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JEE • CHEMISTRY • SOLUTIONS

Solutions practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 460 questions

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271 Medium
271 of 460
Application +4 | -1
If 0.2 m aqueous solution of K4[Fe(CN)6]{K_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right] is 100% ionized then the freezing point of the solution will be (Kf=1.86 K kg mol−1)\left( {{K_f} = 1.86\,K\,kg\,mo{l^{ - 1}}} \right)
View answer and explanation
Correct option: B
−1.860C- {1.86^0}C
Option A (−1.860C- {1.86^0}C) is correct because it's the freezing point calculated using the van't Hoff factor and the freezing point depression formula.
272 Medium
272 of 460
Understanding +4 | -1
Given below are two statements:

Statement (I): NaCl is added to the ice at 0∘C,0^{\circ} \mathrm{C}, present in the ice cream box to prevent the melting of ice cream.

Statement (II): On addition of NaCl to ice at 0∘C,0^{\circ} \mathrm{C}, there is a depression in freezing point.

In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: B
Both Statement I and Statement II are true
The correct answer is B (Both Statement I and Statement II are true) because adding NaCl to ice lowers the melting point, which is the principle behind freezing mixtures.
273 Easy
273 of 460
Understanding +4 | -1
The mixture which shows positive deviation from Raoult’s law is
View answer and explanation
Correct option: A
Ethanol + Acetone
Option A (Ethanol + Acetone) is correct because the interaction between ethanol and acetone is weaker than the hydrogen bonding in pure ethanol, leading to positive deviation.
274 Medium
274 of 460
Analyzing +4 | -1
Assertion: The mixing of two completely miscible liquids. A and B showing positive deviation from Raoult's law is followed by an absorption of heat

Reason: The A-B molecular interaction forces are stronger than the A-A or B-B molecular interaction forces.
View answer and explanation
Correct option: C
Assertion is True, Reason is False
Option C (Assertion is True, Reason is False) is correct because positive deviation implies weaker A-B interactions, contradicting the reason.
275 Medium
275 of 460
Analyzing +4 | -1
Select correct statement ?
View answer and explanation
Correct option: D
All are correct statements
Option D (All are correct statements) is correct because heats of vaporization are similar, entropy change is smaller for solutions, and boiling point elevation occurs in solutions.
276 Medium
276 of 460
Understanding +4 | -1
Which is an application of Henry's law?
View answer and explanation
Correct option: D
Soft drinks (soda)
Option D (Soft drinks (soda)) is correct because Henry's law states that the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid, which is applied in carbonating soft drinks.
277 Easy
277 of 460
Application +4 | -1
How many mole of helium gas occupy 22.4 L22.4 \mathrm{~L} at 0∘C0^{\circ} \mathrm{C} at 1 atm. Pressure
View answer and explanation
Correct option: C
1
Option C (1) is correct because one mole of any ideal gas occupies 22.4 L at standard temperature and pressure (STP).
278 Medium
278 of 460
Understanding +4 | -1
Assertion: After adding non-volatile solute freezing point of solvent depressed.

