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JEE • CHEMISTRY • CO-ORDINATION COMPOUNDS

Co-ordination compounds practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-200 of 200 questions
181 Medium
181 of 200
Analyzing +4 | -1
Which of the following is tetrahedral and paramagnetic complex?
View answer and explanation
Correct option: A
[NiCl4]2−\left[\mathrm{NiCl}_4\right]^{2-}
Option A ([NiCl4]2−\left[\mathrm{NiCl}_4\right]^{2-}) is correct because it is tetrahedral and has unpaired electrons, making it paramagnetic.
182 Medium
182 of 200
Analyzing +4 | -1
Among the following ions, which one has the highest unpaired electrons?
View answer and explanation
Correct option: C
[Fe(H2O)6]2+{\left[ {\mathrm{Fe}{{\left( {{\mathrm{H}_2}\mathrm{O}} \right)}_6}} \right]^{2 + }}
The correct answer is C ([Fe(H2O)6]2+{\left[ {\mathrm{Fe}{{\left( {{\mathrm{H}_2}\mathrm{O}} \right)}_6}} \right]^{2 + }}) because it has the highest number of unpaired electrons (4) among the given options.
183 Medium
183 of 200
Analyzing +4 | -1
Assertion: [Ni(CN)4]−2\left[{Ni}({CN})_4\right]^{-2} has zero unpaired electron while that of [NiCl4]−2\left[{NiCl}_4\right]^{-2} has two unpaired e−{e}^{-}

Reason: [Ni(CN)4]−2\left[{Ni}({CN})_4\right]^{-2} has strong crystal field while [NiCl4]−2\left[{NiCl}_4\right]^{-2} has weak crystal field.
View answer and explanation
Correct option: A
Assertion is true, Reason is true and Reason is correct explanation for Assertion
Option A (Assertion is true, Reason is true and Reason is correct explanation for Assertion) is correct because the cyanide ligand (CN−CN^−) is a strong field ligand causing pairing of electrons, while chloride (Cl−Cl^−) is a weak field ligand resulting in unpaired electrons.
184 Medium
184 of 200
Application +4 | -1
Which of the following compounds has same oxidation state of the central metal atom in the cationic and anionic part?
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Correct option: B
[Pt(py)4][PtCl4]\left[\mathrm{Pt}(\mathrm{py})_4\right]\left[\mathrm{PtCl}_4\right]
Option B ([Pt(py)4][PtCl4]) is correct because the oxidation state of Pt is +2 in both the cationic and anionic parts of the complex.
185 Medium
185 of 200
Analyzing +4 | -1
What will be the correct order for the wavelengths of absorption in the visible region of the following:
[Ni(NH3)6]2+A,Ni(CN)6]−4B,[Ni(H2O)6]+2C,[NiCl6]−4D\mathop {{{\left[ {{\text{Ni}}{{\left( {{\text{N}}{{\text{H}}_3}} \right)}_6}} \right]}^{2 + }}}\limits_{\text{A}} ,\mathop {{\text{Ni}}{{({\text{CN}})}_6}{]^{ - 4}}}\limits_{\text{B}} ,\mathop {{{\left[ {{\text{Ni}}{{\left( {{{\text{H}}_2}{\text{O}}} \right)}_6}} \right]}^{ + 2}}}\limits_{\text{C}} ,\mathop {{{\left[ {{\text{NiC}}{{\text{l}}_6}} \right]}^{ - 4}}}\limits_{\text{D}}
View answer and explanation
Correct option: B
D >> C >> A >> B
The correct answer is D (D >> C >> A >> B) because the spectrochemical series dictates that stronger field ligands cause larger splitting and absorb at shorter wavelengths (higher energy), so the order of ligand strength is Cl- < H2O < NH3 < CN-.
186 Medium
186 of 200
Remembering +4 | -1
According to spectrochemical series strongest field ligand among the following is
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Correct option: A
NH3\mathrm{NH}_3
Option A (NH3\mathrm{NH}_3) is correct because, according to the spectrochemical series, ammonia (NH3\mathrm{NH}_3) is a stronger field ligand than water, fluoride, or bromide.
187 Medium
187 of 200
Understanding +4 | -1
Which of the following has least conductivity in aqueous solution
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Correct option: B
CO(NH3)3Cl3CO{\left( {N{H_3}} \right)_3}C{l_3}
Option B is correct because CO(NH3)3Cl3CO(NH_3)_3Cl_3 does not ionize in aqueous solution, resulting in the least number of ions and therefore the lowest conductivity.
188 Medium
188 of 200
Understanding +4 | -1
The splitting of the dd - orbitals of transition metals by a particular complex geometry gives rise to the pattern,

