In the chemical reaction, ${\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_2}{\rm{N}}{{\rm{H}}_2} + {\rm{CHC}}{{\rm{I}}_3} + 3{\rm{KOH}} \to \left( A \right) + \left( B \right) + 3{{\rm{H}}_2}{\rm{O}}$ The compounds $\left( A \right)$ and $\left( B \right)$ are respectively

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{NC\;}}$ and $3{\rm{KCI}}$

${\rm{C}}{{\rm{H}}_3}{\rm{C}}{{\rm{H}}_2}{\rm{CON}}{{\rm{H}}_2}$ and $3{\rm{KCl}}$

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{NC}}$ and ${{\rm{K}}_2}{\rm{C}}{{\rm{O}}_3}$

${{\rm{C}}_2}{{\rm{H}}_5}{\rm{CN}}$ and $3{\rm{KCI}}$

In the reaction of (S) 2-phenylpropamide with ${\rm{NaBr}}/{{\rm{H}}_2}{\rm{O}}$ to give 1-phenylethylamine

There is inversion of configuration

A mixture of two products is obtained

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JEE • CHEMISTRY • AMINES

Amines practice · Easy

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Showing 1-30 of 41 questions

1 Easy

1 of 41

Analyzing +4 | -1

Assertion: The main product of reaction of alcoholic silver nitrite and ethyl bromide is nitroethane.

Reason: Silver nitrite is predominantly covalent compound.

View answer and explanation

Correct option: A

If both assertion and reason are true and reason is the correct explanation of assertion

Option A (

\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{3-}

- Diamagnetic) is the wrong match because

\left[\mathrm{Mn}(\mathrm{CN})_6\right]^{3-}

has two unpaired electrons and is therefore paramagnetic, not diamagnetic.

2 Easy

2 of 41

Remembering +4 | -1

Hofmann’s bromamide reaction is to convert

View answer and explanation

Correct option: C

Amide to amine

Option C (Amide to amine) is correct because Hofmann's bromamide reaction converts an amide to an amine with one less carbon atom.

3 Easy

3 of 41

Remembering +4 | -1

Gabriel phthalamide synthesis is used for preparation of :-

View answer and explanation

Correct option: A

{RNH}_2

Option A is correct because the Gabriel phthalamide synthesis is specifically used for the preparation of primary amines (RNH2).

4 Easy

4 of 41

Remembering +4 | -1

Elements found in explosive are:

View answer and explanation

Correct option: C

Both S and N

Option C (Both S and N) is correct because both sulfur and nitrogen are commonly found in explosive compounds, contributing to their explosive properties.

5 Easy

5 of 41

Understanding +4 | -1

In which reaction, nitrene is not the intermediate?

View answer and explanation

Correct option: D

Gabriel’s phthalimide

Option D (Gabriel’s phthalimide) is correct because the Gabriel phthalimide synthesis proceeds through a carbanion intermediate, not a nitrene.

6 Easy

6 of 41

Remembering +4 | -1

The reagent used for conversion of benzene diazonium chloride to benzene is:

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because

{\mathrm{H}_3}\mathrm{P}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{N}{\mathrm{a}_2}\mathrm{Sn}{\mathrm{O}_2} + \mathrm{NaOH}

, and

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}

can all reduce benzene diazonium chloride to benzene.

7 Easy

7 of 41

Understanding +4 | -1

Gas evolved during the reaction of sodium metal on ethyl amine is:

View answer and explanation

Correct option: C

{\mathrm{H}_2}

Option D (Both (A) and (R) are true but (R) is the correct explanation of (A).) is correct because Lithium salts are hydrated due to the high charge density and polarizing power of the small Li+ ion.

8 Easy

8 of 41

Analyzing +4 | -1

The basic strength order of the following in

\mathrm{H}_2 \mathrm{O}

\mathop {{\text{MeN}}{{\text{H}}_{\text{2}}}{\text{,}}}\limits_{{\text{(I)}}} \,\,\,\,\,\mathop {{\text{M}}{{\text{e}}_{\text{2}}}{\text{NH}}}\limits_{{\text{(II)}}} {\text{,}}\,\,\,\,\,\mathop {{\text{M}}{{\text{e}}_{\text{3}}}{\text{N}}}\limits_{{\text{(III)}}}

View answer and explanation

Correct option: A

>

>

III

Option B (II > I > III) is correct because the basic strength order in water is Me2NH > MeNH2 > Me3N due to the combined effects of solvation and steric hindrance.

9 Easy

9 of 41

Analyzing +4 | -1

When

\mathrm{NaN}{\mathrm{O}_2}

and dilute

\mathrm{HCl}

were added to an amine at

\mathrm{0}^\circ \mathrm{C}

, a colourless gas was evolved and an ionic compound is formed. The amine is

View answer and explanation

Correct option: B

An aromatic primary amine

Option B is correct because an aromatic primary amine reacts with NaNO2 and HCl at 0°C to form a diazonium salt, which is an ionic compound, and evolves nitrogen gas upon warming.

10 Easy

10 of 41

Understanding +4 | -1

In aqueous solutions, the basic strength of amines decreases in the order

View answer and explanation

Correct option: D

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{N}{\mathrm{H}_2} > \mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2} > {\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathrm{N}

Option D (

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{N}{\mathrm{H}_2} > \mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2} > {\left( {\mathrm{C}{\mathrm{H}_3}} \right)_3}\mathrm{N}

) is correct because in aqueous solutions, the basic strength of amines depends on the electron-donating effect and steric hindrance.

