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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 320 questions

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241 Medium
241 of 320
Analyzing +4 | -1
Oxide of nitrogen which has smallest ' N−O\mathrm{N}-\mathrm{O} ' bond length among the following is
View answer and explanation
Correct option: B
NO\mathrm{NO}
Option B (NO) is correct because NO has a triple bond character due to resonance, resulting in the shortest N-O bond length.
242 Medium
242 of 320
Understanding +4 | -1
XeO2F2Xe{O_2}{F_2} is obtained by partial bydrolysis of
View answer and explanation
Correct option: C
Both (1) and (2)
Option C (Both (1) and (2)) is correct because XeO2F2XeO_2F_2 can be obtained by partial hydrolysis of both XeOF4XeOF_4 and XeF6XeF_6.
243 Medium
243 of 320
Remembering +4 | -1
Iodide of Millon's base is :
View answer and explanation
Correct option: C
NH2HgO⋅HgI{NH}_2 {HgO} \cdot {HgI}
Option C (NH2HgO⋅HgI{NH}_2 {HgO} \cdot {HgI}) is correct because Iodide of Millon's base is NH2HgO⋅HgI{NH}_2 {HgO} \cdot {HgI}, which is formed when Nessler's reagent reacts with NH3{NH}_3.
244 Medium
244 of 320
Understanding +4 | -1
When copper is heated with conc. HNO3\mathrm{HN}{\mathrm{O}_3} it produces:
View answer and explanation
Correct option: A
Cu(NO3)2  and NO2\mathrm{Cu(N}{\mathrm{O}_3}{\mathrm{)}_2}\,\,\mathrm{and}\,\mathrm{N}{\mathrm{O}_2}
Option A is correct because copper reacts with concentrated nitric acid to produce copper nitrate and nitrogen dioxide.
245 Medium
245 of 320
Remembering +4 | -1
The substance used in Holme’s signal of the ship is a mixture of
View answer and explanation
Correct option: A
CaC2+Ca3P2\mathrm{Ca}{\mathrm{C}_2} + \mathrm{C}{\mathrm{a}_3}{\mathrm{P}_2}
Option A (CaC2+Ca3P2\mathrm{Ca}{\mathrm{C}_2} + \mathrm{C}{\mathrm{a}_3}{\mathrm{P}_2}) is correct because Holmes' signal is a mixture of calcium carbide and calcium phosphide.
246 Medium
246 of 320
Understanding +4 | -1
Which among the following is least covalent in nature?
View answer and explanation
Correct option: B
BiF3{BiF}_3
Option B (BiF3{BiF}_3) is correct because, according to Fajan's rule, larger cations with lower charge tend to form more ionic compounds, making BiF3 the least covalent among the given options.
247 Medium
247 of 320
Remembering +4 | -1
Fertilizer having the highest nitrogen percentage is:
View answer and explanation
Correct option: B
Urea
Option B (Urea) is correct because urea has the highest nitrogen percentage (around 46%) among the given fertilizers.
248 Medium
248 of 320
Application +4 | -1
In qualitative analysis, when H2 S\mathrm{H}_2 \mathrm{~S} is passed through an aqueous solution of salt acidified with dil. HCl\mathrm{HCl}, a black precipitate is obtained. On boiling the precipitate with dil. HNO3\mathrm{HNO}_3, it forms a solution of blue colour. Addition of excess of aqueous solution of ammonia to this solution gives ......... .
View answer and explanation
Correct option: B
deep blue solution of [Cu(NH3)4]2+\left[\mathrm{Cu}\left(\mathrm{NH}_3\right)_4\right]^{2+}
Option B (deep blue solution of [Cu(NH3)4]2+\left[\mathrm{Cu}(\mathrm{NH}_3)_4\right]^{2+}) is correct because copper ions react with excess ammonia to form a tetraammine complex, which has a deep blue color.
249 Medium
249 of 320
Remembering +4 | -1
Red P\mathrm{P} can be obtained by white P\mathrm{P} by
View answer and explanation
Correct option: A
Heating it with a catalyst in an inert atmosphere
Option A (Heating it with a catalyst in an inert atmosphere) is correct because red phosphorus is obtained from white phosphorus by heating it with a catalyst in an inert atmosphere.
250 Medium
250 of 320
Remembering +4 | -1
In the Haber process for the manufacture of ammonia the following catalyst is used
View answer and explanation
Correct option: B
Iron with molybdenum as promoter
Option B (Iron with molybdenum as promoter) is correct because in the Haber process, iron is used as the catalyst and molybdenum is used as a promoter to enhance the catalyst's activity.
251 Medium
251 of 320
Understanding +4 | -1
Liquor ammonia bottles are opened only after cooling because it has high vapour pressure and it is mild explosive.
View answer and explanation
Correct option: C
Both 1 and 2
Option C (Both 1 and 2) is correct because liquor ammonia bottles are opened only after cooling due to its high vapor pressure and mild explosive nature.
252 Medium
252 of 320
Understanding +4 | -1
Which is the correct thermal stability order for H2E (E = O, S, Se, Te and Po)?{H_2}E\,(E\, = \,O,\,S,\,Se,\,Te\,\mathrm{and}\,Po)?
View answer and explanation
Correct option: C
H2PO < H2Te < H2Se < H2S < H2O{H_2}PO\, < \,{H_2}Te\, < \,{H_2}Se\, < \,{H_2}S\, < \,{H_2}O
Option C (H2PO<H2Te<H2Se<H2S<H2O{H_2}PO < {H_2}Te < {H_2}Se < {H_2}S < {H_2}O) is correct because thermal stability decreases down the group due to decreasing bond strength.
253 Medium
253 of 320
Analyzing +4 | -1
Statement I: Noble gases have highest ionization energies in their respective periods

