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JEE • CHEMISTRY • CO-ORDINATION COMPOUNDS

Co-ordination compounds practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-326 of 326 questions
301 Medium
301 of 326
Analyzing +4 | -1
What will be the correct order for the wavelengths of absorption in the visible region of the following:
[Ni(NH3)6]2+A,Ni(CN)6]−4B,[Ni(H2O)6]+2C,[NiCl6]−4D\mathop {{{\left[ {{\text{Ni}}{{\left( {{\text{N}}{{\text{H}}_3}} \right)}_6}} \right]}^{2 + }}}\limits_{\text{A}} ,\mathop {{\text{Ni}}{{({\text{CN}})}_6}{]^{ - 4}}}\limits_{\text{B}} ,\mathop {{{\left[ {{\text{Ni}}{{\left( {{{\text{H}}_2}{\text{O}}} \right)}_6}} \right]}^{ + 2}}}\limits_{\text{C}} ,\mathop {{{\left[ {{\text{NiC}}{{\text{l}}_6}} \right]}^{ - 4}}}\limits_{\text{D}}
View answer and explanation
Correct option: B
D >> C >> A >> B
The correct answer is D (D >> C >> A >> B) because the spectrochemical series dictates that stronger field ligands cause larger splitting and absorb at shorter wavelengths (higher energy), so the order of ligand strength is Cl- < H2O < NH3 < CN-.
302 Medium
302 of 326
Remembering +4 | -1
According to spectrochemical series strongest field ligand among the following is
View answer and explanation
Correct option: A
NH3\mathrm{NH}_3
Option A (NH3\mathrm{NH}_3) is correct because, according to the spectrochemical series, ammonia (NH3\mathrm{NH}_3) is a stronger field ligand than water, fluoride, or bromide.
303 Easy
303 of 326
Remembering +4 | -1
K4[Fe(CN)6]{K}_4\left[{Fe}({CN})_6\right] is a :
View answer and explanation
Correct option: B
Complex compound
Option B (Complex compound) is correct because K4[Fe(CN)6]{K}_4\left[{Fe}({CN})_6\right] is a coordination complex, which does not fully dissociate into its constituent ions in solution.
304 Medium
304 of 326
Understanding +4 | -1
Which of the following has least conductivity in aqueous solution
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Correct option: B
CO(NH3)3Cl3CO{\left( {N{H_3}} \right)_3}C{l_3}
Option B is correct because CO(NH3)3Cl3CO(NH_3)_3Cl_3 does not ionize in aqueous solution, resulting in the least number of ions and therefore the lowest conductivity.
305 Hard
305 of 326
Analyzing +4 | -1
Assertion : In a mixture of Cd(II){\text{Cd(II)}} and Cu(II){\text{Cu(II)}}, (Cd+2){\text{(C}}{{\text{d}}^{ + 2}}{\text{)}} gets precipitated in presence of KCN\mathrm{KCN} by H2S.

Reason : The stability constant of [(Cu(CN)4]−3{\left[ {{\text{(Cu(CN}}{{\text{)}}_{\text{4}}}} \right]^{ - 3}} is greater than [(Cu(CN)4]−2{\left[ {{\text{(Cu(CN}}{{\text{)}}_{\text{4}}}} \right]^{ - 2}}
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because the formation of a stable complex with Cu(II) allows Cd(II) to precipitate as CdS.
306 Medium
306 of 326
Understanding +4 | -1
The splitting of the dd - orbitals of transition metals by a particular complex geometry gives rise to the pattern,

dxy‾  dyz‾  dxz‾ Energy ↑dx2−y2‾  dz2‾\begin{array}{r} \overline{d_{x y}}\,\,\overline{d_{y z}}\,\,\overline{d_{x z}} \\ \text { Energy } \uparrow \overline{d_{x^2-y^2}}\,\,\overline{d_{z^2}} \end{array}