Reason: Vapour pressure of solvent decreases and become equal to solid solvent, at temperature lower than the freezing point of pure solvent.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the depression in freezing point is directly caused by the lowering of vapor pressure due to the non-volatile solute.
279 Medium
279 of 460
Analyzing +4 | -1
Which has maximum freezing point ?
View answer and explanation
Correct option: A
6 g6 \mathrm{~g} urea solution in 100 g H2O100 \mathrm{~g} \mathrm{~H}_2 \mathrm{O}
The correct answer is A because urea is a non-electrolyte and has the lowest van't Hoff factor (i=1), leading to the least depression in freezing point and thus the highest freezing point.
280 Medium
280 of 460
Application +4 | -1
Ethylene glycol is used as an antifreeze in a cold climate. Mass of ethylene glycol which should be added to 4 kg of water to prevent it from freezing at −6∘C- 6^\circ \mathrm{C} will be (Kf  for  water=1.86  K  kg  mol−1).({K_f}\;\mathrm{for}\;\mathrm{ water} = 1.86\;\mathrm{K}\;\mathrm{ kg }\;\mathrm{mo}{\mathrm{l}^{ - 1}}\mathrm{)}\mathrm{.} and molar mass of ethylene glycol =62  g  mol−1= 62\;g\mathrm{ }\;mo{l^{ - 1}}
View answer and explanation
Correct option: A
804.32  g804.32\mathrm{ }\;g
Option A (804.32  g804.32\mathrm{ }\;g) is correct because it is the mass of ethylene glycol required to lower the freezing point of water by 6°C, calculated using the colligative properties formula.
281 Easy
281 of 460
Application +4 | -1
A 5 molar solution of H2SO4{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} is diluted from 1 L to 10 L. What is the normality of the solution?
View answer and explanation
Correct option: B
1  N1\;N
Option B (1  N1 \;N) is correct because after dilution, the normality is calculated using the formula N1V1=N2V2N_1V_1 = N_2V_2.
282 Easy
282 of 460
Remembering +4 | -1
Isotonic solutions have same
View answer and explanation
Correct option: C
osmotic pressure
Option C (osmotic pressure) is correct because isotonic solutions, by definition, have the same osmotic pressure at a given temperature.
283 Medium
283 of 460
Understanding +4 | -1
In liquid CCl4{CCl}_4 which of the following has maximum solubility?
View answer and explanation
Correct option: B
Br2{Br}_2
Option B (Br2{Br}_2) is correct because bromine, being a liquid, exhibits greater solubility in liquid CCl4{CCl}_4 compared to solid iodine or gaseous chlorine and sodium chloride is ionic.
284 Easy
284 of 460
Application +4 | -1
Molarity of 0.2  N  H2SO40.2\;N\;{H_2}S{O_4} is
View answer and explanation
Correct option: D
0.1
Option D (0.1) is correct because molarity is calculated by dividing normality by the basicity of the acid.
285 Medium
285 of 460
Analyzing +4 | -1
Which of the following solution has highest freezing point?
View answer and explanation
Correct option: D
0.1 molal C17H35COONa{C}_{17} {H}_{35} {COONa}
Option D (0.1 molal C17H35COONa{C}_{17} {H}_{35} {COONa}) has the highest freezing point because it has the lowest value of i*molality, resulting in the smallest freezing point depression.
286 Medium
286 of 460
Application +4 | -1
What is the molality of pure water?
View answer and explanation
Correct option: C
55.5
Option C (55.5) is correct because the molality of pure water is calculated by dividing 1000g by the molar mass of water (18 g/mol).
287 Medium
287 of 460
Application +4 | -1
Calculate the osmotic pressure of 0.1NNa3PO40.1 N {Na}_3 {PO}_4 solution at 300 K300 {~K}.
View answer and explanation
Correct option: A
0.821
Option A (0.821) is correct because it is the osmotic pressure calculated using the van't Hoff factor and the osmotic pressure formula.
288 Medium
288 of 460
Application +4 | -1
The vapour pressure of a saturated solution of sparingly soluble salt (XCl3)\left({XCl}_3\right) was 17.20 mm Hg17.20 \mathrm{~mm} \mathrm{~Hg} at 27∘C.27^{\circ} \mathrm{C}. If the vapour pressure of pure water is 17.25 mm Hg17.25 \mathrm{~mm} \mathrm{~Hg} at 27∘C,27^{\circ} \mathrm{C}, then what is the solubility of the sparingly soluble salt XCl3{XCl}_3 in mole per litre?
View answer and explanation
Correct option: A
4.04×10−24.04 \times 10^{-2}
Option A (4.04×10−24.04 \times 10^{-2}) is correct because the solubility is calculated using Raoult's law and the given vapor pressures.
289 Medium
289 of 460
Understanding +4 | -1
When benzoic acid dissolve in benzene, the observed molecular mass is
View answer and explanation
Correct option: A
244
Option A (244) is correct because benzoic acid dimerizes in benzene due to hydrogen bonding, effectively doubling its molecular weight (122 x 2 = 244).
290 Easy
290 of 460
Application +4 | -1
3.65  g  of  HCl3.65\;g\;of\;\mathrm{HCl} is dissolved in 16.2  g16.2\;g of water. The mole fraction of HCl\mathrm{HCl} in the resulting solution is
View answer and explanation
Correct option: A
0.1
Option A (0.1) is correct because the mole fraction of HCl is calculated by dividing the moles of HCl by the total moles of the solution (HCl + water).
291 Easy
291 of 460
Understanding +4 | -1
An azeotropic solution of two liquids has a boiling point lower than either of them when it:
View answer and explanation
Correct option: B
shows positive deviation from Raoult’s law
The correct answer is B (shows positive deviation from Raoult’s law) because solutions with positive deviation have weaker intermolecular forces, leading to a lower boiling point azeotrope.
292 Hard
292 of 460
Application +4 | -1
A 5.25% solution of a substance is isotonic with a 1.5% solution of urea (molar mass =60  g  mol−1= 60\;g\;\mathrm{mo}{\mathrm{l}^{ - 1}}) in the same solvent. If the densities of both the solutions are assumed to be equal to 1.0  g  cm−3,\mathrm{1}\mathrm{.0}\;\mathrm{g}\;\mathrm{c}{\mathrm{m}^{ - 3}}, molarmass of the substance will be
View answer and explanation
Correct option: D
210.0  g  mol−1210.0\;g\;mo{l^{ - 1}}
Option D (210.0  g  mol−1210.0\;g\;mo{l^{ - 1}}) is correct because it is calculated using the isotonic condition where the molar concentrations are equal.
293 Medium
293 of 460
Application +4 | -1
0.48 g0.48 \mathrm{~g} of a substance is dissolved in 10.6 g10.6 \mathrm{~g} of C6H6.\mathrm{C}_6 \mathrm{H}_6. The freezing point of benzene is lowered by 1.8∘C.1.8^{\circ} \mathrm{C}. What will be the molecular weight of the substance (Kf for benzene=5)?\left(K_{\mathrm{f}} \text{ for benzene}=5\right)?
View answer and explanation
Correct option: C
125.79
Option C (125.79) is correct because it is calculated using the depression in freezing point formula, considering the given values for the substance and benzene.
294 Medium
294 of 460
Analyzing +4 | -1
One mole each of urea, glucose and sodium chloride were dissolved in one litre of water Equal osmotic pressure will be produced by solutions of
View answer and explanation
Correct option: B
Urea and glucose
Option B (Urea and glucose) is correct because both urea and glucose are non-electrolytes, so they will produce equal osmotic pressures when dissolved in the same volume of solvent at the same concentration.
295 Medium
295 of 460
Understanding +4 | -1
Statement I: If cells of living organisms are placed in pure water, they swell and burst.

