JEE PHYSICS MCQ: ATOMS

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An X-ray machine is operated at 40 kV. The short wavelength limit of continuous X-rays will be (h=6.63×10−34Js,  c  =  3×108  ms−1,  e=1.6×10−19  C)\left( {h = 6.63 \times {{10}^{ - 34}}Js,\;c\; = \;3 \times {{10}^8}\;m{s^{ - 1}},\;e = 1.6 \times {{10}^{ - 19}}\;C} \right)
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Correct option: A
0.31A∘0.31\mathop A\limits^ \circ
Option A (0.31A∘0.31\mathop A\limits^ \circ) is correct because it is the shortest wavelength calculated using the given voltage and constants.

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