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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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331 Medium
331 of 705
Remembering +4 | -1
In Haber's process for the manufacture of NH3{NH}_3 :
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Correct option: B
Finely divided iron is used as a catalyst
Option B (Finely divided iron is used as a catalyst) is correct because iron is used as a catalyst in Haber's process to increase the rate of ammonia production.
332 Medium
332 of 705
Remembering +4 | -1
Which of the following elements is radioactive?
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Correct option: C
Polonium
Option C (Polonium) is correct because Polonium is a radioactive element.
333 Medium
333 of 705
Analyzing +4 | -1
In which molecule hybrid orbital have only 20%20 \% d- character?
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Correct option: C
SF4\mathrm{SF}_4
The correct answer is C (SF4) because SF4 has sp3d hybridization, which results in 20% d-character.
334 Medium
334 of 705
Understanding +4 | -1
Which of the following is not a monobasic acid?
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Correct option: C
H2 S2O3\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_3
Option C (H2 S2O3\mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_3) is not a monobasic acid because it has two ionizable hydrogen atoms, making it a dibasic acid.
335 Medium
335 of 705
Application +4 | -1
The number of molecules of water needed to convert one molecule of P2O5  {P_2}{O_{5\;}} into orthophosphoric acid is:
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Correct option: B
3
Option B (3) is correct because 3 water molecules are required to convert one molecule of P2O5 into two molecules of orthophosphoric acid.
336 Easy
336 of 705
Remembering +4 | -1
Which noble gas does not form clathrates?
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Correct option: C
HeHe
Option C (HeHe) is correct because Helium (He) does not form clathrates due to its small size and weak intermolecular forces.
337 Medium
337 of 705
Analyzing +4 | -1
When a mixture of NaCl\mathrm{NaCl} and K2Cr2O7\mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7 is gently warmed with conc. H2SO4\mathrm{H}_2 \mathrm{SO}_4
(i) an orange-red vapour is evolved
(ii) the vapour formed when passed into NaOH\mathrm{NaOH} solution gives yellow solution of Na2CrO4\mathrm{Na}_2 \mathrm{CrO}_4
(iii) Chlorine gas is not evolved at all
(iv) chromyl chloride gas is formed
(v) SnCl4\mathrm{SnCl}_4 used instead of NaCl\mathrm{NaCl} also gives same observations
View answer and explanation
Correct option: C
3 statements are correct
Option C (3 statements are correct) is correct because statements (i), (ii), and (iv) are correct regarding the reaction of NaCl and K2Cr2O7 with conc. H2SO4.
338 Easy
338 of 705
Remembering +4 | -1
Berthelot’s salt is:
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Correct option: A
KClO3KCl{O_3}
Option A (KClO3KCl{O_3}) is correct because KClO3KCl{O_3} is the chemical formula for Berthelot's salt, also known as potassium chlorate.
339 Easy
339 of 705
Remembering +4 | -1
Which one is true peroxide?
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Correct option: C
BaO2\mathrm{Ba}{\mathrm{O}_\mathrm{2}}
Option D (BaO2\mathrm{Ba}{\mathrm{O}_\mathrm{2}}) is correct because barium peroxide contains the peroxide ion (O22−O_2^{2-}).
340 Medium
340 of 705
Analyzing +4 | -1
Assertion (A): Cl2\mathrm{Cl}_2 on reaction with NaOH (Cold and dilute) gives NaClO3.\mathrm{NaClO}_3.

