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JEE • MATHEMATICS • MATHEMATICAL REASONING

Mathematical reasoning practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 171 questions

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91 Easy
91 of 171
Analyzing +4 | -1
If Δ∈{∨,∧}\Delta \in\{\vee, \wedge\}, then the negation of Boolean expression (p→p∨q)Δ(p∧q→q)(p \rightarrow p \vee q) \Delta(p \wedge q \rightarrow q) is
View answer and explanation
Correct option: A
A contradiction
Option A (A contradiction) is correct because both implications are tautologies, and the negation of a tautology is a contradiction.
92 Easy
92 of 171
Understanding +4 | -1
Which of the following is not a statement?
View answer and explanation
Correct option: D
Come here
Option D (Come here) is the correct answer because it is an imperative sentence, which is not a statement.
93 Easy
93 of 171
Understanding +4 | -1
Which of the following is equivalent to the Boolean expression p∧∼q?p \wedge \sim q?
View answer and explanation
Correct option: D
∼(p→q)\sim (p \to q)
Option D (∼(p→q)\sim (p \to q)) is correct because it is logically equivalent to p∧∼qp \wedge \sim q based on the definition of implication and negation.
94 Easy
94 of 171
Understanding +4 | -1
The Statement that is TRUE among the following is
View answer and explanation
Correct option: A
The contrapositive of 3x+2=8⇒x=23 x+2=8 \Rightarrow x=2 is x≠2x \neq 2 ⇒3x+2≠8\Rightarrow 3 x+2 \neq 8
Option A (The contrapositive of 3x+2=8⇒x=23 x+2=8 \Rightarrow x=2 is x≠2x \neq 2 ⇒3x+2≠8\Rightarrow 3 x+2 \neq 8) is correct because it correctly identifies the contrapositive of the given statement.
95 Easy
95 of 171
Understanding +4 | -1
If I become a teacher, then I will open a school", is
View answer and explanation
Correct option: A
I will become a teacher and I will not open a school.
Option A (I will become a teacher and I will not open a school) is correct because it is the negation of the given statement.
96 Easy
96 of 171
Understanding +4 | -1
The logically equivalent proposition of p⇔qp \Leftrightarrow q is
View answer and explanation
Correct option: B
(p⇒q)∧(q⇒p)\left( {p \Rightarrow q} \right) \wedge \left( {q \Rightarrow p} \right)
Option B ((p⇒q)∧(q⇒p)\left( {p \Rightarrow q} \right) \wedge \left( {q \Rightarrow p} \right)) is correct because it is the definition of logical equivalence (biconditional).
97 Easy
97 of 171
Analyzing +4 | -1
If p:4p:4 an even prime number q:6q:6 is a divisor of 12 and r:r: the HCF of 4 and 6 is 2, then which one of the following is true?
View answer and explanation
Correct option: D
∼p∨(q∧r)\sim p \vee \left( {q \wedge r} \right)
Option D (∼p∨(q∧r)\sim p \vee (q \wedge r)) is true because pp is false, qq is true, and rr is true, making the disjunction true.
98 Easy
98 of 171
Analyzing +4 | -1
Which of the following is false?
View answer and explanation
Correct option: C
(p∧(p→))→\left( {p \wedge \left( {p \to } \right)} \right) \to is a contradiction
Option C is false because (p∧(p→q))→q(p \wedge (p \to q)) \to q is a tautology, not a contradiction. It represents Modus Ponens.
99 Easy
99 of 171
Analyzing +4 | -1
The statement (p⇒q)∨(p⇒r)(p \Rightarrow q) \vee(p \Rightarrow r) is NOT equivalent to
View answer and explanation
Correct option: B
(∼q)⇒((∼r)∨p)(\sim q) \Rightarrow((\sim r) \vee p)
Option B is the correct answer because (∼q)⇒((∼r)∨p)(\sim q) \Rightarrow((\sim r) \vee p) is not equivalent to (p⇒q)∨(p⇒r)(p \Rightarrow q) \vee(p \Rightarrow r) after logical transformations.
100 Easy
100 of 171
Understanding +4 | -1
Let AA, BB, CC and DD be four non-empty sets. The contrapositive statement of
"If A ⊆ BA\, \subseteq \,B and B ⊆ DB\, \subseteq \,D, then A ⊆ CA\, \subseteq \,C " is
View answer and explanation
Correct option: A
If A⊈C, then  A⊈B  or  B⊈D\mathrm{If}\,A\not \subseteq C,\,\mathrm{then}\,\,A\not \subseteq B\,\,\mathrm{or}\,\,B\not \subseteq D
Option A (If A⊈C,,thenA⊈B,orB⊈D\mathrm{If}\,A\not \subseteq C,\\,\mathrm{then}\\ A\not \subseteq B\\,\mathrm{or}\\ B\not \subseteq D) is correct because it correctly represents the contrapositive of the given statement.
101 Easy
101 of 171
Application +4 | -1
Simplify (p∨q)∧(p∨∼q)\left( {p \vee q} \right) \wedge \left( {p \vee \sim q} \right)
View answer and explanation
Correct option: A
pp
Option A (pp) is correct because the expression simplifies to pp using the distributive and complement laws of Boolean algebra.
102 Easy
102 of 171
Understanding +4 | -1
Consider the following statements:

