Skip to main content
Back to SOLUTIONS

Your Progress

0 / 460 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • CHEMISTRY • SOLUTIONS

Solutions practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 301-330 of 460 questions

Preparing practice and saved progress…

301 Medium
301 of 460
Application +4 | -1
Which of the following solutions boils at the highest temperature
View answer and explanation
Correct option: B
0.1 M NaCl0.1 \,{M} \,{NaCl}
Option B (0.1 M NaCl0.1 \,{M} \,{NaCl}) is correct because NaCl dissociates into two ions, resulting in a higher effective concentration of particles and thus a greater elevation in boiling point compared to the other options.
302 Medium
302 of 460
Analyzing +4 | -1
Which of the following on addition in 1.0 molal KI solution will give rise to increase a vapour pressure?
View answer and explanation
Correct option: D
addition of water
Option D (addition of water) is correct because adding water dilutes the solution, increasing the surface area available for solvent evaporation and thus increasing the vapor pressure.
303 Hard
303 of 460
Application +4 | -1
A solution has 80%wwNaOH80 \% \frac{\mathrm{w}}{\mathrm{w}} \mathrm{NaOH} with density 2g L−1.2 \text{g L}^{-1}. Find

(a) Molarity \quad (b) Molality of solution
View answer and explanation
Correct option: A
(a) 0.04 M;0.04 \mathrm{~M}; (b) 100 mol kg−1100 \mathrm{~mol} \mathrm{~kg}^{-1}
Option A (a) 0.04 M; (b) 100 mol kg⁻¹ is correct because it correctly calculates the molarity and molality of the NaOH solution.
304 Easy
304 of 460
Understanding +4 | -1
Assertion : One molal aqueous solution of urea contains 60 g60 {~g} of urea in 1 kg(1000 g)1 {~kg}(1000 {~g}) water.

Reason : Solution containing one mole of solute in 1000 g1000 {~g} solvent is called as one molal solution.
View answer and explanation
Correct option: A
If both assertion and reason are true and the reason is the correct explanation of the assertion.
Option A (If both assertion and reason are true and the reason is the correct explanation of the assertion) is correct because the definition of molality is accurately stated, and it directly explains the assertion.
305 Hard
305 of 460
Application +4 | -1
A solution is prepared by mixing 8.5 gof CH2Cl28.5 \mathrm{~g}_{\text {of }} \mathrm{CH}_2 \mathrm{Cl}_2 and 11.95 g11.95 \mathrm{~g} of CHCl3\mathrm{CHCl}_3. If vapour pressure of CH2Cl2\mathrm{CH}_2 \mathrm{Cl}_2 and CHCl3\mathrm{CHCl}_3 at 298 K298 \mathrm{~K} are 415 and 200 mmHg200 \mathrm{~mmHg} respectively, the mole fraction of CHCl3\mathrm{CHCl}_3 in vapour form is :
(Molar mass of Cl=35.5 g mol−1\mathrm{Cl}=35.5 \mathrm{~g} \mathrm{~mol}^{-1} )
View answer and explanation
Correct option: C
0.325
Option C (0.325) is correct because it is the mole fraction of CHCl₃ in the vapor phase calculated using Raoult's Law and Dalton's Law.
306 Medium
306 of 460
Application +4 | -1
11.2 L11.2 \mathrm{~L} of HCl(g){HCl}({g}) is completely dissolved in 500 ml500 \mathrm{~ml} of aqueous solution. The molality of the solution is
View answer and explanation
Correct option: C
1 m1 \mathrm{~m}
Option C (1 m1 \mathrm{~m}) is correct because the molality is calculated by dividing the number of moles of HCl by the volume of the solution in liters.
307 Easy
307 of 460
Understanding +4 | -1
Dissolution of a solute is an exothermic process if :
View answer and explanation
Correct option: A
Hydration energy > lattice energy
Option A (Hydration energy > lattice energy) is correct because an exothermic dissolution process implies that the energy released during hydration is greater than the energy required to break the lattice.
308 Medium
308 of 460
Application +4 | -1
What is the molality of pure water?
View answer and explanation
Correct option: C
55.5
Option C (55.5) is correct because the molality of pure water is calculated by dividing 1000 g/kg by the molar mass of water.
309 Hard
309 of 460
Application +4 | -1
What volumes of 1 M  &  2 M H2SO41 \mathrm{~M} \, \, \& \, \, 2 \mathrm{~M} \mathrm{~H}_2 \mathrm{SO}_4 solution are required to produce 2 L2 \mathrm{~L} of 1.75 M H2SO41.75 \mathrm{~M~H}_2 \mathrm{SO}_4 solution?
View answer and explanation
Correct option: A
0.5 L;1.5 L0.5 \mathrm{~L}; 1.5 \mathrm{~L}
Option A (0.5 L;1.5 L0.5 \mathrm{~L}; 1.5 \mathrm{~L}) is correct because these volumes, when mixed, result in the desired concentration and volume of the sulfuric acid solution.
310 Easy
310 of 460
Application +4 | -1
11.1 g of CaCl2CaCl_2 is present in 100 ml of the aqueous solution. The chloride ion concentration is
View answer and explanation
Correct option: B
2 M
Option B (2 M) is correct because the chloride ion concentration is twice the molarity of CaCl2CaCl_2 due to each molecule dissociating into two chloride ions.
311 Medium
311 of 460
Application +4 | -1
In an osmotic pressure measurement experiment, a 5%5\% solution of compound ‘X’ is found to be isotonic with a 2%2\% acetic acid solution . The gram molecular mass of ‘X’ is
View answer and explanation
Correct option: C
150
Option C (150) is correct because the gram molecular mass of X is calculated by equating the molarities of the isotonic solutions and using the given percentages.
312 Easy
312 of 460
Application +4 | -1
The normality of 2.3  M  H2SO42.3\;\mathrm{M}\;{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} solution is
View answer and explanation
Correct option: A
4.6  N4.6\;\mathrm{ }N
Option A (4.6  N4.6\;\mathrm{ }N) is correct because Normality is calculated by multiplying Molarity by the basicity of the acid.
313 Medium
313 of 460
Application +4 | -1
The temperature at which 10%10 \% aqueous solution (w/V)(w / V) of glucose exhibits the osmotic pressure of 16.4 atm16.4 \mathrm{~atm}, is (R=0.082 dm3 atm K Kol−1)\left(R=0.082 \mathrm{~dm}^3 \mathrm{~atm} \mathrm{~K} \mathrm{~Kol}^{-1}\right)
View answer and explanation
Correct option: D
360 K360 \mathrm{~K}
Option D (360 K360 \mathrm{~K}) is correct because it is calculated using the osmotic pressure formula and the given values for concentration, osmotic pressure, and the gas constant.
314 Medium
314 of 460
Understanding +4 | -1
Statement I: Reverse osmosis is used in the desali- nation of sea water.

