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JEE • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE

Chemical bonding & molecular structure practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-150 of 342 questions

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121 Medium

121 of 342

Analyzing +4 | -1

Assertion:

\mathrm{SO}_4^{-2}

is square planar in shape.

Reason :

\mathrm{SO}_4{ }^{-2}

has

\mathrm{sp}^3 \mathrm{d}

hybridisation.

View answer and explanation

Correct option: D

If both Assertion & Reason are false

Option D is correct because SO4^-2 is tetrahedral, not square planar, and it has sp3 hybridization, not sp3d.

122 Medium

122 of 342

Analyzing +4 | -1

Pick up the incorrect statement.

View answer and explanation

Correct option: D

{O}_2, {H}_2

show bond dipole due to polarisation.

Option D is correct because O2 and H2 are nonpolar molecules and do not exhibit bond dipoles due to polarization since they are composed of the same element.

123 Medium

123 of 342

Understanding +4 | -1

In which of the following, the bond length between hybridised carbon atom and other carbon atom is minimum?

View answer and explanation

Correct option: A

Propyne

Option A (Propyne) is correct because propyne contains a carbon-carbon triple bond, which has the shortest bond length compared to single or double bonds.

124 Medium

124 of 342

Analyzing +4 | -1

Which of the following two are isostructural?

View answer and explanation

Correct option: A

\mathrm{Xe}{\mathrm{F}_2},\mathrm{IF}_2^ -

Option A (

\mathrm{Xe}{\mathrm{F}_2},\mathrm{IF}_2^ -

) is correct because both molecules have a linear structure.

125 Medium

125 of 342

Analyzing +4 | -1

Which of the following species is not expected to exist

View answer and explanation

Correct option: C

\mathrm{Be}_2

Option C is correct because Be2 has a bond order of 0, indicating that it is not expected to exist.

126 Medium

126 of 342

Analyzing +4 | -1

Maximum bond angle at nitrogen is present in which of the following

View answer and explanation

Correct option: C

N{O_2}^ +

Option C (

N{O_2}^ +

) is correct because it has a linear structure with a bond angle of 180 degrees.

127 Medium

127 of 342

Analyzing +4 | -1

Polar molecule among the following is

View answer and explanation

Correct option: A

Xe{O_3}

Option A (

Xe{O_3}

) is correct because it has a non-zero dipole moment due to its pyramidal shape.

128 Medium

128 of 342

Understanding +4 | -1

Which one has highest melting point?

View answer and explanation

Correct option: C

{NaF}

Option C (NaF) is correct because the melting point of ionic compounds increases as the size of the ions decreases, and fluoride is the smallest halide.

129 Medium

129 of 342

Analyzing +4 | -1

For two ionic solids

CaO

and

KI

, identify the wrong statement among the following?

View answer and explanation

Correct option: D

KI

has high M.P

Option D (KI has high M.P) is the wrong statement because KI has a lower melting point compared to CaO due to weaker electrostatic forces.

130 Medium

130 of 342

Analyzing +4 | -1

Which of the following has lowest boiling point?

View answer and explanation

Correct option: C

\mathrm{CuC}{\mathrm{l}_2}

Option D (

\mathrm{CuC}{\mathrm{l}_2}

) is correct because, according to Fajan’s rule, smaller cation size and higher charge increase covalent character, lowering the boiling point.

131 Medium

131 of 342

Understanding +4 | -1

The compound possessing most strongly ionic nature is:

View answer and explanation

Correct option: D

\mathrm{CsCl}

Option D (CsCl) is correct because Cesium Chloride has the largest difference in electronegativity between the cation and anion, leading to the most ionic character.

132 Medium

132 of 342

Understanding +4 | -1

Which of the following has largest bond angle?

View answer and explanation

Correct option: A

C{H_4}\,

Option A (

C{H_4}\,

) is correct because

CH_4

has a tetrahedral geometry with bond angles of 109.5°, while

H_2O

and

NH_3

have bent and pyramidal geometries, respectively, due to the presence of lone pairs, which reduce the bond angles.

133 Medium

133 of 342

Understanding +4 | -1

In which compound, the hydrogen bonding is the strongest in its liquid phase

View answer and explanation

Correct option: A

{HF}

Option A (

{HF}

) is correct because fluorine is the most electronegative element and has a small size, leading to the strongest hydrogen bonding.

134 Medium

134 of 342

Remembering +4 | -1

Electron deficient species are known as:

View answer and explanation

Correct option: A

Lewis acids

Option A (Lewis acids) is correct because electron-deficient species can accept electron pairs and are therefore classified as Lewis acids.

135 Medium

135 of 342

Analyzing +4 | -1

Which of the following is the correct order of dipole moment?

View answer and explanation

Correct option: C

{PCl}_3 {F}_2 < {PF}_3 {Cl}_2

Option D is correct. The dipole moment of PF3Cl2 is non-zero, while PCl3F2 has a dipole moment of zero due to its symmetrical structure.

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136 Medium

136 of 342

Application +4 | -1

Which of the following species has four lone pairs in its outer shell?

View answer and explanation

Correct option: C

\mathrm{C}{\mathrm{l}^ - }

Option C (Cl-) is correct because it has 7 valence electrons plus 1 from the negative charge, resulting in 8 electrons or 4 lone pairs.

137 Medium

137 of 342

Understanding +4 | -1

Which one of the following arrangements shows the bonds

\mathrm{H}-\mathrm{H}, \mathrm{C}-\mathrm{C}

and

\mathrm{Si}-\mathrm{Si}

in order of increasing bond energy?

View answer and explanation

Correct option: A

\mathrm{Si}-\mathrm{Si}<\mathrm{C}-\mathrm{C}<\mathrm{H}-\mathrm{H}

The correct answer is A. Bond energy increases with decreasing atomic size, making Si-Si < C-C < H-H the correct order.