PP : I have fever

QQ : I will not take medicine

RR : I will take rest

The statement "If I have fever, then I will take medicine and I will take rest
View answer and explanation
Correct option: C
((∼P)∨∼Q)∧((∼P)∨R)((\sim P) \vee \sim Q) \wedge((\sim P) \vee R)
Option C is correct because it accurately represents the logical statement "If I have fever, then I will not take medicine and I will take rest" in symbolic form.
103 Easy
103 of 171
Understanding +4 | -1
Let RR be the set of real numbers and x∈Rx \in R. Then, x+3=8x+3=8 is
View answer and explanation
Correct option: A
open statement
Option A (open statement) is correct because the truth value of the equation depends on the value of x.
104 Easy
104 of 171
Analyzing +4 | -1
The proposition p→ ∼ (p∧∼q)p \to \, \sim \,(p \wedge \sim q) is equivalent to
View answer and explanation
Correct option: B
(∼p)∨q( \sim p) \vee q
Option B (∼p)∨q( \sim p) \vee q is correct because the given proposition simplifies to this equivalent form using logical equivalences.
105 Easy
105 of 171
Understanding +4 | -1
Let

pp : Ramesh listens to music.

q:q: Ramesh is out of his village.

rr : It is Sunday.

ss : It is Saturday.

Then the statement "Ramesh listens to music only if he is in his village and it is Sunday or Saturday" can be expressed as
View answer and explanation
Correct option: D
p⇒((∼q)∧(r∨s)p \Rightarrow((\sim q) \wedge(r \vee s)
Option D (p⇒((∼q)∧(r∨s)p \Rightarrow((\sim q) \wedge(r \vee s)) is correct because it accurately translates the given statement into logical notation.
106 Easy
106 of 171
Analyzing +4 | -1
If (p→(p∧∼q)(p \to (p \wedge \sim q) is false, then the truth values of p and q are respectively
View answer and explanation
Correct option: D
T, T
Option D (T, T) is correct because for the implication to be false, the antecedent (p) must be true and the consequent (p∧∼qp \wedge \sim q) must be false, which implies both p and q are true.
107 Easy
107 of 171
Understanding +4 | -1
Negation of statement : if we control population growth we prosper, is
View answer and explanation
Correct option: C
we control population and we do not prosper
Option C (we control population and we do not prosper) is correct because the negation of "if p then q" is "p and not q".
108 Easy
108 of 171
Understanding +4 | -1
The contrapositive of the statement “ If I reach the station in time, then I will catch the train” is
View answer and explanation
Correct option: B
If I will not catch the train, then I do not reach the station in time
The correct answer is B (If I will not catch the train, then I do not reach the station in time) because it correctly applies the contrapositive transformation.
109 Easy
109 of 171
Remembering +4 | -1
A compound sentence formed by two simple statements pp and qq using connective 'or' is called
View answer and explanation
Correct option: B
Disjunction
Option B (Disjunction) is correct because a compound statement formed by two simple statements connected by 'or' is called a disjunction.
110 Easy
110 of 171
Understanding +4 | -1
Contrapositive of p→(q→r)p \rightarrow(q \rightarrow r) is logically equivalent to
View answer and explanation
Correct option: A
p→(q→r)p \rightarrow(q \rightarrow r)
Option A (p→(q→r)p \rightarrow (q \rightarrow r)) is correct because the contrapositive of p→(q→r)p \rightarrow (q \rightarrow r) is logically equivalent to itself.
111 Easy
111 of 171
Understanding +4 | -1
Negation of " 3 is an odd number and 7 is a rational number is -
View answer and explanation
Correct option: A
3 is not an odd number and 7 is not a rational number
Option D (3 is not an odd number or 7 is not a rational number) is correct because the negation of 'p and q' is 'not p or not q'.
112 Easy
112 of 171
Application +4 | -1
The negation of the Boolean expression ∼s∨(∼r∧s)\sim s \vee ( \sim r \wedge s) is equivalent to
View answer and explanation
Correct option: A
s∧rs \wedge r
Option A (s∧rs \wedge r) is correct because the negation simplifies to this expression using De Morgan's laws and Boolean algebra identities.
113 Easy
113 of 171
Understanding +4 | -1
The Negation of the statement (p∧q)→r(p \wedge q) \rightarrow r is -
View answer and explanation
Correct option: C
(p∧q)∧∼r(p \wedge q) \wedge \sim r
Option C ((p∧q)∧∼r(p \wedge q) \wedge \sim r) is correct because the negation of a conditional statement (a -> b) is a AND (not b).
114 Easy
114 of 171
Analyzing +4 | -1
If the truth value of the Boolean expression ((p∨q)∧(q→r)∧(∼r)→(p∧q))\left( {\left( {p \vee q} \right) \wedge \left( {q \to r} \right) \wedge \left( { \sim r} \right) \to \left( {p \wedge q} \right)} \right) is false, then the truth values of statements pp, qq and rr respectively can be
View answer and explanation
Correct option: C
T F F
Option C (T F F) is correct because it satisfies the condition where the given Boolean expression evaluates to false.
115 Easy
115 of 171
Understanding +4 | -1
The converse of (p∧(∼q))⇒r(p \wedge(\sim q)) \Rightarrow r is
View answer and explanation
Correct option: C
(∼p∨q)⇒∼r(\sim p \vee q) \Rightarrow \sim r
The correct answer is C because the converse of a conditional statement involves swapping the hypothesis and conclusion, and then applying De Morgan's law and the implication rule.
116 Easy
116 of 171
Analyzing +4 | -1
Among the statements :

