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JEE • MATHEMATICS • PERMUTATION AND COMBINATION
Permutation and combination practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 91-120 of 485 questions
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91
Easy
91 of 485
Application
+4 | -1
A meeting is to be addressed by 5 speakers A, B, C, D, E. In how many ways can the speakers be ordered, if must not precede A (immediately or otherwise)?
View answer and explanation
Correct option: A
24
Option A (24) is correct because, with B not preceding A, we can consider A always following B, and arrange the remaining 4 speakers.
92
Easy
92 of 485
Application
+4 | -1
If , then the value of . The value of is
View answer and explanation
Correct option: A
6
Option A (6) is correct because simplifying the equation leads to , which is .
93
Easy
93 of 485
Analyzing
+4 | -1
There are 6 gentlemen and 3 ladies to dine at a round table. In how many ways can they seat themselves so that two particular ladies refuse to sit beside a particular gentleman?
View answer and explanation
Correct option: B
Option B () is correct because it calculates the total possible arrangements minus the arrangements where the two ladies sit beside the gentleman.
94
Easy
94 of 485
Analyzing
+4 | -1
Let , then (where, [ ] denotes the greatest integer function) is equal to
View answer and explanation
Correct option: C
5
Option C (5) is the correct answer because the remainder when is divided by 7 is 5 for .
95
Easy
95 of 485
Analyzing
+4 | -1
The number of positive integers with the property that they can be expressed as the sum of the cubes of 2 positive integers in two different ways is
View answer and explanation
Correct option: C
inifinite
The correct answer is C (infinite) because there are infinitely many positive integers that can be expressed as the sum of the cubes of two positive integers in two different ways.
96
Easy
96 of 485
Understanding
+4 | -1
The value of is equal to
View answer and explanation
Correct option: A
Option A, , is correct because it can be algebraically simplified to equal using the formula for permutations.
97
Easy
97 of 485
Application
+4 | -1
Find the number of ways of arranging the letters of the word 'PESSIMISTIC'
View answer and explanation
Correct option: D
Option D () is correct because it accounts for the repetitions of the letters S and I in the word PESSIMISTIC.
98
Easy
98 of 485
Application
+4 | -1
Total number of divisors of that are of the form , is equal to
View answer and explanation
Correct option: A
240
Option A (240) is correct because it accurately calculates the number of divisors of the given form by considering the powers of 3, 5, and 7 that satisfy the condition.
99
Easy
99 of 485
Analyzing
+4 | -1
Among permutations of the digits . Consider those arrangements which have the property that if we take any five consecutive positions, the product of the digits in those positions is divisible by 7, the number of such arrangements is
View answer and explanation
Correct option: C
Option C () is the correct answer because the digit 7 must be in the middle position, leaving 8! ways to arrange the remaining digits.
100
Easy
100 of 485
Analyzing
+4 | -1
Let denotes the property that two elements of add upto 1094. Then, maximum number of elements in can be
View answer and explanation
Correct option: C
137
Option C (137) is the correct answer because it represents the maximum number of elements in A that can be chosen without any two adding up to 1094.
101
Easy
101 of 485
Application
+4 | -1
The number of seven digit integers with sum of the digits equal to 10 and formed by using the digits 1, 2 and 3 only is
View answer and explanation
Correct option: C
77
Option C (77) is correct because it accurately counts the number of seven-digit integers formed using the digits 1, 2, and 3, with a digit sum of 10.
102
Easy
102 of 485
Application
+4 | -1
In a certain city, all telephone numbers have six digits, the first two digits always being 41 or 42 or 46 or 62 or 64 . The number of telephone numbers having all six digits distinct is
View answer and explanation
Correct option: A
8400
Option A (8400) is correct because it calculates the number of distinct telephone numbers for each possible starting pair and then multiplies by the number of starting pairs.
103
Easy
103 of 485
Application
+4 | -1
The number of polynomials of the form that are divisible by , where , , is
View answer and explanation
Correct option: A
10
Option A (10) is correct because the divisibility condition implies that b=1 and a=c, so there are 10 choices for a and c.
104
Easy
104 of 485
Application
+4 | -1
The number of ways in which 6 different beads can be string into a necklace is
View answer and explanation
Correct option: A
60
Option A () is correct because we calculate the total arrangements and subtract the arrangements where the two books are together.
105
Easy
105 of 485
Application
+4 | -1
The number of seven digit integers, with sum of the digits equal to 10 and formed by using the digits 1, 2 and 3 only, is
View answer and explanation
Correct option: C
77
Option C (77) is correct because the total number of integers is the sum of the possibilities from two cases: five 1's, one 2, one 3 and four 1's, three 2's.
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106
Easy
106 of 485
Application
+4 | -1
The number of ways in which you can put five beads of five different colours to form a necklace is:
View answer and explanation
Correct option: A
12
Option A (12) is correct because the number of ways to arrange the beads in a necklace is (n-1)!/2 due to rotational and reflectional symmetry.