Statement II: The outer most shell of noble gases is completely filled
View answer and explanation
Correct option: C
Statement I is correct but statement II is false
Option A (Solution of iron salt does not give blue colour with indicator) is correct because the endpoint is reached when all Fe2+ has been oxidized to Fe3+, so no Prussian blue color forms with K3[Fe(CN)6].
254 Medium
254 of 320
Understanding +4 | -1
Which hydride has the lowest boiling point?
View answer and explanation
Correct option: B
H2S{H_2}S
Option B is correct because H2S has the lowest boiling point among the given hydrides due to weaker intermolecular forces compared to water and lower molar mass compared to H2Se and H2Te.
255 Medium
255 of 320
Remembering +4 | -1
Bleaching powder is a mixture of:
View answer and explanation
Correct option: C
Calcium hypochlorite and basic calcium chloride
Option C (Calcium hypochlorite and basic calcium chloride) is correct because bleaching powder is primarily a mixture of calcium hypochlorite and basic calcium chloride.
256 Medium
256 of 320
Remembering +4 | -1
Javelle water is:
View answer and explanation
Correct option: C
Both (1) and (2)
Correct Answer + Core Reason: Option C (Both (1) and (2)) is correct because chlorine is used both as a disinfecting agent in water and as a bleaching agent.
257 Medium
257 of 320
Understanding +4 | -1
Assertion (A) : S3O62−\mathrm{S}_3 \mathrm{O}_6^{2-} (trithionate) has S−S\mathrm{S}-\mathrm{S} bond.

Reason (R) : It is a conjugate base of HS3O6−\mathrm{HS}_3 \mathrm{O}_6^{-}.
View answer and explanation
Correct option: B
Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.
Option B is correct because both the assertion and the reason are true, but the reason does not explain the assertion. Trithionate does have an S-S bond, and it is a conjugate base, but these facts are not directly related.
258 Medium
258 of 320
Application +4 | -1
In the reaction, MnO4−  +  I−  →Alkaline  solution  [X];  [X]  is:\mathrm{MnO}_4^ - \mathrm{\;} + \mathrm{\;}{\mathrm{I}^ - }\;\mathop \to \limits^{A\mathrm{lkaline\;solution}} \;\left[ X \right];\,\,\left[ X \right]\;\mathrm{is}:
View answer and explanation
Correct option: A
IO3−\mathrm{IO}_3^ -
Option A (IO3−\mathrm{IO}_3^ -) is correct because in alkaline solution, permanganate reduces to MnO2 and iodide oxidizes to iodate.
259 Medium
259 of 320
Understanding +4 | -1
The element evolving two different gases on reaction with conc. Sulphuric acid is
View answer and explanation
Correct option: B
C
Option C is correct because carbon reacts with concentrated sulfuric acid to produce two different gases: carbon dioxide (CO2CO_2) and sulfur dioxide (SO2SO_2).
260 Medium
260 of 320
Remembering +4 | -1
Which of the following is not a drying and dehydrating agent?
View answer and explanation
Correct option: D
Hydrated CaCl2CaC{l_2}
Option D (Hydrated CaCl2CaC{l_2}) is correct because hydrated calcium chloride already contains water and cannot be used as a drying or dehydrating agent.
261 Medium
261 of 320
Understanding +4 | -1
Assertion: NH3\mathrm{NH}_3 is easily dissolved in alkaline HgI42−\mathrm{HgI}_4{ }^{2-}

