Skip to main content
Back to TRIGONOMETRIC EQUATIONS

Your Progress

0 / 581 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • TRIGONOMETRIC EQUATIONS

Trigonometric equations practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 451-480 of 581 questions

Preparing practice and saved progress…

451 Easy
451 of 581
Application +4 | -1
If 0≤x≤π0 \le x \le \pi and 81sin⁡2x+  81cos⁡2x=30{81^{{{\sin }^2}x}} + \,\,{81^{{{\cos }^2}x}} = 30, then xx is equal to
View answer and explanation
Correct option: A
π6,  π3\frac{\pi }{6},\,\,\frac{\pi }{3}
Option A (π6, π3\frac{\pi }{6},\,\frac{\pi }{3}) is correct because these values satisfy the given trigonometric equation within the specified interval.
452 Easy
452 of 581
Application +4 | -1
The most general values of θ\mathrm{\theta } satisfying tan⁡  θ+tan⁡  (3 π4+θ)=2\tan \,\,\mathrm{\theta } + \tan \,\,\left( {\frac{{3\,\pi }}{4} + \mathrm{\theta }} \right) = 2 is / are\mathrm{is}\,\mathrm{/}\,\mathrm{are}
View answer and explanation
Correct option: A
nπ  ±  π3,  n∈In\pi \,\, \pm \,\,\frac{\pi }{3},\,\,n \in I
Option A (nπ;±;π3,;n∈In\pi \\; \pm \\; \frac{\pi }{{3}},\\;n \in I) is correct because it represents the general solution of the trigonometric equation after simplification.
453 Medium
453 of 581
Analyzing +4 | -1
Let f:R→Rf: R \rightarrow R be a function defined by f(x)=log⁡m{2(sin⁡x−cos⁡x)+m−2}f(x)=\log _{\sqrt{m}}\{\sqrt{2}(\sin x-\cos x)+m-2\}, for some mm, such that the range of ff is [0,2][0,2]. Then the value of mm is
View answer and explanation
Correct option: D
5
Option D (5) is correct because the range of the function is [0,2], which leads to the equation log⁡m(m−4)=0\log_{\sqrt{m}}(m-4) = 0, and solving for m gives m = 5.
454 Hard
454 of 581
Application +4 | -1
If θ\theta lies in the first quadrant and cos⁡θ\cos \theta =8/17=8 / 17, then the value of cos⁡(30∘+θ)+cos⁡(45∘−θ)+\cos \left(30^{\circ}+\theta\right)+\cos \left(45^{\circ}-\theta\right)+ cos⁡(120∘−θ)\cos \left(120^{\circ}-\theta\right) is
View answer and explanation
Correct option: A
(3−12+12)2317\left(\frac{\sqrt{3}-1}{2}+\frac{1}{\sqrt{2}}\right) \frac{23}{17}
Option A is correct. By using trigonometric identities and the given value of cos⁡θ\cos \theta, the expression simplifies to (3−12+12)2317\left(\frac{{\sqrt{{3}}-1}}{{2}}+\frac{{1}}{{\sqrt{{2}}}}\right) \frac{{23}}{{17}}.
455 Easy
455 of 581
Application +4 | -1
The most general value of θ\theta satisfying
tan⁡  θ+tan⁡(3  π4+θ)=2    are\tan \,\,\theta + \tan \left( {\frac{{3\;\pi }}{4} + \theta } \right) = 2\;\,\,are
View answer and explanation
Correct option: A
n  π  ±  π3,  n∈Zn\;\pi \,\, \pm \,\,\frac{\pi }{3},\,\,n \in Z
Option A (n;π,±,π3,,n∈Zn\\;\pi \\, \pm \\, \frac{\pi }{{3}},\\,n \in Z) is correct because solving the trigonometric equation leads to tan⁡2θ=3\tan^2 \theta = 3, which gives the general solution θ=nπ±π3\theta = n\pi \pm \frac{\pi}{3}.
456 Medium
456 of 581
Analyzing +4 | -1
tan⁡81∘−tan⁡63∘−tan⁡27∘+tan⁡9∘\tan 81^{\circ}-\tan 63^{\circ}-\tan 27^{\circ}+\tan 9^{\circ} equals
View answer and explanation
Correct option: D
4
Option D (4) is correct because simplifying the expression using trigonometric identities leads to the value 4.
457 Easy
457 of 581
Analyzing +4 | -1
If the values of xx and yy satisfy the equation tan⁡2(x+y)+cot⁡2(x+y)=1−2x−x2\tan ^2(x+y)+\cot ^2(x+y)=1-2 x-x^2, then the value of x2−3x+2x^2-3 x+2 is _____.
View answer and explanation
Correct option: A
6
Option C (3) is incorrect. The correct answer is 6 because the given equation is valid only when both sides are equal to 2, leading to x = -1, and thus x2−3x+2=6x^2 - 3x + 2 = 6.
458 Easy
458 of 581
Application +4 | -1
The number of solutions of sin⁡  x=sin⁡  2x\sin \,\,x = \sin \,\,2x between −π2\frac{{ - \pi }}{2} and π2\frac{\pi }{2} is
View answer and explanation
Correct option: A
3
The correct answer is A (3) because solving the trigonometric equation sin⁡x=sin⁡2x\sin x = \sin 2x within the given interval yields three solutions: 0, π3\frac{\pi}{3}, and −π3-\frac{\pi}{3}.
459 Easy
459 of 581
Application +4 | -1
The solution of the equation cos⁡2θ+sin⁡θ+1=0\cos ^2 \theta+\sin \theta+1=0 lies in the interval
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the solution to the equation cos⁡2θ+sin⁡θ+1=0\cos^2 \theta + \sin \theta + 1 = 0 is θ=2nπ−π2\theta = 2n\pi - \frac{\pi}{2}, and none of the given intervals contain this solution.
460 Easy
460 of 581
Understanding +4 | -1
The equation sin⁡x+sin⁡y+sin⁡z=−3\sin x+\sin y+\sin z=-3 for 0≤x≤2π0 \leq x \leq 2 \pi. 0≤y≤2π,0≤z≤2π0 \leq y \leq 2 \pi, 0 \leq z \leq 2 \pi, has
View answer and explanation
Correct option: A
One solution
Option A (One solution) is correct because the maximum value of sin⁡x\sin x is 1, so for the sum to be -3, each term must be -1, leading to a unique solution.
461 Easy
461 of 581
Application +4 | -1
The solution of sin⁡  x+sin⁡  5x=sin⁡  3x\sin \,\,x + \sin \,\,5x = \sin \,\,3x in (0,   π2)\left( {0,\;\,\frac{\pi }{2}} \right)