Which one of the following geometries produces the above splitting pattern?
View answer and explanation
Correct option: D
Tetrahedral
Option D is correct because the splitting pattern with dxyd_{xy}, dyzd_{yz}, and dxzd_{xz} orbitals lower in energy than dx2−y2d_{x^2-y^2} and dz2d_{z^2} orbitals is characteristic of tetrahedral geometry.
307 Medium
307 of 326
Remembering +4 | -1
The correct order of ligands arranged in increasing field strength.
View answer and explanation
Correct option: C
Br−<F−<H2O<NH3\mathrm{Br}^{-}< \mathrm{F}^{-}< \mathrm{H}_2 \mathrm{O}< \mathrm{NH}_3
Option C (Br−<F−<H2O<NH3\mathrm{Br}^{-}< \mathrm{F}^{-}< \mathrm{H}_2 \mathrm{O}< \mathrm{NH}_3) is correct because it represents the correct order of ligands in the spectrochemical series, which arranges ligands by their ability to split d-orbitals.
308 Medium
308 of 326
Application +4 | -1
The number of isomers possible for square planar complex K2[PdClBr2SCN]{\mathrm{K}_2}\left[ {\mathrm{PdClB}{\mathrm{r}_2}\mathrm{SCN}} \right] is:
View answer and explanation
Correct option: C
4
Option C (4) is correct because there are geometrical isomers (cis and trans) and linkage isomers due to -SCN and -CNS.
309 Medium
309 of 326
Understanding +4 | -1
The number of ions formed when a molecule of K4Fe(CN)6{\mathrm{K}_4}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6} dissociates is:
View answer and explanation
Correct option: B
5
Option B is correct because K4Fe(CN)6{\mathrm{K}_4}\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6} dissociates into 4 K+ ions and one Fe(CN)64−\mathrm{Fe}{\left( {\mathrm{CN}} \right)_6}^{4 - } complex ion, totaling 5 ions.
310 Easy
310 of 326
Remembering +4 | -1
Potassium ferrocyanide is a
View answer and explanation
Correct option: A
Complex salt
Option A (Complex salt) is correct because potassium ferrocyanide contains a complex ion, [Fe(CN)6]4−[Fe(CN)_6]^{4-}, which does not dissociate into simple ions in solution.
311 Medium
311 of 326
Analyzing +4 | -1
Assertion: [Fe(CN)6]3−\left[{Fe}({CN})_6\right]^{3-} is weakly paramagnetic while [Fe(CN)6]4−\left[{Fe}({CN})_6\right]^{4-} is diamagnetic.

Reason: [Fe(CN)6]3−\left[{Fe}({CN})_6\right]^{3-} has +3 oxidation state while [Fe(CN)6]4−\left[{Fe}({CN})_6\right]^{4-} has +2 oxidation state.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
Option B is correct. Both Assertion and Reason are correct, but the Reason is not the correct explanation of the Assertion. The paramagnetic/diamagnetic nature depends on the presence of unpaired electrons, not directly on the oxidation state.
312 Medium
312 of 326
Analyzing +4 | -1
[Ma6]+2,[Mb6]+2,[Mc6]+2\left[M a_6\right]^{+2},\left[M b_6\right]^{+2},\left[M c_6\right]^{+2} and [Md6]+2\left[M d_6\right]^{+2} octahydral complex absorbs wavelengths in the region of red, green, blue and yellow respectively. What is the strongest ligand among a,b,ca, b, c and d\mathrm{d}.
View answer and explanation
Correct option: C
c\mathrm{c}
Option C is correct because blue light has the highest energy, indicating the strongest ligand field strength.
313 Medium
313 of 326
Remembering +4 | -1
Which of the following best describes the nature of FeSO4⋅(NH4)2SO4⋅6H2O\mathrm{FeSO}_4 \cdot\left(\mathrm{NH}_4\right)_2 \mathrm{SO}_4 \cdot 6 \mathrm{H}_2 \mathrm{O}
View answer and explanation
Correct option: B
Double salt
Option B is correct because FeSO4⋅(NH4)2SO4⋅6H2O\mathrm{FeSO}_4 \cdot(\mathrm{NH}_4)_2 \mathrm{SO}_4 \cdot 6 \mathrm{H}_2 \mathrm{O} (Mohr's salt) is a double salt that dissociates into its constituent ions in solution.
314 Easy
314 of 326
Understanding +4 | -1
A ligand can also be regarded as
View answer and explanation
Correct option: C
Lewis base
Option C (Lewis base) is correct because ligands donate electron pairs to the central metal atom/ion, which is the definition of a Lewis base.
315 Medium
315 of 326
Analyzing +4 | -1
Statement I: [Ni(CO)4]\left[\mathrm{Ni}(\mathrm{CO})_4\right] is diamagnetic in nature

