Co-ordination compounds practice · Medium

A spin only magnetic moment of $1.73 \mathrm{~BM}$ will be shown by which one among the following:

Assertion : Coordination number of Pt in Zeise's salt is 5.

Reason : ${{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}$ act as bidentate ligand

An octahedral complex with the formula $\mathrm{CoCl}_3 \mathrm{nNH}_3$ upon reaction with excess of $\mathrm{AgNO}_3$ solution given 2 moles of $\mathrm{AgCl}$. Consider the oxidation state of Co in the complex is ' $x$ '. The value of " $x+n$ " is ______.

Statement I: $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{+3}$ is more acidic compared to $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{+3}$

Statement II: Both are inner orbital complexes

In which year, IUPAC draft recommends that anionic ligands will end with-ido so that chloro would become chlorido?

Which of the following has maximum number of geometrical isomers?

To inhibit the growth of tumours, identify the compounds used from the following :

(A) EDTA

(B) Coordination Compounds of Pt

(C) D - Penicillamine

(D) Cis - Platin
Choose the correct answer from the option given below :

Select correct match :

Assertion: ${AgCl}$ dissolves in ${NH}_4 {OH}$ solution.

Reason: Due toformation of a complex.

Assertion: Cis - $\left[{Fe}({en})_2{Cl}_2\right]^{+}$ can form recemic mixture.

Reason: Cis - $\left[{Fe}({en})_2 {Cl}_2\right]^{+}$ is optically active square planar complex.

Correct for ${Ni}({CO})_4$ and $\left[{Ni}({CN})_4\right]^{2-}$ respectively

Statement I: $\mathrm{PF}_3$ is weakest donor as well as weakest acceptor compared to $\mathrm{PMe}_3$ in synergic bonding
Statement II: Me group is having $+ l$ effect while $F$ atom is having $-I$ effect

The complex that doesn’t give a precipitate with $\mathrm{AgN}{\mathrm{O}_3}$ solution

The value of CFSE for complex ion $\left[\mathrm{CoCl}_6\right]^{4-}$ is $18000 \mathrm{~cm}^{-1}$. The CFSE for $\left[\mathrm{CoCl}_4\right]^{2-}$ complex ion will be

Among the following compounds, the most stable compound is

The calculated spin-only magnetic moments of $\mathrm{K}_3\left[\mathrm{Fe}(\mathrm{OH})_6\right]$ and $\mathrm{K}_4\left[\mathrm{Fe}(\mathrm{OH})_6\right]$ respectively are:

$\text{A) }\left[\mathrm{Co}(\mathrm{CN})_6\right]^{-3}$

$\text{B) }\left[\mathrm{Co}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right]^{+3}$

Correct combination about the hybridization of central metal in these complexes is

The order of energy absorbed which is responsible for the color of complexes.
A) ${\left[ {Ni{{({H_2}O)}_2}{{(en)}_2}} \right]^{2 + }}$
B) ${\left[ {Ni{{({H_2}O)}_4}(en)} \right]^{2 + }}$ and
C) ${\left[ {Ni{{(en)}_3}} \right]^{2 + }}$

Read the following statements

(i) Macromolecules cannot behave as a ligand.

(ii) $[{EDTA}]^{4-}$ can bind through two oxygen and four nitrogen atom.

(iii) Chelate complexes are more stable than similar complexes containing unidentate ligands.

(iv) Coordination number of the central atom/ion is determined only by the number of sigma bonds formed by the ligand with central atom/ion

Which of the following is the correct code for statements above?

Assertion: The spin only magnetic moment of $\left[{MnBr}_4\right]^{2-}$ is $5.9 \, \mathrm{BM}.$

Reason: $\left[{MnBr}_4\right]^{2-}$ is tetrahedral with $s p^3$ hybridisation of ${Mn}^{2+}$ having $3 d^5$ configuration.

S-I:- The complex
$\left[{Cr}({SCN})\left({NH}_3\right)_5\right] {Cl}_2$ is linkage isomer of $\left[{Cr}({NCS})\left({NH}_3\right)_5\right] {Cl}_2$.

S-II:- $S C N^{-}$is an ambident ligand.

Assertion: ${K}_2\left[{PtCl}_6\right]$ gives white ppt when reacts with ${AgNO}_3.$

Reason: Chloride ion in the complex is non-ionisable.

Assertion (A): $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}_6\right)\right] \mathrm{Cl}_2$ and $\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_2$ are reducing in nature.

Reason (R): Unpaired electrons are present in their $d$-orbitals.

Which of the following carbonyls will have the strongest C – O bond

Assertion: The $\left[{Ni}({en})_3\right] {Cl}_2({en}=$ ethylene- diamine $)$ has lower stability than $\left[{Ni}\left({NH}_3\right)_6\right] {Cl}_2$.

Reason: In $\left[{Ni}({en})_3\right] {Cl}_2$, the geometry of ${Ni}$ is trigonal bipyramidal.

Statement I: Only cis $\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]$ react with oxalic acid $\left(\mathrm{H}_2 \mathrm{C}_2 \mathrm{O}_4\right)$ to form $\left[\mathrm{Pt} \mathrm{Cl}{ }_2(\mathrm{OX})\right]^{-2}$ not the trans isomer
Statement II: The oxalate ion is a bidentate ligand which occupies adjacent positions only

Assertion : Hexa chloroplatinate is a complex anion

Reason: Complex has negatively charged ligands

One mole of $\,Co{(N{H_3})_5}\,B{r_3}$ gives 3 moles of ions on dissolution in water. One mole of this reacts with two moles of $AgN{O_3}$ to give two moles of $AgBr.$ The complex is :

$\mathrm{CuS}{\mathrm{O}_4}$ decolourises on addition of KCN, the product is:

Which one is the most likely structure of $CrC{l_3}.6{H_2}O$ if 1/3 of total chlorine of the compound is precipitated by adding $AgN{O_3}$