View answer and explanation
Correct option: B
π6,   π3\frac{\pi }{6},\;\,\frac{\pi }{3}
Option B (π6,   π3\frac{\pi }{6},\;\,\frac{\pi }{3}) is correct because these are the solutions to the trigonometric equation within the given interval after simplification.
462 Medium
462 of 581
Analyzing +4 | -1
If cos⁡x=tan⁡y,cot⁡y=tan⁡z\cos x=\tan y, \cot y=\tan z and cot⁡z=tan⁡x\cot z=\tan x, then sin⁡x\sin x is equal to
View answer and explanation
Correct option: D
5−12\frac{\sqrt{5}-1}{2}
Option D (5−12\frac{\sqrt{5}-1}{2}) is correct because substituting the given relations leads to a quadratic equation in sin⁡x\sin x, and solving it yields this value as the valid solution.
463 Easy
463 of 581
Application +4 | -1
The smallest positive angle which satisfies the equation 2sin⁡2θ+3cos⁡θ+1=02 \sin ^2 \theta+\sqrt{3} \cos \theta+1=0 is
View answer and explanation
Correct option: A
5π6\frac{5 \pi}{6}
Option A (5π6\frac{{5 \pi}}{{6}}) is correct because it is the smallest positive angle that satisfies the given trigonometric equation after simplification and solving for θ\theta.
464 Medium
464 of 581
Application +4 | -1
The number of solutions of 16sin⁡2x+16cos⁡2x=10,0≤x≤2π16^{\sin ^2 x}+16^{\cos ^2 x}=10,0 \leq x \leq 2 \pi is
View answer and explanation
Correct option: A
8
Option A (8) is correct because solving the equation 16sin⁡2x+16cos⁡2x=1016^{\sin^2 x} + 16^{\cos^2 x} = 10 leads to sin⁡x=±12\sin x = \pm \frac{1}{2} and sin⁡x=±32\sin x = \pm \frac{\sqrt{3}}{2}, which have a total of 8 solutions in the interval [0,2π][0, 2\pi].
465 Medium
465 of 581
Application +4 | -1
If tan⁡(A+B)=3tan⁡A\tan ({A}+{B})=3 \tan {A}, then sin⁡2(A+B)+sin⁡2Asin⁡2B=\frac{\sin 2({A}+{B})+\sin 2 {A}}{\sin 2 {B}}=
View answer and explanation
Correct option: A
2
Option A (2) is correct because it represents the value of the expression sin⁡2(A+B)+sin⁡2Asin⁡2B\frac{{\sin 2(A+B)+\sin 2 A}}{{\sin 2 B}} given the condition tan⁡(A+B)=3tan⁡A\tan (A+B)=3 \tan A, which simplifies to 2 using trigonometric identities.
466 Easy
466 of 581
Analyzing +4 | -1
If tan⁡(πcos⁡θ)=cot⁡(πsin⁡θ)\tan (\pi \cos \theta)=\cot (\pi \sin \theta), then the value(s) of cos⁡(θ−π4)\cos \left(\theta-\frac{\pi}{4}\right) is/are
View answer and explanation
Correct option: C
±122\pm \frac{1}{2 \sqrt{2}}
Option C, ±122\pm \frac{{1}}{{2 \sqrt{{2}}}} is correct because it represents the possible values of cos⁡(θ−π4)\cos \left(\theta-\frac{{\pi}}{{4}}\right) obtained by solving the given trigonometric equation.
467 Medium
467 of 581
Application +4 | -1
If −π≤x≤π,−π≤y≤π-\pi \leq x \leq \pi,-\pi \leq y \leq \pi and cos⁡x+cos⁡y=2\cos x+\cos y=2, then the value of cos⁡(x−y)\cos (x-y) is
View answer and explanation
Correct option: C
1
Option C (1) is correct because the maximum value of cos⁡x\cos x is 1, so both cos⁡x\cos x and cos⁡y\cos y must be 1, leading to x=0x=0 and y=0y=0, and thus cos⁡(x−y)=1\cos(x-y) = 1.
