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JEE • CHEMISTRY • SOLUTIONS

Solutions practice · Mixed difficulty

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331 Easy
331 of 460
Understanding +4 | -1
Which one of the following binary liquid systems shows positive deviation from Raoult's law?
View answer and explanation
Correct option: B
Carbon disulphide-acetone
Option B (Carbon disulphide-acetone) is correct because the intermolecular forces between CS2 and acetone are weaker than the forces within each pure liquid, leading to positive deviation.
332 Hard
332 of 460
Analyzing +4 | -1
A current of dry air was passed through a series of bulbs containing 1.25 g1.25 \mathrm{~g} of a solute A2B\mathrm{A}_2 \mathrm{B} (molar mass =90 g/mol=90 \mathrm{~g} / \mathrm{mol}) in 49 g49 \mathrm{~g} of water and then through pure water. The loss in weight of the former series of bulbs was 0.98 g0.98 \mathrm{~g} and in the later series 0.01 g.0.01 \mathrm{~g}. The percentage dissociation of solute is
View answer and explanation
Correct option: A
50%50 \%
Option A is correct. The percentage dissociation is calculated using the vapor pressure lowering and Raoult's law, accounting for the van't Hoff factor.
333 Medium
333 of 460
Application +4 | -1
At 300 K300 \mathrm{~K}, the vapour pressure of an ideal solution containing 1 mole of liquid A{A} and 2 moles of liquid B{B} is 500 mm500 \mathrm{~mm} of Hg\mathrm{Hg}. The vapour pressure of the solution increases by 25 mm25 \mathrm{~mm} of Hg\mathrm{Hg} if one more mole of B{B} is added to the above ideal solution at 300 K300 \mathrm{~K}. The vapour pressure of AA in pure state is (in mm\mathrm{mm} of Hg\mathrm{Hg} ) :-
View answer and explanation
Correct option: A
300
Option A (300) is correct because it is derived from Raoult's Law by setting up and solving a system of equations based on the given vapor pressures.
334 Hard
334 of 460
Application +4 | -1
Acetic acid exists in benzene solution in the dimeric form. In an actual experiment the Van't Hoff factor of acetic acid in benzene solution was found to be 0.52 . Calculate the degree of association and osmotic pressure of 0.1M0.1 \mathrm{M} acetic acid solution in benzene at 300 K300 \mathrm{~K}
View answer and explanation
Correct option: B
0.96 and 1.28 atm1.28 \mathrm{~atm}
Option B (0.96 and 1.28 atm) is correct. The degree of association is calculated using the Van't Hoff factor, and osmotic pressure is calculated using π=iCRT\pi = iCRT.
335 Easy
335 of 460
Application +4 | -1
The mass of a non-volatile, non-electrolyte solute (molar mass =50 g mol−1=50 {~g} {~mol}^{-1} ) needed to be dissolved in 114 g114 {~g} octane to reduce its vapour pressure by 75%75 \%, is :-
View answer and explanation
Correct option: D
150 g150 {~g}
Option D (150 g150 {~g}) is correct because it is calculated using Raoult's law for vapor pressure lowering, considering the mole fraction of the solute.
336 Medium
336 of 460
Analyzing +4 | -1
Assertion: On mixing aniline and Acetone shows +ve deviation.

Reason: Interaction between Acetone and aniline is weaker than interaction of AcetoneAcetone and aniline-aniline.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the Assertion and the Reason are false. Aniline and acetone show negative deviation, and the interaction between them is stronger.
337 Medium
337 of 460
Application +4 | -1
Mole fraction of solute in an aqueous solution which boils at 100.104. Kb  for  H2O=0.52  K  molality−1{K_b}\;for\;{\mathrm{H}_2}\mathrm{O} = 0.52\;K\;\mathrm{molalit}{\mathrm{y}^{ - 1}}:
View answer and explanation
Correct option: B
0.0040.004
Option B (0.004) is correct because it calculates the mole fraction of the solute using the elevation in boiling point and the ebullioscopic constant.
338 Hard
338 of 460
Application +4 | -1
Dry air was passed successively through a solution containing 5 g of solute (non-volatile and non-electrolytic) in 90 ml H2O\mathrm{H}_2 \mathrm{O} and then through pure H2O.\mathrm{H}_2 \mathrm{O}. The loss in weight of solution was 2 g and that of pure solvent 0.05 g. The mol. wt. of solute (in gm) is: (Given: density of water = 1 g/cc)
View answer and explanation
Correct option: B
40
Option B (40) is correct because it is the molar mass calculated using Raoult's Law and the given weight losses.
339 Medium
339 of 460
Understanding +4 | -1
Assertion: At high altitude cooking food is difficult.