138 Medium

138 of 342

Analyzing +4 | -1

Which of the following statement is incorrect?

View answer and explanation

Correct option: A

Low solubility of LiF in water is due to its small hydration enthalpy.

Option A is correct. The low solubility of LiF in water is primarily due to its high lattice enthalpy, not small hydration enthalpy. While Li⁺ has high hydration enthalpy, the lattice enthalpy dominates.

139 Medium

139 of 342

Understanding +4 | -1

The correct increasing order off polarising power is:

View answer and explanation

Correct option: D

{\mathrm{K}^ + } < C{\mathrm{a}^{2 + }} < M{\mathrm{g}^{2 + }} < B{\mathrm{e}^{2 + }}

Option D (

{\mathrm{K}^ + } < C{\mathrm{a}^{2 + }} < M{\mathrm{g}^{2 + }} < B{\mathrm{e}^{2 + }}

) is correct because polarising power increases with increasing charge and decreasing size.

140 Medium

140 of 342

Analyzing +4 | -1

Find the pair that has the same bond order with diamagnetic and paramagnetic properties respectively

View answer and explanation

Correct option: C

L{i_2}\,\,\mathrm{and}\,\,{B_2}

The correct answer is C because Li2 has a bond order of 1 and is diamagnetic, while B2 has a bond order of 1 and is paramagnetic.

141 Medium

141 of 342

Understanding +4 | -1

The species analogous to paramagnetic behaviour like

{O}_2

View answer and explanation

Correct option: D

Gaseous sulphur.

Option D (Gaseous sulphur) is correct because gaseous sulfur exists as

S_2

, which has unpaired electrons similar to

O_2

, leading to paramagnetic behavior.

142 Medium

142 of 342

Analyzing +4 | -1

Arrange the following in order of increasing dipole moment (I) Toluene (II)

m

- dichlorobenzene (III)

o

- dichlorobenzene (IV)

p

- dichlorobenzene :

View answer and explanation

Correct option: B

IV < I < II < III

The correct answer is B (IV < I < II < III) because dipole moment increases as follows: para < toluene < meta < ortho due to vector addition of bond dipoles.

143 Medium

143 of 342

Remembering +4 | -1

Polarization of an anion is maximum by high charged cation

View answer and explanation

Correct option: A

Polarization of an anion is maximum by high charged cation

Option A (Polarization of an anion is maximum by high charged cation) is correct because, according to Fajans' rules, a higher charge on the cation increases the polarization of the anion.

144 Medium

144 of 342

Analyzing +4 | -1

Consider the following statements.

I. In

F_2

molecule

F - F\,\,\,\sigma - {\text{bond}}

is formed by axial overlapping of two p-orbitals.

II. In

O_2

molecule one

\sigma - {\text{bond}}

is formed by axial overlap of p-orbitals and one

\pi - {\text{bond}}

is formed by lateral overlap of p-orbitals.

III. In

N_2

molecule one

\sigma

and two

\pi - {\text{bonds,}}

i.e., all the three bonds are formed by lateral overlap of p-orbitals.

Which of the above statements are incorrect?

View answer and explanation

Correct option: C

Only III

Option C (Only III) is correct because in

N_2

molecule, one sigma bond is formed by axial overlap and two pi bonds are formed by lateral overlap of p-orbitals.

145 Medium

145 of 342

Analyzing +4 | -1

The bond order and magnetic property of acetylide ion are same as that of

View answer and explanation

Correct option: C

\mathrm{NO}^{+}

The correct answer is NO⁺ because both acetylide ion (C_2^2-) and NO⁺ have a bond order of 3 and are diamagnetic.

146 Medium

146 of 342

Understanding +4 | -1

Which of the following has maximum bond energy?

View answer and explanation

Correct option: A

\mathrm{C}{\mathrm{l}_2}

Option A (Cl2) is correct because, among the given halogens, Cl2 has the highest bond dissociation energy due to a balance between bond length and interelectronic repulsions.

147 Medium

147 of 342

Understanding +4 | -1

Carbon tetrachloride has no net dipole moment because of

View answer and explanation

Correct option: B

Its regular tetrahedral structure

Option B (Its regular tetrahedral structure) is correct because the symmetrical tetrahedral arrangement of CCl4 cancels out the individual bond dipoles, resulting in a net dipole moment of zero.

148 Medium

148 of 342

Analyzing +4 | -1

Assertion : p-nitrophenol is more volatile than o-nitrophenol.

Reason : Molecular wt. of p-nitrophenol is higher than o-nitrophenol.

View answer and explanation

Correct option: D

If both Assertion & Reason are false

Option D (If both Assertion & Reason are false) is correct because p-nitrophenol is less volatile than o-nitrophenol due to intermolecular hydrogen bonding, and their molecular weights are the same.

149 Medium

149 of 342

Understanding +4 | -1

The higher values of specific heat of water in comparison to other liquids is due to:

View answer and explanation

Correct option: C

H

-bonding

Option C (

H

-bonding) is correct because the extensive hydrogen bonding network in water requires a large amount of energy to break, leading to its high specific heat.

150 Medium

150 of 342

Understanding +4 | -1

The type of bonds present in

CuS{O_4}.5{H_2}O

are

View answer and explanation

Correct option: C

Electrovalent, covalent and coordinate

Option C (Electrovalent, covalent and coordinate) is correct because

CuSO_4.5H_2O

contains ionic bonds between Cu and

SO_4

, covalent bonds within the sulfate ion, and coordinate bonds between Cu and water ligands.

Revision notes and key takeaways

Review CHEMICAL BONDING & MOLECULAR STRUCTURE in your textbook or class notes, then use this set to check your understanding.

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