JEE MATHEMATICS MCQ: PERMUTATIONS

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There are 10 points in a plane, of which no 3 points are collinear and 4 points are concyclic. The number of different circles that can be drawn through atleast 3 of these points, is

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Correct option: C

117

Option C (117) is correct because it calculates the total number of circles possible minus the circles formed by the 4 concyclic points, plus 1 (for the circle formed by the 4 concyclic points).

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