468 Easy
468 of 581
Application +4 | -1
If 1+cot⁡θ≤π21+\cot \theta \leq \frac{\pi}{2}, for 0<θ<π0 < \theta < \pi, then θ\theta is equal to
View answer and explanation
Correct option: C
π2\frac{\pi}{2}
Option C (π2\frac{{\pi}}{{2}}) is correct because it satisfies the inequality 1+cot⁡θ≤cot⁡θ21 + \cot \theta \le \cot \frac{{\theta}}{{2}} for 0<θ<π0 < \theta < \pi.
469 Easy
469 of 581
Application +4 | -1
If sin⁡αsin⁡β−cos⁡αcos⁡β+1=0\sin \alpha \sin \beta-\cos \alpha \cos \beta+1=0, then the value of cot⁡αtan⁡β\cot \alpha \tan \beta is
View answer and explanation
Correct option: A
−1-1
Option A (-1) is correct because the given condition implies that α+β=2nπ\alpha + \beta = 2n\pi, and thus cot⁡αtan⁡β=−1\cot \alpha \tan \beta = -1.
470 Easy
470 of 581
Application +4 | -1
x=tan⁡−13+tan⁡−12x=\tan ^{-1} 3+\tan ^{-1} 2,   y=tan⁡−13−tan⁡−12\,\,y=\tan ^{-1} 3-\tan ^{-1} 2 If atan⁡x+btan⁡y=0a \tan x+b \tan y=0, then a+ba+b is equal to kak a where kk is equal to
View answer and explanation
Correct option: D
8
The correct answer is D (8) because solving for tan⁡x\tan x and tan⁡y\tan y and substituting into the given equation allows us to find the value of k.
471 Medium
471 of 581
Application +4 | -1
If m=cosec⁡θ−sin⁡θm=\operatorname{cosec} \theta-\sin \theta and n=sec⁡θ−cos⁡θn=\sec \theta-\cos \theta, then m2/3+n2/3=\mathrm{m}^{2 / 3}+\mathrm{n}^{2 / 3}=
View answer and explanation
Correct option: A
(mn)−2/3(\mathrm{mn})^{-2 / 3}
Option C ((mn)−2/3(mn)^{-2 / 3}) is correct because simplifying the expressions for m and n and then substituting them into the target expression yields the result.
472 Medium
472 of 581
Analyzing +4 | -1
The sum of the series sin⁡θsec⁡3θ+sin⁡3θsec⁡32θ+sin⁡32θsec⁡33θ\sin \theta \sec 3 \theta+\sin 3 \theta \sec 3^2 \theta+\sin 3^2 \theta \sec 3^3 \theta +…n+\ldots n terms, is
View answer and explanation
Correct option: C
12[tan⁡3nθ−tan⁡θ]\frac{1}{2}\left[\tan 3^n \theta-\tan \theta\right]
Option C, 12[tan⁡3nθ−tan⁡θ]\frac{1}{2}\left[\tan 3^n \theta-\tan \theta\right], is correct because the series telescopes, leaving only the first and last terms after simplification.
473 Medium
473 of 581
Application +4 | -1
The sum of all the solutions of the equation cos⁡x⋅cos⁡(π3+x)⋅cos⁡(π3−x)=14,x∈[0,6π]\cos x \cdot \cos \left(\frac{\pi}{3}+x\right) \cdot \cos \left(\frac{\pi}{3}-x\right)=\frac{1}{4}, x \in[0,6 \pi] is
View answer and explanation
Correct option: C
110π3\frac{110 \pi}{3}
None of the options are correct. The sum of all solutions is 30π30\pi, so Option D (None of these) is correct.
474 Medium
474 of 581
Application +4 | -1
If 2tan⁡2θ=sec⁡2θ2 \tan ^2 \theta=\sec ^2 \theta, then the general value of θ\theta is
View answer and explanation
Correct option: C
nπ±π4n \pi \pm \frac{\pi}{4}
Option C (nπ±π4n \pi \pm \frac{{\pi}}{{4}}) is correct because it represents the general solution derived from solving the given trigonometric equation.
