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JEE • MATHEMATICS • RELATIONS

Relations practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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181 Medium
181 of 238
Application +4 | -1
The relation RR defined on the set A={1,2,3,4,5}A=\{1,2,3,4,5\} by R={(x,y):∣x2−y2∣<16}R=\left\{(x, y):\left|x^2-y^2\right|<16\right\} is given by
View answer and explanation
Correct option: D
None of the above
Option D (None of the above) is correct because the provided options do not fully represent the relation RR defined by ∣x2−y2∣<16|x^2 - y^2| < 16 on the set A={1,2,3,4,5}A = \{1, 2, 3, 4, 5\}.
182 Easy
182 of 238
Understanding +4 | -1
Let A={p,q,r,s}A=\{p, q, r, s\} and B={1,2,3}B=\{1,2,3\}. Which of the following relations from AA to BB is not a function?
View answer and explanation
Correct option: C
R3={(p,1),(q,2),(r,2),(r,2)}R_3=\{(p, 1),(q, 2),(r, 2),(r, 2)\}
Option C (R3={(p,1),(q,2),(r,2),(r,2)}R_3=\{(p, 1),(q, 2),(r, 2),(r, 2)\}) is not a function because the element 'r' in A is mapped to two different elements in B.
183 Easy
183 of 238
Understanding +4 | -1
Let A={1,2,3},B={1,3,5}.AA=\{1,2,3\}, B=\{1,3,5\} . A relation R:A→BR: A \rightarrow B is defined by R={(1,3),(1,5),(2,1)}R=\{(1,3),(1,5),(2,1)\}. Then R−1R^{-1} is defined by:
View answer and explanation
Correct option: C
{(1,2),(5,1),(3,1)\{(1,2),(5,1),(3,1)
Option C ({(1,2),(5,1),(3,1)}\{(1,2),(5,1),(3,1)\}) is correct because the inverse relation R−1R^{-1} is obtained by swapping the elements in each ordered pair of RR.
184 Easy
184 of 238
Understanding +4 | -1
If the relation R:A→BR: A \rightarrow B, where A={1,2,3}A=\{1,2,3\} and B={1,3,5}B=\{1,3,5\} is defined by

R={(x,y):x<y,x∈A,y∈B}R=\{(x, y): x < y, x \in A, y \in B\}, then
View answer and explanation
Correct option: A
R={(1,3),(1,5),(2,3),(2,5),(3,5)}R=\{(1,3),(1,5),(2,3),(2,5),(3,5)\}
Option A (R={(1,3),(1,5),(2,3),(2,5),(3,5)}R=\{ (1,3),(1,5),(2,3),(2,5),(3,5) \}) is correct because it lists all pairs (x, y) where x is from A, y is from B, and x < y.
185 Medium
185 of 238
Understanding +4 | -1
The relation ≤\leq on numbers has the following properties.

(i) a≤a ∀ a∈Ra \leq a \, \forall \, a \in {R} (Reflexivity)

(ii) If a≤ba \leq {b} and b≤a{b} \leq a then a=b ∀ a,b∈Ra={b} \, \forall \, a, {b} \in {R} (Antisymmetry)

(iii) If a≤b{a} \leq {b} and b≤c{b} \leq {c} then a≤c ∀ a,b∈Ra \leq {c} \, \forall \, a, {b} \in {R} (Transitivity)

