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JEE • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE

Chemical bonding & molecular structure practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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301 Medium
301 of 494
Analyzing +4 | -1
In which of the following ionisation processes, the bond order has increased and the magnetic behaviour has changed
View answer and explanation
Correct option: B
NO→NO+NO \to N{O^ + }
Option B (NO→NO+NO \to N{O^ + }) is correct because the bond order increases from 2.5 to 3.0, and the magnetic behavior changes from paramagnetic to diamagnetic upon ionization.
302 Easy
302 of 494
Analyzing +4 | -1
Which of the following molecules has the maximum dipole moment
View answer and explanation
Correct option: C
NH3N{H_3}
Option C is correct because NH3 has the maximum dipole moment due to the additive nature of bond moments and the lone pair's contribution.
303 Hard
303 of 494
Analyzing +4 | -1
Barium ions, CN−\mathrm{CN}^{-}and Co+2\mathrm{Co}^{+2} form an ionic complex. If this complex is 75%75 \% ionized in aqueous solution with Vant Hoff factor(i) equal to four and paramagnetic moment is found to be 1.73BM1.73 \mathrm{BM} (due to spin only) then hybridization state of Co(II)\mathrm{Co}(\mathrm{II}) in the complex will be
View answer and explanation
Correct option: D
dsp3\mathrm{dsp}^3
Option D (dsp3\mathrm{dsp}^3) is correct because the complex formed is Ba3[Co(CN)5]2\mathrm{Ba}_3[\mathrm{Co}(\mathrm{CN})_5]_2 with one unpaired electron, leading to dsp3\mathrm{dsp}^3 hybridization.
304 Medium
304 of 494
Analyzing +4 | -1
Which among the following is/are paramagnetic in nature?
View answer and explanation
Correct option: D
Both (1) and (3)
Option D is correct because both B2B_2 and N2+N_2^+ have unpaired electrons in their molecular orbitals, making them paramagnetic.
305 Medium
305 of 494
Analyzing +4 | -1
Which amongst the following is incorrect statement?
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Correct option: C
O2+{O}_2^{+}ion is diamagnetic.
Option C is correct. O2+ is paramagnetic, not diamagnetic, because it has an unpaired electron in its molecular orbital configuration.
306 Medium
306 of 494
Understanding +4 | -1
Which of the following halogens has the highest bond energy
View answer and explanation
Correct option: B
Cl2Cl_2
The correct answer is B (Cl2Cl_2) because chlorine has the highest bond energy among the given halogens due to its smaller size and strong interatomic attraction.
307 Medium
307 of 494
Application +4 | -1
Two elements XX and YY have following electronic configuration
X=1s2 2s22p6  3s23p6  4s2X = 1{s^2}\,2{s^2}2{p^6}\,\,3{s^2}3{p^6}\,\,4{s^2}
Y=1s2 2s22p6  3s23p5 Y = 1{s^2}\,2{s^2}2{p^6}\,\,3{s^2}3{p^5}\,
The expected compound formed by combination of XX and YY will be expressed as
View answer and explanation
Correct option: A
XY2X{Y_2}
Option A (XY2X{Y_2}) is correct because X forms a +2 ion and Y forms a -1 ion, leading to the compound XY2.
308 Medium
308 of 494
Application +4 | -1
The bond order of CO\mathrm{CO} molecule on the basis of molecular orbital theory is:
View answer and explanation
Correct option: C
33
Option C (33) is correct because the bond order is calculated from the number of bonding and antibonding electrons in the molecular orbital configuration.
309 Medium
309 of 494
Analyzing +4 | -1
Some of the properties of the two species, NO3−\mathrm{NO}_3^ - and H3O+{\mathrm{H}_3}{\mathrm{O}^ + } are described below. Which one of them is correct?
View answer and explanation
Correct option: A
Dissimilar in hybridization for the central atom with different structure
Option A (x > y) is correct because the enthalpy of combustion of CH4 is more negative than that of CH3OH, indicating that more heat is released during the combustion of CH4.
310 Medium
310 of 494
Understanding +4 | -1
Which bond in a molecule of ethyl magnesium bromide is ionic in nature?
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Correct option: C
Mg−Br{Mg}-{Br} bond
Option C (Mg−Br{Mg}-{Br} bond) is correct because magnesium is a metal and bromine is a nonmetal, leading to a significant electronegativity difference and an ionic bond.
311 Easy
311 of 494
Remembering +4 | -1
The hybridisation state of carbon in fullerene is
View answer and explanation
Correct option: B
sp2s p^2
Option B (sp2s p^2) is correct because each carbon atom in fullerene is bonded to three other carbon atoms, resulting in sp2s p^2 hybridization.
312 Easy
312 of 494
Understanding +4 | -1
Which of the following statement is not true
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Correct option: C
HFHF is less polar than HBrHBr
Option C (HFHF is less polar than HBrHBr) is correct because the polarity of a bond increases with the electronegativity difference between the atoms, and F is more electronegative than Br.
313 Medium
313 of 494
Analyzing +4 | -1
Decreasing order of bond angle is
View answer and explanation
Correct option: A
BeCl2>NO2>SO2BeC{l_2} > N{O_2} > S{O_2}
Option A is correct because the bond angle decreases with increasing lone pair repulsion, and BeCl2 has no lone pairs, NO2 has one, and SO2 has one.
314 Medium
314 of 494
Analyzing +4 | -1
Bond order of N2+N_2^{+}and N2−N_2^{-}are same. Which relation is correct for N2+N_2^{+}and N2−?N_2^{-}?
View answer and explanation
Correct option: B
Bond energy of N2+>N_2^{+}> Bond energy of N2−N_2^{-}
Option B is correct because the bond energy of N2+N_2^+ is greater than the bond energy of N2−N_2^- due to the electron being removed from a bonding orbital in N2+N_2^+ and added to an antibonding orbital in N2−N_2^-.
315 Medium
315 of 494
Understanding +4 | -1
Which does not contain sigma bond:
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Correct option: C
B2B_2
Option C (B2B_2) is correct because the last molecular orbitals are π2px\pi 2 p x and π2py\pi 2 p y, which form only π\pi-bonds, and thus it does not contain a sigma bond.
316 Medium
316 of 494
Analyzing +4 | -1
Assertion : ClF3{ClF}_3 has T\mathrm{T}-shape structure.

