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JEE • MATHEMATICS • RELATIONS

Relations practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 238 questions
1 Easy
1 of 238
Analyzing +4 | -1
In the set Z\mathrm{Z} of all integers, which of the following relation RR is not an equivalence relation?
View answer and explanation
Correct option: A
x R yx \,R \,y : if x≤yx \leq y
Option A is correct because the relation xRyxRy if x≤yx \leq y is not symmetric. If x≤yx \leq y, it is not necessarily true that y≤xy \leq x.
2 Medium
2 of 238
Analyzing +4 | -1
Let N\mathrm{N} denote the set of all natural numbers and R\mathrm{R} be the relation on N×N\mathrm{N} \times \mathrm{N} defined by (a,b)R(c,d)(\mathrm{a}, \mathrm{b}) \mathrm{R}(\mathrm{c}, \mathrm{d}) if ad(b+c)=bc(a+d)a d(b+c)=b c(a+d), then R\mathrm{R} is
View answer and explanation
Correct option: D
An equivalence relation
Option D (An equivalence relation) is correct because the relation R is reflexive, symmetric, and transitive, thus satisfying the conditions for an equivalence relation.
3 Easy
3 of 238
Analyzing +4 | -1
Let WW denote the words in the English dictionary. Define the relation RR by: R={(x,y)∈W×W∣R=\{(x, y) \in W \times W \mid the words xx and yy have at least one letter in common }\}
View answer and explanation
Correct option: B
Reflexive, symmetric and not transitive
Option B (Reflexive, symmetric and not transitive) is correct because a word always shares a letter with itself (reflexive), if word x shares a letter with word y, then word y shares a letter with word x (symmetric), but it's possible for x to share a letter with y, and y to share a letter with z, without x and z sharing any letters (not transitive).
4 Easy
4 of 238
Analyzing +4 | -1
Let SS be the set of all real numbers. Then, the relation R={(a,  b):1+ab>0}R = \{ \left( {a,\;b} \right):1 + ab > 0\} on SS is
View answer and explanation
Correct option: A
Reflexive and symmetric but not transitive
The correct answer is A (Reflexive and symmetric but not transitive) because the relation satisfies the reflexive and symmetric properties but fails the transitive property.
5 Easy
5 of 238
Understanding +4 | -1
Let XX be a family of sets and RR be a relation on XX defined by ' AA is disjoint from BB '. Then RR is:
View answer and explanation
Correct option: B
Symmetric
Option B (Symmetric) is correct because if set A is disjoint from set B, then set B is also disjoint from set A.
6 Medium
6 of 238
Application +4 | -1
RR is relation on NN given by R={(x,  y):4x+3y=20}R = \left\{ {\left( {x,\;y} \right):4x + 3y = 20} \right\}. Which of the following belongs to RR?
View answer and explanation
Correct option: D
(2,4)\left( {2,\mathrm{ }4} \right)
The correct answer is D ((2, 4)) because it's the only pair of natural numbers that satisfies the equation 4x + 3y = 20.
7 Easy
7 of 238
Understanding +4 | -1
If AΔB=A∪BA \Delta B=A \cup B then
View answer and explanation
Correct option: B
A∩B=ϕA \cap B=\phi
Option B (A∩B=ϕA \cap B=\phi) is correct because if AΔB=A∪BA \Delta B = A \cup B, it means that the intersection of A and B is empty.
8 Easy
8 of 238
Application +4 | -1
If A={x:x2−5x+6=0},B={2,4}A=\left\{x: x^2-5 x+6=0\right\}, B=\{2,4\} and C={4,5}C=\{4,5\}, then A×(B∩C)A \times(B \cap C) is
View answer and explanation
Correct option: A
{(2,4),(3,4)}\{(2,4),(3,4)\}
Option A ({ (2,4), (3,4) }) is correct because it represents the Cartesian product of set A and the intersection of sets B and C.
9 Easy
9 of 238
Understanding +4 | -1
For n,m∈N,n/m{n}, {m} \in {N}, {n} / {m} means that n{n} is a factor of m{m}, the relation // is
View answer and explanation
Correct option: D
Reflexive transitive and not symmetric
Option D is correct because the divisibility relation is reflexive (n/n), transitive (if n/m and m/k, then n/k), but not symmetric (n/m does not imply m/n).
10 Easy
10 of 238
Understanding +4 | -1
Let A={x,  y,  z}  and  B={a,  b,  c,  d}A = \left\{ {x,\;y,\;z} \right\}\;and\;B = \left\{ {a,\;b,\;c,\;d} \right\}. Which one of the following is not a relation from A  to  BA\;to\;B?
View answer and explanation
Correct option: D
{(z,  b),  (y,  b),  (a,  d)}\left\{ {\left( {z,\;b} \right),\;\left( {y,\;b} \right),\;\left( {a,\;d} \right)} \right\}
Option D is correct because it contains an element (a, d) where 'a' is not in set A, thus violating the definition of a relation from A to B.
11 Medium
11 of 238
Analyzing +4 | -1
Let R={(3,3)(5,5),(9,9),(12,12),(5,12),(3,9),(3,12),(3,5)}R=\{(3,3)(5,5),(9,9),(12,12),(5,12),(3,9),(3,12),(3,5)\} be a relation on the set⁡A={3,5,9,12}\operatorname{set} A=\{3,5,9,12\}. Then, RR is :
View answer and explanation
Correct option: D
reflexive, transitive but not symmetric.
Option D (reflexive, transitive but not symmetric) is correct because the given relation satisfies the reflexive and transitive properties but fails to satisfy the symmetric property.
12 Easy
12 of 238
Analyzing +4 | -1
Consider the following two binary relations on the set A={a,b,c}:R1={(c,a)(b,b),(a,c),(c,c),(b,c),(a,a)}A=\{a, b, c\}: R_{1}=\{(\mathrm{c}, a)(b, b),(\mathrm{a}, c),(c, c),(b, c),(a, a)\} and R2={(a,b),(b,a),(c,c),(c,a),(a,a),(b,b),(a,c)R_{2}=\{(a, b),(b, a),(c, c),(c, a),(a, a),(b, b),(a, c). Then
View answer and explanation
Correct option: A
R2R_{2} is symmetric but it is not transitive
Option A (R2R_2 is symmetric but it is not transitive) is correct because R2R_2 satisfies the symmetric property but not the transitive property.
13 Easy
13 of 238
Understanding +4 | -1
In order that a relation RR defined on a non-empty set AA is an equivalence relation. It is sufficient, if RR
View answer and explanation
Correct option: D
possesses all the above three properties
Option D (possesses all the above three properties) is correct because an equivalence relation must be reflexive, symmetric, and transitive.
14 Easy
14 of 238
Analyzing +4 | -1
Let R1R_1 and R2R_2 be two relations defined as follows:

R1={(a,b)∈R2:a2+b2∈Q}R_1=\left\{(a, b) \in R^2: a^2+b^2 \in Q\right\}

and R2={(a,b)∈R2:a2+b2∉Q}.R_2=\left\{(a, b) \in R^2: a^2+b^2 \notin Q\right\}. Then,
View answer and explanation
Correct option: C
neither R1R_1 nor R2R_2 is transitive
The correct answer is C. Neither R1R_1 nor R2R_2 is transitive because counterexamples can be found for both relations.
15 Medium
15 of 238
Analyzing +4 | -1
The minimum number of elements that must be added to the relation R={a,b),(b,c)}R=\{a, b),(b, c)\} on the set {a,b,c}\{a, b, c\} so that it becomes symmetric and transitive is
View answer and explanation
Correct option: A
7
The minimum number of elements that must be added is 7. To make the relation symmetric and transitive, we need to add (b, a), (c, b), (a, c), (c, a), (a, a), (b, b), and (c, c).
16 Easy
16 of 238
Application +4 | -1
If f(x)=4x−x2,x∈Rf(x)=4 x-x^2, x \in R, then f(b+1)−f(b−1)f(b+1)-f(b-1) is equal to m(2−b){m}(2-{b}). The value of 'm{m}' is
View answer and explanation
Correct option: A
4
Option A (4) is correct because expanding f(b+1) - f(b-1) and comparing it to m(2-b) gives m = 4.
17 Medium
17 of 238
Understanding +4 | -1
Let XX be a set containing nn elements. The number of reflexive relations that can be defined on XX is
View answer and explanation
Correct option: B
2n2−n2^{n^2-n}
Option B (2n2−n2^{n^2-n}) is correct because a reflexive relation must contain n elements, leaving n2−nn^2 - n elements that can either be in the relation or not, resulting in 2n2−n2^{n^2-n} possible relations.
18 Easy
18 of 238
Understanding +4 | -1
Let L\mathrm{L} denote the set of all straight lines in a plane. Let a relation RR be defined by αRβ⇔α⊥β,α,β∈L\alpha R \beta \Leftrightarrow \alpha \perp \beta, \alpha, \beta \in L. Then, R\mathrm{R} is
View answer and explanation
Correct option: B
Symmetric
Option B (Symmetric) is correct because if line α\alpha is perpendicular to line β\beta, then line β\beta is also perpendicular to line α\alpha.
19 Easy
19 of 238
Analyzing +4 | -1
aRb⇔∣a∣≤ba R b \Leftrightarrow|a| \leq b. Then RR is
View answer and explanation
Correct option: C
Transitive
Option C (Transitive) is correct because if |a| ≤ b and |b| ≤ c, then |a| ≤ c, satisfying the transitive property.
20 Easy
20 of 238
Understanding +4 | -1
Let RR be a relation defined by R={(a,b):a≥b}R=\{(a, b): a \geq b\}, where aa and bb are real numbers, then RR is
View answer and explanation
Correct option: B
reflexive, transitive but not symmetric
Option B (reflexive, transitive but not symmetric) is correct because the relation a≥ba \geq b holds for a=ba=b (reflexive), if a≥ba \geq b and b≥cb \geq c then a≥ca \geq c (transitive), but a≥ba \geq b does not imply b≥ab \geq a (not symmetric).
21 Easy
21 of 238
Analyzing +4 | -1
Let A={2,3,4}A=\{2,3,4\} and B={8,9,12}B=\{8,9,12\}. Then the number of elements in the relation
R={((a1,b1),(a2,b2))∈(A×B,A×B):a1R=\left\{\left(\left(a_1, b_1\right),\left(a_2, b_2\right)\right) \in(A \times B, A \times B): a_1\right. divides b2b_2 and a2a_2 divides b1}\left.b_1\right\} is
View answer and explanation
Correct option: A
36
Option A (36) is correct because the number of elements in the relation R is calculated by considering all possible pairs (a1, b2) and (a2, b1) where a1 divides b2 and a2 divides b1.
22 Easy
22 of 238
Application +4 | -1
Let RR be the relation in the set N\mathrm{N} given by R={(a,b):a=b−2,b>6}R=\{(a, b): a=b-2, b>6\}. Choose the correct answer.
View answer and explanation
Correct option: C
