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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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91 Medium
91 of 320
Analyzing +4 | -1
Which reaction is not valid?
View answer and explanation
Correct option: B
HF+Cl2→F2+HClHF\mathrm{ } + \mathrm{ }C{l_2} \to {F_2} + \mathrm{ }HCl
Option B (HF+Cl2→F2+HClHF\mathrm{ } + \mathrm{ }C{l_2} \to {F_2} + \mathrm{ }HCl) is not valid because fluorine is more electronegative than chlorine and can displace it, but chlorine cannot displace fluorine.
92 Medium
92 of 320
Analyzing +4 | -1
Which species has the largest dipole moment?
View answer and explanation
Correct option: A
NH3\mathrm{N}{\mathrm{H}_3}
Option A is correct. NH₃ has the largest dipole moment because nitrogen is more electronegative than phosphorus, arsenic, and antimony, leading to a greater difference in electronegativity between N and H.
93 Medium
93 of 320
Analyzing +4 | -1
Statement I: Single N−N\mathrm{N}-\mathrm{N} bond is weaker than the single P−P\mathrm{P}-\mathrm{P} bond due to high interelectronic repulsion of the non-bonding electrons, owing to the small bond length.

Statement II: The catenation tendency is stronger in nitrogen as compared to phosphorus.
View answer and explanation
Correct option: B
Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I.
Option B (Statement I and Statement II are correct but Statement II is not the correct explanation of Statement I) is correct because both statements are true, but the catenation tendency of nitrogen is weaker, not stronger, than that of phosphorus.
94 Medium
94 of 320
Analyzing +4 | -1
Which of the following is the correct code for statements below?

(i) Due to small size oxygen has less negative electron gain enthalpy than sulphur.

(ii) Oxygen shows only -2 oxidation state whereas S{S}, Se{Se} and Te shows +4 O.S in their compounds with oxygen and +6 with fluorine.

(iii) All hydrides of oxygen family possess reducing property which increases from H2 S{H}_2 {~S} to H2{H}_2 TeTe.

(iv) Among hexahalides of group 16 hexafluorides are the onlys table halides.

(v) Dimeric monohalides of group 16 undergo disproportionation.
View answer and explanation
Correct option: A
TFFTT
Option A (TFFTT) is correct because statements (i), (iv), and (v) are true, while statements (ii) and (iii) are false.
95 Medium
95 of 320
Remembering +4 | -1
Which of the following is strongest oxyacid of chlorine?
View answer and explanation
Correct option: C
Perchloric acid
Option C (Perchloric acid) is correct because Perchloric acid has the highest oxidation state of chlorine, making it the strongest oxyacid.
96 Medium
96 of 320
Understanding +4 | -1
Assertion: Fluorine forms only one oxo acid HOFHOF.

