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JEE • MATHEMATICS • PERMUTATION AND COMBINATION
Permutation and combination practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 61-90 of 485 questions
61
Easy
61 of 485
Application
+4 | -1
The lock of a safe consists of five discs each of which features the digits 0, 1, 2, … ,9.The safe can be opened by dialing a special combination of the digits. The number of days sufficient enough to open the safe. If the work day lasts 13 h and 5 s are needed to dial one combination of digits is
View answer and explanation
Correct option: C
11
Option C (11) is correct because calculating the total time to try all combinations and dividing by the workday length results in approximately 11 days.
62
Easy
62 of 485
Understanding
+4 | -1
The product of consecutive positive integers is divisible by
View answer and explanation
Correct option: A
!
Option A ( !) is correct because the product of consecutive positive integers can be expressed as , which is divisible by .
63
Easy
63 of 485
Application
+4 | -1
In a steamer there are stalls for 12 animals and there are cows, horses and calves (not less than 12 of each) ready to be shipped. The total number of ways in which the ship load can be made is
View answer and explanation
Correct option: C
Option C () is correct because each of the 12 stalls can be filled with one of the 3 types of animals.
64
Easy
64 of 485
Application
+4 | -1
The number of four-letter words that can be formed (the words need not be meaningful) using the letters of the word MEDITERRANEAN such that the first letter is E and the last letter is , is
View answer and explanation
Correct option: B
59
Option B (59) is correct because it is the total number of four-letter words formed with E as the first and R as the last letter, considering repetitions of letters in MEDITERRANEAN.
65
Easy
65 of 485
Application
+4 | -1
A man invites 10 friends for a dinner party. In how many they can be seated around a circular table so that two particular friends on either side of man?
View answer and explanation
Correct option: D
!
Option D () is correct because the two friends and the man are considered a single unit, leaving 8 other friends to arrange, and the two friends can switch places.
66
Easy
66 of 485
Application
+4 | -1
The number of ways of permuting the letters of the word DEVIL so that neither D is the first letter nor is the last letter is
View answer and explanation
Correct option: D
78
Option D (78) is correct because it accurately calculates the number of permutations of the word DEVIL where 'D' is not the first letter and 'L' is not the last letter using inclusion-exclusion principle.
67
Easy
67 of 485
Understanding
+4 | -1
The number of combinations of 4 different objects , taken 2 at a time is
View answer and explanation
Correct option: A
6
Option A (6) is correct because there are 6 ways to choose 2 objects from 4 distinct objects without regard to order.
68
Easy
68 of 485
Application
+4 | -1
The letters of the word 'HOSTEL' are arranged so that vowels occupy the end places. Then the number of arrangements is
View answer and explanation
Correct option: A
48
Option A (48) is correct because the 2 vowels can be arranged in the end places in 2! ways, and the remaining 4 letters can be arranged in 4! ways.
69
Easy
69 of 485
Application
+4 | -1
The number of ways to 16 different things to three persons so that gets one more than and gets two more than , is
View answer and explanation
Correct option: A
Option A () is correct because it represents the number of ways to divide 16 distinct items into groups of 4, 5, and 7.
70
Easy
70 of 485
Understanding
+4 | -1
The set to be partitioned into three sets of equal size. Thus,
. The number of ways to partition , is
. The number of ways to partition , is
View answer and explanation
Correct option: C
The correct answer is C () because it represents the number of ways to divide 12 distinct objects into 3 groups of 4, where the order of the groups doesn't matter.
71
Easy
71 of 485
Application
+4 | -1
The number of ways in which ten candidates can be arranged in a row "If are sit together in a specified order is
View answer and explanation
Correct option: C
8 !
Option C (8 !) is correct because treating A1, A2, and A3 as one unit reduces the problem to arranging 8 entities.
72
Easy
72 of 485
Application
+4 | -1
The number of divisors a number 38808 can have, excluding 1 and the number itself is
View answer and explanation
Correct option: A
70
Option A (70) is correct because it calculates the total number of divisors excluding 1 and the number itself.
73
Easy
73 of 485
Application
+4 | -1
Eleven animals of a circus have to be placed in eleven cages one in each cage. If 4 of the cages are too small for 6 of the animals, then the number of ways of caging the animals is
View answer and explanation
Correct option: C
604800
Option C (604800) is correct because it represents the total number of ways to cage the animals, considering the size constraints.
74
Easy
74 of 485
Application
+4 | -1
The number of numbers greater than 50,000 that can be formed by using the digits is
View answer and explanation
Correct option: B
48
Option A (3265920) is correct because we calculate the number of 8-digit numbers with distinct digits, considering that the first digit cannot be 0.