(6,8)∈R(6,8) \in R
Option C ((6,8) ∈ R) is correct because it satisfies the condition a = b - 2 and b > 6.
23 Easy
23 of 238
Analyzing +4 | -1
On the set NN of all natural numbers define the relation RR by aRba R b if and only if the G.C.D. of aa and bb is 2 . then RR is
View answer and explanation
Correct option: B
Symmetric only
Option B (Symmetric only) is correct because if the GCD of a and b is 2, then the GCD of b and a is also 2, but a number's GCD with itself is itself, and transitivity doesn't hold.
24 Easy
24 of 238
Analyzing +4 | -1
If R={(a,b):3a−3b+7R=\{(a, b): 3 a-3 b+\sqrt{7} is irrational}\}. Then which among the following options are correct
View answer and explanation
Correct option: C
RR is reflexive but not symmetric
Option C (RR is reflexive but not symmetric) is correct because the relation satisfies the reflexive property but fails to satisfy the symmetric property.
25 Easy
25 of 238
Understanding +4 | -1
In a set of teachers of a school, two teachers are said to be related if they “teach the same subject”, then the relation is
View answer and explanation
Correct option: D
Equivalence
Option D (Equivalence) is correct because the relation "teach the same subject" is reflexive, symmetric, and transitive, thus it is an equivalence relation.
26 Easy
26 of 238
Application +4 | -1
Given two finite sets AA and BB such that n(A)=2,n(B)=3n(A)=2, n(B)=3. Then total number of relations from AA to BB is?
View answer and explanation
Correct option: C
64
The correct answer is C (64) because the total number of relations from A to B is 2 raised to the power of the cardinality of A cross B.
27 Medium
27 of 238
Analyzing +4 | -1
Let PP be the relation defined on the set of all real numbers such that P={(a,b):sec⁡2a−tan⁡2b=1}P=\left\{(a, b): \sec ^2 a-\tan ^2 b=1\right\}. Then PP is
View answer and explanation
Correct option: C
Symmetric and transitive but not reflexive.
Option C (Symmetric and transitive but not reflexive) is correct because the relation satisfies symmetry and transitivity but fails the reflexive property.
28 Easy
28 of 238
Understanding +4 | -1
Let RR be an equivalence relation on a finite set A having nn elements. Then, the number of ordered pairs in RR is
View answer and explanation
Correct option: B
Greater than or equal to nn
Option B (Greater than or equal to nn) is correct because an equivalence relation must be reflexive, meaning (a, a) is in R for all a in A, resulting in at least n ordered pairs.
29 Easy
29 of 238
Application +4 | -1
The solution set of 8x≡6( mod 14),x∈Z8 x \equiv 6(\bmod 14), x \in Z, are:
View answer and explanation
Correct option: C
[6]∪[13][6] \cup[13]
The correct answer is C ([6] ∪ [13]) because the solution set consists of equivalence classes that satisfy the given congruence relation.
30 Medium
30 of 238
Understanding +4 | -1
Consider the following statements.

I. If the set A{A} has 3 elements and set B={3,4,5}{B}=\{3,4,5\}, then the number of elements in A×B=9{A} \times {B}=9.

II. The domain of the relation R{R} defined by
R={(x,x+5):x∈(0,1,2,3,4,5)} is {5,6,7,8,9,10}.{R}=\{({x}, {x}+5): {x} \in(0,1,2,3,4,5)\} \text { is }\{5,6,7,8,9,10\} .

Choose the correct option.
View answer and explanation
Correct option: A
Only I is true
Only I is true because the number of elements in the Cartesian product is the product of the number of elements in each set, while the domain in statement II is incorrectly calculated.
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