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JEE • MATHEMATICS • RELATIONS

Relations practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 56 questions
1 Medium
1 of 56
Analyzing +4 | -1
Let N\mathrm{N} denote the set of all natural numbers and R\mathrm{R} be the relation on N×N\mathrm{N} \times \mathrm{N} defined by (a,b)R(c,d)(\mathrm{a}, \mathrm{b}) \mathrm{R}(\mathrm{c}, \mathrm{d}) if ad(b+c)=bc(a+d)a d(b+c)=b c(a+d), then R\mathrm{R} is
View answer and explanation
Correct option: D
An equivalence relation
Option D (An equivalence relation) is correct because the relation R is reflexive, symmetric, and transitive, thus satisfying the conditions for an equivalence relation.
2 Medium
2 of 56
Application +4 | -1
RR is relation on NN given by R={(x,  y):4x+3y=20}R = \left\{ {\left( {x,\;y} \right):4x + 3y = 20} \right\}. Which of the following belongs to RR?
View answer and explanation
Correct option: D
(2,4)\left( {2,\mathrm{ }4} \right)
The correct answer is D ((2, 4)) because it's the only pair of natural numbers that satisfies the equation 4x + 3y = 20.
3 Medium
3 of 56
Analyzing +4 | -1
Let R={(3,3)(5,5),(9,9),(12,12),(5,12),(3,9),(3,12),(3,5)}R=\{(3,3)(5,5),(9,9),(12,12),(5,12),(3,9),(3,12),(3,5)\} be a relation on the set⁡A={3,5,9,12}\operatorname{set} A=\{3,5,9,12\}. Then, RR is :
View answer and explanation
Correct option: D
reflexive, transitive but not symmetric.
Option D (reflexive, transitive but not symmetric) is correct because the given relation satisfies the reflexive and transitive properties but fails to satisfy the symmetric property.
4 Medium
4 of 56
Analyzing +4 | -1
The minimum number of elements that must be added to the relation R={a,b),(b,c)}R=\{a, b),(b, c)\} on the set {a,b,c}\{a, b, c\} so that it becomes symmetric and transitive is
View answer and explanation
Correct option: A
7
The minimum number of elements that must be added is 7. To make the relation symmetric and transitive, we need to add (b, a), (c, b), (a, c), (c, a), (a, a), (b, b), and (c, c).
5 Medium
5 of 56
Understanding +4 | -1
Let XX be a set containing nn elements. The number of reflexive relations that can be defined on XX is
View answer and explanation
Correct option: B
2n2−n2^{n^2-n}
Option B (2n2−n2^{n^2-n}) is correct because a reflexive relation must contain n elements, leaving n2−nn^2 - n elements that can either be in the relation or not, resulting in 2n2−n2^{n^2-n} possible relations.
6 Medium
6 of 56
Analyzing +4 | -1
Let PP be the relation defined on the set of all real numbers such that P={(a,b):sec⁡2a−tan⁡2b=1}P=\left\{(a, b): \sec ^2 a-\tan ^2 b=1\right\}. Then PP is
View answer and explanation
Correct option: C
Symmetric and transitive but not reflexive.
Option C (Symmetric and transitive but not reflexive) is correct because the relation satisfies symmetry and transitivity but fails the reflexive property.
7 Medium
7 of 56
Understanding +4 | -1
Consider the following statements.

I. If the set A{A} has 3 elements and set B={3,4,5}{B}=\{3,4,5\}, then the number of elements in A×B=9{A} \times {B}=9.

II. The domain of the relation R{R} defined by
R={(x,x+5):x∈(0,1,2,3,4,5)} is {5,6,7,8,9,10}.{R}=\{({x}, {x}+5): {x} \in(0,1,2,3,4,5)\} \text { is }\{5,6,7,8,9,10\} .

Choose the correct option.
View answer and explanation
Correct option: A
Only I is true
Only I is true because the number of elements in the Cartesian product is the product of the number of elements in each set, while the domain in statement II is incorrectly calculated.
8 Medium
8 of 56
Understanding +4 | -1
If R\mathrm{R} be a relation defined as R={(x,y):x+y=p\mathrm{R}=\{(\mathrm{x}, \mathrm{y}): \mathrm{x}+\mathrm{y}=\mathrm{p} for some rational p;x,y\mathrm{p} ; \mathrm{x}, \mathrm{y} are real numbers }\}, then RR is
View answer and explanation
Correct option: D
equivalence
Option D (equivalence) is correct because the relation R satisfies reflexive, symmetric, and transitive properties, thus making it an equivalence relation.
9 Medium
9 of 56
Analyzing +4 | -1
Let A={1,2,3,4,5,6,7}A=\{1,2,3,4,5,6,7\}. Then the relation R={(x,y)∈A×A:x+y=7}R=\{(x, y) \in A \times A: x+y=7\} is
View answer and explanation
Correct option: B
Symmetric but neither reflexive nor transitive
Option B is correct because the relation is symmetric (if x+y=7, then y+x=7), but it's neither reflexive (e.g., 1+1≠7) nor transitive (e.g., (1,6) and (6,1) are in R, but (1,1) is not).
10 Medium
10 of 56
Analyzing +4 | -1
Let R\mathrm{R} be a relation on N×N\mathrm{N} \times \mathrm{N} defined by (a,b)R(c,d)(a, b) \mathrm{R}(c,d) if and only if ad(b−c)=bc(a−d)a d(b-c)=b c(a-d). Then RR is
View answer and explanation
Correct option: C
Symmetric but neither reflexive nor transitive
Option C is correct because the relation R is symmetric but neither reflexive nor transitive, as demonstrated by the provided counterexamples.
11 Medium
11 of 56
Analyzing +4 | -1
SS is a relation over the set RR of all real numbers and it is given by (a,b)∈S⇔ab≥0.(a, b) \in S \Leftrightarrow a b \geq 0. Then, SS is
View answer and explanation
Correct option: D
An equivalence relation
The correct answer is D. SS is an equivalence relation because it is reflexive, symmetric, and transitive.
12 Medium
12 of 56
Analyzing +4 | -1
Among the relations

