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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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541 Easy
541 of 705
Application +4 | -1
How many of the following given atomic number have noble gas configuration?
56,57,70,80,2456,57,70,80,24
View answer and explanation
Correct option: A
0
Option A (0) is correct because none of the given atomic numbers (56, 57, 70, 80, 24) correspond to noble gases.
542 Medium
542 of 705
Remembering +4 | -1
In the Haber process for the manufacture of ammonia the following catalyst is used
View answer and explanation
Correct option: B
Iron with molybdenum as promoter
Option B (Iron with molybdenum as promoter) is correct because in the Haber process, iron is used as the catalyst and molybdenum is used as a promoter to enhance the catalyst's activity.
543 Medium
543 of 705
Understanding +4 | -1
Liquor ammonia bottles are opened only after cooling because it has high vapour pressure and it is mild explosive.
View answer and explanation
Correct option: C
Both 1 and 2
Option C (Both 1 and 2) is correct because liquor ammonia bottles are opened only after cooling due to its high vapor pressure and mild explosive nature.
544 Hard
544 of 705
Analyzing +4 | -1
Which of the following statements is correct?

(i) Number of S−S\mathrm{S}-\mathrm{S} bonds in H2SnO6\mathrm{H}_2 \mathrm{S}_n \mathrm{O}_6 are (n+1)(n+1)

(ii) When F2\mathrm{F}_2 reacts with water, it gives HF\mathrm{HF} and O2\mathrm{O}_2

(iii) Zn\mathrm{Zn} evolves N2O\mathrm{N}_2 \mathrm{O} gas on reaction with dil. HNO3\mathrm{HNO}_3

(iv) Both, white and red phosphorous react with boiling alkali to evolve PH3( g)\mathrm{PH}_3(\mathrm{~g})
View answer and explanation
Correct option: C
(ii) and (iii) only
Option C is correct because statements (ii) and (iii) are accurate chemical reactions, while (i) and (iv) contain inaccuracies regarding the number of S-S bonds and the reactivity of phosphorus allotropes.
545 Medium
545 of 705
Understanding +4 | -1
Which is the correct thermal stability order for H2E (E = O, S, Se, Te and Po)?{H_2}E\,(E\, = \,O,\,S,\,Se,\,Te\,\mathrm{and}\,Po)?
View answer and explanation
Correct option: C
H2PO < H2Te < H2Se < H2S < H2O{H_2}PO\, < \,{H_2}Te\, < \,{H_2}Se\, < \,{H_2}S\, < \,{H_2}O
Option C (H2PO<H2Te<H2Se<H2S<H2O{H_2}PO < {H_2}Te < {H_2}Se < {H_2}S < {H_2}O) is correct because thermal stability decreases down the group due to decreasing bond strength.
546 Medium
546 of 705
Analyzing +4 | -1
Statement I: Noble gases have highest ionization energies in their respective periods