107
Easy
107 of 485
Application
+4 | -1
Five persons are to address a meeting. If a specified speaker is to speak before another specified speaker, find the number of ways in which this could be arranged. In how many of these arrangements will the first speaker come immediately before the second?
View answer and explanation
Correct option: A
60 , 24
Option A (60 , 24) is correct because it accurately calculates the number of arrangements with the specified speaker order and the number of arrangements where they speak immediately before each other.
108
Easy
108 of 485
Application
+4 | -1
In how many ways a garland can be made from exactly 10 flowers?
View answer and explanation
Correct option: D
Option D () is correct because arranging flowers in a garland is a circular permutation, and since a garland can be flipped, we divide by 2.
109
Easy
109 of 485
Application
+4 | -1
From 6 different novels and 3 different dictionaries, 4 novels and 1 dictionary are to be selected and arranged in a row on the shelf so that the dictionary is always in the middle. Then the number of such arrangement is
View answer and explanation
Correct option: C
At least 1000
Option C (At least 1000) is correct because the total number of arrangements is calculated by selecting the novels and dictionary, then arranging them with the dictionary in the middle, resulting in 1080.
110
Easy
110 of 485
Application
+4 | -1
The number of ways in which 5 pictures can be hung from 7 picture nails on the wall is
View answer and explanation
Correct option: C
2520
Option C (2520) is correct because the number of ways to hang 5 pictures from 7 nails is a permutation problem, calculated as .
111
Easy
111 of 485
Application
+4 | -1
How many nine digit numbers can be formed by using the digits so that the odd digits occupy even positions?
View answer and explanation
Correct option: D
60
The correct answer is 60 because the odd digits must occupy the even positions, and the even digits must occupy the odd positions. The number of arrangements is calculated by multiplying the arrangements of odd digits in even places and even digits in odd places.
112
Easy
112 of 485
Analyzing
+4 | -1
Total number of divisors of that are of the form , is equal to
View answer and explanation
Correct option: C
384
Option C (384) is correct because it accurately counts the number of divisors of the specified form 4λ+2.
113
Easy
113 of 485
Application
+4 | -1
The number of 4-digit even numbers that can be formed using without repetition is
View answer and explanation
Correct option: C
420
Option C (420) is correct because it accounts for the restrictions on the first digit (cannot be 0) and the last digit (must be even) when forming the 4-digit even numbers.
114
Easy
114 of 485
Application
+4 | -1
Seven women and seven men are to sit round a circular table such that there is a man on either side of every women; the number of seating arrangements is
View answer and explanation
Correct option: C
Option C () is correct because it accounts for arranging the women around the table and then arranging the men in the spaces between them.
115
Easy
115 of 485
Application
+4 | -1
In a class of 10 students there are 3 girls students. The number of ways in which they can be arranged in a row, so that no two girls are consecutive is then is equal to
View answer and explanation
Correct option: D
42
Option D (42) is correct because arranging the boys and then placing the girls in the gaps results in k=42 when expressed as k(8!).
116
Easy
116 of 485
Application
+4 | -1
Let be a set containing elements. The number of ways of choosing two subsets and of such that is
View answer and explanation
Correct option: B
Option B () is correct because each element has three possibilities: belonging to P, belonging to Q, or belonging to neither.
117
Easy
117 of 485
Understanding
+4 | -1
The number of five digits numbers that can be formed without any restriction, is
View answer and explanation
Correct option: C
90000
Option C (90000) is correct because the first digit can be any number from 1 to 9 (9 options), and the remaining four digits can be any number from 0 to 9 (10 options each).
118
Easy
118 of 485
Application
+4 | -1
Seven atheletes are participating in a race. In how many ways can the first three prizes be won?
View answer and explanation
Correct option: B
210
Option B (210) is correct because it represents the number of ways to arrange 7 athletes taken 3 at a time, calculated using permutations.
119
Easy
119 of 485
Analyzing
+4 | -1
The number of ways in which the letters of the word ARRANGE be arranged so that "neither two A's nor two R's are together
View answer and explanation
Correct option: B
660
The correct answer is B (660) because it represents the number of arrangements where neither two A's nor two R's are together, calculated by subtracting arrangements with two R's together from those with two A's together.
120
Easy
120 of 485
Application
+4 | -1
How many numbers of 6 digits can be formed from the digits of the number 112233?
View answer and explanation
Correct option: C
90
Option C (90) is correct because the number of 6-digit numbers formed from 112233 is calculated by dividing the total permutations by the repetitions of each digit.
Revision notes and key takeaways
Review PERMUTATION AND COMBINATION in your textbook or class notes, then use this set to check your understanding.
Showing 91-120 of 485 questions
