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JEE • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE

Chemical bonding & molecular structure practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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271 Medium
271 of 494
Understanding +4 | -1
The correct decreasing order of the boiling points of H2O,  HF{H_2}O,\,\,HF and NH3N{H_3} is
View answer and explanation
Correct option: A
H2O>HF>NH3{H_2}O > HF > N{H_3}
Option A is correct because water has the highest boiling point due to extensive hydrogen bonding, followed by HF, and then NH3.
272 Medium
272 of 494
Analyzing +4 | -1
Which of the following diatomic molecules would be stabilized by the removal of an electron?
View answer and explanation
Correct option: D
O2{\mathrm{O}_2}
Option D (O2{\mathrm{O}_2}) is correct because removing an electron from O2, which has electrons in antibonding orbitals, increases the bond order and stabilizes the molecule.
273 Medium
273 of 494
Analyzing +4 | -1
Read the following statements and choose the correct option. Here T stands for True and F stands for False statement.

(i) The smaller the size of the cation and the larger the size of the anion, the greater the covalent character of an ionic bond.

(ii) The smaller the charge on the cation, the greater the covalent character of the ionic bond.

(iii) For cations of the same size and charge, the one, with electronic configuration (n−1)dnns0(n-1) d^n n s^0, typical of transition metals, is more polarising than the one with a noble gas configuration, ns2np6n s^2 n p^6, typical of alkali and alkaline earth metal cations.
View answer and explanation
Correct option: C
TFT
Option C (TFT) is correct because the first statement is true, the second is false (covalent character increases with charge), and the third is true (transition metals are more polarizing).
274 Medium
274 of 494
Analyzing +4 | -1
Statement-1: The number of bonding electrons in N2N_2 and N2−N_2^{-}is same.

Statement-2: The bond order and bond length of N2+N_2{ }^{+} and N2−N_2^{-}are same.
View answer and explanation
Correct option: C
Statement-1 is true, statement-2 is false.
Statement-1 is true, statement-2 is false because while the bond order is the same for N2+N_2^+ and N2−N_2^-, their bond lengths are not necessarily the same due to differing electron configurations.
275 Medium
275 of 494
Understanding +4 | -1
Assertion : Ionic compounds tend to be non-volalite.

Reason : Inter ionic forces in these compounds are strong.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because ionic compounds are non-volatile due to strong interionic forces.
276 Medium
276 of 494
Understanding +4 | -1
Consider the following statements.
I. Bond enthalpy increases as bond order decreases
II. Bond length decreases as bond order increases
III. There is a effect of electronegativity on bond energy
Select the correct statement (s).
View answer and explanation
Correct option: B
II & III
Option B (II & III) is correct because bond length decreases with increasing bond order and electronegativity difference affects bond energy.
277 Medium
277 of 494
Analyzing +4 | -1
The correct order of increasing bond angles in the following species is:
View answer and explanation
Correct option: D
ClO2−<Cl2O<ClO2\mathrm{ClO}_2^ - < C{\mathrm{l}_2}\mathrm{O} < Cl{\mathrm{O}_2}
Option D (ClO2−<Cl2O<ClO2\mathrm{ClO}_2^ - < C{\mathrm{l}_2}\mathrm{O} < Cl{\mathrm{O}_2}) is correct because the bond angle depends on the number of lone pairs and the electronegativity of the surrounding atoms.
278 Medium
278 of 494
Understanding +4 | -1
Bond energy of Cl2,Br2{Cl}_2, {Br}_2 and I2{I}_2 follow the order
View answer and explanation
Correct option: A
Cl2>Br2>I2{Cl}_2>{Br}_2>{I}_2
Option A (Cl2>Br2>I2{Cl}_2>{Br}_2>{I}_2) is correct because bond energy decreases down the halogen group due to increasing atomic size and bond length.
279 Easy
279 of 494
Understanding +4 | -1
Among the bonds formed by a chlorine atom with atoms of hydrogen, chlorine, sodium and carbon, the strongest bond is formed between
View answer and explanation
Correct option: C
Na−Cl{Na}-{Cl}
Option C (Na−Cl{Na}-{Cl}) is correct because ionic bonds are generally stronger than covalent bonds, and Na−Cl{Na}-{Cl} is an ionic bond.
280 Medium
280 of 494
Analyzing +4 | -1
Statement-1: C2,F2,B2,N2{C}_2, {F}_2, {B}_2, {N}_2 are diamagnetic species
Statement-2: Species with unpaired electrons only in anti bonding orbitals are paramagnetic
View answer and explanation
Correct option: C
STATEMENT–1 is False, STATEMENT–2 is False
The correct answer is C (STATEMENT–1 is False, STATEMENT–2 is False) because both statements about the magnetic properties of the given species and the origin of paramagnetism are incorrect.
281 Hard
281 of 494
Analyzing +4 | -1
Statement-I: The geometry of C⊖H3\stackrel{\ominus}{\mathrm{C}} \mathrm{H}_3 is tetrahedral.

