Henry’s constant (in kbar) for four gases $\alpha $, $\beta $, $\gamma $ and $\delta $ in water at 298 K is given below: $\begin{array}{*{20}{c}} {}&\alpha &\beta &\gamma &\delta \\ {{K_H}}&{50}&2&{2 \times {{10}^{ - 5}}}&{0.5} \end{array}$ (density of water $ = {10^3}\,kg\,{m^{ - 3}}$ at 298 K) This implies that

$\alpha $ has the highest solubility in water at a given pressure

Solubility of $\gamma $ at 308 K is lower than at 298 K

The pressure of a 55.5 molal solution of $\gamma $ is 1 bar

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Solutions practice · Medium

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Showing 1-30 of 265 questions

1 Medium

1 of 265

Application +4 | -1

An aqueous solution of a solute which neither associates nor dissociates has a freezing point depression of

\mathrm{X}^{\circ} \mathrm{C}.

An equimolal solution of a second salt has a freezing point depression of

3 \mathrm{X}^{\circ} \mathrm{C}.

Assuming

100 \%

dissociation of salt, the second solution could be a salt of formula

View answer and explanation

Correct option: B

\mathrm{AB}_2

Option B (

\mathrm{AB}_2

) is correct because the van't Hoff factor for this salt is 3, matching the given freezing point depression ratio.

2 Medium

2 of 265

Understanding +4 | -1

Read the following statements carefully and choose the correct option

(i) Osmotic pressure is not a colligative property.

(ii) For dilute solutions, osmotic pressure is proportional to the molarity,

{C}

of the solution at a given temperature

T

.

(iii) During osmosis, solvent molecules always flow from higher concentration to lower concentration of solution.

(iv) The osmotic pressure has been found to depend on the concentration of the solution

View answer and explanation

Correct option: B

(ii) and (iv) are correct

Option B is correct because osmotic pressure is a colligative property that depends on the concentration of the solution, making statements (ii) and (iv) correct.

3 Medium

3 of 265

Remembering +4 | -1

A solution that obeys Raoult’s law is called

View answer and explanation

Correct option: C

Ideal solution

Option C (Ideal solution) is correct because an ideal solution is defined as one that obeys Raoult's law over the entire composition range.

4 Medium

4 of 265

Analyzing +4 | -1

Information

I. Semipermeable membrane contains network of submacroscopic holes or pores.

II. Semipermeable membrane appears to be continuous sheets or films.

III. Solvent molecules cannot pass through the holes of semipermeable membrane but solute molecules can pass On the basis of the information given above select the correct option.

View answer and explanation

Correct option: C

Only III

Option C (Only III) is correct because semipermeable membranes allow solvent molecules to pass through but hinder the passage of larger solute molecules.

5 Medium

5 of 265

Analyzing +4 | -1

Assertion (A) : Addition of

\mathrm{HgI}_2

to aqueous solution of

\mathrm{KI}

shows an increase in vapour pressure.

Reason (R) : The number of particles present in solution decreases due to formation of complex

\mathrm{K}_2 \mathrm{HgI}_4

View answer and explanation

Correct option: C

Both Assertion and Reason are correct and Reason is correct explantion of Assertion

Option C (Both Assertion and Reason are correct and Reason is correct explantion of Assertion) is correct because the addition of

\mathrm{HgI}_2

to KI decreases the number of particles due to complex formation, leading to an increase in vapor pressure.

6 Medium

6 of 265

Analyzing +4 | -1

Three solutions have been provided

I.

3 \mathrm{~g} \mathrm{~HCl}

1 \mathrm{~kg} \mathrm{~H}_2 \mathrm{O}

II.

2 \mathrm{~L} \mathrm{~HCl}(g)

and

1 \mathrm{~L} \mathrm{~H}_2 \mathrm{O}

at room temperature

III. Aqueous solution of

\mathrm{HCl}

with

\chi_{\mathrm{HCl}}=1.5 \times 10^{-3}

.

Solutions containing same number of moles of

\mathrm{HCl}

is/are

View answer and explanation

Correct option: B

I and III

Option D (Statement II is incorrect but Statement I is correct) is correct because the equilibrium constant Kc is indeed 1, but doubling the initial moles of A and B does not double the percentage dissociation.