Reason : It has two lone pair arrange at 180∘180^{\circ} (Angle).
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
The correct answer is C (If Assertion is True but the Reason is False) because ClF3{ClF}_3 does have a T-shape structure, but the two lone pairs are arranged in the equatorial positions to minimize repulsion, not at 180 degrees.
317 Medium
317 of 494
Analyzing +4 | -1
Which of the following is diamagnetic
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Correct option: D
None
Option D (None) is correct because oxygen molecule, boron molecule, and N2+ ion all have unpaired electrons, making them paramagnetic, not diamagnetic.
318 Medium
318 of 494
Remembering +4 | -1
The decreasing order of bond dissociation energies of C−C,C−H\mathrm{C}-\mathrm{C}, \mathrm{C}-\mathrm{H} and H−H\mathrm{H}-\mathrm{H} bonds in
View answer and explanation
Correct option: A
H−H>−C−H>−C−C−\mathrm{H}-\mathrm{H}>-\mathrm{C}-\mathrm{H}>-\mathrm{C}-\mathrm{C}-
Option A (H−H>−C−H>−C−C−\mathrm{H}-\mathrm{H}>-\mathrm{C}-\mathrm{H}>-\mathrm{C}-\mathrm{C}-) is correct because the bond dissociation energy is related to bond strength, and smaller atoms generally form stronger bonds.
319 Easy
319 of 494
Analyzing +4 | -1
Assertion: Hydrogen bonding is responsible for the unique properties of water, such as its high boiling point and density.

Reason: Hydrogen bonding is a type of intermolecular force that occurs between molecules containing polar covalent bonds, resulting in strong attractive forces.
View answer and explanation
Correct option: B
Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion
Option A is correct because both statements are correct, and Statement II correctly explains Statement I. Exothermic reactions can become spontaneous at low temperatures due to the decrease in entropy's influence.
320 Medium
320 of 494
Understanding +4 | -1
Assertion (A): The order of thermal stability of

Li2CO3<Na2CO3<K2CO3<Rb2CO3<Cs2CO3\mathrm{Li}_2 \mathrm{CO}_3< \mathrm{Na}_2 \mathrm{CO}_3< \mathrm{K}_2 \mathrm{CO}_3< \mathrm{Rb}_2 \mathrm{CO}_3< \mathrm{Cs}_2 \mathrm{CO}_3

