JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1

The solution of trigonometric equation

\cos ^4 x+\sin ^4 x=2 \cos (2 x+\pi) \cos (2 x-\pi)

View answer and explanation

Correct option: B

x=\frac{n \pi}{4}+\frac{(-1)^n}{4} \sin ^{-1}\left(\frac{ \pm 2 \sqrt{2}}{3}\right)

Option B (

x=\frac{{n \pi}}{{4}}+\frac{{(-1)^n}}{{4}} \sin^{-1}(\frac{{ \pm 2 \sqrt{{2}}}}{{3}})

) is correct because simplifying the given equation leads to this general solution.

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