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JEE • MATHEMATICS • RELATIONS

Relations practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-56 of 56 questions
31 Medium
31 of 56
Application +4 | -1
If A={x∈z+:x<10A=\left\{x \in z^{+}: x<10\right. and xx is a multiple of 3 or 4}\}, where z+z^{+}is the set of positive integers, then the total number of symmetric relations on AA is
View answer and explanation
Correct option: B
2152^{15}
The correct answer is B (215) because it correctly determines the number of symmetric relations on set A by considering the pairs and their reverses.
32 Medium
32 of 56
Understanding +4 | -1
The relation R defined on the set of natural numbers as {(a,b):a differs from b by 3} is given by
View answer and explanation
Correct option: B
{(4,1),(5,2),(6,3),...}\left\{ {\left( {4,\mathrm{ }1} \right),\mathrm{ }\left( {5,\mathrm{ }2} \right),\mathrm{ }\left( {6,\mathrm{ }3} \right),\mathrm{ }...} \right\}
Option B is correct because the relation R is defined as a differs from b by 3, meaning a - b = 3, which is satisfied by the elements in option B.
33 Medium
33 of 56
Application +4 | -1
RR is a relation from {11,12,13}\{11,12,13\} to {8,10,12}\{8,10,12\} defined by y=x−3y=x-3. The relation R−1R^{-1} is
View answer and explanation
Correct option: B
{(8,11),(10,13)}\{(8,11),(10,13)\}
Option B ({(8,11),(10,13)}\left\{(8,11),(10,13)\right\}) is correct because it represents the inverse relation R−1R^{-1}, where the ordered pairs are reversed from the original relation RR.
34 Medium
34 of 56
Understanding +4 | -1
A relation on the set A={x:∣x∣<3,x∈Z}A=\{x:|x| < 3, x \in Z\}, where ZZ is the set of integers is defined by R={(x,y):y=∣x∣,x≠−1}R=\{(x, y): y=|x|, x \neq-1\}. Then the number of elements in the power set of RR is:
View answer and explanation
Correct option: B
16
Option B (16) is correct because the relation R has 4 elements, and the number of elements in the power set of a set with n elements is 2n2^n, so 24=162^4 = 16.
35 Medium
35 of 56
Analyzing +4 | -1
Let RR be a relation defined on NN as a RbR b if 2a+3b2 a+3 b is a multiple of 5,a,b∈N5, a, b \in N. Then RR is
View answer and explanation
Correct option: A
an equivalence relation
Option A (an equivalence relation) is correct because the relation R satisfies the reflexive, symmetric, and transitive properties.
36 Medium
36 of 56
Understanding +4 | -1
Let R={(x,y):x2+y2=1R=\left\{(x, y): x^2+y^2=1\right. and x,y∈R}\left.x, y \in R\right\} be a relation in RR. The relation RR is
View answer and explanation
Correct option: B
Symmetric
Option B (Symmetric) is correct because if (x, y) is in R, then x² + y² = 1, which implies y² + x² = 1, so (y, x) is also in R.
37 Medium
37 of 56
Analyzing +4 | -1
R={(a,b):2a+3bR=\{(a, b): 2 a+3 b is divisible by 5 and a,b∈N}a, b \in N\} is
View answer and explanation
Correct option: B
Equivalence relation
The correct answer is B (Equivalence relation) because the relation R satisfies reflexive, symmetric, and transitive properties.
38 Medium
38 of 56
Application +4 | -1
If RR be a relation < from A={1,2,3,4}A=\{1,2,3,4\} to B={1,3,5}B=\{1,3,5\} i.e., (a,b)∈R⇔a<b(a,b) \in R \Leftrightarrow a < b, then R∘R−1R^\circ {R^{ - 1}} is:
View answer and explanation
Correct option: C
{(3,3),(3,5),(5,3),(5,5)}\{(3,3),(3,5),(5,3),(5,5)\}
The correct answer is C ({(3,3),(3,5),(5,3),(5,5)}) because it represents the composition of the relation R with its inverse.
39 Medium
39 of 56
Application +4 | -1
If two sets AA and BB are having 99 elements in common, then the number of elements common to each of the sets A×BA \times B and B×AB \times A are
View answer and explanation
Correct option: B
99299^2
Option B (99299^2) is correct because the number of common elements in A×BA \times B and B×AB \times A is the square of the number of common elements in A and B.
40 Medium
40 of 56
Understanding +4 | -1
With reference to a universal set, the inclusion of a subset
in another, is relation, which is?
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the inclusion of a subset in another is reflexive and transitive, but not symmetric.
41 Medium
41 of 56
Application +4 | -1
The relation RR defined on the set A={1,2,3,4,5}A=\{1,2,3,4,5\} by R={(x,y):∣x2−y2∣<16}R=\left\{(x, y):\left|x^2-y^2\right|<16\right\} is given by
View answer and explanation
Correct option: D
None of the above
Option D (None of the above) is correct because the provided options do not fully represent the relation RR defined by ∣x2−y2∣<16|x^2 - y^2| < 16 on the set A={1,2,3,4,5}A = \{1, 2, 3, 4, 5\}.
42 Medium
42 of 56
Understanding +4 | -1
The relation ≤\leq on numbers has the following properties.

