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JEE • MATHEMATICS • MATRICES

Matrices practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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391 Easy
391 of 922
Understanding +4 | -1
If every element of a third order determinant of value Δ\Delta is multiplied by 5, then the value of new determinant, is
View answer and explanation
Correct option: D
125Δ125 \Delta
Option D (125Δ125 \Delta) is correct because multiplying each element of a third-order determinant by 5 multiplies the determinant's value by 53=1255^3 = 125.
392 Easy
392 of 922
Application +4 | -1
If x,y,zx, y, z are real and
A=[02yzxy−zx−yz]A=\left[\begin{array}{ccc} 0 & 2 y & z \\ x & y & -z \\ x & -y & z \end{array}\right]
is such that AAT=IA A^{\mathrm{T}}=I, then
View answer and explanation
Correct option: B
x2+y2+z2=1x^2+y^2+z^2=1
Option B is correct. By multiplying A with its transpose and equating it to the identity matrix, we can deduce that x2 + y2 + z2 = 1.
393 Easy
393 of 922
Understanding +4 | -1
Assuming that the sum and product given below are defined, which of the following is not true for matrices?
View answer and explanation
Correct option: C
AB=OAB = O implies A=OA = O or B=OB = O
Option C (AB=OAB = O implies A=OA = O or B=OB = O) is not true because the product of two non-zero matrices can be a zero matrix.
394 Easy
394 of 922
Application +4 | -1
Let A=[abcd],a,b,c,d∈R.A=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right], a, b, c, d \in {R}. If A5=A3+IA^5=A^3+I, then AA is
View answer and explanation
Correct option: C
An invertible matrix
Option C (An invertible matrix) is correct because the given equation implies that A has an inverse, which is A4−A2A^4 - A^2.
395 Easy
395 of 922
Application +4 | -1
Let A=[3211]A=\left[\begin{array}{ll}3 & 2 \\ 1 & 1\end{array}\right] satisfies A2+aA+bI=OA^2+a A+b I=O, then a,ba, b are respectively equal to
View answer and explanation
Correct option: C
−4,1-4,1
Option C (−4,1-4,1) is correct because these values satisfy the equation A2+aA+bI=OA^2 + aA + bI = O.
396 Easy
396 of 922
Analyzing +4 | -1
The system of linear equations x+y+z=2,2x+3y+2z=5x + y + z = 2,2x + 3y + 2z = 5
2x+3y+(a2−1)z=a+12x + 3y + ({a^2} - 1)z = a + 1
View answer and explanation
Correct option: D
is inconsistent when ∣a∣=3\left| a \right| = \sqrt 3
Option D (is inconsistent when |a| = √3) is correct because when |a| = √3, the determinant of the coefficient matrix is zero, while at least one of the determinants formed by replacing a column with the constants is non-zero, indicating no solution.
397 Easy
397 of 922
Application +4 | -1
The number of solutions of the matrix equation X2=IX^2=I other than II is
View answer and explanation
Correct option: D
More than 2
Option D (More than 2) is correct because there are infinitely many matrices that satisfy X2 = I, beyond just the identity matrix itself.
398 Easy
398 of 922
Application +4 | -1
Let A=[2−134],B=[5274],C=[2538]A=\left[\begin{array}{cc}2 & -1 \\ 3 & 4\end{array}\right], B=\left[\begin{array}{ll}5 & 2 \\ 7 & 4\end{array}\right], C=\left[\begin{array}{ll}2 & 5 \\ 3 & 8\end{array}\right]. Let DD be a matrix such that CD=ABC D=A B, then DD equals
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated matrix DD does not match any of the given options.
399 Easy
399 of 922
Application +4 | -1
Let
A=[23−1410],B=[−123154] and C=[2−123−41]A=\left[\begin{array}{rr} 2 & 3 \\ -1 & 4 \\ 1 & 0 \end{array}\right], B=\left[\begin{array}{rr} -1 & 2 \\ 3 & 1 \\ 5 & 4 \end{array}\right] \text { and } C=\left[\begin{array}{rr} 2 & -1 \\ 2 & 3 \\ -4 & 1 \end{array}\right]

If
A−B+xC=[7−109−12−2]A-B+x C=\left[\begin{array}{cc} 7 & -1 \\ 0 & 9 \\ -12 & -2 \end{array}\right]
then the value of xx is
View answer and explanation
Correct option: D
2
Option D (2) is correct because solving the matrix equation A−B+xC=[7−109−12−2]A-B+x C=\left[\begin{array}{cc} 7 & -1 \\ 0 & 9 \\ -12 & -2 \end{array}\right] for x yields x=2.
