${{\rm{N}}_2}$ and ${{\rm{O}}_2}$ are converted into ${\rm{N}}_2^ + $ and ${\rm{O}}_2^ + $ respectively. Which of the following is not correct?

In ${\rm{N}}_2^ + $, the $N{\rm{ }}--{\rm{ }}N$bond weakens

In ${\rm{O}}_2^ + $, $O{\rm{ }}--{\rm{ }}O$ bond order increases

In ${\rm{O}}_2^ + $,paramagnetism decreases

A compound contains $X,{\rm{ }}Y\,and\,Z$ atoms. The oxidation states of $X,{\rm{ }}Y\,and\,Z$ are $ + 2$, $ + 2$ and $ - 2$ respectively. The possible formula of the compound is

${Y_2}{\left( {X{Z_3}} \right)_2}$

${X_3}{\left( {{Y_4}Z} \right)_2}$

${X_3}{\left( {Y{Z_4}} \right)_3}$

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JEE • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE

Chemical bonding & molecular structure practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 342 questions

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271 Medium

271 of 342

Analyzing +4 | -1

Assertion :-

\mathrm{CH}_2=\mathrm{CH}-\mathrm{CH}=\mathrm{CH}_2

is a planar compuond.

Reason :- It has

9 \sigma

bonds and

2 \pi

bonds.

View answer and explanation

Correct option: B

If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion

The correct answer is B because both the assertion and reason are true, but the reason doesn't explain why the compound is planar.

272 Medium

272 of 342

Analyzing +4 | -1

In which of the following transitions, the bond order has increased and the magnetic behaviour has changed

View answer and explanation

Correct option: A

{C_2}^ + \to {C_2}

Option A (

{C_2}^ + \to {C_2}

) is correct because the bond order increases from 1.5 to 2, and the magnetic behavior changes from paramagnetic to diamagnetic.

273 Medium

273 of 342

Analyzing +4 | -1

In which of the following groups all the members have linear shape?

View answer and explanation

Correct option: B

{N}_3^{-}, {I}_3^{-}, {NO}_2^{+}

Option B is correct because N3-, I3-, and NO2+ all have a linear shape.

274 Medium

274 of 342

Analyzing +4 | -1

{\mathrm{N}_2}

and

{\mathrm{O}_2}

are converted into

\mathrm{N}_2^ +

and

\mathrm{O}_2^ +

respectively.
Which of the following is not correct?

View answer and explanation

Correct option: D

\mathrm{N}_2^ +

becomes diamagnetic

Option A (4) is correct because, based on general trends, four of the comparisons are correct concerning limiting molar conductivity.

275 Medium

275 of 342

Understanding +4 | -1

In which of the molecules, bond angle is maximum

View answer and explanation

Correct option: D

C{O_2}

Option D (

C{O_2}

) is correct because carbon dioxide has a linear structure with a bond angle of 180°, which is the maximum among the given molecules.

276 Medium

276 of 342

Analyzing +4 | -1

The correct order of decreasing dipole moment of

(I) toluene

(II) m-dichlorobenzene

(III) o-dichlorobenzene

(IV) P-dichlorobenzene

View answer and explanation

Correct option: B

<

<

<

III

Option B (IV

<

<

<

III) is correct because the dipole moment increases from para-dichlorobenzene (0) to toluene to meta-dichlorobenzene to ortho-dichlorobenzene.

277 Medium

277 of 342

Understanding +4 | -1

proton plays an important role in…bonding.

View answer and explanation

Correct option: D

Coordinate

Option D (Coordinate) is correct because a proton (H+) can accept a lone pair of electrons from a donor atom, which is the basis of coordinate bonding.

278 Medium

278 of 342

Analyzing +4 | -1

Statement I: According to molecular orbital theory

\mathrm{C}_2

molecules exist with bond order 2 .

Statement II:

\mathrm{C}_2

molecule has 8 electrons in bonding molecular orbitals and 2 pair of electrons in anti-bonding molecular orbitals.

View answer and explanation

Correct option: A

Statement I and Statement II both are correct.

Option A is correct. Statement I and Statement II both are correct about the C2 molecule and its bond order.

279 Medium

279 of 342

Analyzing +4 | -1

Assertion : p-nitrophenol is more viscous than o-nitrophenol.