(S1) ((p∨q)⇒r)⇔(p⇒r)((p \vee q) \Rightarrow r) \Leftrightarrow(p \Rightarrow r)

(S2) ((p∨q)⇒r)⇔((p⇒r)∨(q⇒r))((p \vee q) \Rightarrow r) \Leftrightarrow((p \Rightarrow r) \vee(q \Rightarrow r))
View answer and explanation
Correct option: C
neither (S1) nor (S2) is a tautology
Neither (S1) nor (S2) is a tautology because we can find truth values for p, q, and r that make the statements false. A tautology must be true for all possible truth values.
117 Easy
117 of 171
Analyzing +4 | -1
Given that water freezes below zero degree Celsius. Consider the following statements :
p:p: Water froze this morning, qq: This morning temperature was below 00C{0^0}\mathrm{C}
Which of the following is the correct?
View answer and explanation
Correct option: A
pp and qq are logically equivalent
Option A (pp and qq are logically equivalent) is correct because the statements express the same condition: water freezes if and only if the temperature is below zero.
118 Easy
118 of 171
Application +4 | -1
The region represented by the inequality ∣2Z−3i∣<∣3Z−2i∣|2 Z-3 i|<|3 Z-2 i| is

1) the unit disc with its centre at Z=0Z=0

2) the exterior of the unit circle with its centre at Z=0Z=0

3) the interior of a square of side 2 units with its centre at Z=0Z=0

4) the exterior of a square of side 2 units with its centre at Z=0Z=0
View answer and explanation
Correct option: A
2
Option A (2) is correct because the inequality represents the region outside the unit circle centered at the origin.
119 Easy
119 of 171
Application +4 | -1
If p,q,rp,q,r have truth values T,F,TT,F,T respectively, which of the following is true?
View answer and explanation
Correct option: D
q→(p∧r)q \to \left( {p \wedge r} \right)
Option D (q→(p∧r)q \to (p \wedge r)) is correct because with the given truth values, it evaluates to True, while the other options evaluate to False.
120 Easy
120 of 171
Understanding +4 | -1
The contrapositive of the statement "If it is raining, then I will not come", is :
View answer and explanation
Correct option: D
If I will come, then it is not raining.
Option D (If I will come, then it is not raining) is correct because it is the contrapositive of the given statement.
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