400 Easy
400 of 922
Analyzing +4 | -1
If a1 b1 c1,a2 b2 c2a_1\, b_1\, c_1, a_2\, b_2\, c_2 and a3 b3 c3a_3\, b_3\, c_3 are three digit even natural numbers and
Δ=∣c1a1b1c2a2b2c3a3b3∣\Delta=\left|\begin{array}{lll}c_1 & a_1 & b_1 \\ c_2 & a_2 & b_2 \\ c_3 & a_3 & b_3\end{array}\right|, then Δ\Delta is
View answer and explanation
Correct option: A
divisible by 2 but not necessarily by 4
Option A (divisible by 2 but not necessarily by 4) is correct because each cic_i is divisible by 2, making the determinant divisible by 2, but not necessarily by 4.
401 Easy
401 of 922
Application +4 | -1
Let P=[100310931]  and  Q=[qij]  be  two  3×3P = \left[ {\begin{array}{cccccccccccccccccccc} 1&0&0\\ 3&1&0\\ 9&3&1 \end{array}} \right]\mathrm{ }\,\,\mathrm{and}\,\,\mathrm{ }Q = \left[ {{q_{ij}}} \right]\mathrm{ }\,\,\mathrm{be}\,\,\mathrm{ two }\,\,3 \times 3 matrices such that Q−P5=I3.Q - {P^5} = {I_3}. Then, q21+q31q32\frac{{{q_{21}} + {q_{31}}}}{{{q_{32}}}} is equal to
View answer and explanation
Correct option: A
10
Option A (10) is correct. After calculating P5 and then Q, the value of (q_{21} + q_{31})/q_{32} is found to be 10.
402 Easy
402 of 922
Application +4 | -1
If Δ=∣cos⁡θ2111cos⁡θ2−cos⁡θ2−cos⁡θ21−1∣\Delta=\left|\begin{array}{ccc}\cos \frac{\theta}{2} & 1 & 1 \\ 1 & \cos \frac{\theta}{2} & -\cos \frac{\theta}{2} \\ -\cos \frac{\theta}{2} & 1 & -1\end{array}\right| lies in the interval
View answer and explanation
Correct option: A
[2,4][2,4]
Option A, [2,4][2,4], is correct because the determinant simplifies to 2cos⁡2(θ/2)+22 \cos^2(\theta/2) + 2, which ranges from 2 to 4.
403 Easy
403 of 922
Application +4 | -1
If for a matrix A,A2+I=O,A,{A^2} + I = O, where II is the identity matrix, then AA equals
View answer and explanation
Correct option: B
[−i00−i]\left[ {\begin{array}{cccccccccccccccccccc} { - i}&0\\ 0&{ - i} \end{array}} \right]
Option B ([−i00−i]\left[ {\begin{array}{cccccccccccccccccccc} { - i}&0\\ 0&{ - i} \end{array}} \right]) is correct because when this matrix is squared and added to the identity matrix, the result is the zero matrix.
404 Easy
404 of 922
Analyzing +4 | -1
The matrices P=[u1v1w1u2v2w2u3v3w3];Q=19[22113−5m−815]P = \left[ {\begin{array}{cccccccccccccccccccc} {{u_1}}&{{v_1}}&{{w_1}}\\ {{u_2}}&{{v_2}}&{{w_2}}\\ {{u_3}}&{{v_3}}&{{w_3}} \end{array}} \right];Q = \frac{1}{9}\left[ {\begin{array}{cccccccccccccccccccc} 2&2&1\\ {13}&{ - 5}&m\\ { - 8}&1&5 \end{array}} \right] are such that PQ=IPQ = I, an identity matrix. Solving the equation [u1v1w1u2v2w2u3v3w3][xyz]=[115]\left[ {\begin{array}{cccccccccccccccccccc} {{u_1}}&{{v_1}}&{{w_1}}\\ {{u_2}}&{{v_2}}&{{w_2}}\\ {{u_3}}&{{v_3}}&{{w_3}} \end{array}} \right]\left[ {\begin{array}{cccccccccccccccccccc} x\\ y\\ z \end{array}} \right] = \left[ {\begin{array}{cccccccccccccccccccc} 1\\ 1\\ 5 \end{array}} \right], the value of yy comes out to be −3- 3. Then, the value of mm is equal to
View answer and explanation
Correct option: D
−7- 7
Option D (-7) is correct because solving the matrix equation PQ = I and using the given value of y allows us to determine the value of m.
