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JEE • MATHEMATICS • MATHEMATICAL REASONING

Mathematical reasoning practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 171 questions
1 Easy
1 of 171
Understanding +4 | -1
If p:Ap:A man is happy
q:Aq:A man is rich
Then, the statement, "If a man is not happy, then he is not rich" is written as
View answer and explanation
Correct option: A
∼p→∼q\sim p \to \sim q
Option A (∼p→∼q\sim p \to \sim q) is correct because it directly translates the given statement \"If a man is not happy, then he is not rich\" into symbolic form.
2 Easy
2 of 171
Understanding +4 | -1
Let pp and qq be two Statements. Amongst the following, the Statement that is equivalent to p→qp \rightarrow q is
View answer and explanation
Correct option: B
∼p∨q\sim p \vee q
Option B (∼p∨q\sim p \vee q) is correct because it is the logically equivalent form of the implication p→qp \rightarrow q.
3 Easy
3 of 171
Analyzing +4 | -1
Let F1(A, B, C)=(A∧∼B)∨[∼C∧(A∨B)]∨∼A{F_1}(A,\,B,\,C) = \left( {A \wedge \sim B} \right) \vee \left[ { \sim C \wedge \left( {A \vee B} \right)} \right] \vee \sim A and F2(A, B)=(A∨B)∨(B→ ∼ A){F_2}(A,\,B) = \left( {A \vee B} \right) \vee (B \to \, \sim \,A) be two logical expressions. Then,
View answer and explanation
Correct option: C
F1{F_1} is not tautology but F2{F_2} is a tautology
Option C (F1{F_1} is not tautology but F2{F_2} is a tautology) is correct because F1 can be false for some truth values of A, B, and C, while F2 is always true.
4 Easy
4 of 171
Understanding +4 | -1
The contrapositive of the following statement, "If the side of a square doubles, then its area increases four times", is :
View answer and explanation
Correct option: C
If the area of a square does not increases four times, then its side is not doubled.
Option C (If the area of a square does not increases four times, then its side is not doubled) is correct because it is the contrapositive of the given statement.
5 Easy
5 of 171
Understanding +4 | -1
The negation of the proposition "If 2 is prime, then 3 is odd" is
View answer and explanation
Correct option: B
2 is prime and 3 is not odd
Option B (2 is prime and 3 is not odd) is correct because it represents the negation of the conditional statement using the rule ∼(p→q)≡p∧∼q\sim (p \to q) \equiv p \wedge \sim q.
6 Easy
6 of 171
Understanding +4 | -1
Statement - 1: Contrapositive of "If the weather is cold, then it will snow" is "If it will not snow, then the weather is not cold".

Statement - 2: Negation of "If it snows then they do not drive the car" is "it snows and they drive the car".

