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JEE MATHEMATICS MCQ: PERMUTATIONS

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A library has a copies of one book, bb copies of each of two books, cc copies of each of three books and single copies of d books. The total number of ways in which these book can be distributed, is
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Correct option: B
(a+2b+3c+d)!a!(b!)2(c!)3\frac{{\left( {a + 2b + 3c + d} \right)!}}{{a!{{\left( {b!} \right)}^2}{{\left( {c!} \right)}^3}}}
Option B is correct because it accounts for the repetitions of identical books within each group (two books with b copies each and three books with c copies each) when calculating the total number of arrangements.

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