Which of the above properties the relation ⊂\subset on p(A){p}({A}) has?
View answer and explanation
Correct option: D
(i), (ii) and (iii)
Option D is correct because the subset relation ⊆ on P(A) is reflexive, antisymmetric, and transitive.
186 Easy
186 of 238
Application +4 | -1
Let R{R} be the relation on the set N{N} of natural numbers defined by
R:{(x,y)}:x+3y=12x∈N,y∈N}{R}:\{({x}, {y})\}: {x}+3 {y}=12 {x} \in {N}, {y} \in {N}\} then domain of R{R}
View answer and explanation
Correct option: C
{9,6,3}\{9,6,3\}
Option C (9,6,3\\{9,6,3\\}) is correct because substituting y=1,2,3y = 1, 2, 3 into the equation x+3y=12x + 3y = 12 yields x=9,6,3x = 9, 6, 3 respectively, and these are the only natural number solutions.
187 Easy
187 of 238
Understanding +4 | -1
Let A={1,2,3}A=\{1,2,3\}. The total number of distinct relations that can be defined over AA is:
View answer and explanation
Correct option: A
292^9
Option A (292^9) is correct because each element in A×AA \times A can either be in the relation or not, leading to 292^9 possible relations.
188 Easy
188 of 238
Understanding +4 | -1
If AA is a non-empty set, then which of the following is false?
p  :p\;: There is at least one reflexive relation on AA
q  :q\;: There is at least one symmetric relation on AA
View answer and explanation
Correct option: D
Neither pp nor qq
Option D (Neither pp nor qq) is correct because the identity relation on a set A is both reflexive and symmetric.
189 Medium
189 of 238
Analyzing +4 | -1
The relation RR defined on the set NN of natural numbers by xRy⇔2x2−3xy+y2=0x R y \Leftrightarrow 2 x^2-3 x y+y^2=0 is
View answer and explanation
Correct option: C
Not symmetric but reflexive
The correct answer is C (Not symmetric but reflexive) because the relation satisfies the reflexive property but not the symmetric property.
190 Easy
190 of 238
Application +4 | -1
Let AA and BB be two non-empty sets having nn elements in common. Then, the number of elements common to A×BA \times B and B×AB \times A is
View answer and explanation
Correct option: C
n2n^2
Option C (n2n^2) is correct because the number of elements common to A×BA \times B and B×AB \times A is the square of the number of elements common to AA and BB.
191 Easy
191 of 238
Understanding +4 | -1
Let L\mathrm{L} denote the set of all straight lines in a plane. Let a relation R\mathrm{R} be defined by αRβ⇔α⊥β,α,β∈L\alpha \mathrm{R} \beta \Leftrightarrow \alpha \perp \beta, \alpha, \beta \in \mathrm{L}. The R\mathrm{R} is
View answer and explanation
Correct option: B
Symmetric
Option B (Symmetric) is correct because if line α is perpendicular to line β, then line β is also perpendicular to line α.
192 Easy
192 of 238
Application +4 | -1
If n(A×B)=45,n\left( {A \times B} \right) = 45, then n(A)n\left( A \right) cannot be
View answer and explanation
Correct option: B
17
The correct answer is B (17) because the number of elements in A must be a factor of 45, and 17 is not a factor of 45.
193 Medium
193 of 238
Application +4 | -1
A relation RR from CC to RR is defined by xRyx R y iff ∣x∣=y|x|=y. Which of the following is correct?
View answer and explanation
Correct option: D
iR1i R 1
Option D (iR1i R 1) is correct because the absolute value of ii is equal to 1, satisfying the given relation.
194 Easy
194 of 238
Analyzing +4 | -1
Let R={(x,y):x,y∈N\mathrm{R}=\left\{(x, y): x, y \in N\right. and x2−4xy+3y2=0}\left.x^{2}-4 x y+3 y^{2}=0\right\}, where NN is the set of all natural numbers. Then the relation RR is :
View answer and explanation
Correct option: D
reflexive and transitive.
Option D (reflexive and transitive) is correct because the relation satisfies the reflexive and transitive properties but not the symmetric property.
195 Easy
195 of 238
Application +4 | -1
If f:R→Rf:R \to R is defined by f(x)=x2−6x−14f\left( x \right) = {x^2} - 6x - 14, then f−1(2){f^{ - 1}}\left( 2 \right) equals to
View answer and explanation
Correct option: D
{ϕ}\left\{ \phi \right\}
Option D ({ϕ}\{\phi\}) is correct because the function is not one-to-one, and thus does not have a well-defined inverse at x=2.
196 Easy
196 of 238
Application +4 | -1
If RR be a relation << from A={1,2,3,4}A = \left\{ {1,2,3,4} \right\} to B={1,3,5}  i.e.  (a,b)∈R⇔a<b,B = \left\{ {1,3,5} \right\}\;i.e.\;\left( {a,b} \right) \in R \Leftrightarrow a < b, then R  o  R−1R\;o\;{R^{ - 1}} is
View answer and explanation
Correct option: C
{(3,3),(3,5),(5,3),(5,5)}\left\{ {\left( {3,3} \right),\left( {3,5} \right),\left( {5,3} \right),\left( {5,5} \right)} \right\}
Option C is correct because the composition of the relation R with its inverse R-1 results in the set {{(3,3), (3,5), (5,3), (5,5)}} based on the given conditions.
197 Easy
197 of 238
Understanding +4 | -1
Let Y={1,  2,  3,  4,  5},  A{1,  2},  B={3,  4,  5}Y = \left\{ {1,\;2,\;3,\;4,\;5} \right\},\;A\left\{ {1,\;2} \right\},\;B = \left\{ {3,\;4,\;5} \right\} and ϕ\phi denotes null set. If (A×B)\left( {A \times B} \right) denotes cartesian product of the sets AA and BB; then (Y×A)∩(Y×B)\left( {Y \times A} \right) \cap \left( {Y \times B} \right) is
View answer and explanation
Correct option: D
ϕ\phi
Option D (ϕ\phi) is correct because the intersection of the two Cartesian products is an empty set since A and B have no common elements.