Reason: Water boils at high temperature.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option D (9.32 eV, 8.29 eV) is correct because Beryllium (Be) has a higher ionization potential than Boron (B) due to its stable, fully-filled 2s orbital configuration.
340 Hard
340 of 460
Understanding +4 | -1
Assertion: Isotonic solutions don't show net phenomenon of osmosis.

Reason: Isotonic solutions have equal osmotic pressure at constant temperature.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because isotonic solutions have the same osmotic pressure, which prevents net osmosis.
341 Medium
341 of 460
Application +4 | -1
How many grams of cane sugar are present in 534.2 g534.2 \mathrm{~g} of its aqueous solution having molality 0.2?
View answer and explanation
Correct option: B
34.2
Option B (34.2) is correct because it is the mass of cane sugar calculated using the given molality and the mass of the solution.
342 Medium
342 of 460
Analyzing +4 | -1
For each of the following dilute solutions, van't Hoff factor is equal of 3, except:
View answer and explanation
Correct option: C
K3PO4\mathrm{K}_3 \mathrm{PO}_4
Option C (K3PO4\mathrm{K}_3 \mathrm{PO}_4) is correct because it dissociates into 4 ions, resulting in a van't Hoff factor of 4.
343 Medium
343 of 460
Analyzing +4 | -1
A liquid freezes at 7∘C7^{\circ} \mathrm{C} and boils at 77∘C.77^{\circ} \mathrm{C}. If the KfK_{\mathrm{f}} and KbK_{\mathrm{b}} values for the liquid are 5.65.6 and 2.5 deg/molal,2.5 \, \mathrm{deg} / \mathrm{molal}, respectively, then the ratio of molar latent heat of fusion to molar latent heat of vaporization is
View answer and explanation
Correct option: C
2:72: 7
The correct answer is C (2:7) because it is calculated using the ratio of Kf/Kb and the squares of the freezing and boiling points.
344 Medium
344 of 460
Remembering +4 | -1
The pressure under which liquid and its vapour can coexist in equilibrium is known as:
View answer and explanation
Correct option: B
Saturated vapour pressure
Option B (Saturated vapour pressure) is correct because it is the pressure exerted by a vapor in equilibrium with its liquid at a given temperature.
345 Medium
345 of 460
Application +4 | -1
In an osmotic pressure measurement experiment, a 5%5\% solution of compound ‘X’ is found to be isotonic with a 2%2\% acetic acid solution . The gram molecular mass of ‘X’ is
View answer and explanation
Correct option: C
150
Option C (150) is correct because the gram molecular mass of X is calculated by equating the molarities of the isotonic solutions and using the given percentages.
346 Medium
346 of 460
Understanding +4 | -1
The Van't Hoff factor will be highest for
View answer and explanation
Correct option: C
Sodium phosphate
Option C (Sodium phosphate) is correct because it dissociates into the highest number of ions (4), leading to the highest van't Hoff factor.
347 Medium
347 of 460
Understanding +4 | -1
For a binary ideal liquid solution, the total pressure of the solution is given as:
View answer and explanation
Correct option: B
Ptotal =PB∘+(PA∘−PB∘)XAP_{\text {total }}=P_B^{\circ}+\left(P_A^{\circ}-P_B^{\circ}\right) X_A
Option B (Ptotal =PB∘+(PA∘−PB∘)XAP_{\text {total }} = P_B^{\circ} + (P_A^{\circ} - P_B^{\circ}) X_A) is correct because it represents Raoult's law for an ideal binary solution, expressing total pressure in terms of mole fraction and vapor pressures of pure components.
348 Medium
348 of 460
Analyzing +4 | -1
Assertion: Van't Hoff factor is always more or equal to one.

