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JEE • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE
Chemical bonding & molecular structure practice · Medium
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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301
Medium
301 of 342
Analyzing
+4 | -1
For molecule, correct statement is
View answer and explanation
Correct option: C
Antibonding orbital will donate electron for the formation of
The correct answer is C because CO donates electrons from its bonding 2s orbital, not the antibonding.
302
Medium
302 of 342
Understanding
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In which of the following state of compound the magnitude of -bonding will be maximum and in which case it will be minimum ?
View answer and explanation
Correct option: C
Maximum Solid, Minimum Gas
Option C is correct because hydrogen bonding is strongest in the solid state due to the close proximity of molecules and weakest in the gaseous state due to large intermolecular distances.
303
Medium
303 of 342
Remembering
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Among the following, which is water insoluble?
View answer and explanation
Correct option: D
Magnesium fluoride
Option D (Magnesium fluoride) is correct because fluorides of alkaline earth metals like magnesium are generally insoluble in water.
304
Medium
304 of 342
Analyzing
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Assertion(A) All angles in are greater than but less than .
Reason(R) The lone pair-bond repulsion is weaker than bond pairbond repulsion.
Reason(R) The lone pair-bond repulsion is weaker than bond pairbond repulsion.
View answer and explanation
Correct option: C
If (A) is correct but (R) is incorrect.
The correct answer is C (If (A) is correct but (R) is incorrect) because the assertion about F-S-F angles in SF4 is true, but the reason regarding lone pair-bond pair repulsion is stated incorrectly.
305
Medium
305 of 342
Understanding
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Consider the following statements
I. The canonical forms have no real existence.
II. The molecule does not exist for a certain fraction of time in one canonical form and for other fractions of time in other canonical forms.
III. There is no such equilibrium between the canonical forms as we have between tautomeric forms (keto and enol) in tautomerism.
IV. The molecule such as has a single structure which is the resonance hybrid of the canonical forms and which cannot such as be depicted by a single Lewis structure.
Which of the above statements are correct?
I. The canonical forms have no real existence.
II. The molecule does not exist for a certain fraction of time in one canonical form and for other fractions of time in other canonical forms.
III. There is no such equilibrium between the canonical forms as we have between tautomeric forms (keto and enol) in tautomerism.
IV. The molecule such as has a single structure which is the resonance hybrid of the canonical forms and which cannot such as be depicted by a single Lewis structure.
Which of the above statements are correct?
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because all the statements accurately describe the nature of canonical forms and resonance hybrids.
306
Medium
306 of 342
Understanding
+4 | -1
Which of the following ion has maximum polarsing power.
View answer and explanation
Correct option: B
Option B () is correct because, according to Fajan's rule, a higher positive charge and smaller size of the cation lead to greater polarizing power.
307
Medium
307 of 342
Analyzing
+4 | -1
Which of the following has the minimum bond length?
View answer and explanation
Correct option: B
The correct answer is because it has the highest bond order (2.5) among the given options, leading to the shortest bond length.
308
Medium
308 of 342
Understanding
+4 | -1
Which of the following gives correct arrangement of compounds involved based on their bond strength
View answer and explanation
Correct option: A
Option A () is correct because bond strength decreases as the size of the halogen increases, with HF having the strongest bond due to fluorine's small size and high electronegativity.
309
Medium
309 of 342
Analyzing
+4 | -1
The d-orbital which is not involved in hybridization of central atom in :
View answer and explanation
Correct option: D
Option D () is correct because the hybridization of the central atom in is , which involves and orbitals, but not orbitals.
310
Medium
310 of 342
Analyzing
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Assertion : molecule is diamagnetic.
Reason : The highest occupied molecular orbital is of type.
Reason : The highest occupied molecular orbital is of type.
View answer and explanation
Correct option: D
If both the Assertion and Reason are incorrect.
Option D (If both the Assertion and Reason are incorrect) is correct because the molecule is paramagnetic due to unpaired electrons in the molecular orbitals.
311
Medium
311 of 342
Analyzing
+4 | -1
Which one of the following molecules has zero dipole moment?
View answer and explanation
Correct option: A
Option A () is correct because the individual bond dipoles cancel each other out due to the linear structure, resulting in a zero net dipole moment.
312
Medium
312 of 342
Understanding
+4 | -1
Which of the following boils at higher temperature?
View answer and explanation
Correct option: D
Option D () is correct because it is an ionic compound, and ionic compounds generally have higher boiling points than covalent compounds due to strong electrostatic forces.
313
Medium
313 of 342
Analyzing
+4 | -1
Select the correct statements regarding shapes of
View answer and explanation
Correct option: C
One of the given compound is square pyramidal
Option C is correct because has a square pyramidal shape, while is trigonal bipyramidal and is pentagonal bipyramidal.
314
Medium
314 of 342
Understanding
+4 | -1
Which of the following statements is true for an ion having hybridisation?
View answer and explanation
Correct option: D
-atoms are situated at the corners of tetrahedron
Option D is correct. An ion with sp3 hybridization has a tetrahedral geometry, with the H-atoms (or other atoms) situated at the corners of a tetrahedron.
315
Medium
315 of 342
Remembering
+4 | -1
The O-H bond distance in water molecule is:
View answer and explanation
Correct option: C
Option C () is correct because the O-H bond distance in a water molecule is an experimentally determined value close to 0.96 Angstroms.