Reason (R): Cl2\mathrm{Cl}_2 get oxidized only in this reaction.
View answer and explanation
Correct option: D
Both (A) and (R) are false
The correct answer is D because chlorine reacts with cold and dilute NaOH to form NaCl and NaClO, not NaClO3, and chlorine can be oxidized in other reactions as well.
341 Easy
341 of 705
Remembering +4 | -1
Which does not show allotropy
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Correct option: A
N
Option A (N) is correct because nitrogen is the only element in the nitrogen family that does not exhibit allotropy.
342 Medium
342 of 705
Understanding +4 | -1
Which blue liquid is obtained on reacting equimolar amounts of two gases at −30∘C- {30^ \circ }C ?
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Correct option: B
N2O3{N_2}{O_3}
The correct answer is B (N2O3{N_2}{O_3}) because equimolar amounts of NO(g) and NO2N{O_2}(g) react at -30°C to form liquid N2O3N_2O_3, which is blue.
343 Easy
343 of 705
Understanding +4 | -1
Assertion (A) : On cooling, the brown colour of nitrogen dioxide disappears.

Reason (R): On cooling NO2\mathrm{NO}_2 undergoes dimerisation resulting in the pairing of odd electrons of NO2\mathrm{NO}_2.
View answer and explanation
Correct option: A
Both A\mathbf{A} and R\mathbf{R} are true and R\mathbf{R} is the correct explanation of A\mathbf{A}.
Option A is correct because cooling nitrogen dioxide causes it to dimerize, pairing its odd electrons and reducing the brown color.
344 Medium
344 of 705
Remembering +4 | -1
The compound that attacks pyrex glass is:
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Correct option: C
XeF6Xe{F_6}
Option C (XeF6Xe{F_6}) is correct because xenon hexafluoride reacts with silica in glass to form volatile silicon tetrafluoride and other xenon compounds, thus attacking the glass.
345 Easy
345 of 705
Understanding +4 | -1
The shape of IF7I{F_7} molecule is:
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Correct option: B
Pentagonal bipyramidal
The correct answer is B (Pentagonal bipyramidal) because IF7IF_7 has sp3d3sp^3d^3 hybridization with 7 bond pairs and 0 lone pairs, resulting in a pentagonal bipyramidal shape.
346 Easy
346 of 705
Remembering +4 | -1
Helium gives a characteristic spectrum with:
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Correct option: C
Yellow lines
Option C (Yellow lines) is correct because Helium exhibits a characteristic emission spectrum with prominent yellow lines.
347 Medium
347 of 705
Analyzing +4 | -1
Assertion (A) : Equivalent mass of N2H4\mathrm{N}_2 \mathrm{H}_4 is 8 in acidic medium or basic medium.

Reason (R) : It is oxidised to N2\mathrm{N}_2 with loss of four electron per N2H4\mathrm{N}_2 \mathrm{H}_4 unit.
View answer and explanation
Correct option: A
Both A\mathbf{A} and R\mathbf{R} are true and R\mathbf{R} is the correct explanation of A\mathbf{A}.
Option A is correct because the equivalent mass of N2H4 is indeed 8, and this is because it is oxidized to N2 with a loss of four electrons per N2H4 unit, making the reason a correct explanation of the assertion.
348 Easy
348 of 705
Understanding +4 | -1
Which of the following has no action with starch solution?
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Correct option: A
F2{F_2} and Cl2C{l_2}
Option A (F2{F_2} and Cl2C{l_2}) is correct because fluorine and chlorine react with starch solution differently than bromine and iodine.
349 Easy
349 of 705
Understanding +4 | -1
Assertion: Group 15 elements can exhibit multiple oxidation states.