(i) a≤a ∀ a∈Ra \leq a \, \forall \, a \in {R} (Reflexivity)

(ii) If a≤ba \leq {b} and b≤a{b} \leq a then a=b ∀ a,b∈Ra={b} \, \forall \, a, {b} \in {R} (Antisymmetry)

(iii) If a≤b{a} \leq {b} and b≤c{b} \leq {c} then a≤c ∀ a,b∈Ra \leq {c} \, \forall \, a, {b} \in {R} (Transitivity)

Which of the above properties the relation ⊂\subset on p(A){p}({A}) has?
View answer and explanation
Correct option: D
(i), (ii) and (iii)
Option D is correct because the subset relation ⊆ on P(A) is reflexive, antisymmetric, and transitive.
43 Medium
43 of 56
Analyzing +4 | -1
The relation RR defined on the set NN of natural numbers by xRy⇔2x2−3xy+y2=0x R y \Leftrightarrow 2 x^2-3 x y+y^2=0 is
View answer and explanation
Correct option: C
Not symmetric but reflexive
The correct answer is C (Not symmetric but reflexive) because the relation satisfies the reflexive property but not the symmetric property.
44 Medium
44 of 56
Application +4 | -1
A relation RR from CC to RR is defined by xRyx R y iff ∣x∣=y|x|=y. Which of the following is correct?
View answer and explanation
Correct option: D
iR1i R 1
Option D (iR1i R 1) is correct because the absolute value of ii is equal to 1, satisfying the given relation.
45 Medium
45 of 56
Application +4 | -1
Let AA be a non-empty set such that A×AA \times A has 9 elements among which are found (−1,0)(-1,0) and (0,1).(0,1). Then,
View answer and explanation
Correct option: C
A={−1,0,1}A=\{-1,0,1\}
Option C (A={−1,0,1}A=\{-1,0,1\}) is correct because it is the only set that contains -1, 0, and 1, and has 3 elements, resulting in A×AA \times A having 9 elements.
46 Medium
46 of 56
Application +4 | -1
A relation RR is defined over the set of non- negative integers as xRy⇒x2+y2=36x R y \Rightarrow x^{2}+y^{2}=36 what is R\mathrm{R} ?
View answer and explanation
Correct option: C
{(6,0)(0,6)}\{(6,0)(0,6)\}
Option C ({ (6,0)(0,6) }) is correct because it contains the pairs of non-negative integers that satisfy the equation x² + y² = 36.
47 Medium
47 of 56
Application +4 | -1
If n(A)=3n(A)=3, and n(B)=4n(B)=4, then n(A×A×B)n(A \times A \times B) is equal to
View answer and explanation
Correct option: A
36
Option A (36) is correct because the number of elements in the Cartesian product A x A x B is the product of the number of elements in each set.
48 Medium
48 of 56
Application +4 | -1
A relation RR from C\mathbb{C} to R\mathbb{R} is defined by xRyx R y iff ∣x∣=y|x|=y. Which of the following is correct?
View answer and explanation
Correct option: D
iR1i R 1
Option D (iR1i R 1) is correct because the absolute value of i is equal to 1.
49 Medium
49 of 56
Understanding +4 | -1
In the set N{N} of natural numbers, define the binary operation ∗* by m∗n=GCD⁡(m,n),m,n∈Nm * {n}=\operatorname{GCD}({m}, {n}), {m}, {n} \in {N}. Then, which of the following is true?