Statement II: The outer most shell of noble gases is completely filled
View answer and explanation
Correct option: C
Statement I is correct but statement II is false
Option A (Solution of iron salt does not give blue colour with indicator) is correct because the endpoint is reached when all Fe2+ has been oxidized to Fe3+, so no Prussian blue color forms with K3[Fe(CN)6].
547 Easy
547 of 705
Understanding +4 | -1
The van der Waal’s forces are the greatest in:
View answer and explanation
Correct option: D
Xenon
Option D (Xenon) is correct because Van der Waals forces increase with increasing atomic size and number of electrons, and Xenon has the largest atomic size among the given noble gases.
548 Medium
548 of 705
Understanding +4 | -1
Which hydride has the lowest boiling point?
View answer and explanation
Correct option: B
H2S{H_2}S
Option B is correct because H2S has the lowest boiling point among the given hydrides due to weaker intermolecular forces compared to water and lower molar mass compared to H2Se and H2Te.
549 Medium
549 of 705
Remembering +4 | -1
Bleaching powder is a mixture of:
View answer and explanation
Correct option: C
Calcium hypochlorite and basic calcium chloride
Option C (Calcium hypochlorite and basic calcium chloride) is correct because bleaching powder is primarily a mixture of calcium hypochlorite and basic calcium chloride.
550 Easy
550 of 705
Understanding +4 | -1
Which is the most volatile compound?
View answer and explanation
Correct option: A
HClHCl
Option A (HCl) is correct because it has the lowest boiling point among the given hydrogen halides due to weaker intermolecular forces.
551 Easy
551 of 705
Understanding +4 | -1
Iodine is formed when potassium iodide reacts with a solution of
View answer and explanation
Correct option: B
CuSO4CuS{O_4}
Option B (CuSO4CuS{O_4}) is correct because copper sulfate reacts with potassium iodide to produce iodine.
552 Easy
552 of 705
Remembering +4 | -1
Pure nitrogen is prepared in the laboratory by heating a mixture of
View answer and explanation
Correct option: D
NH4Cl+NaNO2N{H_4}Cl + NaN{O_2}
Option D (NH4Cl+NaNO2NH_4Cl + NaNO_2) is correct because heating this mixture produces nitrogen gas.
553 Easy
553 of 705
Remembering +4 | -1
Which gas is used to improve the atmosphere of crowded places?
View answer and explanation
Correct option: C
O3{\mathrm{O}_3}
Option C (O3{\mathrm{O}_3}) is correct because ozone decomposes to produce oxygen, which improves the air quality in crowded places.
554 Medium
554 of 705
Remembering +4 | -1
Javelle water is:
View answer and explanation
Correct option: C
Both (1) and (2)
Correct Answer + Core Reason: Option C (Both (1) and (2)) is correct because chlorine is used both as a disinfecting agent in water and as a bleaching agent.
555 Easy
555 of 705
Remembering +4 | -1
White smoke is formed when ammonia gas meets with:
View answer and explanation
Correct option: B
HClHCl
Option B (HClHCl) is correct because ammonia gas reacts with hydrogen chloride to form white fumes of ammonium chloride.
556 Medium
556 of 705
Understanding +4 | -1
Assertion (A) : S3O62−\mathrm{S}_3 \mathrm{O}_6^{2-} (trithionate) has S−S\mathrm{S}-\mathrm{S} bond.

Reason (R) : It is a conjugate base of HS3O6−\mathrm{HS}_3 \mathrm{O}_6^{-}.
View answer and explanation
Correct option: B
Both A\mathbf{A} and R\mathbf{R} are true but R\mathbf{R} is not the correct explanation of A\mathbf{A}.
Option B is correct because both the assertion and the reason are true, but the reason does not explain the assertion. Trithionate does have an S-S bond, and it is a conjugate base, but these facts are not directly related.
557 Medium
557 of 705
Application +4 | -1
In the reaction, MnO4−  +  I−  →Alkaline  solution  [X];  [X]  is:\mathrm{MnO}_4^ - \mathrm{\;} + \mathrm{\;}{\mathrm{I}^ - }\;\mathop \to \limits^{A\mathrm{lkaline\;solution}} \;\left[ X \right];\,\,\left[ X \right]\;\mathrm{is}:
View answer and explanation
Correct option: A
IO3−\mathrm{IO}_3^ -
Option A (IO3−\mathrm{IO}_3^ -) is correct because in alkaline solution, permanganate reduces to MnO2 and iodide oxidizes to iodate.
558 Easy
558 of 705
Remembering +4 | -1
Oxide of nitrogen used as a catalyst in the lead chamber process for the manufacture of sulphuric acid is:
View answer and explanation
Correct option: A
NO
Option A (NO) is correct because nitric oxide (NO) acts as a catalyst in the lead chamber process for the manufacture of sulfuric acid.
559 Medium
559 of 705
Understanding +4 | -1
The element evolving two different gases on reaction with conc. Sulphuric acid is
View answer and explanation
Correct option: B
C
Option C is correct because carbon reacts with concentrated sulfuric acid to produce two different gases: carbon dioxide (CO2CO_2) and sulfur dioxide (SO2SO_2).
560 Medium
560 of 705
Remembering +4 | -1
Which of the following is not a drying and dehydrating agent?
View answer and explanation
Correct option: D
Hydrated CaCl2CaC{l_2}
Option D (Hydrated CaCl2CaC{l_2}) is correct because hydrated calcium chloride already contains water and cannot be used as a drying or dehydrating agent.
561 Easy
561 of 705
Remembering +4 | -1
Most abundant element in earth’s crust is:
View answer and explanation
Correct option: A
OO
Option A (OO) is correct because oxygen is the most abundant element in the Earth's crust.
562 Medium
562 of 705
Understanding +4 | -1
Assertion: NH3\mathrm{NH}_3 is easily dissolved in alkaline HgI42−\mathrm{HgI}_4{ }^{2-}