S={(a,b):a,b∈R−{0},2+ab>0} and T={(a,b):a,b∈R,a2−b2∈Z},\begin{array}{l} S=\left\{(a, b): a, b \in \mathbb{R}-\{0\}, 2+\frac{a}{b} > 0\right\} \text { and } \\ T=\left\{(a, b): a, b \in \mathbb{R}, a^{2}-b^{2} \in \mathbb{Z}\right\},\end{array}
View answer and explanation
Correct option: D
TT is symmetric but SS is not
Option A ((−∞,−214]∪[0,∞)(-\infty,-\frac{21}{4}] \cup[0, \infty)) is correct because by finding the range of the function, we get y∈(−∞,−214]∪[0,∞)y \in(-\infty,-\frac{21}{4}] \cup[0, \infty).
13 Medium
13 of 56
Understanding +4 | -1
The number of reflexive relations of a set with four elements is equal to
View answer and explanation
Correct option: B
212{2^{12}}
Option B (212{2^{12}}) is correct because the number of reflexive relations on a set with four elements is 242−4=212{2^{{4^2} - 4}} = {2^{12}}.
14 Medium
14 of 56
Application +4 | -1
The solution of 8x≡6( mod 14)8 x \equiv 6(\bmod 14) are
View answer and explanation
Correct option: C
[6],[13][6],[13]
Option C ([6],[13]) is correct because it provides the two solutions to the congruence equation within the modulo 14 system.
15 Medium
15 of 56
Understanding +4 | -1
The relation R={(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)}R=\{(1,1),(2,2),(3,3),(1,2),(2,3),(1,3)\} on set A={1,2,3}A=\{1,2,3\} is:
View answer and explanation
Correct option: A
Reflexive but not symmetric
Option A (Reflexive but not symmetric) is correct because the relation contains (1,1), (2,2), and (3,3), making it reflexive, but it lacks (2,1) for (1,2) and (3,2) for (2,3), making it not symmetric.
16 Medium
16 of 56
Understanding +4 | -1
Consider the following statements.

I. Addition, subtraction and multiplication are binary operations on R{R}.

II. Division is a binary operation on R{R} but not a binary operation on non-zero real numbers.
View answer and explanation
Correct option: A
Only I is true
Option A (Only I is true) is correct because addition, subtraction, and multiplication are indeed binary operations on the set of real numbers, while division is not.
17 Medium
17 of 56
Application +4 | -1
If RR is a relation on the set A={1,2,3,4,5,6,7,8,9}A=\{1,2,3,4,5,6,7,8,9\} given by xRy⇔y=3xx R y \Leftrightarrow y=3 x, then R∘R−1R \circ R^{-1} is
View answer and explanation
Correct option: B
{(1,1),(2,2),(3,3)}\{(1,1),(2,2),(3,3)\}
Option B ({(1,1),(2,2),(3,3)}\left\{(1,1),(2,2),(3,3)\right\}) is correct because it represents the composition of the relation RR with its inverse R−1R^{-1}, where y=3xy = 3x.
18 Medium
18 of 56
Understanding +4 | -1
Consider the following statements.

I. Let A{A} and B{B} are non-empty sets such that A⊆B{A} \subseteq {B}. Then, A×C⊆B×C{A} \times {C} \subseteq {B} \times {C}.