Statement II: When the applied pressure is more than the osmotic pressure, pure water is squeezed out of sea water through the membrane.
View answer and explanation
Correct option: A
If both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I
Option A is correct. Reverse osmosis uses pressure greater than osmotic pressure to force pure water through a semipermeable membrane, effectively desalinating seawater.
315 Easy
315 of 460
Analyzing +4 | -1
Equimolal solutions of A and B show depression in freezing point in the ratio 2:1.2 : 1. A remains in its normal state in solution. BB will be ……. in solution:
View answer and explanation
Correct option: C
Associated
Option C (Associated) is correct because the depression in freezing point is inversely proportional to the van't Hoff factor, indicating association.
316 Medium
316 of 460
Analyzing +4 | -1
Statement - I: When an ideal binary solution of liquids A and B is distilled, the boiling point of
the distillate becomes lower than that of the parental liquid solution.

Statement - II: When an ideal binary solution of liquids A and B is distilled, the distillate
contains relatively larger amount of the more volatile liquid.
View answer and explanation
Correct option: A
If both Statement-I and Statement-II are true, and Statement-II is the correct
explanation of Statement-I
Option A is correct because when an ideal binary solution is distilled, the distillate has a lower boiling point and contains more of the volatile liquid.
317 Easy
317 of 460
Analyzing +4 | -1
Which of the following statements is false?
View answer and explanation
Correct option: A
Two sucrose solution of same molality prepared in different solvent will have the same freezing point depression
Option A (Two sucrose solution of same molality prepared in different solvent will have the same freezing point depression) is false because the freezing point depression depends on the cryoscopic constant (kfk_f) of the solvent, which varies for different solvents.
318 Medium
318 of 460
Application +4 | -1
The relative lowering of vapour pressure of an aqueous solution containing non-volatile solute is 0.0125. The molality of the solution is
View answer and explanation
Correct option: A
0.700.70
The correct answer is A (0.70) because it correctly uses Raoult's law and the relationship between relative lowering of vapor pressure and molality.
319 Hard
319 of 460
Understanding +4 | -1
The degree of dissociation (α)(\alpha) of a week electrolyte, A2SO4\mathrm{A}_2 \mathrm{SO}_4 is related to Vant Hoff factor (i) by the expression
View answer and explanation
Correct option: A
i=1+2α\mathrm{i}=1+2 \alpha
Option A (i=1+2α\mathrm{i}=1+2 \alpha) is correct because the van't Hoff factor for A2SO4 dissociating into 3 ions is i = 1 + (n-1)α = 1 + 2α.
320 Medium
320 of 460
Understanding +4 | -1
If molality of the dilute solutions is doubled, the value of molal depression constant (Kf)\left({K}_{{f}}\right) will be
View answer and explanation
Correct option: C
Unchanged
The correct answer is C (Unchanged) because the molal depression constant (Kf) is a property of the solvent and is independent of the solute's molality.
321 Medium
321 of 460
Application +4 | -1
A liquid solution is formed by mixing 10 moles of aniline and 20 moles of phenol at a temperature where the vapour pressures of pure liquid aniline and phenol are 9090 and 87 mm Hg,87 \mathrm{~mm} \mathrm{~Hg}, respectively. The possible vapour pressure of solution at that temperature is
View answer and explanation
Correct option: A
82 mm Hg82 \mathrm{~mm} \mathrm{~Hg}
Option A (82 mm Hg82 \mathrm{~mm} \mathrm{~Hg}) is correct because the solution exhibits negative deviation from Raoult's law, resulting in a vapor pressure lower than the ideal value.
322 Hard
322 of 460
Application +4 | -1
1.2%NaCl1.2 \% \mathrm{NaCl} solution is isotonic with 7.2%7.2 \% glucose solution. What will be the van't Hoff factor ' ii ' for NaCl\mathrm{NaCl} ?
View answer and explanation
Correct option: C