dxy‾  dyz‾  dxz‾ Energy ↑dx2−y2‾  dz2‾\begin{array}{r} \overline{d_{x y}}\,\,\overline{d_{y z}}\,\,\overline{d_{x z}} \\ \text { Energy } \uparrow \overline{d_{x^2-y^2}}\,\,\overline{d_{z^2}} \end{array}

Which one of the following geometries produces the above splitting pattern?
View answer and explanation
Correct option: D
Tetrahedral
Option D is correct because the splitting pattern with dxyd_{xy}, dyzd_{yz}, and dxzd_{xz} orbitals lower in energy than dx2−y2d_{x^2-y^2} and dz2d_{z^2} orbitals is characteristic of tetrahedral geometry.
189 Medium
189 of 200
Remembering +4 | -1
The correct order of ligands arranged in increasing field strength.
View answer and explanation
Correct option: C
Br−<F−<H2O<NH3\mathrm{Br}^{-}< \mathrm{F}^{-}< \mathrm{H}_2 \mathrm{O}< \mathrm{NH}_3
Option C (Br−<F−<H2O<NH3\mathrm{Br}^{-}< \mathrm{F}^{-}< \mathrm{H}_2 \mathrm{O}< \mathrm{NH}_3) is correct because it represents the correct order of ligands in the spectrochemical series, which arranges ligands by their ability to split d-orbitals.
190 Medium
190 of 200
Application +4 | -1
The number of isomers possible for square planar complex K2[PdClBr2SCN]{\mathrm{K}_2}\left[ {\mathrm{PdClB}{\mathrm{r}_2}\mathrm{SCN}} \right] is:
View answer and explanation
Correct option: C
4
Option C (4) is correct because there are geometrical isomers (cis and trans) and linkage isomers due to -SCN and -CNS.
191 Medium
191 of 200
Understanding +4 | -1
The number of ions formed when a molecule of K4Fe(CN)6{\mathrm{K}_4}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6} dissociates is:
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Correct option: B
5
Option B is correct because K4Fe(CN)6{\mathrm{K}_4}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6} dissociates into 4 K+ ions and one Fe(CN)64−\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}^{4 - } complex ion, totaling 5 ions.
192 Medium
192 of 200
Analyzing +4 | -1
Assertion: [Fe(CN)6]3−\left[{Fe}({CN})_6\right]^{3-} is weakly paramagnetic while [Fe(CN)6]4−\left[{Fe}({CN})_6\right]^{4-} is diamagnetic.

Reason: [Fe(CN)6]3−\left[{Fe}({CN})_6\right]^{3-} has +3 oxidation state while [Fe(CN)6]4−\left[{Fe}({CN})_6\right]^{4-} has +2 oxidation state.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
Option B is correct. Both Assertion and Reason are correct, but the Reason is not the correct explanation of the Assertion. The paramagnetic/diamagnetic nature depends on the presence of unpaired electrons, not directly on the oxidation state.
193 Medium
193 of 200
Analyzing +4 | -1
[Ma6]+2,[Mb6]+2,[Mc6]+2\left[M a_6\right]^{+2},\left[M b_6\right]^{+2},\left[M c_6\right]^{+2} and [Md6]+2\left[M d_6\right]^{+2} octahydral complex absorbs wavelengths in the region of red, green, blue and yellow respectively. What is the strongest ligand among a,b,ca, b, c and d\mathrm{d}.
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Correct option: C
c\mathrm{c}
Option C is correct because blue light has the highest energy, indicating the strongest ligand field strength.
194 Medium
194 of 200
Remembering +4 | -1
Which of the following best describes the nature of FeSO4⋅(NH4)2SO4⋅6H2O\mathrm{FeSO}_4 \cdot\left(\mathrm{NH}_4\right)_2 \mathrm{SO}_4 \cdot 6 \mathrm{H}_2 \mathrm{O}
View answer and explanation
Correct option: B
Double salt
Option B is correct because FeSO4⋅(NH4)2SO4⋅6H2O\mathrm{FeSO}_4 \cdot(\mathrm{NH}_4)_2 \mathrm{SO}_4 \cdot 6 \mathrm{H}_2 \mathrm{O} (Mohr's salt) is a double salt that dissociates into its constituent ions in solution.
195 Medium
195 of 200
Analyzing +4 | -1
Statement I: [Ni(CO)4]\left[\mathrm{Ni}(\mathrm{CO})_4\right] is diamagnetic in nature