Statement II: Due to osmosis, the movement of water molecules into the cell dilutes the salt content.
View answer and explanation
Correct option: A
If both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I
Option A (If both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I) is correct because cells burst due to water entering them by osmosis, diluting the internal salt concentration.
296 Medium
296 of 460
Application +4 | -1
Air was drawn through a solution containing 40 g40 \mathrm{~g} of solute (non-volatile and non-electrolyte) in 100 g100 \mathrm{~g} of water and then through water. The loss of mass of water was 0.05 g0.05 \mathrm{~g} and the total mass of water absorbed in sulphuric acid tube was 2.05 g.2.05 \mathrm{~g}. The molecular mass of the solute is
View answer and explanation
Correct option: B
288
The correct answer is 288 because the molecular mass of the solute is calculated using Raoult's Law and the given mass loss and absorption data.
297 Medium
297 of 460
Application +4 | -1
24 g24 {~g} of difluoroacetic acid in 400  g400 \,{~g} of water has observed freezing point depression by 1.4  K1.4 \,{~K}. The van't Hoff factor for difluoroacetic acid is
(Kf\left({K}_{{f}}\right. of water =1.86  K  kg mol−1=1.86 \,{~K}\, {~kg} {~mol}^{-1}; Atomic weight of F=19{F}=19 )
View answer and explanation
Correct option: D
1.2
Option D (1.2) is correct because the van't Hoff factor is calculated using the freezing point depression formula, and the result is approximately 1.2.
298 Medium
298 of 460
Understanding +4 | -1
AN aqueous solution is 1.00  \, molal in  KI\,{KI}. Which change will cause the vapour pressure of the solution to increase?
View answer and explanation
Correct option: A
Addition of water
Option A is correct because adding water increases the mole fraction of the solvent, which increases the vapor pressure of the solution according to Raoult's law.
299 Medium
299 of 460
Remembering +4 | -1
What is the composition of gases in the tanks used by the scuba divers?
View answer and explanation
Correct option: B
11.7%11.7 \% helium 56.2%56.2 \% nitrogen 32.1%32.1 \% oxygen
Option B (11.7%11.7 \% helium 56.2%56.2 \% nitrogen 32.1%32.1 \% oxygen) is correct because scuba divers use a mixture of helium, nitrogen, and oxygen with these approximate percentages to avoid nitrogen narcosis at depth.
300 Medium
300 of 460
Application +4 | -1
Van't Hoff factor for the aqueous solution of AlCl3\mathrm{AlCl}_3 is 2.8. The percentage dissociation of AlCl3\mathrm{AlCl}_3 is:
View answer and explanation
Correct option: A
60%60 \%
Option A (60%60 \%) is correct because it calculates the percentage dissociation using the Van't Hoff factor and the number of ions produced.
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