Reason: Compound of Hg−\mathrm{Hg}^{-}and I−\mathrm{I}^{-}is used in detection of NH3\mathrm{NH}_3.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is correct explanation of the Assertion) is correct because ammonia dissolves readily in alkaline HgI42- solution, and Hg- and I- compounds are indeed used for NH3 detection.
262 Medium
262 of 320
Understanding +4 | -1
HNO3  HN{O_3}\; oxidises :
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because nitric acid (HNO3HNO_3) is a strong oxidizing agent and can oxidize H2O2H_2O_2, H2SH_2S, and SO2SO_2.
263 Medium
263 of 320
Remembering +4 | -1
Coloured oxide is nitrogen is:
View answer and explanation
Correct option: D
NO2N{O_2}
Option D (NO2NO_2) is correct because nitrogen dioxide (NO2NO_2) is a brown gas, which makes it a colored oxide of nitrogen.
264 Medium
264 of 320
Understanding +4 | -1
Hydrolysis of PI3P{I_3} yields:
View answer and explanation
Correct option: B
Monobasic acid and dibasic acid
Option D (Monobasic acid and tribasic acid) is incorrect, the correct answer is monobasic acid and dibasic acid because the hydrolysis of PI₃ yields HI (monobasic) and H₃PO₃ (dibasic).
265 Medium
265 of 320
Analyzing +4 | -1
Statement-I: The solid N2O5{N}_2 {O}_5 is ionic.

Statement-II: In solid state N2O5{N}_2 {O}_5 exist as [NO3]+[NO2]−\left[{NO}_3\right]^{+}\left[{NO}_2\right]^{-}
View answer and explanation
Correct option: C
If Statement-I is true but Statement-II is false
Option C (If Statement-I is true but Statement-II is false) is correct because solid N2O5 exists as [NO2]+[NO3]-, making it ionic, but the ions are incorrectly identified in Statement II.
266 Medium
266 of 320
Application +4 | -1
Sulphur reacts with chlorine in 1:2 ratio and forms X{X}. Hydrolysis of X{X} gives a sluphur compound Y{Y}. The hybridization of central atom in the anion Y{Y} is
View answer and explanation
Correct option: A
sp3s p^3
Option A (sp3s p^3) is correct because the sulphur compound formed after hydrolysis is H2SO3{H_2}S{O_3}, and the hybridization of S in SO32−{SO_3}^{2-} is sp3sp^3.
267 Medium
267 of 320
Analyzing +4 | -1
Which can act as an acid in sulphuric acid?
View answer and explanation
Correct option: C
HClO4HCl{O_4}
Option C (HClO4HClO_4) is correct because perchloric acid is a strong acid and can donate a proton to sulfuric acid, acting as an acid in this context.
268 Medium
268 of 320
Analyzing +4 | -1
Consider the following statements

(i) H3PO2H_3{PO}_2 is called phosphinic acid
(ii) Pyrophosphorous acid contains two P−HP-H
bonds
(iii) Oxidation state of phosphorous in
hypophosphoric acid is +5
The correct statements are
View answer and explanation
Correct option: A
(i) and (ii) only
Option A ((i) and (ii) only) is correct because H3PO2H_3PO_2 is phosphinic acid and pyrophosphorous acid (H4P2O5H_4P_2O_5) contains two P-H bonds, while hypophosphoric acid (H4P2O6H_4P_2O_6) has an oxidation state of +4 for phosphorus.
269 Medium
269 of 320
Remembering +4 | -1
Liquid oxygen:
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because liquid oxygen is used in rocket fuels, artificial respiration, and can be explosive when mixed with finely divided carbon.
270 Medium
270 of 320
Understanding +4 | -1
When SO2S{O_2} is passed through acidified solution of H2S{H_2}S :
View answer and explanation
Correct option: C
Sulphur sol is formed
Option C is correct because when SO2SO_2 is passed through an acidified solution of H2SH_2S, it oxidizes the H2SH_2S to elemental sulfur, forming a sulfur sol.
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