Reason: Fluorine does not have dd- orbitals in its valence shell.
View answer and explanation
Correct option: A
Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
Option A (Both assertion and reason are correct statements, and reason is the correct explanation of the assertion) is correct because fluorine's inability to expand its octet due to the absence of d-orbitals limits it to forming only one oxoacid.
97 Medium
97 of 320
Understanding +4 | -1
White phosphorus reacts with thionyl chloride to give
View answer and explanation
Correct option: B
PCl3,SO2\mathrm{PCl}_3, \mathrm{SO}_2 and S2Cl2\mathrm{S}_2 \mathrm{Cl}_2
Option B (PCl3,SO2\mathrm{PCl}_3, \mathrm{SO}_2 and S2Cl2\mathrm{S}_2 \mathrm{Cl}_2) is correct because white phosphorus reacts with thionyl chloride to produce phosphorus trichloride, sulfur dioxide, and disulfur dichloride.
98 Medium
98 of 320
Analyzing +4 | -1
Which of the following combination does not liberate NH3{NH}_3 gas?
View answer and explanation
Correct option: A
Heating of NH4ClO4{NH}_4 {ClO}_4
Option A (Heating of NH4ClO4{NH}_4 {ClO}_4) is correct because it decomposes into nitrogen, chlorine, oxygen, and water, not ammonia.
99 Medium
99 of 320
Remembering +4 | -1
Nitrogen gas is obtained by thermal decomposition of
View answer and explanation
Correct option: B
Ba(N3)2Ba{\left( {{N_3}} \right)_2}
Option B (Ba(N3)2Ba{\left( {{N_3}} \right)_2}) is correct because barium azide decomposes upon heating to produce barium metal and nitrogen gas.
100 Medium
100 of 320
Understanding +4 | -1
Xenon hexafluoride reacts with silica to form a xenon compound X. The oxidation state of xenon in X is
View answer and explanation
Correct option: C
6
Option C is correct because in the reaction of XeF6XeF_6 with silica, XeOF4XeO{F_4} is formed, where the oxidation state of Xe is +6.
101 Medium
101 of 320
Analyzing +4 | -1
Which of the following orders are correct as per the properties mentioned against each.
View answer and explanation
Correct option: A
AS2O3<SiO2<P2O3<SO2A{S_2}{O_3} < Si{O_2} < {P_2}{O_3} < S{O_2} : Acid strength
Option A is correct because the acid strength order ASH3<SiO2<P2O3<SO2AS{H_3} < Si{O_2} < {P_2}{O_3} < S{O_2} is correct.
102 Medium
102 of 320
Analyzing +4 | -1
The largest bond angle exists in:
View answer and explanation
Correct option: B
NH3N{H_3}
Option B (NH3NH_3) is correct because it has one lone pair, while the others have two, leading to a larger bond angle due to less lone pair repulsion.
103 Medium
103 of 320
Understanding +4 | -1
Nitrogen forms N2,{N_2}, but phosphorous does not form P2,{P_2}, however it converts P4,{P_4}, reason is
View answer and explanation
Correct option: B
Pπ−PπP\pi \mathrm{ - }P\pi Bonding is weak.
Option B is correct. Phosphorus does not form P2 because Pπ-Pπ bonding is weak due to its larger size and lower electronegativity compared to nitrogen.
104 Medium
104 of 320
Understanding +4 | -1
The nitrate which when heated gives-off a gas or a mixture of gases which cannot relight a glowing splinter is:
View answer and explanation
Correct option: B
Ammonium nitrate
Option B (Ammonium nitrate) is correct because when heated, it decomposes to nitrous oxide (N2O\mathrm{N}_2\mathrm{O}) and water, and nitrous oxide does not support combustion.
105 Medium
105 of 320
Analyzing +4 | -1
Which one of the following orders is not in accordance with the property stated against it?
View answer and explanation
Correct option: C
O>S>Se>Te\mathrm{O} > \mathrm{S} > \mathrm{Se} > \mathrm{Te} - Electron gain enthalpy (magnitude)
Option C (O > S > Se > Te - Electron gain enthalpy (magnitude)) is correct because the electron gain enthalpy of oxygen is less negative than sulfur due to its small size and high electron density.
106 Medium
106 of 320
Analyzing +4 | -1
Choose the correct statement among the following
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Correct option: B
SO2{SO}_2 is both oxidising as well reducing but SO3{SO}_3 is only oxidising
Option B (SO2{SO}_2 is both oxidising as well reducing but SO3{SO}_3 is only oxidising) is correct because sulfur in SO₂ has an intermediate oxidation state (+4) allowing it to both gain and lose electrons, while in SO₃ sulfur has its maximum oxidation state (+6) and can only gain electrons.
107 Medium
107 of 320
Remembering +4 | -1
Choose the correct statement:
View answer and explanation
Correct option: A
White phosphorous is soluble in CS2{CS}_2 but red phosphorous is insoluble in CS2{CS}_2
Option A (White phosphorous is soluble in CS₂ but red phosphorous is insoluble in CS₂) is correct because white phosphorus exists as discrete P₄ molecules and is soluble in CS₂, while red phosphorus is a polymer and insoluble.
108 Medium
108 of 320
Analyzing +4 | -1
Assertion: XeF4\mathrm{XeF}_4 is a good fluorinating agent

Reason: XeF4\mathrm{XeF}_4 sublimes at 298 K298 \mathrm{~K}.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B is correct because both the assertion and reason are true, but the reason (sublimation) does not explain why XeF4 is a good fluorinating agent.
109 Medium
109 of 320
Remembering +4 | -1
Which gas is filled in electric bulbs/tubes?
View answer and explanation
Correct option: C
ArAr
Option C (ArAr) is correct because Argon (Ar) is an inert gas commonly used in electric bulbs and tubes to prevent the filament from oxidizing and prolong its life.
110 Medium
110 of 320
Analyzing +4 | -1
Assertion (A): F−F{F}-{F} bond in F2{F}_2 molecule is weak.