Statement II: Nickel atom undergoes sp3\mathrm{sp}^3 hybridization
View answer and explanation
Correct option: B
Statement I and statement II are correct but statement II is not the correct explanation of statement I
Option B (Statement I and statement II are correct but statement II is not the correct explanation of statement I) is correct because both statements are true, but the diamagnetic nature is due to the strong field CO ligand causing pairing of electrons, not directly due to sp3 hybridization.
316 Easy
316 of 326
Understanding +4 | -1
Which among the following complexes can named "dichlorido-bis-(ethane-1, 2-diamine) platinum (IV) nitrate" ?
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Correct option: A
[PtCl2(en)2](NO3)2\left[{PtCl}_2({en})_2\right]\left({NO}_3\right)_2
Option A ([PtCl2(en)2](NO3)2\left[{PtCl}_2({en})_2\right]\left({NO}_3\right)_2) is correct because it accurately represents the given name, with platinum(IV), two chloride ligands, two ethylenediamine ligands, and two nitrate counterions.
317 Easy
317 of 326
Understanding +4 | -1
The number of geometrical isomers of [Co(NH3)3(NO2)3]\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_3}{{\left( {\mathrm{N}{\mathrm{O}_2}} \right)}_3}} \right] are:
View answer and explanation
Correct option: B
2
Option B (2) is correct because the complex can exist as cis and trans isomers.
318 Medium
318 of 326
Analyzing +4 | -1
The correct statements from following are:

A. The strength of anionic ligands can be explained by crystal field theory.

B. Valence bond theory does not give a quantitative interpretation of kinetic stability of coordination compounds.

C. The hybridization involved in formation of [Ni(CN)4]2−\left[\mathrm{Ni}(\mathrm{CN})_4\right]^{2-} complex is dsp 2{ }^2.

D. The number of possible isomer(s) of cis- [PtCl2(en)2]2+\left[\mathrm{PtCl}_2(\mathrm{en})_2\right]^{2+} is one

Choose the correct answer from the options given below:
View answer and explanation
Correct option: D
B, C only
Option D (B, C only) is correct because Valence Bond Theory doesn't give quantitative kinetic stability, and the hybridization of [Ni(CN)4]2- is dsp2.
319 Hard
319 of 326
Analyzing +4 | -1
Complex XX of composition Cr(H2O)6ClnCr{\left( {{H_2}O} \right)_6}C{l_n} has a spin only magnetic moment of 3.83 BM. It reacts with AgNO3AgN{O_3} and shows geometrical isomerism. The IUPAC nomenclature of XX is
View answer and explanation
Correct option: D
tetraaquadichlorido - chromium (III) chloride dihydrate
Option D is correct because the complex has a Cr³⁺ ion with 3 unpaired electrons, reacts with AgNO₃ indicating a Cl⁻ ion outside the coordination sphere, and exhibits geometrical isomerism, leading to the formula [Cr(H₂O)₄Cl₂]Cl·2H₂O.
320 Easy
320 of 326
Understanding +4 | -1
Which of the following is an organometallic compound?
View answer and explanation
Correct option: D
Ti(C2H5)4\mathrm{Ti}{\left( {{\mathrm{C}_2}{\mathrm{H}_5}} \right)_4}
Option D (Ti(C2H5)4\mathrm{Ti}{\left( {{\mathrm{C}_2}{\mathrm{H}_5}} \right)_4}) is correct because it contains a direct bond between the metal (Ti) and carbon (from the ethyl group).
321 Medium
321 of 326
Analyzing +4 | -1
Assertion: The geometrical isomers of the complex [M(NH3)4Cl2]\left[{M}\left({NH}_3\right)_4 {Cl}_2\right] are optically inactive.