Reason (R): As we go

Li2CO3→Na2CO3→ K2CO3→Rb2CO3→Cs2CO3\mathrm{Li}_2 \mathrm{CO}_3 \rightarrow \mathrm{Na}_2 \mathrm{CO}_3 \rightarrow \mathrm{~K}_2 \mathrm{CO}_3 \rightarrow \mathrm{Rb}_2 \mathrm{CO}_3 \rightarrow \mathrm{Cs}_2 \mathrm{CO}_3

ionic character of carbonates increases.
View answer and explanation
Correct option: A
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Option A is correct because both the assertion and the reason are true, and the reason correctly explains the assertion regarding the thermal stability of alkali metal carbonates.
321 Medium
321 of 494
Analyzing +4 | -1
Given below are two statements:

Assertion (A): Double bond in carbon molecule (C2)\left(C_2\right) is consist of two pi-bonds.

Reason (R): Due to presence of four electrons in two pi-molecular orbitals.

In the light of the above statements, choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: D
Both (A) and (R) are correct and (R) is the correct explanation of (A)
The correct answer is D (Both (A) and (R) are correct and (R) is the correct explanation of (A)) because the carbon molecule (C2C_2) indeed has a double bond consisting of two pi-bonds, which is due to the presence of four electrons in two pi-molecular orbitals.
322 Easy
322 of 494
Analyzing +4 | -1
Which of the following has the highest dipole moment
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Correct option: C
H2O{H_2}O
The correct answer is C (H2O) because water has a bent structure and two lone pairs, resulting in a significant dipole moment.
323 Easy
323 of 494
Understanding +4 | -1
HCl\mathrm{HCl} molecule in the vapour state is an example of:
View answer and explanation
Correct option: C
Polar covalent bond
Option C (Polar covalent bond) is correct because chlorine is more electronegative than hydrogen, resulting in an unequal sharing of electrons and a dipole moment.
324 Medium
324 of 494
Understanding +4 | -1
In which of the following hydrogen bond is present?
View answer and explanation
Correct option: B
Ice
Option B (Ice) is correct because hydrogen bonding is significant in ice due to the presence of hydrogen atoms bonded to highly electronegative oxygen atoms.
325 Easy
325 of 494
Understanding +4 | -1
The lowest bond order present in :
View answer and explanation
Correct option: B
He2\mathrm{He}_2
Option B (He2\mathrm{He}_2) is correct because it has a bond order of 0, which is the lowest among the given options.
326 Easy
326 of 494
Analyzing +4 | -1
Which of the following sets of species does not follow octet rule?
View answer and explanation
Correct option: C
AlCl3,BF3,PCl5,SF6\mathrm{AlCl}_3, \mathrm{BF}_3, \mathrm{PCl}_5, \mathrm{SF}_6
Option C is correct because AlCl3,BF3\mathrm{AlCl}_3, \mathrm{BF}_3 are electron deficient, and PCl5,SF6\mathrm{PCl}_5, \mathrm{SF}_6 have expanded octets.
327 Medium
327 of 494
Remembering +4 | -1
Dipole-dipole interaction energy between stationary polar molecules is proportional to
View answer and explanation
Correct option: C
1r3\frac{1}{{{r^3}}}
Option C (1r3\frac{1}{{{r^3}}}) is correct because the dipole-dipole interaction energy between stationary polar molecules is inversely proportional to the cube of the distance between them.
328 Medium
328 of 494
Analyzing +4 | -1
N2{\mathrm{N}_2} and O2{\mathrm{O}_2} are converted into monocations, N2+\mathrm{N}_2^ + and O2+\mathrm{O}_2^ + respectively. Which of the following is wrong?
View answer and explanation
Correct option: D
N2+\mathrm{N}_2^ + become diamagnetic
Option D (N2+\mathrm{N}_2^ + become diamagnetic) is wrong because the removal of an electron from N2N_2 (which is diamagnetic) results in N2+N_2^+ which is paramagnetic due to the presence of an unpaired electron.
329 Medium
329 of 494
Remembering +4 | -1
Which has the highest bond energy?
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Correct option: B
Triple bond
Option B (Triple bond) is correct because triple bonds have the highest bond energy due to the presence of three bonds between the atoms.
330 Easy
330 of 494
Analyzing +4 | -1
Which of the following has least bond energy?
View answer and explanation
Correct option: A
XeF2Xe{F_2}
Option A (XeF2Xe{F_2}) is correct because it has the least bond energy due to the weak interaction between Xenon and Fluorine.
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Review CHEMICAL BONDING & MOLECULAR STRUCTURE in your textbook or class notes, then use this set to check your understanding.

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