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JEE • CHEMISTRY • AMINES

Amines practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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121 Medium

121 of 132

Understanding +4 | -1

When aniline is heated with glacial acetic acid in presence of anhydrous

ZnC{l_2}

,the product is:

View answer and explanation

Correct option: B

Acetanilide

Option B (Acetanilide) is correct because aniline reacts with glacial acetic acid in the presence of anhydrous

ZnCl_2

to form acetanilide, which is an acetylation reaction.

122 Medium

122 of 132

Remembering +4 | -1

Urea is not used:

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Correct option: D

In purification of water

Option D (In purification of water) is correct because urea is primarily used as a fertilizer, in plastic manufacturing, and in medicines, but not for water purification.

123 Medium

123 of 132

Remembering +4 | -1

Aniline on treatment with bromine water gives

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Correct option: C

2,4,6-tribromoaniline

Option C (2,4,6-tribromoaniline) is correct because aniline is highly reactive and undergoes tribromination at the ortho and para positions when treated with bromine water.

124 Medium

124 of 132

Analyzing +4 | -1

Assertion: Aniline forms significant amount of meta derivative on nitration with con.

HNO_3

and Con.

H_2SO_4

Reason: The ortho and para positions in aniline is electron rich due to the activating nature of

-NH_2

group.

View answer and explanation

Correct option: B

Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion.

Option B is correct. Aniline does form meta derivatives during nitration, and the amino group is activating, but the reason isn't the direct explanation for meta substitution.

125 Easy

125 of 132

Understanding +4 | -1

Aniline is weaker base than ethylamine because:

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Correct option: A

Lone pair of electrons of N-atom is not freely available for coordination with a proton due to resonance than in ethylamine

Option A is correct because the lone pair of electrons on the nitrogen atom in aniline is delocalized into the benzene ring through resonance, making it less available for protonation compared to ethylamine.

126 Medium

126 of 132

Analyzing +4 | -1

Most basic among the following in aqueous medium is

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Correct option: C

\left(\mathrm{C}_2 \mathrm{H}_5\right)_2 \mathrm{NH}

Option C is correct because diethylamine

(\mathrm{C}_2 \mathrm{H}_5)_2 \mathrm{NH}

is the most basic among the given options in aqueous medium due to a combination of inductive effect and solvation effects.

127 Easy

127 of 132

Remembering +4 | -1

Hinsberg’s reagent is

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Correct option: C

{C_6}{H_5}S{O_2}Cl

Option C (

{C_6}{H_5}S{O_2}Cl

) is correct because Hinsberg’s reagent is benzene sulphonyl chloride, used to distinguish between primary, secondary, and tertiary amines.

128 Easy

128 of 132

Analyzing +4 | -1

Which one of the following is most basic?

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Correct option: D

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2}

Option D (

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2}

) is the most basic because the lone pair on the nitrogen is not delocalized into the benzene ring, making it more available for protonation.

129 Medium

129 of 132

Analyzing +4 | -1

Assertion: Tertiary amines have lower boiling point than corresponding secondary and primary amines.

Reason: Tertiary amines have higher intermolecular hydrogen bonding.

View answer and explanation

Correct option: C

Assertion is correct, but reason is wrong statement.

Option C is correct because the assertion is correct (tertiary amines have lower boiling points), but the reason is wrong (tertiary amines cannot form intermolecular hydrogen bonds).

130 Medium

130 of 132

Analyzing +4 | -1

Considering the basic strength of amines in aqueous solution, which one has the smallest

p{K_b}

value?

View answer and explanation

Correct option: A

{(C{H_3})_2}NH

Option A (

{(C{H_3})_2}NH

) is correct because secondary aliphatic amines generally have the smallest

pK_b

value (highest basicity) in aqueous solutions due to a combination of inductive effects and solvation.

131 Easy

131 of 132

Remembering +4 | -1

Schiff’s bases are formed when aniline is condensed with:

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Correct option: B

Aromatic aldehydes

Option B (Aromatic aldehydes) is correct because Schiff's bases are formed by the condensation reaction between primary amines (like aniline) and aldehydes (especially aromatic aldehydes).

132 Medium

132 of 132

Remembering +4 | -1

Which test is used for the presence of nitro group in nitrobenzene:

View answer and explanation

Correct option: B

Mullikan barker test

The correct answer is B (Mullikan barker test) because the Mullikan-Barker test is specifically used to detect the presence of a nitro group in organic compounds like nitrobenzene.

Revision notes and key takeaways

Review AMINES in your textbook or class notes, then use this set to check your understanding.

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Amines practice · Mixed difficulty

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