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316
Medium
316 of 342
Analyzing
+4 | -1
The angle is maximum in :
View answer and explanation
Correct option: D
The correct answer is because it has a linear shape due to hybridization, resulting in a maximum ONO angle of 180 degrees.
317
Medium
317 of 342
Understanding
+4 | -1
Consider following statements.
(a) molecule does not exist.
(b) Energy of molecular orbital is always higher than that of and molecular orbital.
(c) The formation of molecular orbitals may be described by linear combination of atomic orbitals.
The correct statement(s) is/are
(a) molecule does not exist.
(b) Energy of molecular orbital is always higher than that of and molecular orbital.
(c) The formation of molecular orbitals may be described by linear combination of atomic orbitals.
The correct statement(s) is/are
View answer and explanation
Correct option: B
(a) and (c) only
Option B ((a) and (c) only) is correct because He2 molecule does not exist due to zero bond order, and molecular orbitals are formed by linear combination of atomic orbitals (LCAO).
318
Medium
318 of 342
Analyzing
+4 | -1
Common feature between and is that;
(I) both are isoelectronic.
(II) both have same bond order.
(III) both are paramagnetic.
(IV) both have unpaired, electron in same orbital.
(I) both are isoelectronic.
(II) both have same bond order.
(III) both are paramagnetic.
(IV) both have unpaired, electron in same orbital.
View answer and explanation
Correct option: C
II and III
Option C is correct because both N2+ and O2+ are paramagnetic and have the same bond order of 2.5.
319
Medium
319 of 342
Analyzing
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Assertion : Bond order of and is same.
Reason : and are isoelectron
Reason : and are isoelectron
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct. The assertion is true because both and have a bond order of 2.5. However, the reason is false because and are not isoelectronic.
320
Medium
320 of 342
Remembering
+4 | -1
How much energy is required to dissociate one mole of molecule?
View answer and explanation
Correct option: A
Option A () is correct because the bond dissociation energy for one mole of H2 is 435.8 kJ/mol.
321
Medium
321 of 342
Understanding
+4 | -1
The correct order of decreasing polarisability of ion is:
View answer and explanation
Correct option: C
Option C () is correct because polarizability increases with increasing size of the ion.
322
Medium
322 of 342
Analyzing
+4 | -1
In which of the given molecules only bonds are present?
View answer and explanation
Correct option: B
Option B is correct because the C2 molecule has only pi bonds and no sigma bonds.
323
Medium
323 of 342
Understanding
+4 | -1
Decreasing order of bond length is
(I) (II)
(III) (IV)
(I) (II)
(III) (IV)
View answer and explanation
Correct option: A
Option D (IV > III > I > II) is correct because single bonds are longer than double bonds, which are longer than triple bonds, and the bond length in benzene is intermediate between single and double bonds.
324
Medium
324 of 342
Analyzing
+4 | -1
Which one of the following molecules has the smallest bond angle?
View answer and explanation
Correct option: D
Option D () is correct because it has the smallest bond angle due to the increasing size of the central atom down the group, leading to decreased bond pair-bond pair repulsion.
325
Medium
325 of 342
Analyzing
+4 | -1
The compound with the maximum dipole moment among the following is:
View answer and explanation
Correct option: C
-dichlorobenzene
The correct answer is C (-dichlorobenzene) because the dipole moments of the C-Cl bonds add vectorially, resulting in a non-zero dipole moment.
326
Medium
326 of 342
Analyzing
+4 | -1
Arrange the following species in the correct order of their stability
View answer and explanation
Correct option: C
The correct answer is A because the stability of a molecule is directly proportional to its bond order, and the bond orders are He2+ (0.5) < Li2 (1) < C2 (2) < O2+ (2.5).
327
Medium
327 of 342
Analyzing
+4 | -1
Which has the lowest bond angle?
View answer and explanation
Correct option: A
Option A () is correct because the presence of a lone pair on the nitrogen atom in ammonia causes greater repulsion, leading to a smaller bond angle compared to the other molecules.
328
Medium
328 of 342
Analyzing
+4 | -1
The correct order of decreasing polarity is
View answer and explanation
Correct option: B
Option B () is correct because it reflects the decreasing order of polarity based on electronegativity differences and molecular geometry.
329
Medium
329 of 342
Analyzing
+4 | -1
Which of the following molecules are expected to exhibit intermolecular H – bonding
(i) Acetic acid (ii) o – nitro phenol
(iii) m – nitro phenol (iv) o –boric acid
Select the correct option
(i) Acetic acid (ii) o – nitro phenol
(iii) m – nitro phenol (iv) o –boric acid
Select the correct option
View answer and explanation
Correct option: C
i, iii and iv
Option C is correct because acetic acid, m-nitro phenol, and o-boric acid can form intermolecular hydrogen bonds, while o-nitro phenol forms intramolecular hydrogen bonds.
330
Medium
330 of 342
Understanding
+4 | -1
Which statement is wrong?
View answer and explanation
Correct option: D
-hybrid orbitals are directed towards the corners of a regular tetrahedron
Option D (-hybrid orbitals are directed towards the corners of a regular tetrahedron) is wrong because d2sp2 hybridization leads to square planar geometry, not tetrahedral.
Revision notes and key takeaways
Review CHEMICAL BONDING & MOLECULAR STRUCTURE in your textbook or class notes, then use this set to check your understanding.
Showing 301-330 of 342 questions