Reason : In p-nitrophenol, intermolecular compound

\mathrm{H}

-bonding occurs.

View answer and explanation

Correct option: A

If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion

Option A is correct because p-nitrophenol exhibits intermolecular hydrogen bonding, leading to higher viscosity compared to o-nitrophenol.

280 Medium

280 of 342

Understanding +4 | -1

Considering x axis as the intermolecular axis, which of the following will not form sigma bond?

View answer and explanation

Correct option: D

\mathrm{2}{\mathrm{p}_y}\mathrm{ \,\,and\,\, 2}{\mathrm{p}_y}

Option D is correct. When the x-axis is the intermolecular axis,

2p_y

and

2p_y

orbitals will overlap sideways, forming a pi bond, not a sigma bond.

281 Medium

281 of 342

Remembering +4 | -1

The bond formed as a result of the electrostatic attraction between the positive and negative ions is termed as …

View answer and explanation

Correct option: B

Electrovalent bond

Option B (Electrovalent bond) is correct because electrovalent bonds are formed by the electrostatic attraction between positive and negative ions.

282 Medium

282 of 342

Application +4 | -1

A compound contains

X,\mathrm{ }Y\,and\,Z

atoms. The oxidation states of

X,\mathrm{ }Y\,and\,Z

are

+ 2

+ 2

and

- 2

respectively. The possible formula of the compound is

View answer and explanation

Correct option: A

XY{Z_2}

Option A (XYZ₂) is correct because the charges must balance in a neutral compound, and with X and Y having +2 and Z having -2, the formula XYZ₂ achieves this balance.

283 Medium

283 of 342

Understanding +4 | -1

Which of the following statement is correct?

View answer and explanation

Correct option: A

Polarization of an anion is maximum by high charged cation

Option A (Polarization of an anion is maximum by high charged cation) is correct because according to Fajans' rule, higher charge on the cation increases polarization.

284 Medium

284 of 342

Understanding +4 | -1

Which is not linear?

View answer and explanation

Correct option: D

{\mathrm{H}_2}\mathrm{O}

The correct answer is

{\mathrm{H}_2}\mathrm{O}

because it has a bent or V-shaped geometry due to the two lone pairs on the oxygen atom, while the others are linear.

285 Medium

285 of 342

Analyzing +4 | -1

Which of the following species has a bond order other than 3?

View answer and explanation

Correct option: D

\mathrm{O}_2^ +

The correct answer is D (O2+) because CO, CN-, and NO+ are isoelectronic, each having 14 electrons and a bond order of 3, while O2+ has 15 electrons and a bond order of 2.5.

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286 Medium

286 of 342

Analyzing +4 | -1

Which of the following is false?

View answer and explanation

Correct option: D

Acetylene is non-linear

Option D (Acetylene is non-linear) is correct because acetylene (

{\mathrm{C}_2}{\mathrm{H}_2}

) is a linear molecule due to

sp

hybridization of the carbon atoms.

287 Medium

287 of 342

Analyzing +4 | -1

Assertion (A) : The bond dissociation energy increases from

{F}_2

{Cl}_2

and then decreases to

{I}_2

Reason (R): The low bond energy of fluorine is due to the repulsion between the lone pairs of electrons in two fluorine atoms.

The correct option among the following is :

View answer and explanation

Correct option: A

(A) is true, (R) is true and (R) is the correct explanation for (A)

The correct answer is A ((A) is true, (R) is true and (R) is the correct explanation for (A)) because the bond dissociation energy trend and the reason for fluorine's low bond energy are both accurate and related.

288 Medium

288 of 342

Understanding +4 | -1

Which one of the following has not triangular pyramidal shape?

View answer and explanation

Correct option: D

\mathrm{BC}{\mathrm{l}_3}

Option D (

\mathrm{BC}{\mathrm{l}_3}

) is correct because it has a trigonal planar shape due to sp² hybridization, while the others have a triangular pyramidal shape due to sp³ hybridization with a lone pair.

289 Medium

289 of 342

Remembering +4 | -1

The bond length

({pm})

{F}_2, {H}_2, {Cl}_2

and

{I}_2

, respectively is

View answer and explanation

Correct option: A

144,74,199,267

Option A (

144, 74, 199, 267

) is correct because it represents the increasing trend of bond lengths down the halogen group due to increasing atomic size.