Statement-II: Carbon of C⊖H3\stackrel{\ominus}{\mathrm{C}} \mathrm{H}_3 is sp2\mathrm{sp}^2 hybridized.
View answer and explanation
Correct option: C
Statement I is correct, but Statement II is incorrect
Option C is correct because the geometry of C⊖H3\stackrel{\ominus}{\mathrm{C}} \mathrm{H}_3 is tetrahedral, indicating sp3sp^3 hybridization, not sp2sp^2.
282 Hard
282 of 494
Understanding +4 | -1
Which of the following shows minimum bond angle?
View answer and explanation
Correct option: D
H2Te{\mathrm{H}_2}\mathrm{Te}
Option D (H2Te{\mathrm{H}_2}\mathrm{Te}) is correct because as we go down the group, the electronegativity of the central atom decreases, leading to a smaller bond angle.
283 Medium
283 of 494
Understanding +4 | -1
In He2{He}_2, the electrons in bonding and antibonding orbitals are
View answer and explanation
Correct option: A
2,2
Option A (2,2) is correct because in He2{He}_2, there are 4 electrons, with 2 filling the bonding molecular orbital and 2 filling the antibonding molecular orbital.
284 Easy
284 of 494
Understanding +4 | -1
Which shows the least dipole moment?
View answer and explanation
Correct option: D
CCl4\mathrm{CC}{\mathrm{l}_4}
Option D (CCl4\mathrm{CC}{\mathrm{l}_4}) is correct because due to its symmetrical tetrahedral geometry, the bond dipoles cancel out, resulting in a zero dipole moment.
285 Medium
285 of 494
Analyzing +4 | -1
The pair of species having identical shape of both species:
View answer and explanation
Correct option: D
XeF2,CO2\mathrm{Xe}{\mathrm{F}_2},\mathrm{C}{\mathrm{O}_2}
Option D is correct. Both XeF2 and CO2 are linear molecules.
286 Medium
286 of 494
Analyzing +4 | -1
Which of the following is correct order of σ\sigma bond strength
I) 2S – 2S II) 2S – 2P III) 2P – 2P IV) 3S – 3S
View answer and explanation
Correct option: B
III > II > I > IV
Option B (III > II > I > IV) is correct because the sigma bond strength depends on the energy levels of the orbitals involved, with 2p-2p being the strongest and 3s-3s being the weakest.
287 Medium
287 of 494
Analyzing +4 | -1
Which of the following molecules does not possess a permanent electric dipole moment?
View answer and explanation
Correct option: D
CS2\mathrm{C}{\mathrm{S}_2}
Option D (CS2\mathrm{C}{\mathrm{S}_2}) is correct because it is a linear molecule with symmetrical bond dipoles that cancel each other out, resulting in a zero dipole moment.
288 Medium
288 of 494
Analyzing +4 | -1
Which of the following statements are correct?
(A) Both LiCl  and  MgCl2\mathrm{LiCl}\,\,\mathrm{and}\,\,\mathrm{MgC}{\mathrm{l}_\mathrm{2}} are soluble in ethanol.
(B) The oxides Li2O   and  MgO\mathrm{L}{\mathrm{i}_\mathrm{2}}\mathrm{O}\,\,\,\mathrm{and}\,\,\mathrm{MgO} combine with excess of oxygen to give superoxide.
(C) LiF\mathrm{LiF} is less soluble in water than other alkali metal fluorides.
(D) Li2O\mathrm{L}{\mathrm{i}_2}\mathrm{O} is more soluble in water than other alkali metal oxides.
Choose the most appropriate answer from the options given below:
View answer and explanation
Correct option: A
(A) and (C) only
Option A ((A) and (C) only) is correct because LiCl and MgCl₂ are soluble in ethanol due to their covalent nature, and LiF is less soluble in water due to its high lattice energy.
289 Hard
289 of 494
Analyzing +4 | -1
Choose the correct order
View answer and explanation
Correct option: B
CaCl2>CdCl2\mathrm{CaCl}_2 > \mathrm{CdCl}_2 (Melting point)
Option D (BeSO4 < MgSO4 (solubility)) is correct because the solubility of sulfates of group 2 elements decreases down the group due to decreasing hydration energy.
290 Medium
290 of 494
Analyzing +4 | -1
Among the following species, identify the isostructural pairs