Statement II: Nickel atom undergoes sp3\mathrm{sp}^3 hybridization
View answer and explanation
Correct option: B
Statement I and statement II are correct but statement II is not the correct explanation of statement I
Option B (Statement I and statement II are correct but statement II is not the correct explanation of statement I) is correct because both statements are true, but the diamagnetic nature is due to the strong field CO ligand causing pairing of electrons, not directly due to sp3 hybridization.
196 Medium
196 of 200
Analyzing +4 | -1
The correct statements from following are:

A. The strength of anionic ligands can be explained by crystal field theory.

B. Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.

C. The hybridization involved in formation of [Ni(CN)4]2−\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-} complex is dsp 2{ }^2.

D. The number of possible isomer(s) of cis- [PtCl2(en)2]2+\left[\mathrm{PtCl}_2(\mathrm{en})_2\right]^{2+} is one

Choose the correct answer from the options given below:
View answer and explanation
Correct option: D
B, C only
Option D (B, C only) is correct because Valence Bond Theory doesn't give quantitative kinetic stability, and the hybridization of [Ni(CN)4]2- is dsp2.
197 Medium
197 of 200
Analyzing +4 | -1
Assertion: The geometrical isomers of the complex [M(NH3)4Cl2]\left[{M}\left({NH}_3\right)_4 {Cl}_2\right] are optically inactive.

Reason: Both geometrical isomers of the complex [M(NH3)4Cl2]\left[{M}\left({NH}_3\right)_4 {Cl}_2\right] posses axis of symmetry.
View answer and explanation
Correct option: A
Assertion is true, Reason is true and Reason is correct explanation for Assertion
Option A is correct because the geometrical isomers of [M(NH3)4Cl2] are optically inactive, and this is due to the presence of a plane or axis of symmetry in both isomers.
198 Medium
198 of 200
Remembering +4 | -1
Which of the following sequence is correct regarding field strength of ligands as per spectrochemical series?
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Correct option: A
SCN−<F−<CN−<CO{SCN}^{-} < {F}^{-} < {CN}^{-} < {CO}
Option A (SCN−<F−<CN−<CO{SCN}^{-} < {F}^{-} < {CN}^{-} < {CO}) is correct because it represents the correct increasing order of field strength according to the spectrochemical series.
199 Medium
199 of 200
Analyzing +4 | -1
Which of the following statements is not correct?
View answer and explanation
Correct option: A
In oxyhaemoglobin Fe2+\mathrm{F}{\mathrm{e}^{2 + }} is paramagnetic
Option A (In oxyhaemoglobin Fe2+\mathrm{F}{\mathrm{e}^{2 + }} is paramagnetic) is not correct because in oxyhaemoglobin, Fe2+Fe^{2+} is diamagnetic due to strong field ligands causing pairing of electrons.
200 Medium
200 of 200
Analyzing +4 | -1
Statement I: [Co(en)2(NH3)Br]SO4\left[\mathrm{Co}(\mathrm{en})_2\left(\mathrm{NH}_3\right) \mathrm{Br}\right] \mathrm{SO}_4 has lower electrical conductivity as compared to [Co(en)2(NH3)SO4]Br\left[\mathrm{Co}(\mathrm{en})_2\left(\mathrm{NH}_3\right) \mathrm{SO}_4\right] \mathrm{Br}

Statement II: Both the complexes produce the same number of ions in solution
View answer and explanation
Correct option: D
Statement I if false but statement II is correct
Option D (Statement I if false but statement II is correct) is correct because the electrical conductivity depends on the number and type of ions, and in this case, both complexes produce the same number of ions.
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