2
Option C (2) is correct because the van't Hoff factor is calculated by comparing the osmotic pressures of the NaCl and glucose solutions.
323 Medium
323 of 460
Application +4 | -1
Two liquids AA and BB are mixed in a ratio of 2:32: 3. If PA∘=100 mmHgP_A^{\circ}=100 \,{mmHg} and PB∘=300 mmHgP_B^{\circ}=300 \,{mmHg}, then the mole fraction of AA in vapour phase will be
View answer and explanation
Correct option: A
211\frac{2}{11}
Option A (2/11) is correct because it is calculated by first finding the partial pressures of A and B and then using those to calculate the mole fraction of A in the vapor phase.
324 Easy
324 of 460
Understanding +4 | -1
Which method cannot be used to find out the molecular weight of non-volatile solute?
View answer and explanation
Correct option: A
Victor Meyer’s method
Option A (Victor Meyer’s method) is correct because it is used to determine the molecular weight of volatile solutes, not non-volatile solutes.
325 Medium
325 of 460
Analyzing +4 | -1
The boiling point of 0.2 mol kg−10.2 \mathrm{~mol} \mathrm{~kg}^{-1} solution X{X} in water is greater than equimolal solution of Y{Y} in water. Which one of the following statements is true in this case?
View answer and explanation
Correct option: D
XX is undergoing dissociation is water
Option D (XX is undergoing dissociation is water) is correct because a higher boiling point elevation for XX indicates a larger van't Hoff factor, implying dissociation.
326 Medium
326 of 460
Application +4 | -1
Two liquids X and Y form an ideal solution at 300K,vapour pressure of the solution containing 1 mol of X and 3, mol of Y is 550 mmHg. At the same temperature, if 1 mol of Y is further added to this solution, vapour pressure of the solution increases by 10 mmHg. Vapour pressure (in mmHg)of XandY in their pure states will be, respectively
View answer and explanation
Correct option: C
400 and 600
Option C (400 and 600) is correct because the vapor pressures of X and Y are calculated using Raoult's law and solving the system of equations.
327 Medium
327 of 460
Understanding +4 | -1
Assertion: Soda bottles are sealed under high pressure.

Reason: High pressure increases the solubility of carbon dioxide gas.
View answer and explanation
Correct option: A
Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
Option A (Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.) is correct because high pressure increases the solubility of gases in liquids, which is why soda bottles are sealed under high pressure to keep the carbon dioxide dissolved.
328 Hard
328 of 460
Remembering +4 | -1
The relationship which describes the variation of vapour pressure of a liquid with temperature is called :
View answer and explanation
Correct option: B
Clausius Clapeyron equation
Option B (Clausius Clapeyron equation) is correct because it describes the relationship between the vapor pressure of a liquid and temperature.
329 Medium
329 of 460
Understanding +4 | -1
The value of Henry's constant KHK_{\mathrm{H}} is
View answer and explanation
Correct option: B
greater for gases with lower solubility.
Option B (greater for gases with lower solubility) is correct because Henry's law states that the partial pressure of a gas is directly proportional to its solubility, with Henry's constant being the proportionality constant. Therefore, higher Henry's constant implies lower solubility.
330 Easy
330 of 460
Application +4 | -1
Which solution will have least vapour pressure?
View answer and explanation
Correct option: D
0.1  M  Na3PO40.1\;M\;\mathrm{N}{\mathrm{a}_3}\mathrm{P}{\mathrm{O}_4}
Answer 2 is correct because the equilibrium constant for the reverse reaction is the inverse of the square root of the original equilibrium constant.
Revision notes and key takeaways

Review SOLUTIONS in your textbook or class notes, then use this set to check your understanding.

Showing 301-330 of 460 questions

Your practice

0 / 460 answered · 460 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.