II. For any two sets A{A} and B,A×B=B×A{B}, {A} \times {B}={B} \times {A}
Choose the correct option.
View answer and explanation
Correct option: A
Only I is true
Only I is true because if A is a subset of B, then the Cartesian product of A with any set C will also be a subset of the Cartesian product of B with C.
19 Medium
19 of 56
Application +4 | -1
Suppose that the number of elements in set A\mathrm{A} is p\mathrm{p}, the number of elements in set B\mathrm{B} is q\mathrm{q} and the number of elements in A×B\mathrm{A} \times \mathrm{B} is 7 . Then p2+q2=\mathrm{p}^{2}+\mathrm{q}^{2}=
View answer and explanation
Correct option: C
50
Option C (50) is correct because it is the sum of the squares of the number of elements in set A and set B, calculated using the given information about the Cartesian product.
20 Medium
20 of 56
Understanding +4 | -1
A relation RR on set of point of given plane defined as (A,B)∈R(A, B) \in R if OA=OBO A=O B where OO is fixed point on same plane. Then relation R\mathrm{R} is:
View answer and explanation
Correct option: B
equivalence relation
Option B (equivalence relation) is correct because the relation satisfies reflexive, symmetric, and transitive properties, thus making it an equivalence relation.
21 Medium
21 of 56
Understanding +4 | -1
Let n(A)=mn(A)=m and n(B)=nn(B)=n. Then, the total number of non-empty relations that can be defined from AA to BB is
View answer and explanation
Correct option: D
2min −12^{\text {min }}-1
Option 2mn−12^{mn}-1 is correct, as the total number of relations from A to B is 2mn2^{mn}, and subtracting 1 excludes the empty relation.
22 Medium
22 of 56
Understanding +4 | -1
A Relation R{R} is defined in the set of integers I{I} as follows (x,y)∈R(x, y) \in {R} if x2+y2=9x^2+{y}^2=9 which of the following is false?
View answer and explanation
Correct option: D
None of the above
Option D is correct because all the given statements about the relation R are true.
23 Medium
23 of 56
Application +4 | -1
If RR is a relation &#39;<<&#39; from A={1,2,3,4}A=\{1,2,3,4\} to B={1,3,5}B=\{1,3,5\}, i.e. (a,b)∈R(a, b) \in R iff a<ba < b, then R∘R−1R \circ R { }^{-1} is
View answer and explanation
Correct option: C
{(3,3),(3,5),(5,3),(5,5)}\{(3,3),(3,5),(5,3),(5,5)\}
Option C ({ (3,3),(3,5),(5,3),(5,5) }) is correct because it represents the composition of the relation R with its inverse.
24 Medium
24 of 56
Application +4 | -1
Let A={1,2,3,4,5};B={2,3,6,7}A=\{1,2,3,4,5\} ; B=\{2,3,6,7\}. Then the number of elements in (A×B)∩(B×A)(A \times B) \cap(B \times A) is :
View answer and explanation
Correct option: D
4
Option D (4) is correct because there are 4 elements that are present in both A x B and B x A, which are (2,2), (2,3), (3,2), and (3,3).
25 Medium
25 of 56
Analyzing +4 | -1
Let R1{R_1} be a relation defined by
R1={(a,b)|a⩾b,a,b∈R}.{R_1} = \left\{ {\left( {a,b} \right){\text{|}}a \geqslant b,a,b \in R} \right\}. Then, R1{R_1} is
View answer and explanation
Correct option: B
Reflexive, transitive but not symmetric
Option B (Reflexive, transitive but not symmetric) is correct because the relation satisfies the reflexive and transitive properties but fails to be symmetric.
26 Medium
26 of 56
Application +4 | -1
Let xx denote the total number of one-one functions from a set AA with 3 elements to a set BB with 5 elements and yy denote the total number of one-one functions from the set AA to the set A×BA \times B. Then,
View answer and explanation
Correct option: A
2y=91x2y = 91x
The correct answer is A (2y=91x2y = 91x) because it correctly calculates the number of one-one functions and establishes the relationship between x and y.
27 Medium
27 of 56
Understanding +4 | -1
If A={a,b,c,d},B={1,2,3}A=\{a, b, c, d\}, B=\{1,2,3\}, which of the following sets of ordered pairs are not relations from AA to BB ?
View answer and explanation
Correct option: C
{(a,2),(b,3),(3,b)}\{(a, 2),(b, 3),(3, b)\}
Option C is correct because (3, b) is not an element of A x B since 3 is not in A and b is not in B.
28 Medium
28 of 56
Application +4 | -1
If RR is the smallest equivalence relation on the set {1,2,3,4}\{1,2,3,4\} such that {(1,2),(1,3)}⊂R\{(1,2),(1,3)\} \subset R, then the number of elements in RR is
View answer and explanation
Correct option: B
10
The correct answer is B (10) because it represents the minimum number of ordered pairs required to satisfy the properties of an equivalence relation given the initial conditions.
29 Medium
29 of 56
Understanding +4 | -1
Total number of equivalence relations defined in the set S={a,b,c}S=\{a, b, c\} is
View answer and explanation
Correct option: A
5
Option A (5) is correct because the number of equivalence relations on a set is equivalent to the number of partitions of the set, which is 5 for a set with 3 elements.
30 Medium
30 of 56
Understanding +4 | -1
Let N\mathrm{N} denote the set of all natural numbers. Define two binary relations on NN as R1={(x,y)∈N×N:2x+y=10}R_{1}=\{(x, y) \in N \times N: 2 x+y=10\} and R2={(x,y)∈N×N:x+2y=10}R_{2}=\{(x, y) \in N \times N: x+2 y=10\}. Then
View answer and explanation
Correct option: C
Range of R2R_{2} is {1,2,3,4}\{1,2,3,4\}
Option C is correct because the range of R2, defined by x + 2y = 10, with x and y being natural numbers, is {1, 2, 3, 4}.
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