405 Easy
405 of 922
Analyzing +4 | -1
Two fair dice are thrown. The numbers on them are taken as λ\lambda and μ\mu, and a system of linear equations x+y+z=5,  x+2y+3z=μx + y + z = 5,\,\,x + 2y + 3z = \mu and x+3y+λz=1x + 3y + \lambda z = 1 is constructed. If pp is the probability that the system has a unique solution and qq is the probability that the system has no solution, then
View answer and explanation
Correct option: B
p=56p = \frac{5}{6} and q=536q = \frac{5}{{36}}
Option B (p=56p = \frac{5}{6} and q=536q = \frac{5}{{36}}) is correct because it calculates the probabilities of a unique solution and no solution based on the determinant of the coefficient matrix.
406 Easy
406 of 922
Understanding +4 | -1
Let A,B,CA, B, C be three square matrices of the same order, such that whenever AB=ACA B=A C then B=CB=C, if AA is
View answer and explanation
Correct option: B
Non-singular
Option B (Non-singular) is correct because if A is non-singular, it has an inverse, allowing us to cancel A from both sides of the equation AB = AC.
407 Easy
407 of 922
Analyzing +4 | -1
∣a−bb−cc−ax−yy−zz−xp−qp−rr−p∣\left| {\begin{array}{cccccccccccccccccccc} {a - b}&{b - c}&{c - a}\\ {x - y}&{y - z}&{z - x}\\ {p - q}&{p - r}&{r - p} \end{array}} \right| is equal to
View answer and explanation
Correct option: B
0
Option B (0) is correct because the determinant simplifies to zero due to the linear dependence of the columns.
408 Easy
408 of 922
Application +4 | -1
If An=[2n0002n0002n]{A}^n=\left[\begin{array}{ccc}2^n & 0 & 0 \\ 0 & 2^n & 0 \\ 0 & 0 & 2^n\end{array}\right], then A10={A}^{10}=
View answer and explanation
Correct option: C
1024I1024 {I}
Option C (1024I1024I) is correct because A10A^{10} simplifies to 210I2^{10}I, which equals 1024I1024I.
409 Easy
409 of 922
Understanding +4 | -1
Which one of the following statement is true?
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Correct option: C
If A′=AA^{\prime}=A, then AA is square matrix
Option A (If A′=AA^{\prime}=A, then AA is square matrix) is correct because if a matrix is equal to its transpose, it must be a square matrix to maintain the same dimensions.
410 Easy
410 of 922
Analyzing +4 | -1
If the system of linear equations.
8x+y+4z=−2x+y+z=0λx−3y=μ\begin{gathered} 8x + y + 4z = - 2 \quad \\ x + y + z = 0 \quad \\ \lambda x - 3y = \mu \quad \\ \end{gathered}
has infinitely many solutions, then the distance of the point (λ,μ,−12)\left(\lambda, \mu,-\frac{1}{2}\right) from the plane 8x+y+4z+2=08 x+y+4 z+2=0 is
View answer and explanation
Correct option: D
103\frac{10}{3}
Option D (103\frac{10}{3}) is correct because it represents the distance of the point from the plane after finding the values of λ\lambda and μ\mu for which the system has infinitely many solutions.
411 Easy
411 of 922
Analyzing +4 | -1
Consider the following system of equations
x+2y−3z=ax + 2y - 3z = a
2x+6y−11z=b2x + 6y - 11z = b
x−2y+7z=cx - 2y + 7z = c
Where, a, ba,\,b and cc are real constants. Then, the system of equations
View answer and explanation
Correct option: B
has infinite number of solutions when 5a=2b+c5a = 2b + c
Option B (has infinite number of solutions when 5a = 2b + c) is correct because the determinant of the coefficient matrix is zero, and the condition 5a = 2b + c makes the system consistent, leading to infinite solutions.
412 Easy
412 of 922
Application +4 | -1
The matrix A=(p−qqp)A=\left(\begin{array}{cc}p & -q \\ q & p\end{array}\right) is orthogonal if and only if
View answer and explanation
Correct option: A
p2+q2=1p^2+q^2=1
Option A (p2+q2=1p^2+q^2=1) is correct because for a matrix to be orthogonal, A*A' = I, which leads to the condition p2 + q2 = 1.