Reason: Compound of Hg−\mathrm{Hg}^{-}and I−\mathrm{I}^{-}is used in detection of NH3\mathrm{NH}_3.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is correct explanation of the Assertion) is correct because ammonia dissolves readily in alkaline HgI42- solution, and Hg- and I- compounds are indeed used for NH3 detection.
563 Easy
563 of 705
Understanding +4 | -1
The correct order of acid strength is
View answer and explanation
Correct option: A
HClO<HClO2<HClO3<HClO4{HClO} < {HClO}_2 < {HClO}_3 < {HClO}_4
Option A (HClO<HClO2<HClO3<HClO4{HClO} < {HClO}_2 < {HClO}_3 < {HClO}_4) is correct because the acid strength increases with the number of oxygen atoms bonded to the central chlorine atom.
564 Medium
564 of 705
Understanding +4 | -1
HNO3  HN{O_3}\; oxidises :
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because nitric acid (HNO3HNO_3) is a strong oxidizing agent and can oxidize H2O2H_2O_2, H2SH_2S, and SO2SO_2.
565 Medium
565 of 705
Remembering +4 | -1
Coloured oxide is nitrogen is:
View answer and explanation
Correct option: D
NO2N{O_2}
Option D (NO2NO_2) is correct because nitrogen dioxide (NO2NO_2) is a brown gas, which makes it a colored oxide of nitrogen.
566 Medium
566 of 705
Understanding +4 | -1
Hydrolysis of PI3P{I_3} yields:
View answer and explanation
Correct option: B
Monobasic acid and dibasic acid
Option D (Monobasic acid and tribasic acid) is incorrect, the correct answer is monobasic acid and dibasic acid because the hydrolysis of PI₃ yields HI (monobasic) and H₃PO₃ (dibasic).
567 Hard
567 of 705
Remembering +4 | -1
Select the CORRECT reactant for brown ring test of NO3−\mathrm{NO}_3{ }^{-} ion
View answer and explanation
Correct option: C
Aqueous solution of salt + ferrous sulphate solution + conc. H2SO4\mathrm{H}_2 \mathrm{SO}_4
Option C (Aqueous solution of salt + ferrous sulphate solution + conc. H2SO4H_2SO_4) is correct because this combination of reactants is required for the brown ring test to detect nitrate ions.
568 Medium
568 of 705
Analyzing +4 | -1
Statement-I: The solid N2O5{N}_2 {O}_5 is ionic.

Statement-II: In solid state N2O5{N}_2 {O}_5 exist as [NO3]+[NO2]−\left[{NO}_3\right]^{+}\left[{NO}_2\right]^{-}
View answer and explanation
Correct option: C
If Statement-I is true but Statement-II is false
Option C (If Statement-I is true but Statement-II is false) is correct because solid N2O5 exists as [NO2]+[NO3]-, making it ionic, but the ions are incorrectly identified in Statement II.
569 Medium
569 of 705
Application +4 | -1
Sulphur reacts with chlorine in 1:2 ratio and forms X{X}. Hydrolysis of X{X} gives a sluphur compound Y{Y}. The hybridization of central atom in the anion Y{Y} is
View answer and explanation
Correct option: A
sp3s p^3
Option A (sp3s p^3) is correct because the sulphur compound formed after hydrolysis is H2SO3{H_2}S{O_3}, and the hybridization of S in SO32−{SO_3}^{2-} is sp3sp^3.
570 Medium
570 of 705
Analyzing +4 | -1
Which can act as an acid in sulphuric acid?
View answer and explanation
Correct option: C
HClO4HCl{O_4}
Option C (HClO4HClO_4) is correct because perchloric acid is a strong acid and can donate a proton to sulfuric acid, acting as an acid in this context.
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