7 Medium

7 of 265

Analyzing +4 | -1

Assertion : Ifred blood cells were removed from the body and placed in pure water, pressure inside the cells increases.

Reason : The concentration of salt content in the cells increases.

View answer and explanation

Correct option: C

If the Assertion is correct but Reason is incorrect.

Option C is correct because if red blood cells are placed in pure water, water enters the cells due to osmosis, increasing the pressure inside. The salt concentration inside decreases, not increases.

8 Medium

8 of 265

Application +4 | -1

Exactly

1 {~g}

of urea dissolved in

75 {~g}

of water gives a solution that boils at

100.114^{\circ} {C}

at 760

torr

. The molecular weight of urea is 60.1 . The boiling point elevation constant for water is

View answer and explanation

Correct option: B

0.51

Option B (

0.51

) is correct because the boiling point elevation constant is calculated using the colligative properties formula.

9 Medium

9 of 265

Application +4 | -1

What is the freezing point of one litre of an aqueous solution of a non-electrolyte having an osmotic pressure of 2 atm at

300 \mathrm{~K}

View answer and explanation

Correct option: D

272.849 \mathrm{~K}

Option D (272.849 K) is correct because it is the freezing point calculated using the osmotic pressure to find molality and then applying the freezing point depression formula.

10 Medium

10 of 265

Application +4 | -1

What is the molarity of

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}

solution if 25 mL is exactly neutralised with

32.63\mathrm{ }\;mL\mathrm{ }\;of\mathrm{ }\;0.164\mathrm{ }\;M\;\mathrm{ }NaOH

View answer and explanation

Correct option: A

0.107\;\mathrm{ }M

Option A (

0.107\;\mathrm{ }M

) is correct because it is the molarity of H2SO4 calculated using the neutralization reaction with NaOH and accounting for the basicity of H2SO4.

11 Medium

11 of 265

Application +4 | -1

Henry's law constant for the solubility of methane in benzene at

298 \mathrm{~K}

4.27 \times 10^5 \mathrm{~mm} \mathrm{Hg}

. Calculate the solubility of methane in benzene at

298 \mathrm{~K}

under

760 \mathrm{~mm~Hg}

View answer and explanation

Correct option: A

1.78 \times 10^{-3}

Option A (

1.78 \times 10^{-3}

) is correct because it is calculated directly from Henry's Law:

p = K_H \times x

, where x is the solubility.

12 Medium

12 of 265

Application +4 | -1

What is the boiling point of a solution of

1.00 \mathrm{~g}

of naphthalene dissolved in

94.0 \mathrm{~g}

of toluene? The normal boiling point of toluene is

110.75^{\circ} \mathrm{C}

and

K_{{x}, {b}}=32.0 \mathrm{~K}

for toluene.

View answer and explanation

Correct option: B

111.0^{\circ} \mathrm{C}

The correct answer is

111.0^{\circ} \mathrm{C}

. The boiling point elevation is calculated using the ebullioscopic constant and the mole fraction of the solute.

13 Medium

13 of 265

Application +4 | -1

\mathrm{KMnO}_4

reacts with oxalic acid as:

\mathrm{MnO}_4^{-}+\mathrm{C}_2 \mathrm{O}_4^{2-}+\mathrm{H}^{+} \rightarrow \mathrm{Mn}^{2+}+\mathrm{CO}_2+\mathrm{H}_2 \mathrm{O}

Hence, 50 ml of

0.04 \mathrm{~M~KMnO}_4

is acidic medium is chemically equivalent to

View answer and explanation

Correct option: C

50 ml of

0.1 \mathrm{~M~H}_2 \mathrm{C}_2 \mathrm{O}_4

Option B (50 ml of 0.2 M H₂C₂O₄) is correct because the number of milliequivalents of KMnO₄ and H₂C₂O₄ are equal.

14 Medium

14 of 265

Application +4 | -1

Five percent solution of a solute

(X)

is isotonic
with 0.855% solution of sucrose (molecular
weight = 342). What is the molecular mass of
solute

(X)?

View answer and explanation

Correct option: D

2000

Option D (2000) is correct because the molecular mass of solute X is calculated using the isotonic condition, equating concentrations of the two solutions.