Reason: Group 15 elements have five valence electrons that can be lost or gained to form ions with different charges.
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Correct option: A
Both Assertion and Reason are true and Reason is the correct explanation for Assertion
Option A (Both Assertion and Reason are true and Reason is the correct explanation for Assertion) is correct because Group 15 elements exhibit multiple oxidation states due to having five valence electrons.
350 Medium
350 of 705
Remembering +4 | -1
In the ring test for NO3−\mathrm{NO}_3^{-}ion, a brown ring is formed due to the formation of
View answer and explanation
Correct option: C
[Fe(H2O)5(NO)]2+\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5(\mathrm{NO})\right]^{2+}
Option C ([Fe(H2O)5(NO)]2+\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5(\mathrm{NO})\right]^{2+}) is correct because the brown ring in the nitrate test is due to the formation of the pentaaquanitrosyliron(II) complex.
351 Easy
351 of 705
Understanding +4 | -1
The following acids have been arranged in the order of decreasing acid strength. Identify the correct order
ClOH(I)  BrOH(II)  IOH(III)\mathrm{ClOH}\left( \mathrm{I} \right)\mathrm{\;BrOH}\left( {\mathrm{II}} \right)\mathrm{\;IOH}\left( {\mathrm{III}} \right)
View answer and explanation
Correct option: A
I>II>IIII > II > III
Option A (I>II>IIII > II > III) is correct because acid strength decreases as the electronegativity of the halogen decreases.
352 Medium
352 of 705
Remembering +4 | -1
A colourless gas with the smell of rotten fish is
View answer and explanation
Correct option: B
PH3{PH}_3
Option B (PH3{PH}_3) is correct because phosphine gas has a characteristic smell of rotten fish.
353 Medium
353 of 705
Remembering +4 | -1
Ammonia is used in detection of Cu2+\mathrm{Cu}^{2+} ion because
View answer and explanation
Correct option: A
Aqueous solution of NH3\mathrm{NH}_3 reacts with Cu2+\mathrm{Cu}^{2+} ion to form deep blue coloured complex
Option A (Aqueous solution of NH3\mathrm{NH}_3 reacts with Cu2+\mathrm{Cu}^{2+} ion to form deep blue coloured complex) is correct because this is the basis of the test for copper(II) ions.
354 Medium
354 of 705
Understanding +4 | -1
Statement I : CIF undergoes hydrolysis as below,
CIF+H2O→HF+HOClCIF + {H_2}O \to HF + HOCl
Statement II : Fluorine containing interhalogen compounds are very useful as fluorinating agents
View answer and explanation
Correct option: A
Both Statement I and II are correct
Option A (Both Statement I and II are correct) is correct because CIF undergoes hydrolysis to form HF and HOCl, and fluorine-containing interhalogen compounds are indeed useful as fluorinating agents.
355 Medium
355 of 705
Remembering +4 | -1
Cl2  C{l_2}\; is used in the manufacture of:
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Correct option: D
All of these
Option D (All of these) is correct because chlorine (Cl2Cl_2) is used in the manufacture of chloroform (CHCl3CHCl_3), carbon tetrachloride (CCl4CCl_4), and Westron (C2H2Cl4C_2H_2Cl_4).
356 Easy
356 of 705
Remembering +4 | -1
Pnicogens are the elements of group?
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Correct option: A
15
Option A (15) is correct because pnicogens are the elements belonging to Group 15 of the periodic table.
357 Easy
357 of 705
Remembering +4 | -1
Which of the following is the life saving mixture for an asthma patient?
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Correct option: A
Mixture of helium and oxygen
Option A (Mixture of helium and oxygen) is correct because helium is less soluble in blood than nitrogen, making it a life-saving mixture for asthma patients.
358 Easy
358 of 705
Understanding +4 | -1
How many lone pair of electrons are present on XeXe in XeOF4XeO{F_4} ?
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Correct option: A
1
Option B (2) is correct because a 3p orbital has one angular node (l=1) and one radial node (n-l-1 = 3-1-1 = 1).
359 Easy
359 of 705
Remembering +4 | -1
The last orbit of argon would have electrons
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Correct option: C
8
Option C (8) is correct because Argon (Ar) has an atomic number of 18, and its electronic configuration is 2, 8, 8, meaning it has 8 electrons in its outermost shell.
360 Medium
360 of 705
Understanding +4 | -1
Assertion (A): Ammonia cannot be dried over concentrated H2SO4{H}_2 {SO}_4.

Reason (R): Conc. H2SO4{H}_2 {SO}_4 reacts with NH3{NH}_3.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because concentrated sulfuric acid reacts with ammonia, making it unsuitable as a drying agent for ammonia.
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