475 Medium
475 of 581
Application +4 | -1
Let nn be a positive integer such that sin⁡π2n+cos⁡π2n=n2\sin \frac{\pi}{2 n}+\cos \frac{\pi}{2 n}=\frac{\sqrt{n}}{2}, then
View answer and explanation
Correct option: D
4<n<84 < n < 8
Option D (4<n<84 < n < 8) is correct because by squaring the given equation and substituting n=6, the equation is satisfied.
476 Easy
476 of 581
Application +4 | -1
If sin⁡  (π  cos⁡  θ)=cos⁡  (π  sin⁡  θ)\sin \,\,\left( {\pi \,\,\cos \,\,\theta } \right) = \cos \,\,\left( {\pi \,\,\sin \,\,\theta } \right), then the value of cos⁡  (θ+π4)\cos \,\,\left( {\theta + \frac{\pi }{4}} \right) equals
View answer and explanation
Correct option: B
12 2\frac{1}{{2\,\sqrt 2 }}
Option B (122\frac{1}{2\sqrt 2 }) is correct because by using trigonometric identities, the equation simplifies to cos⁡(θ+π4)=122\cos(\theta + \frac{\pi}{4}) = \frac{1}{2\sqrt 2 }.
477 Easy
477 of 581
Application +4 | -1
cot⁡  θ=sin⁡  2  θ,  θ≠nπ,  n∈Z\cot \,\,\theta = \sin \,\,2\;\theta ,\,\,\theta \ne n\pi ,\,\,n \in Z, if θ\theta equals
View answer and explanation
Correct option: A
45∘45^\circ or 90∘90^\circ
Option A (45∘45^\circ or 90∘90^\circ) is correct because these are the solutions to the equation cot⁡θ=sin⁡2θ\cot \theta = \sin 2\theta within the given constraints.
478 Medium
478 of 581
Analyzing +4 | -1
The equation e∣sin⁡x∣+e−∣sin⁡x∣+4k=0e^{|\sin x|}+e^{-|\sin x|}+4 k=0 will have exactly four distinct solutions in [0,2π][0,2 \pi] if
View answer and explanation
Correct option: D
none of these
Option D (none of these) is correct because the given equation has no solution for k in the specified ranges.
479 Medium
479 of 581
Application +4 | -1
If f(θ)=12−3cos⁡θf(\theta)=\frac{1}{2-3 \cos \theta}, then range of f(θ)f(\theta) is
View answer and explanation
Correct option: C
(−∞,−1]∪(15,∞)(-\infty,-1] \cup\left(\frac{1}{5}, \infty\right)
Option D ((−∞,−1]∪(15,∞)( -\infty, -1] \cup (\frac{1}{5}, \infty)) is correct because by analyzing the range of 2−3cos⁡θ2-3\cos \theta, we find the range of f(θ)f(\theta) to be (−∞,−1]∪[15,∞)(-\infty, -1] \cup [\frac{1}{5}, \infty) excluding 0.
480 Medium
480 of 581
Analyzing +4 | -1
The number of values of θ\theta in the interval (−π2,π2)\left(-\frac{\pi}{2}, \frac{\pi}{2}\right) satisfying the equation (1−tan⁡θ)(1+tan⁡θ)sec⁡2θ+2tan⁡2θ=0(1-\tan \theta)(1+\tan \theta) \sec ^2 \theta+2^{\tan ^2 \theta}=0 is
View answer and explanation
Correct option: C
4
Option D (None of these) is correct because the equation simplifies to a form where there are no solutions for θ in the given interval.
Revision notes and key takeaways

Review TRIGONOMETRIC EQUATIONS in your textbook or class notes, then use this set to check your understanding.

Showing 451-480 of 581 questions

Your practice

0 / 581 answered · 581 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.