Reason: Both geometrical isomers of the complex [M(NH3)4Cl2]\left[{M}\left({NH}_3\right)_4 {Cl}_2\right] posses axis of symmetry.
View answer and explanation
Correct option: A
Assertion is true, Reason is true and Reason is correct explanation for Assertion
Option A is correct because the geometrical isomers of [M(NH3)4Cl2] are optically inactive, and this is due to the presence of a plane or axis of symmetry in both isomers.
322 Hard
322 of 326
Understanding +4 | -1
Which of the following complexes are heteroleptic ?
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Correct option: B
[Fe(NH3)4Cl2]+\left[\mathrm{Fe}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]^{+}
Option B (Fe(NH3)4Cl2+\mathrm{Fe}(\mathrm{NH}_3)_4 \mathrm{Cl}_2^{+}) is correct because heteroleptic complexes contain more than one type of ligand.
323 Medium
323 of 326
Remembering +4 | -1
Which of the following sequence is correct regarding field strength of ligands as per spectrochemical series?
View answer and explanation
Correct option: A
SCN−<F−<CN−<CO{SCN}^{-} < {F}^{-} < {CN}^{-} < {CO}
Option A (SCN−<F−<CN−<CO{SCN}^{-} < {F}^{-} < {CN}^{-} < {CO}) is correct because it represents the correct increasing order of field strength according to the spectrochemical series.
324 Medium
324 of 326
Analyzing +4 | -1
Which of the following statements is not correct?
View answer and explanation
Correct option: A
In oxyhaemoglobin Fe2+\mathrm{F}{\mathrm{e}^{2 + }} is paramagnetic
Option A (In oxyhaemoglobin Fe2+\mathrm{F}{\mathrm{e}^{2 + }} is paramagnetic) is not correct because in oxyhaemoglobin, Fe2+Fe^{2+} is diamagnetic due to strong field ligands causing pairing of electrons.
325 Easy
325 of 326
Analyzing +4 | -1
Which statement is not correct in the case of [Co(NH3)6]3+{\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}} \right]^{3 + }} complex?
View answer and explanation
Correct option: B
It involves d2sp2{d^2}s{p^2} - hybridization
Option B is the correct answer because [Co(NH3)6]3+{\left[ {\mathrm{Co}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_6}} \right]^{3 + }} has a coordination number of 6, requiring six hybridized orbitals, hence d2sp3{d^2}s{p^3} hybridization, not d2sp2{d^2}s{p^2}.
326 Medium
326 of 326
Analyzing +4 | -1
Statement I: [Co(en)2(NH3)Br]SO4\left[\mathrm{Co}(\mathrm{en})_2\left(\mathrm{NH}_3\right) \mathrm{Br}\right] \mathrm{SO}_4 has lower electrical conductivity as compared to [Co(en)2(NH3)SO4]Br\left[\mathrm{Co}(\mathrm{en})_2\left(\mathrm{NH}_3\right) \mathrm{SO}_4\right] \mathrm{Br}

Statement II: Both the complexes produce the same number of ions in solution
View answer and explanation
Correct option: D
Statement I if false but statement II is correct
Option D (Statement I if false but statement II is correct) is correct because the electrical conductivity depends on the number and type of ions, and in this case, both complexes produce the same number of ions.
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