198 Medium
198 of 238
Application +4 | -1
Let AA be a non-empty set such that A×AA \times A has 9 elements among which are found (−1,0)(-1,0) and (0,1).(0,1). Then,
View answer and explanation
Correct option: C
A={−1,0,1}A=\{-1,0,1\}
Option C (A={−1,0,1}A=\{-1,0,1\}) is correct because it is the only set that contains -1, 0, and 1, and has 3 elements, resulting in A×AA \times A having 9 elements.
199 Easy
199 of 238
Understanding +4 | -1
Let nn be a fixed positive integer. Let a relation RR be defined in ZZ (the set of all integers) as follows: aRba R b iff n/(a−b)n /(a-b), that is, iff a−ba-b is divisible by nn. Then, the relation RR is
View answer and explanation
Correct option: D
An equivalence relation
Option D (An equivalence relation) is correct because the relation R is reflexive, symmetric, and transitive, satisfying the conditions for an equivalence relation.
200 Easy
200 of 238
Analyzing +4 | -1
Let RR be a relation on the set NN be defined by {(x,y)|x,y∈N,2  x+y=41}.\left\{ {\left( {x,y} \right){\text{|}}x,y \in N,2\;x + y = 41} \right\}. Then, RR is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the relation R is neither reflexive, symmetric, nor transitive, as demonstrated by the counterexamples provided.
201 Easy
201 of 238
Analyzing +4 | -1
For any two real numbers xx and yy, we define xRyx R y if and only if sin⁡2x+cos⁡2y=1\sin ^2 x+\cos ^2 y=1. The relation RR is
View answer and explanation
Correct option: D
An equivalence relation
Option D (An equivalence relation) is correct because the relation R is reflexive, symmetric, and transitive.
202 Easy
202 of 238
Analyzing +4 | -1
Let RR be a relation on R\mathbb{R}, given by R={(a,b):3a−3b+7R=\{(a, b): 3 a-3 b+\sqrt{7} is an irrational number}\}. Then RR is
View answer and explanation
Correct option: A
Reflexive but neither symmetric nor transitive
Option A (Reflexive but neither symmetric nor transitive) is correct because the relation satisfies the reflexive property but fails to satisfy symmetric and transitive properties.
203 Medium
203 of 238
Application +4 | -1
A relation RR is defined over the set of non- negative integers as xRy⇒x2+y2=36x R y \Rightarrow x^{2}+y^{2}=36 what is R\mathrm{R} ?
View answer and explanation
Correct option: C
{(6,0)(0,6)}\{(6,0)(0,6)\}
Option C ({ (6,0)(0,6) }) is correct because it contains the pairs of non-negative integers that satisfy the equation x² + y² = 36.
204 Easy
204 of 238
Understanding +4 | -1
In a set of ants in a locality, two ants are said to be related iff they walk on a same straight line, then the relation is
View answer and explanation
Correct option: D
Equivalence
Option D (Equivalence) is correct because the relation is reflexive (an ant walks on the same line as itself), symmetric (if ant A walks on the same line as ant B, then ant B walks on the same line as ant A), and transitive (if ant A walks on the same line as ant B, and ant B walks on the same line as ant C, then ant A walks on the same line as ant C).
205 Easy
205 of 238
Analyzing +4 | -1
If A={n:n3+5n2+2n  is  an  integer  and  itself  is  an  integer},A = \left\{ {n:\frac{{{n^3} + 5{n^2} + 2}}{n}\;\mathrm{is\;an\;integer\;and\;itself\;is\;an\;integer}} \right\}, then the number of elements in the set AA, is
View answer and explanation
Correct option: D
4
Option D (4) is correct because the expression is an integer when n is a factor of 2, including both positive and negative factors.
206 Medium
206 of 238
Application +4 | -1
If n(A)=3n(A)=3, and n(B)=4n(B)=4, then n(A×A×B)n(A \times A \times B) is equal to
View answer and explanation
Correct option: A
36
Option A (36) is correct because the number of elements in the Cartesian product A x A x B is the product of the number of elements in each set.
207 Easy
207 of 238
Analyzing +4 | -1
Let R1R_1 and R2R_2 be two relations defined on R\mathbb{R} by a R1b⇔ab≥0R_1 b \Leftrightarrow a b \geq 0 and aR2b⇔a≥ba R_2 b \Leftrightarrow a \geq b. Then,
View answer and explanation
Correct option: D
Neither R1R_1 nor R2R_2 is an equivalence relation
Option D (Neither R1R_1 nor R2R_2 is an equivalence relation) is correct because neither relation satisfies all three properties of an equivalence relation: reflexivity, symmetry, and transitivity.
208 Easy
208 of 238
Application +4 | -1
The relation RR defined on the set A={1,2,3,4,5}A=\{1,2,3,4,5\} by R={(x,y):∣x2−y2∣<16}R=\left\{(x, y):\left|x^2-y^2\right| < 16\right\} is given by
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because none of the given relations satisfy the condition ∣x2−y2∣<16|x^2 - y^2| < 16 for all pairs.
209 Easy
209 of 238
Understanding +4 | -1
Let RR be a reflexive relation on a finite set A having nn elements, and let there be mm ordered pairs in RR. Then,
View answer and explanation
Correct option: A
m⩾nm \geqslant n
Option A (m⩾nm \geqslant n) is correct because a reflexive relation on a set with n elements must have at least n ordered pairs.
210 Easy
210 of 238
Remembering +4 | -1
If a set is denoted as B=ϕ{B}=\phi, then the number of element in B{B} is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the number of elements in an empty set, denoted by ϕ\phi, is zero.
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