NF3,NO3−,BF3,H3O+,HN3\mathrm{NF}_3, \mathrm{NO}_3^{-}, \mathrm{BF}_3, \mathrm{H}_3 \mathrm{O}^{+}, \mathrm{HN}_3
View answer and explanation
Correct option: C
[NF3,H3O+]\left[\mathrm{NF}_3, \mathrm{H}_3 \mathrm{O}^{+}\right]and [NO3−,BF3]\left[\mathrm{NO}_3^{-}, \mathrm{BF}_3\right]
The correct answer is C because NF3 and H3O+ are both pyramidal (sp3 hybridization), while NO3- and BF3 are trigonal planar (sp2 hybridization).
291 Easy
291 of 494
Understanding +4 | -1
According to MO theory
View answer and explanation
Correct option: A
O2+{O_2}^{^ + } is paramagnetic and B.O is greater than O2{O_2}
Option A (O2+{O_2}^{^ + } is paramagnetic and B.O is greater than O2{O_2}) is correct because O2+{O_2}^+ has an unpaired electron making it paramagnetic, and its bond order is 2.5, which is greater than the bond order of O2{O_2} (which is 2).
292 Medium
292 of 494
Understanding +4 | -1
Bond angles of NH3,PH3,AsH3\mathrm{N}{\mathrm{H}_3},\mathrm{P}{\mathrm{H}_3},\mathrm{As}{\mathrm{H}_3} and SbH3\mathrm{Sb}{\mathrm{H}_3} is in the order
View answer and explanation
Correct option: D
NH3>PH3>AsH3>SbH3\mathrm{N}{\mathrm{H}_3} > P{\mathrm{H}_3} > As{\mathrm{H}_3} > Sb{\mathrm{H}_3}
Option D (NH3>PH3>AsH3>SbH3\mathrm{N}{\mathrm{H}_3} > P{\mathrm{H}_3} > As{\mathrm{H}_3} > Sb{\mathrm{H}_3}) is correct because as the size of the central atom increases down the group, the bond angle decreases due to decreasing electronegativity and increasing bond length.
293 Medium
293 of 494
Understanding +4 | -1
Which of the following has the lowest bond angle?
View answer and explanation
Correct option: C
H2S{H}_2 {S}
Option C (H2S{H}_2 {S}) is correct because sulfur's larger size compared to oxygen leads to less repulsion between the bonding pairs, resulting in a smaller bond angle.
294 Hard
294 of 494
Understanding +4 | -1
The maximum possible number of hydrogen bonds is a H2O{\mathrm{H}_2}\mathrm{O} molecule can participate is
View answer and explanation
Correct option: D
4
Option D (4) is correct because each water molecule can form two hydrogen bonds through its two hydrogen atoms and accept two hydrogen bonds through its two lone pairs on the oxygen atom.
295 Easy
295 of 494
Analyzing +4 | -1
In which of the following processes, the bond order is decreased?
View answer and explanation
Correct option: A
CO+⟶CO\mathrm{CO}^{+} \longrightarrow \mathrm{CO}
Option A is correct. The bond order decreases when CO+ is converted to CO.
296 Medium
296 of 494
Understanding +4 | -1
The hybrid state of 1 and 3 carbon atoms in CH2=C=CH2C{H_2} = C = C{H_2}
View answer and explanation
Correct option: B
sp2s{p^2}
Option B (sp2s{p^2}) is correct because the terminal carbon atoms in allene (CH2=C=CH2C{H_2} = C = C{H_2}) are sp2s{p^2} hybridized.
297 Medium
297 of 494
Remembering +4 | -1
In a crystal cations and anions are held together by
View answer and explanation
Correct option: B
Electrostatic forces
Option B (Electrostatic forces) is correct because cations and anions in a crystal are held together by electrostatic forces of attraction.
298 Easy
298 of 494
Understanding +4 | -1
In the transition of Zn{Zn} atoms to Zn++{Zn}^{++}ions there is a decrease in the
View answer and explanation
Correct option: A
Number of valency electrons
Option A (Number of valency electrons) is correct because when Zn atoms transform to Zn++ ions, they lose two valence electrons.
299 Easy
299 of 494
Analyzing +4 | -1
Which species does not exhibit paramagnetism?
View answer and explanation
Correct option: C
CO{CO}
The correct answer is C (CO{CO}) because it has an even number of electrons and all molecular orbitals are filled, resulting in no unpaired electrons.
300 Medium
300 of 494
Remembering +4 | -1
Among the following the weakest one is
View answer and explanation
Correct option: C
Van der Waal's force
Option C (Van der Waal's force) is correct because Van der Waal's forces are the weakest intermolecular forces compared to metallic, ionic, and covalent bonds.
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