290 Medium

290 of 342

Understanding +4 | -1

Glycerol has strong intermolecular bonding therefore it is

View answer and explanation

Correct option: D

Viscous

Option D (Viscous) is correct because glycerol's strong intermolecular hydrogen bonding due to the presence of three -OH groups leads to high viscosity.

291 Medium

291 of 342

Analyzing +4 | -1

Among the interhalide species:

\mathrm{IF}_2^{\ominus}, \mathrm{IF}_3, \mathrm{IF}_4^{\ominus}

and

\mathrm{IF}_7

View answer and explanation

Correct option: C

The anionic species are both isoelectronic and isostructural to

\mathrm{XeF}_2

and

\mathrm{XeF}_4

Option C is correct because the anionic species IF2- and IF4- are isoelectronic and isostructural with XeF2 and XeF4, respectively.

292 Medium

292 of 342

Understanding +4 | -1

Which of the following compounds is a good conductor of electricity in solution state?

View answer and explanation

Correct option: D

ionic compounds

Option D (ionic compounds) is correct because ionic compounds dissociate into ions in solution, and these ions are charge carriers, making the solution conductive.

293 Medium

293 of 342

Analyzing +4 | -1

Which of the following order is correct :-

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because all the given boiling point/melting point orders are accurate due to factors like hydrogen bonding and increasing molecular weight.

294 Medium

294 of 342

Analyzing +4 | -1

Dipole moment is highest for:

View answer and explanation

Correct option: C

\mathrm{CH}{\mathrm{F}_3}

Option C (

\mathrm{CH}{\mathrm{F}_3}

) is correct because the C-F bond is significantly more polar than C-Cl, leading to a higher dipole moment for the molecule.

295 Medium

295 of 342

Analyzing +4 | -1

According to the molecular orbital theory which of the following statement is incorrect?
[LUMO = lowest unoccupied molecular orbital]

View answer and explanation

Correct option: D

{C}_2

is paramagnetic but

{C}_2^{2-}

is diamagnetic.

Option D (

{C}_2

is paramagnetic but

{C}_2^{2-}

is diamagnetic.) is incorrect because

{C}_2

is diamagnetic, not paramagnetic.

296 Medium

296 of 342

Understanding +4 | -1

The important condition(s) for Lewis dot structure of covalent compounds is/are

View answer and explanation

Correct option: D

All of the above

Option D (All of the above) is correct because all the listed statements are fundamental conditions for forming valid Lewis dot structures.

297 Medium

297 of 342

Analyzing +4 | -1

Which of the following is paramagnetic in nature?

View answer and explanation

Correct option: C

{B_2}

Option C (

{B_2}

) is correct because its molecular orbital configuration results in unpaired electrons, making it paramagnetic.

298 Medium

298 of 342

Analyzing +4 | -1

Select pair of compounds in which both have different hybridization but have same molecular geometry

View answer and explanation

Correct option: B

ICl_2^ - ,\,BeC{l_2}

Option B (

ICl_2^ - ,\,BeCl_2

) is correct because

ICl_2^-

has

sp^3d

hybridization and linear geometry, while

BeCl_2

has

sp

hybridization and linear geometry.

299 Medium

299 of 342

Understanding +4 | -1

Statement I : According to wave mechanics, the atomic orbitals can be expressed by wave functions which represent the magnitude of the electron waves. These are obtained from the solution of Schrodinger wave equation
Statement II : The magnitude of H-bonding depends on the physical state of the compound. It is maximum in the gaseous state and minimum in the solid state

View answer and explanation

Correct option: B

Both Statement I and II are incorrect

Option B (Both Statement I and II are incorrect) is correct because wave functions represent the probability of finding an electron, and H-bonding is strongest in the solid state.

300 Medium

300 of 342

Understanding +4 | -1

In compound

X

, all the bond angles are exactly

109^\circ 28\prime

X

is:

View answer and explanation

Correct option: C

Carbon tetrachloride

Option C (Carbon tetrachloride) is correct because it has a tetrahedral structure with all bond angles exactly

109^\circ 28\prime

due to its symmetrical arrangement.

Revision notes and key takeaways

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