I. ∗* is not a binary operation

II. ∗* is a binary operation

III. Inverse of each element of N{N} exist

IV. Inverse of each element of N{N} does not exist
View answer and explanation
Correct option: D
II and IV are true
Option D (II and IV are true) is correct because the GCD is a binary operation, and not all elements have an inverse under this operation.
50 Medium
50 of 56
Analyzing +4 | -1
Let X={1,2,3,4,5}X=\{1,2,3,4,5\} and Y={1,3,5,7,9}Y=\{1,3,5,7,9\}. Which of the following is not a relation from XX to YY ?
View answer and explanation
Correct option: D
R4={(1,3),(2,5),(2,4),(7,9)}R_4=\{(1,3),(2,5),(2,4),(7,9)\}
Option D is the correct answer because R4R_4 contains elements that are not in the Cartesian product of XX and YY, specifically (2,4) and (7,9).
51 Medium
51 of 56
Understanding +4 | -1
If RR is a relation from a set AA to the set⁡B\operatorname{set} B and SS is a relation from BB to CC, then the relation S∘RS \circ R
View answer and explanation
Correct option: B
is from AA to CC
Option B (is from AA to CC) is correct because the composition of relation R from A to B and S from B to C results in a relation from A to C.
52 Medium
52 of 56
Analyzing +4 | -1
Which of the following statements is not correct for the relation R defined by aRb, if and only, if b lives within on kilometre from a?
View answer and explanation
Correct option: C
RR is anti-symmetric
Option C RR is anti-symmetric is correct because the relation is not anti-symmetric. If aRb and bRa, it doesn't imply a=b.
53 Medium
53 of 56
Understanding +4 | -1
If a set has 13 elements and RR is a reflexive relation on AA with nn elements, then
View answer and explanation
Correct option: C
13⩽n⩽16913 \leqslant n \leqslant 169
Option C (13⩽n⩽16913 \leqslant n \leqslant 169) is correct because a reflexive relation on a set with 13 elements must contain at least 13 elements (the pairs (a,a) for each element a in A) and at most 132=16913^2 = 169 elements.
54 Medium
54 of 56
Understanding +4 | -1
Let A={1,2,3},B={1,3,5}A=\{1,2,3\}, B=\{1,3,5\}. If relation RR from AA to BB is given by {(1,3),(2,5),(3,3)}\{(1,3),(2,5),(3,3)\}, then R−1R^{-1} is
View answer and explanation
Correct option: D
None of the above
Option None of the above is correct. The inverse relation R−1R^{-1} is obtained by swapping the elements in each ordered pair of R. Therefore, R−1={(3,1),(5,2),(3,3)}R^{-1} = \{(3, 1), (5, 2), (3, 3)\}, which is not among the given options.
55 Medium
55 of 56
Application +4 | -1
Let a relation RR be defined by R={(4,5),(1,4),(4,6),(7,6),(3,7)}R=\{(4,5),(1,4),(4,6),(7,6),(3,7)\}. The relation R−1oRR^{-1} o R is given by
View answer and explanation
Correct option: B
{(1,1),(4,4),(4,7),(7,4),(7,7),(3,3)}\{(1,1),(4,4),(4,7),(7,4),(7,7),(3,3)\}
Option B ({(1,1),(4,4),(4,7),(7,4),(7,7),(3,3)}\left\{(1,1),(4,4),(4,7),(7,4),(7,7),(3,3)\right\}) is correct because it accurately represents the composition of the inverse relation R−1R^{-1} with the original relation RR.
56 Medium
56 of 56
Analyzing +4 | -1
Assume R\mathrm{R} and S\mathrm{S} are (nonempty) relations in a set AA. Which of the following relation given below is false
View answer and explanation
Correct option: A
If R\mathrm{R} and S\mathrm{S} are transitive, then R∪SR \cup S is transitive.
Option A (If R and S are transitive, then R ∪ S is transitive) is false because the union of two transitive relations is not necessarily transitive. A counterexample can be easily constructed.
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