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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 344 questions

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61 Easy

61 of 344

Remembering +4 | -1

]The idea which prompted Bartlett to prepare first ever compound of noble gas was:

View answer and explanation

Correct option: C

Ionization energies of

{O_2}

and xenon were almost similar

Option C (Ionization energies of

{O_2}

and xenon were almost similar) is correct because Bartlett's initial discovery was based on the similar ionization energies of oxygen and xenon.

62 Easy

62 of 344

Understanding +4 | -1

{I_2}

dissolves in KI solution due to the formation of

View answer and explanation

Correct option: C

I_3^ -

Option C is correct because iodine dissolves in KI solution due to the formation of the triiodide ion (

I_3^ -

63 Easy

63 of 344

Understanding +4 | -1

Consider the following compounds

Sulphur dioxide

Hydrogen peroxide

Ozone

Among these compounds identify those that can act as bleaching agent.

View answer and explanation

Correct option: D

1,2 and 3

Option D (1,2 and 3) is correct because Sulphur dioxide, Hydrogen peroxide and Ozone can act as bleaching agents.

64 Easy

64 of 344

Remembering +4 | -1

Bond angle in

{O_3}

molecule is:

View answer and explanation

Correct option: C

{116^ \circ }90'

Option C (

{116^ \circ }90'

) is correct because the bond angle in

{O_3}

molecule is

{116^ \circ }90'

65 Easy

65 of 344

Remembering +4 | -1

Good conductor of electricity is:

View answer and explanation

Correct option: D

Black P

Option D (Black P) is correct because Black Phosphorus is the most thermodynamically stable allotrope and exhibits metallic properties, making it a good conductor of electricity.

66 Easy

66 of 344

Understanding +4 | -1

With excess of chlorine, ammonia forms:

View answer and explanation

Correct option: A

NC{l_3}

Option A (

NC{l_3}

) is correct because with excess chlorine, ammonia reacts to form nitrogen trichloride (

NC{l_3}

67 Easy

67 of 344

Understanding +4 | -1

Which one of the following represents noble gas configuration?

View answer and explanation

Correct option: C

1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^{10}},4{s^2}4{p^6}4{d^{10}},5{s^2}5{p^6}

Option B, C, and E are correct statements, while A and D are incorrect.

68 Easy

68 of 344

Analyzing +4 | -1

Which one of the following statements is not true?

View answer and explanation

Correct option: D

HF is a stronger acid than HCl

Option D (HF is a stronger acid than HCl) is not true because HF is a weaker acid than HCl due to strong hydrogen bonding in HF which stabilizes it and makes it less likely to donate a proton.

69 Easy

69 of 344

Remembering +4 | -1

The element which is the most abundant in the earth crust is

View answer and explanation

Correct option: A

{O}

Option A (

{O}

) is correct because oxygen is the most abundant element in the Earth's crust.

70 Easy

70 of 344

Understanding +4 | -1

Which of the following gives

\;{M^{3 + }}

ion most readily?

View answer and explanation

Correct option: D

Option D (Bi) is correct because Bismuth (Bi) readily forms a +3 ion due to the inert pair effect, where the 6s² electrons are reluctant to participate in bonding.

71 Easy

71 of 344

Understanding +4 | -1

When chlorine reacts with dil. NaOH under cold conditions, the oxidation state of chlorine changes from zero to

View answer and explanation

Correct option: D

- 1\,\,\,\mathrm{and} + 1

Option D (-1 and +1) is correct because when chlorine reacts with cold dilute NaOH, it forms NaCl (oxidation state -1) and NaClO (oxidation state +1).

72 Easy

72 of 344

Understanding +4 | -1

The species that does not contain peroxide ion is

View answer and explanation

Correct option: A

Pb{O_2}

Option A (

Pb{O_2}

) is correct because lead dioxide does not contain the peroxide ion (O2^2-).

73 Easy

73 of 344

Remembering +4 | -1

Calcium phosphide is:

View answer and explanation

Correct option: B

\mathrm{C}{\mathrm{a}_3}{\mathrm{P}_2}

Option B (

\mathrm{C}{\mathrm{a}_3}{\mathrm{P}_2}

) is correct because the chemical formula for calcium phosphide is Ca3P2, representing the correct ratio of calcium and phosphorus atoms.

74 Easy

74 of 344

Understanding +4 | -1

Number of hydroxyl groups present in pyrosulphuric acid is:

View answer and explanation

Correct option: C

Option B (5) is correct because one molecule of the compound dissociates into 5 ions: Fe2+, 2 SO42-, and 2 NH4+.

75 Easy

75 of 344

Remembering +4 | -1

Which of the following is formed by xenon?

View answer and explanation

Correct option: B

Xe{F_4}

The correct answer is B (

Xe{F_4}

) because Xenon tetrafluoride (

XeF_4

) is a known and well-characterized compound of xenon, while the others are not typically formed.

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76 Easy

76 of 344

Understanding +4 | -1

S-I: Hybridisation of

{Xe}

{XeF}_2

{sp}^3 {d}

.

S-II: Shape of

{XeF}_2

is angular.

View answer and explanation

Correct option: C

S-I is true, S-II is false

Option C (S-I is true, S-II is false) is correct because the hybridization of Xe in XeF2 is sp3d, but the shape is linear, not angular.