Which of the following is true, regarding the above statements?
View answer and explanation
Correct option: B
Both S1,S2S_1, S_2
Option B (Both S1,S2S_1, S_2) is correct because Statement 1 correctly states the contrapositive, and Statement 2 correctly states the negation of the given conditional statements.
7 Easy
7 of 171
Analyzing +4 | -1
Statement (P⇒Q)∧(R⇒Q)(P \Rightarrow Q) \wedge(R \Rightarrow Q) is logically equivalent to
View answer and explanation
Correct option: D
(P∧R)⇒Q(P \wedge R) \Rightarrow Q
Option D ((P∧R)⇒Q(P \wedge R) \Rightarrow Q) is correct because it is the logical equivalent derived by converting implications to disjunctions and applying De Morgan's law.
8 Easy
8 of 171
Analyzing +4 | -1
p\mathrm{p} and q\mathrm{q} be two statements then ∼(∼p∧q)∧(p∨q)\sim(\sim p \wedge q) \wedge(p \vee q) is logically equivalent to
View answer and explanation
Correct option: C
pp
The correct answer is C. By simplifying the given logical expression using De Morgan's laws and other logical equivalences, it is shown to be logically equivalent to p.
9 Easy
9 of 171
Understanding +4 | -1
The expression ∼(∼p→q)\sim \left( { \sim p \to q} \right) is logically equivalent to
View answer and explanation
Correct option: D
∼p∧∼q\sim p \wedge \sim q
Option A (p∧∼qp \wedge \sim q) is correct because the expression simplifies to p∧∼qp \wedge \sim q using logical equivalences.
10 Easy
10 of 171
Understanding +4 | -1
The statement A→(B→A)A \to \left( {B \to A} \right) is equivalent to
View answer and explanation
Correct option: D
A→(A∨B)A \to \left( {A \vee B} \right)
Option D (A→(A∨B)A \to (A \vee B)) is correct because the given statement is a tautology and is equivalent to A→(A∨B)A \to (A \vee B).
11 Easy
11 of 171
Understanding +4 | -1
Consider the proposition : “ If the pressure increases, the volume decreases:. The negation of this proposition is
View answer and explanation
Correct option: C
If the volume does not decreases, the pressure does not increase
The correct answer is D because it represents the contrapositive of the original implication, which is logically equivalent to the negation.
12 Easy
12 of 171
Understanding +4 | -1
If pp is any statement, tt is tautology & cc is a contradiction, then which of following is not correct-
View answer and explanation
Correct option: A
p∨(∼p)≡cp \vee(\sim p) \equiv c
Option A is correct because p OR (NOT p) is always true (tautology), not a contradiction.
13 Easy
13 of 171
Understanding +4 | -1
Negation of the statement (p∨q)⇒(q∨r)(p \vee q) \Rightarrow (q \vee r) is
View answer and explanation
Correct option: A
p∧∼q∧∼rp \wedge \sim q \wedge \sim r
The correct answer is A (p∧∼q∧∼rp \wedge \sim q \wedge \sim r) because it represents the negation of the given implication using logical equivalences.
14 Easy
14 of 171
Understanding +4 | -1
Which of the following not a statement in logic?
1. Earth is planet.
2. Plants are living objects.
3. −3\sqrt { - 3} is a rational number.
4. x2−5x+6<0{x^2} - 5x + 6 < 0 , when x∈−Rx \in - R.
View answer and explanation
Correct option: C
2
Option D (4) is correct because x2−5x+6<0{x^2} - 5x + 6 < 0 is a statement for a specific x value, but not a statement in logic for all x in R.
15 Easy
15 of 171
Understanding +4 | -1
Assertion: The compound statement with 'And' is true if all its component statements are true.

Reason: The compound statement with 'And' is false if any of its component statements is false.
View answer and explanation
Correct option: B
Assertion is correct, reason is correct; reason is not a correct explanation for assertion
Option B (Assertion is correct, reason is correct; reason is not a correct explanation for assertion) is correct because both statements about compound statements with 'And' are true, but the reason doesn't explain the assertion.
16 Easy
16 of 171
Understanding +4 | -1
Let p,q,rp, q, r be the following three statements:

p:np: n is prime

q:nq: n is odd

r:nr: n is 2

Then p→q∨rp \rightarrow q \vee r means
View answer and explanation
Correct option: A
If nn is prime then nn is odd or 2
Option A (If nn is prime then nn is odd or 2) is correct because p→q∨rp \rightarrow q \vee r means "If nn is prime, then nn is odd or nn is 2".
17 Easy
17 of 171
Analyzing +4 | -1
(p∧∼q)∧(∼p∧q)(p \wedge \sim q) \wedge(\sim p \wedge q) is
View answer and explanation
Correct option: B
A contradiction
Option B (A contradiction) is correct because the given expression simplifies to a contradiction using associative and commutative laws.
18 Easy
18 of 171
Understanding +4 | -1
p∧q→pp \wedge q \to p is
View answer and explanation
Correct option: A
A tautology
Option A is correct because p∧q→pp \wedge q \to p is always true, making it a tautology.
19 Easy
19 of 171
Understanding +4 | -1
The contrapositive of the statement "if I am not feeling well, then I will go to the doctor" is
View answer and explanation
Correct option: C
If I will not go to the doctor, then I am feeling well
Option C (If I will not go to the doctor, then I am feeling well) is correct because it is the contrapositive of the given statement.
20 Easy
20 of 171
Understanding +4 | -1
If pp is any logical statement, then:
View answer and explanation
Correct option: C
p∧p≡pp \wedge p \equiv p
Option C (p∧p≡pp \wedge p \equiv p) is correct because it represents the idempotent law, which states that the conjunction of a statement with itself is equivalent to the statement itself.
21 Easy
21 of 171
Analyzing +4 | -1
Which of the following Boolean expression is not a tautology?
View answer and explanation
Correct option: D
(∼p⇒q)∨(∼q⇒p)( \sim p \Rightarrow q) \vee ( \sim q \Rightarrow p)
Option D ((∼p⇒q)∨(∼q⇒p)(\sim p \Rightarrow q) \vee (\sim q \Rightarrow p)) is not a tautology because its truth value depends on the values of p and q, and it is not always true.
22 Easy
22 of 171
Understanding +4 | -1
If pp is false and qq is true, then
View answer and explanation
Correct option: D
p⇒qp \Rightarrow q is true
Option D (p⇒qp \Rightarrow q) is correct because a false premise implies any conclusion, so p⇒qp \Rightarrow q is true when pp is false and qq is true.
23 Easy
23 of 171
Analyzing +4 | -1
The Boolean expression (p⇒q)∧(q⇒ ∼p)\left( {p \Rightarrow q} \right) \wedge \left( {q \Rightarrow \, \sim p} \right) is equivalent to
View answer and explanation
Correct option: D
∼q\sim q
Option A (∼q\sim q) is correct because the given Boolean expression simplifies to ∼p∧∼q\sim p \wedge \sim q, which is equivalent to ∼(p∨q)\sim (p \vee q), and further simplifies to ∼q\sim q given the initial conditions.
24 Easy
24 of 171
Analyzing +4 | -1
If the Boolean expression (p∧q)∗(p⊗q)(p \wedge q)*(p \otimes q) is a tautology, then * and ⊗\otimes are respectively, given by
View answer and explanation
Correct option: A
→,  →\to ,\,\, \to
Option A (→,,→\to ,\\,\to) is correct because it results in a tautology when substituted into the given Boolean expression.
25 Easy
25 of 171
Understanding +4 | -1
Let pp and qq denote the following statements p:p: The sun is shining qq : I shall play tennis in the afternoon The negation of the statement "If the sun is shining then I shall play tennis in the afternoon", is
View answer and explanation
Correct option: C
p∧∼qp \wedge \sim q
Option C (p∧∼qp \wedge \sim q) is correct because it represents the negation of the given conditional statement.
26 Easy
26 of 171
Analyzing +4 | -1
Which of the following is not tautology?
View answer and explanation
Correct option: B
(p∨q)→(p∨∼q)(p \vee q) \rightarrow(p \vee \sim q)
Option A, (p∨q)→p(p \vee q) \rightarrow p, is not a tautology because its truth value is not always true for all possible values of p and q.
27 Easy
27 of 171
Analyzing +4 | -1
Which of the following is not logically equivalent to the following proposition ' AA real number is either rational or irrational'?
View answer and explanation
Correct option: B
If a number is not a rational or not an irrational, then it is not real
Option B is correct because it is not logically equivalent to the given proposition; the original statement asserts that every real number must be either rational or irrational, while option B implies that if a number is not rational OR not irrational, then it is not real, which is not the same.
28 Easy
28 of 171
Analyzing +4 | -1
The logical statement [∼(∼p∨q)∨(p∧r)]∧(∼q∧r)[ \sim ( \sim p \vee q) \vee (p \wedge r)] \wedge ( \sim q \wedge r) is equivalent to
View answer and explanation
Correct option: C
(p∧r)∧∼q(p \wedge r) \wedge \sim q
Option C ((p∧r)∧∼q(p \wedge r) \wedge \sim q) is correct because the logical statement simplifies to this expression using De Morgan's laws and distributive properties.
29 Easy
29 of 171
Understanding +4 | -1
Consider the statement “For an integer nn if n3−1{n^3} - 1 even, then n is odd”. The contrapositive statement of this statement is
View answer and explanation
Correct option: A
For an integer n,n, if nn is even, then n3−1{n^3} - 1 is odd
Option A (For an integer n,n, if nn is even, then n3−1{n^3} - 1 is odd) is correct because it correctly represents the contrapositive of the given statement.
30 Easy
30 of 171
Understanding +4 | -1
Negation of "Pairs is in France and Londan is in England" is
View answer and explanation
Correct option: B
Pairs is not in France or Londan is not in England
Option B (Pairs is not in France or Londan is not in England) is correct because it represents the negation of the conjunction using De Morgan's Law.
Revision notes and key takeaways

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Key Takeaways

  • ✓ This set contains 171 single-correct-answer MCQs on MATHEMATICAL REASONING.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
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