15 Medium

15 of 265

Application +4 | -1

An aqueous solution is

6 \%

methanol,

\mathrm{CH}_3 \mathrm{OH}

, by mass with

d=0.988 \mathrm{~g} \mathrm{~mL}^{-1}

. Thus, molarity of

\mathrm{CH}_3 \mathrm{OH}

in this solution is

View answer and explanation

Correct option: D

1.85 M

Option D (1.85 M) is correct because the molarity is calculated by finding the moles of methanol and dividing by the volume of the solution in liters.

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16 Medium

16 of 265

Application +4 | -1

What is the molality of pure water?

View answer and explanation

Correct option: C

55.5

Option C (55.5) is correct because the molality of pure water is calculated by dividing 1000g by the molar mass of water (18 g/mol).

17 Medium

17 of 265

Application +4 | -1

A closed container contains equal number of oxygen and hydrogen molecules at a pressure of 740 mm. If oxygen is removed from the system then pressure will:

View answer and explanation

Correct option: B

Become half of 740 mm

Option B is correct because removing oxygen from the system halves the total pressure, as the partial pressures of oxygen and hydrogen were initially equal.

18 Medium

18 of 265

Understanding +4 | -1

Which of the following is not correct for a solution showing negative deviation from Raoult's law?

View answer and explanation

Correct option: A

(\Delta \mathrm{S})_{\text {mixing }} < 0

Option A is correct because for solutions showing negative deviation from Raoult's law, the mixing process leads to a decrease in entropy (ΔS < 0).

19 Medium

19 of 265

Analyzing +4 | -1

Henry’s constant (in kbar) for four gases

\alpha

\beta

\gamma

and

\delta

in water at 298 K is given below:

\begin{array}{cccccccccccccccccccc} {}&\alpha &\beta &\gamma &\delta \\ {{K_H}}&{50}&2&{2 \times {{10}^{ - 5}}}&{0.5} \end{array}

(density of water

= {10^3}\,kg\,{m^{ - 3}}

at 298 K)
This implies that

View answer and explanation

Correct option: D

The pressure of a 55.5 molal solution of

\delta

is 250 bar

Option D (The pressure of a 55.5 molal solution of

\delta

is 250 bar) is correct because it is derived from Henry's Law using the given Henry's constant and molality.

20 Medium

20 of 265

Analyzing +4 | -1

The boiling point of water and

{HCl}

are

100^{\circ} {C}

and

86^{\circ} {C}

respectively. An azeotropic mixture boils at about

120^{\circ} {C}

. Fractional distillation of this solution will give :

View answer and explanation

Correct option: D

A mixture of

{HCl}

in the ratio in which they are present in mixture

Option D is correct because mechanism B is consistent with the rate law, as the slow step involves one molecule of H2 and one molecule of ICl.

21 Medium

21 of 265

Analyzing +4 | -1

Which one of the following statements is FALSE?

View answer and explanation

Correct option: D

none of these

Option D (none of these) is correct because all the statements about Raoult's law, osmotic pressure, and the order of osmotic pressure are true.

22 Medium

22 of 265

Application +4 | -1

Molality and molarity of sucrose solution are equal to 0.1.
What is density of solution?

View answer and explanation

Correct option: A

1.0342

Option A (1.0342) is correct because it is calculated using the relationship between molality, molarity, density, and molar mass of the solute.

23 Medium

23 of 265

Analyzing +4 | -1

Assertion: A non - volatile solute is mixed in a solution then elevation in boiling point and depression in freezing point both are

2 \mathrm{~K}

.

Reason: Elevation in boiling point and depression in freezing point both depend on melting point of non-volatile solute

View answer and explanation

Correct option: D

If both Assertion & Reason are false

Option D is correct because both the assertion and the reason are false. Elevation in boiling point and depression in freezing point depend on the molality of the solution and the cryoscopic/ebullioscopic constants, not the melting point of the solute. The assertion is false because equal molal concentrations will not necessarily result in equal changes.

24 Medium

24 of 265

Application +4 | -1

The vapour pressure of two liquids A and B are 135 and 171 torr respectively. The total vapour pressure of solution obtained by mixing 6 moles of A and 3 moles of B would be:

View answer and explanation

Correct option: A

147 torr

Option A (147 torr) is correct because it is calculated using Raoult's law, considering the mole fractions and vapor pressures of the two liquids.