Reason (R): F{F} atom is small in size.
View answer and explanation
Correct option: B
Both (A) and (R) are true and (R) is not the correct explanation of (A)
Option B (Both (A) and (R) are true and (R) is not the correct explanation of (A)) is correct because both the weakness of the F-F bond and the small size of the fluorine atom are true, but the small size isn't the primary reason for the weak bond.
111 Medium
111 of 320
Understanding +4 | -1
Pure HBr gas may be obtained by heating sodium bromide with syrupy phosphoric acid and not with concentrated sulphuric acid because concentrated sulphuric acid is:
View answer and explanation
Correct option: D
An oxidizing agent
Option D (An oxidizing agent) is correct because concentrated sulphuric acid acts as an oxidizing agent and oxidizes HBr, preventing its formation.
112 Medium
112 of 320
Remembering +4 | -1
Chlorine acts as a bleaching agent only in presence of
View answer and explanation
Correct option: B
Moisture
Option B (Moisture) is correct because chlorine acts as a bleaching agent due to the formation of nascent oxygen in the presence of moisture.
113 Medium
113 of 320
Remembering +4 | -1
Atomicity of sulphur in rhombic sulphur is
View answer and explanation
Correct option: A
8
Option A (8) is correct because rhombic sulfur exists as S8 molecules, thus having an atomicity of 8.
114 Medium
114 of 320
Remembering +4 | -1
The oxoacid of SO2\mathrm{S}{\mathrm{O}_2} is:
View answer and explanation
Correct option: A
H2SO3{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_3}
Option A (H2SO3{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_3}) is correct because it is the oxoacid formed when sulfur dioxide (SO2\mathrm{S}{\mathrm{O}_2}) reacts with water.
115 Medium
115 of 320
Understanding +4 | -1
Assertion (A): Na2S2O3\mathrm{Na}_2 \mathrm{S}_2 \mathrm{O}_3 on reaction with I2\mathrm{I}_2 gives Na2S4O6.\mathrm{Na}_2 \mathrm{S}_4 \mathrm{O}_6.

Reason (R): This reaction involves colour and electronic change Both.
View answer and explanation
Correct option: B
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
Option B (Both (A) & (R) are true but the (R) is not the correct explanation of the (A)) is correct because the reaction of Na2S2O3\mathrm{Na}_2 \mathrm{S}_2 \mathrm{O}_3 with I2\mathrm{I}_2 does indeed produce Na2S4O6\mathrm{Na}_2 \mathrm{S}_4 \mathrm{O}_6, and the reaction involves both color and electronic changes, but the color/electronic change isn't the direct *reason* for the reaction itself.
116 Medium
116 of 320
Remembering +4 | -1
Temperature at which α\alpha and β\beta forms of sulphur are at equilibrium, is known as
View answer and explanation
Correct option: D
Transition temperature
Option D (Transition temperature) is correct because the transition temperature is the temperature at which two allotropic forms of a substance are in equilibrium.
117 Medium
117 of 320
Analyzing +4 | -1
Assertion (A): HI cannot be prepared by the reaction of KI\mathrm{KI} with conc. H2SO4\mathrm{H}_2 \mathrm{SO}_4.

Reason (R): HI\mathrm{HI} has lowest H−X\mathrm{H}-X bond strength among halogen acids.
View answer and explanation
Correct option: B
Both A\mathrm{A} and R\mathrm{R} are correct; R\mathrm{R} is not the correct explanation of A.
Option B is correct because both the assertion and the reason are true, but the reason does not correctly explain the assertion. The instability of HI in the presence of conc. H2SO4 is due to its reducing nature, not its bond strength.
118 Medium
118 of 320
Analyzing +4 | -1
Assertion: Inter-halogen compounds are better oxidising agents than halogens

Reason: X−X′X-X^{\prime} bonds are stronger than X−XX-X bonds.
View answer and explanation
Correct option: A
Both assertion and reason are correct statements, and reason is the correct explanation of the assertion.
Option A is correct because interhalogen compounds are better oxidizing agents due to weaker X−X′X-X^{\prime} bonds compared to X−XX-X bonds, making them more reactive.
119 Medium
119 of 320
Analyzing +4 | -1
Assertion (A): The gas phase reaction, PCl3( g)+Cl2( g)⇌PCl5( g);ΔH=−32.8 k cal mol−1\mathrm{PCl}_3(\mathrm{~g})+\mathrm{Cl}_2(\mathrm{~g}) \rightleftharpoons \mathrm{PCl}_5(\mathrm{~g}) ; \Delta \mathrm{H}=-32.8 \mathrm{~k~cal} \mathrm{~mol}^{-1} shifts to the right direction on increasing temperature.

Reason (R): When temperature increases, equilibrium shifts towards right for an endothermic reaction.
View answer and explanation
Correct option: D
Assertion (A) is false, but Reason (R) is true
Option D is correct because the assertion is false, as increasing temperature shifts the equilibrium to the left for an exothermic reaction, while the reason is true.
120 Medium
120 of 320
Remembering +4 | -1
Which of the following forms vortex ring?
View answer and explanation
Correct option: B
PH3P{H_3}
Option B (PH3P{H_3}) is correct because phosphine (PH3P{H_3}) forms vortex rings of P2O5P_2O_5 when it comes into contact with air, creating white smoke rings.
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