77 Easy

77 of 344

Analyzing +4 | -1

Assertion:

{Fe}^{3+}

does not give brown ring test.

Reason: Because

{NO}_3^{-}

is first converted into

{NO}_2^{-}

View answer and explanation

Correct option: C

If Assertion is correct but Reason is incorrect.

Option C is correct because in the brown ring test, Fe2+ oxidizes to Fe3+, and NO3- reduces to NO, not NO2- as stated in the reason, and Fe3+ does not give the brown ring test.

78 Easy

78 of 344

Analyzing +4 | -1

Which of the following statements are correct?

(I)

{HF}

is a stronger acid than

{HCl}

(II) Among halide ions, iodide is the most powerful reducing agent.

(III) Fluorine is the only halogen that does not show a variable oxidation state.

(IV)

{HOCl}

is a stronger acid than

{HOBr}

View answer and explanation

Correct option: D

II, III and IV

The correct answer is D (II, III and IV) because iodide is the strongest reducing agent, fluorine has a fixed oxidation state, and HOCl is a stronger acid than HOBr.

79 Easy

79 of 344

Remembering +4 | -1

Which of the following is not an interhalogen compound?

View answer and explanation

Correct option: C

\mathrm{HF}

Option C (

\mathrm{HF}

) is correct because

\mathrm{HF}

is a hydrogen halide, not an interhalogen compound.

80 Easy

80 of 344

Remembering +4 | -1

Which of the element of nitrogen family produce maximum number of oxy-acids?

View answer and explanation

Correct option: B

Option B (P) is correct because phosphorus forms a greater variety of oxyacids compared to other elements in the nitrogen family.

81 Easy

81 of 344

Remembering +4 | -1

Which one among the following non-metals is liquid at

{25^ \circ }C

View answer and explanation

Correct option: A

Bromine

Option A (Bromine) is correct because bromine is the only non-metal that exists as a liquid at room temperature (25°C).

82 Easy

82 of 344

Remembering +4 | -1

The strongest oxidising agent is :

View answer and explanation

Correct option: A

{F}_2

Option A (

\mathrm{F_2}

) is correct because fluorine is the strongest oxidizing agent among the halogens due to its high electronegativity and small size.

83 Easy

83 of 344

Remembering +4 | -1

Which of the following attacks glass:

View answer and explanation

Correct option: B

Option B (HF) is correct because hydrofluoric acid (HF) is known to react with silica (

SiO_2

), the main component of glass.

84 Easy

84 of 344

Remembering +4 | -1

Fluorine is usually obtained from:

View answer and explanation

Correct option: A

Fluorspar

The correct answer is A (Fluorspar) because fluorine is commercially obtained from fluorspar, which is calcium fluoride (CaF2).

85 Easy

85 of 344

Remembering +4 | -1

Swimming pools are disinfected by bubbling through water with a controlled quantity of:

View answer and explanation

Correct option: A

\mathrm{B}{\mathrm{r}_2}

Option B (

\mathrm{C}{\mathrm{l}_2}

) is correct because chlorine is commonly used to disinfect swimming pools due to its antibacterial properties.

86 Easy

86 of 344

Understanding +4 | -1

Assertion (A): Sulphur shows paramagnetism.

Reason (R): In vapour state sulphur partly exists as

\mathrm{S}_2

molecule which has two unpaired electrons in the antibonding

\hat{\pi}

-orbitals.

View answer and explanation

Correct option: A

Both

\mathrm{A}

and

\mathrm{R}

are correct;

\mathrm{R}

is the correct explanation of

A

Option A is correct because both the assertion and the reason are true, and the reason correctly explains why sulfur exhibits paramagnetism in the vapor state.

87 Easy

87 of 344

Understanding +4 | -1

Statement-I: Red phosphorus glows in dark and is frequently used in glow signs.

Statement-II: White phosphorus is an allotropic form of red phosphorus.

View answer and explanation

Correct option: D

Statement I is wrong but Statement II is correct

Option D (Statement I is wrong but Statement II is correct) is correct because red phosphorus does not glow in the dark, while white phosphorus is an allotrope of red phosphorus.

88 Easy

88 of 344

Remembering +4 | -1

The last member of inert gas family is:

View answer and explanation

Correct option: B

Radon

Option B (Radon) is correct because Radon (Rn) is the last element in Group 18, the noble gases.

89 Easy

89 of 344

Understanding +4 | -1

Assertion (A): Most of the reactions of fluorine are exothermic.

Reason (R): Fluorine forms small and strong bond with it and other elements.

View answer and explanation

Correct option: A

Both

\mathrm{A}

and

\mathrm{R}

are correct;

\mathrm{R}

is the correct explanation of

A

The correct answer is A (Both A and R are correct; R is the correct explanation of A) because fluorine's reactions are exothermic due to its small size and strong bond formation.

90 Easy

90 of 344

Remembering +4 | -1

Ammonia is dried over

View answer and explanation

Correct option: D

Quick lime

Option D (Quick lime) is correct because quick lime (CaO) is used to dry ammonia as ammonia reacts with other given dehydrating agents.

Revision notes and key takeaways

Review P-BLOCK ELEMENTS in your textbook or class notes, then use this set to check your understanding.

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