25 Medium

25 of 265

Application +4 | -1

293 \mathrm{~K},

the vapour pressure of water is

2400 \, \mathrm{Pa}

and the vapour pressure of an aqueous urea solution is

2300 \mathrm{~Pa}.

The osmotic pressure of solution at

300 \mathrm{~K},

if the density of solution at this temperature is

1185 \mathrm{~kg} / \mathrm{m}^3,

(R=0.08 \mathrm{~L}-\mathrm{atm/K-mol})

View answer and explanation

Correct option: A

60 \mathrm{~atm}

Option A (60 atm) is correct because the osmotic pressure is calculated using the relative lowering of vapor pressure and the ideal gas law.

26 Medium

26 of 265

Application +4 | -1

The slope of

\pi

C

was made against insulin concentration

({C})

{g} {mL}^{-1}

and temperature

27^{\circ} {C}

. If

{C}

is ing litre

{ }^{-1}

and the slope of line obtained is

4.65 \times 10^{-3}

{g} / {mL}

, the molar mass (in

{g} \,{mol}^{-1}

) of insulin is :

View answer and explanation

Correct option: D

5.30 \times 10^6

Option D (

5.30 \times 10^6

) is correct because it is the molar mass calculated using the osmotic pressure formula and the given slope.

27 Medium

27 of 265

Analyzing +4 | -1

Which of the following pair of aqueous solutions will not have the same value of osmotic pressure? (Assume complete dissociation in aqueous solution)

View answer and explanation

Correct option: B

0.1 M

\mathrm{Na}_3 \mathrm{PO}_4

and 0.1 M

\mathrm{K}_2 \mathrm{SO}_4

Option B (0.1 M

\mathrm{Na}_3 \mathrm{PO}_4

and 0.1 M

\mathrm{K}_2 \mathrm{SO}_4

) is correct because their van't Hoff factors and concentrations result in different osmotic pressures.

28 Medium

28 of 265

Analyzing +4 | -1

Benzene and naphthalene form an ideal solution at room temperature. For this process, the wrong statement is

View answer and explanation

Correct option: D

\Delta G

is positive

Option D is correct because for an ideal solution, mixing is spontaneous, so ΔG must be negative.

29 Medium

29 of 265

Application +4 | -1

A 100 proof solution of ethanol in water consists of

50.0 \mathrm{~mL}

\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}(l)

and

50.0 \mathrm{~mL}

\mathrm{H}_2 \mathrm{O}(l)

, mixed at

16^{\circ} \mathrm{C}

. Given,

Density of

\mathrm{H}_2 \mathrm{O}=1 \mathrm{~g} \mathrm{~mL}^{-1}

Density of

\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}=0.7939 \mathrm{~g} \mathrm{~mL}^{-1}

Density of mixture

=0.9344 \mathrm{~g} \mathrm{~mL}^{-1}

Volume of the solution is

View answer and explanation

Correct option: C

96 mL

Option C (96 mL) is correct because the volume of the mixture is calculated by dividing the total mass by the density of the mixture.

30 Medium

30 of 265

Analyzing +4 | -1

1.24 g of

\mathrm{AX}_2

(molar mass

124 \mathrm{~g} \mathrm{~mol}^{-1})

is dissolved in 1 kg of water to form a solution with boiling point of

100.0156^{\circ} \mathrm{C},

while 25.4 g of

\mathrm{AY}_2

(molar mass

250 \mathrm{~g} \mathrm{~mol}^{-1})

in 2 kg of water constitutes a solution with a boiling point of

100.0260^{\circ} \mathrm{C}.

\mathrm{K}_{\mathrm{b}}\left(\mathrm{H}_2 \mathrm{O}\right)=0.52 \mathrm{~K} \mathrm{~kg} \mathrm{~mol}^{-1}

Which of the following is correct?

View answer and explanation

Correct option: D

\mathrm{AX}_2

is fully ionised while

\mathrm{AY}_2

is completely unionised

Option D is correct.

\mathrm{AX}_2

is fully ionized while

\mathrm{AY}_2

is completely unionized, as determined by the van't Hoff factor.

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