75
Easy
75 of 485
Application
+4 | -1
The number of ways that 8 beads of different colures be string as a necklace, is
View answer and explanation
Correct option: A
2520
Option A (2520) is correct because it applies the formula for circular permutations with the correction for flipping the necklace.
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76
Easy
76 of 485
Application
+4 | -1
The number of ways in which the six faces of a cube is painted with six different colours, is
View answer and explanation
Correct option: D
None of the above
The correct answer is None of the above because the number of ways to paint the cube is 30, not 1.
77
Easy
77 of 485
Application
+4 | -1
There are 6 letters and 3 post-boxes. The number of ways in which these letters can be posted, is
View answer and explanation
Correct option: B
Option B () is correct because each of the 6 letters can be posted in any of the 3 post-boxes, leading to possibilities.
78
Easy
78 of 485
Analyzing
+4 | -1
How many different words can be formed by Jumbling the letters in the word MISSISSIPPI in which no two S's are adjacent?
View answer and explanation
Correct option: C
Option A () is correct because it calculates the number of arrangements where no two S's are adjacent by first arranging the other letters and then placing the S's in the gaps.
79
Easy
79 of 485
Application
+4 | -1
The total number of words which can be formed out of the letters taken 3 together, such that each word contains at least one vowel, is
View answer and explanation
Correct option: C
96
Option C (96) is correct because it calculates the number of 3-letter words with at least one vowel from the given letters.
80
Easy
80 of 485
Application
+4 | -1
There are 5 letters and 5 different envelopes. The number of ways in which all the letters can be put in wrong envelope, is
View answer and explanation
Correct option: B
44
Option B (44) is correct because it uses the derangement formula to calculate the number of ways to put all letters in the wrong envelopes.
81
Easy
81 of 485
Application
+4 | -1
The letters of the word 'MEERUT' are arranged in all possible ways as in a dictionary, then the rank of the word 'MEERUT' is
View answer and explanation
Correct option: D
122
Option D (122) is correct because it is the sum of the number of words starting with letters before M, plus the number of words starting with MEERUT.
82
Easy
82 of 485
Application
+4 | -1
Number of numbers between 5000 and 10000 by using the digits without repetition is equal to
View answer and explanation
Correct option: B
72
Option B (72) is correct because there are 3 choices for the first digit (5, 7, or 9) and then 4! ways to arrange the remaining 4 digits.
83
Easy
83 of 485
Application
+4 | -1
8 different persons are sitting around a table. Numbers of ways in which we can select 3 of them so that no two are consecutive is
View answer and explanation
Correct option: B
16
Option B (16) is correct because it represents the number of ways to select 3 non-consecutive persons around a circular table.
84
Easy
84 of 485
Application
+4 | -1
If , then the total number of onto functions is equal to
View answer and explanation
Correct option: D
240
Option D (240) is correct because it accurately calculates the number of onto functions using the inclusion-exclusion principle.
85
Easy
85 of 485
Application
+4 | -1
Find the number of ways of arranging 6 boys and 6 girls around a circle
View answer and explanation
Correct option: B
11 !
Option B (11 !) is correct because arranging n people around a circle is (n-1)!, so with 12 people, it is (12-1)! = 11!.
86
Easy
86 of 485
Application
+4 | -1
The number of different 7 digit numbers that can be written using only the three digits 1,2 and 3 with the condition that the digit 2 occurs twice in each number is
View answer and explanation
Correct option: B
Option B () is correct because it calculates the number of ways to arrange the digits with the given condition.
87
Easy
87 of 485
Application
+4 | -1
Let be the set of four digit numbers , where , then is
View answer and explanation
Correct option: C
210
Option C (210) is correct because it represents the number of ways to choose 4 distinct digits from 10, which automatically arranges them in descending order.
88
Easy
88 of 485
Application
+4 | -1
The letters of the word "CONTINUE" are arranged in all possible ways. If the order of the vowels is not to be considered then the number of possible arrangements is
View answer and explanation
Correct option: C
840
Option C (840) is correct because it calculates the arrangements of consonants and then divides by the repetition of the letter N.
89
Easy
89 of 485
Application
+4 | -1
Out of 10 consonants four vowels, the number of words that can be formed using six consonants and three vowels
View answer and explanation
Correct option: C
Option C () is correct because it selects 6 consonants out of 10, 3 vowels out of 4, and then arranges the 9 selected letters.
90
Easy
90 of 485
Application
+4 | -1
The number of ways in which 5 boys and 5 girls can be seated for a photograph so that no two girls sit next to each other is
View answer and explanation
Correct option: A
Option A () is correct because it arranges the boys first and then places the girls in the gaps between them.
Revision notes and key takeaways
Review PERMUTATION AND COMBINATION in your textbook or class notes, then use this set to check your understanding.
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