Reason: Van't Hoff factor is the ratio of experimental colligative properties to observed colligative properties.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
The correct answer is D (If both Assertion & Reason are false) because the Van't Hoff factor can be less than 1 for association, and the Reason incorrectly defines the Van't Hoff factor as the inverse ratio.
349 Easy
349 of 460
Remembering +4 | -1
Which of the following is not a colligative property
View answer and explanation
Correct option: A
Vapour pressure
Option A (Vapour pressure) is correct because vapor pressure itself is not a colligative property, but the *lowering* of vapor pressure is.
350 Medium
350 of 460
Application +4 | -1
A 5% solution of cane sugar (Molar mass 342) is isotonic with 1% of a solution of an unknown solute. The molar mass of unknown solute is
View answer and explanation
Correct option: C
68.468.4
Option C (Mol. wt./6) is correct because the equivalent weight is calculated by dividing the molecular weight by the change in oxidation number of iodine in the reaction.
351 Easy
351 of 460
Understanding +4 | -1
Which of the following represents a metastable system?
View answer and explanation
Correct option: D
A supersaturated solution
Option D (A supersaturated solution) is correct because a supersaturated solution is a metastable system that can easily precipitate upon disturbance.
352 Hard
352 of 460
Application +4 | -1
Calculate osmotic pressure of a solution obtained by mixing 100 mL100 \mathrm{~mL} of 3.4%3.4 \% (mass/vol.) solution of urea (molar mass 60 ) and 100 mL100 \mathrm{~mL} of 1.6%1.6 \% solution of cane-sugar (molar mass 342 ) at 20∘C20^{\circ} \mathrm{C}.
View answer and explanation
Correct option: B
7.38 atm7.38 \mathrm{~atm}
Option B (7.38 atm7.38 \mathrm{~atm}) is correct because the total osmotic pressure is the sum of the osmotic pressures of urea and cane-sugar, calculated separately using the osmotic pressure formula.
353 Medium
353 of 460
Application +4 | -1
The ratio of elevation in boiling point for Fe3[Fe(CN)6]2{Fe}_3\left[{Fe}({CN})_6\right]_2 (assume complete ionization) to elevation in boiling point of sugar solution of equal molal concentration is
View answer and explanation
Correct option: A
5:15: 1
The correct answer is A (5:15: 1) because the ratio of elevation in boiling point is directly proportional to the van't Hoff factor, which is 5 for the complex and 1 for sugar.
354 Medium
354 of 460
Understanding +4 | -1
Statement I: Vapour pressure of water is less than 1.013 bar at 373 K373 \mathrm{~K}.

Statement II: Water boils at 373 K373 \mathrm{~K} as the vapour pressure of water at this temperature becomes equal to atmospheric pressure
View answer and explanation
Correct option: D
If Statement I is false but Statement II is correct
Option D (If Statement I is false but Statement II is correct) is correct because the vapor pressure of water at 373 K is equal to 1.013 bar, and water boils when its vapor pressure equals atmospheric pressure.
355 Hard
355 of 460
Understanding +4 | -1
The partition coefficient of solute XX in between immiscible liquids AA and BB is 10 in favour of AA. The partition coefficient of XX in favour of BB is :
View answer and explanation
Correct option: A
0.1
Option A (0.1) is correct because the partition coefficient in favor of B is the inverse of the partition coefficient in favor of A.
356 Medium
356 of 460
Analyzing +4 | -1
Assertion (A): 0.1 M solution of glucose has higher increment in the freezing point than 0.1 M solution of urea.

Reason (R): Kf\mathrm{K}_{\mathrm{f}} for both has different values.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D (Both (A) and (R) are false) is correct because the freezing point depression is a colligative property and depends on the number of particles. Glucose and urea are both non-electrolytes, so for the same molarity, they will have the same freezing point depression. Also, Kf is a constant for a given solvent.
357 Medium
357 of 460
Application +4 | -1
Find out molality of 0.8 M H2SO40.8 \mathrm{~M} \mathrm{~H}_2 \mathrm{SO}_4 solution having density of solution equal to 1.02 gm/ml1.02 \mathrm{~gm} / \mathrm{ml} (Nearest integer)
View answer and explanation
Correct option: A
1
Option A (1) is correct because the molality is calculated using the given molarity and density, and the result is closest to 1.
358 Medium
358 of 460
Understanding +4 | -1
Assertion (A) : At low concentration, benzene and toluene forms ideal solution.

Reason (R) : Components with structural similarity forms ideal solution
View answer and explanation
Correct option: C
Both Assertion and Reason are correct and Reason is correct explantion of Assertion
Option C is correct because benzene and toluene are structurally similar and form ideal solutions at low concentrations, and structural similarity is the reason for ideal solution formation.
359 Medium
359 of 460
Application +4 | -1
Ice begins to separate at −0.744∘C-0.744^{\circ} \mathrm{C} from an aqueous solution containing 2.4 g2.4 \mathrm{~g} of a non-volatile, non-electrolyte in 100 g100 \mathrm{~g} water. The osmotic pressure of the solution at 27∘C27^{\circ} \mathrm{C} is (Kf\left(K_{\mathrm{f}}\right. for water =1.86,=1.86, assume molality == molarity)
View answer and explanation
Correct option: B
9.852 atm
Option B (9.852 atm) is correct because the osmotic pressure is calculated using the freezing point depression and the ideal gas law.
360 Easy
360 of 460
Understanding +4 | -1
Assertion (A): When 10 ml10 \, \mathrm{ml} of liquid A mixed with 20 ml20 \, \mathrm{ml} of liquid B, then total volume of solution is 30 ml30 \, \mathrm{ml}.

Reason (R): ΔVmix=0\Delta V_{\text {mix}}=0 for ideal solution.
View answer and explanation
Correct option: A
Both A & R are true, R is the correct explanation of A
Option A is correct because for an ideal solution, the volume change upon mixing is zero, which directly explains why the total volume is the sum of individual volumes.
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