P-block elements practice · Easy

Option D (Dissociation energy of its molecule is fairly high) is correct because nitrogen has a triple bond (N≡N), which requires a large amount of energy to break, making it relatively inert.

Option B (5) is correct because one molecule of the compound dissociates into 5 ions: Fe2+, 2 SO42-, and 2 NH4+.

Option D (Zero) is correct because the zero group (noble gases) lies between highly electronegative and electropositive elements, acting as a buffer.

Option B (Cancer) is correct because radon's radioactivity is used in cancer therapy.

The correct answer is A ($\mathrm{NH}_3$) because ammonia is the strongest base among the given hydrides of group 15 elements due to nitrogen's small size and high electronegativity.

Option A (1.27 ${A^ \circ }$) is correct because the O-O bond length in ozone is approximately 1.27 Angstroms.

Option B (Ionisation potential) is correct because the oxidizing power of fluorine is primarily due to its low bond dissociation enthalpy, high hydration enthalpy, and high electron affinity, but not its ionization potential.

Option B ($N{H_3}$ molecule is triangular planar) is correct because ammonia ($N{H_3}$) has a pyramidal shape due to the presence of a lone pair of electrons on the nitrogen atom.

Option D (A mixed salt) is correct because bleaching powder (calcium hypochlorite) contains more than one type of anion.

Option C (The most abundant noble gas in the atmosphere is He) is false because Argon (Ar) is the most abundant noble gas in the atmosphere.

Option D ($Cl{O^ - } < ClO_2^ - < ClO_3^ - < ClO_4^ -$) is correct because the Cl-O bond order increases with the number of oxygen atoms bonded to chlorine.

Option D (Ne) is correct because J.J. Thomson's experiments with neon isotopes were crucial in the discovery of isotopes.

Option C (Air) is correct because the Birkeland-Eyde process starts with nitrogen and oxygen from the air to produce nitric oxide, which is then converted to nitric acid.

Option A (Render iron passive) is correct because concentrated nitric acid forms a passivating oxide layer on the surface of iron, preventing further reaction.

Option D ($\mathrm{H}_2 \mathrm{S}$) is correct because sulfur is more electronegative than phosphorus, and $\mathrm{H}_2 \mathrm{S}$ has less electronic repulsion than $\mathrm{H}_2 \mathrm{O}$, making it the weakest Lewis base.

Option D (All of these) is correct because ozone acts as an oxidizing agent due to its ability to donate oxygen atoms, a reducing agent in specific reactions, and a bleaching agent due to its oxidizing properties.

Option A (${H_2}S$) is correct because nitric acid oxidizes hydrogen sulfide to colloidal sulfur.

Option A (${H_2}S{O_4}$) is correct because oil of vitriol is the common name for sulfuric acid, which has the chemical formula H2SO4.

Option B (0) is correct because Sc3+ has no unpaired electrons, resulting in a zero magnetic moment.

Option C (Oganesson) is correct because Oganesson is the last radioactive element in the noble gas family.

Option C (8) is correct because Phosphorus in $PCl_3$ has 5 valence electrons, and each Chlorine contributes 1, totaling 8 electrons in the valence shell of P.

Option D (Both (A) and (R) are false) is correct because ammonium nitrate decomposes to nitrous oxide and water, not ammonia, and the nitrate ion is indeed an oxidizing agent, but that's not why ammonia isn't produced.

Option C ($2 \mathrm{SO}_2+\mathrm{O}_2 \longrightarrow 2 \mathrm{SO}_3$) is correct because $\mathrm{V}_2 \mathrm{O}_5$ acts as a catalyst in the oxidation of $\mathrm{SO}_2$ to $\mathrm{SO}_3$ during sulfuric acid production.

Option C (7) is correct because the maximum number of halogen atoms in known interhalogen compounds is 7, as seen in $I{F_7}$.

Option B ($\mathrm{AgI}$) is correct because silver iodide is a covalent compound and therefore insoluble in water.

Option A (He) is correct because the mineral clevite, when heated, releases Helium gas.

Option A (Basic) is correct because phosphine ($\mathrm{P}{\mathrm{H}_3}$) has a lone pair of electrons on the phosphorus atom, making it capable of accepting a proton and acting as a Lewis base.

Option A (CN⁻) is correct because cyanide ion (CN⁻) shares similar properties with halide ions like Cl⁻, Br⁻, and I⁻, such as forming dimers and disproportionating in alkaline medium.

Option A ($SbCl_3$) is correct because antimony reacts with chlorine to form antimony(III) chloride ($SbCl_3$).

Option D (Zero) is correct because inert gases have a stable electronic configuration and thus have no tendency to attract electrons.