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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1
The general solution of sin⁡  x−3  sin⁡  2x+sin⁡  3x=cos⁡  x −3  cos⁡  2x+cos⁡  3x\sin \,\,x - 3\,\,\sin \,\,2x + \sin \,\,3x = \cos \,\,x\, - 3\,\,\cos \,\,2x + \cos \,\,3x is
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Correct option: B
nπ2+π8  \frac{{n\pi }}{2} + \frac{\pi }{8}\;
Option B is correct because by rearranging the equation and factoring, we can find the general solution for x.

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