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JEE MATHEMATICS MCQ: MATHEMATICAL REASONING

1 Easy

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Understanding +4 | -1

If

p

is any statement,

t

is tautology &

c

is a contradiction, then which of following is not correct-

View answer and explanation

Correct option: A

p \vee(\sim p) \equiv c

Option A is correct because p OR (NOT p) is always true (tautology), not a contradiction.

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p:A

q:A

man is rich
Then, the statement, "If a man is not happy, then he is not rich" is written as Consider the following compound statements.
(i) Mumbai is the capital of Rajasthan or Maharashtra.
(ii)

\sqrt{3}

is a rational or an irrational number.
(iii) 125 is a multiple of 7 or 8 .
(iv) A rectangle is a quadrilateral or a regular hexagon.
Which of the above statements is not true? Let

p

q

be two Statements. Amongst the following, the Statement that is equivalent to

p \rightarrow q

{F_1}(A,\,B,\,C) = \left( {A \wedge \sim B} \right) \vee \left[ { \sim C \wedge \left( {A \vee B} \right)} \right] \vee \sim A

{F_2}(A,\,B) = \left( {A \vee B} \right) \vee (B \to \, \sim \,A)

be two logical expressions. Then, The contrapositive of the following statement, "If the side of a square doubles, then its area increases four times", is : Suppose

p

: A natural number

n

q:

n

is not divisible by 2 , then the biconditional statement

p \Leftrightarrow q