413 Easy
413 of 922
Application +4 | -1
If
A=[α22α] and ∣A3∣=125A=\left[\begin{array}{ll} \alpha & 2 \\ 2 & \alpha \end{array}\right] \text { and }\left|A^3\right|=125
then α\alpha is equal to
View answer and explanation
Correct option: A
±3\pm 3
Option A (±3\pm 3) is correct because solving the equation ∣A3∣=125\left|A^3\right|=125 for α\alpha yields α=±3\alpha = \pm 3.
414 Easy
414 of 922
Analyzing +4 | -1
If the system of equations

x+y+az=b2x+5y+2z=6x+2y+3z=3\begin{array}{l} x+y+a z=b \\ 2 x+5 y+2 z=6 \\ x+2 y+3 z=3 \end{array}

has infinitely many solutions, then 2a+3b2 a+3 b is equal to
View answer and explanation
Correct option: C
23
Option C (23) is correct because it is the value of 2a+3b when the system has infinitely many solutions, which means the equations are dependent.
415 Easy
415 of 922
Application +4 | -1
If P=[sin⁡θcos⁡θ−cos⁡θsin⁡θ]\mathrm{P}=\left[\begin{array}{cc}\sin \theta & \cos \theta \\ -\cos \theta & \sin \theta\end{array}\right], then P−1=\mathrm{P}^{-1}=
View answer and explanation
Correct option: A
PT\mathrm{P}^{\mathrm{T}}
Option A (PTP^T) is correct because the inverse of the given matrix P is equal to its transpose, which can be verified by calculating the inverse and comparing it to the transpose.
416 Easy
416 of 922
Application +4 | -1
Which of the given values of x\mathrm{x} and yy make the following pairs of matrices equal:
[3x+75y+12−3x]⋅[0y−284]\left[\begin{array}{cc} 3 x+7 & 5 \\ y+1 & 2-3 x \end{array}\right] \cdot\left[\begin{array}{cc} 0 & y-2 \\ 8 & 4 \end{array}\right]
View answer and explanation
Correct option: B
Not possible to find
Option B (Not possible to find) is correct because the value of x obtained from different matrix elements is inconsistent, making it impossible to find a unique solution.
417 Easy
417 of 922
Remembering +4 | -1
In how many ways, the determinant of order 3 can be expanded?
View answer and explanation
Correct option: A
6
Option A (6) is correct because a 3x3 determinant can be expanded along any of its 3 rows or 3 columns, giving 6 possible expansions.
418 Easy
418 of 922
Application +4 | -1
If A=[abba]A=\left[\begin{array}{ll}a & b \\ b & a\end{array}\right] and A2=[αββα]A^2=\left[\begin{array}{ll}\alpha & \beta \\ \beta & \alpha\end{array}\right], then
View answer and explanation
Correct option: A
α=a2+b2β=2ab\alpha=a^2+b^2 \beta=2 a b
Option A (α=a2+b2,β=2ab\alpha=a^2+b^2, \beta=2 a b) is correct because it is the result of the matrix multiplication A2=A×AA^2 = A \times A.
419 Easy
419 of 922
Understanding +4 | -1
Let AA be a 3×33 \times 3 matrix such that A2−5A+7I=OA^2-5 A+7 I=O.

Statement −I:A−1=17(5I−A)-I: A^{-1}=\frac{1}{7}(5 I-A).

Statement −II-I I : The polynomial A3−2A2−3A+IA^3-2 A^2-3 A+I can be reduced to 5(A−4I)5(A-4 I). Then
View answer and explanation
Correct option: C
Both the statements are true.
Option C (Both the statements are true) is correct because both the inverse matrix and the polynomial reduction are derived correctly from the given matrix equation.
420 Easy
420 of 922
Analyzing +4 | -1
The value of ∣10C410C511Cm11C611C712Cm+212C812C913Cm+4∣=0,\left| {\begin{array}{cccccccccccccccccccc} {^{10}{C_4}}&{^{10}{C_5}}&{^{11}{C_m}}\\ {^{11}{C_6}}&{^{11}{C_7}}&{^{12}{C_{m + 2}}}\\ {^{12}{C_8}}&{^{12}{C_9}}&{^{13}{C_{m + 4}}} \end{array}} \right| = 0, when mm is equal to
View answer and explanation
Correct option: B
5
Option B (5) is correct because when m = 5, the first column becomes identical to another column after applying column operations, resulting in a zero determinant.
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