11 Easy

11 of 41

Analyzing +4 | -1

The basicity of compounds I, II, III and IV

\mathop {\mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2}}\limits_\mathrm{I} ,\,\,\,\mathop {{{\left( {\mathrm{C}{\mathrm{H}_3}} \right)}_2}\mathrm{NH}}\limits_{\mathrm{II}} ,\mathrm{\;}\,\,\mathop {{{\left( {\mathrm{C}{\mathrm{H}_3}} \right)}_3}\mathrm{N}}\limits_{\mathrm{III}} ,\mathrm{\;}\mathop {{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2}}\limits_{\mathrm{IV}}

varies in the order

View answer and explanation

Correct option: B

II > I > III > IV

Option B is correct because the basicity order is II > I > III > IV due to the combined effects of +I effect, steric hindrance, and the electron-withdrawing nature of the phenyl group.

12 Easy

12 of 41

Application +4 | -1

In the chemical reaction,

\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2} + \mathrm{CHC}{\mathrm{I}_3} + 3\mathrm{KOH} \to \left( A \right) + \left( B \right) + 3{\mathrm{H}_2}\mathrm{O}

The compounds

\left( A \right)

and

\left( B \right)

are respectively

View answer and explanation

Correct option: C

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{NC\;}

and

3\mathrm{KCI}

Option C (

{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{NC\;}

and

3\mathrm{KCI}

) is correct because this reaction is the carbylamine reaction, which produces an isocyanide and potassium chloride.

13 Easy

13 of 41

Analyzing +4 | -1

Which of the following statements is correct?

View answer and explanation

Correct option: B

Methylamine is a stronger base than aniline and ammonia

Option B (Methylamine is a stronger base than aniline and ammonia) is correct because alkylamines are generally stronger bases than ammonia due to the +I effect of the alkyl group, and aniline is a weaker base due to resonance.

14 Easy

14 of 41

Analyzing +4 | -1

Assertion (A) Gabriel phthalimide reaction can be used to prepare aryl and alkyl amines.

Reason (R) Both Aryl halides have same reactivity as alkyl halides towards nucleophilic substitution reactions.

View answer and explanation

Correct option: D

If both Assertion and Reason and false.

Option D is correct because Gabriel phthalimide reaction cannot be used to prepare aryl amines, and aryl halides are less reactive than alkyl halides in nucleophilic substitution.

15 Easy

15 of 41

Analyzing +4 | -1

Which can be used to distinguish

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{N}{\mathrm{H}_2}\,\mathrm{and}\,{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2}\,?

View answer and explanation

Correct option: A

Diazotisation followed with coupling with phenol

Option A is correct because diazotization followed by coupling with phenol will produce an orange-red dye with aniline (C6H5NH2), distinguishing it from benzylamine (C6H5CH2NH2).

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16 Easy

16 of 41

Understanding +4 | -1

Reaction of nitrous acid on

1^\circ

aliphatic amines in cold will give:

View answer and explanation

Correct option: B

An alcohol

Option B (An alcohol) is correct because primary aliphatic amines react with nitrous acid in cold conditions to form diazonium salts, which are unstable and decompose to form alcohols.

17 Easy

17 of 41

Analyzing +4 | -1

Benzyl amine cannot be prepared by

View answer and explanation

Correct option: D

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{NC}\mathop \to \limits^{\mathrm{\;LiAl}{\mathrm{H}_4}\mathrm{\;}}

Option D is correct because

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{NC}

on reduction with

{\mathrm{LiAl}{\mathrm{H}_4}}

gives a secondary amine, not benzyl amine.

18 Easy

18 of 41

Understanding +4 | -1

The correct order of the basic strength of methyl substituted amines in aqueous solution is:

View answer and explanation

Correct option: A

{(C{H_3})_2}NH\, > \,C{H_3}N{H_2}\, > \,{(C{H_3})_3}N

Option A ({(C{H_3})_2}NH > C{H_3}N{H_2} > {(C{H_3})_3}N) is correct because in aqueous solution, the basic strength order is secondary > primary > tertiary due to a combination of inductive effect, solvation, and steric hindrance.

19 Easy

19 of 41

Remembering +4 | -1

The reaction,

\mathrm{C}{\mathrm{H}_3}\mathrm{CN} + 4\mathrm{H}\mathop \to \limits^{\mathrm{Na}/{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}} \mathrm{\;C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2}

is called:

View answer and explanation

Correct option: B

Mendius reaction

Option B (Mendius reaction) is correct because the reduction of a cyanide to a primary amine using Na/C2H5OH is known as the Mendius reaction.

20 Easy

20 of 41

Understanding +4 | -1

Aliphatic amines are……basic than

\mathrm{N}{\mathrm{H}_3}

but aromatic amines are ……basic than

\mathrm{N}{\mathrm{H}_3}

View answer and explanation

Correct option: A

More, less

Option A (More, less) is correct because aliphatic amines are more basic than ammonia due to the +I effect of alkyl groups, while aromatic amines are less basic than ammonia due to resonance delocalization of the lone pair on nitrogen into the benzene ring.

21 Easy

21 of 41

Understanding +4 | -1

In the reaction,

R\mathrm{N}{\mathrm{H}_2}\mathop \to \limits^{\mathrm{HN}{\mathrm{O}_2}} A + B + C \uparrow ;C

View answer and explanation

Correct option: B

{\mathrm{N}_2}

Option B (

{\mathrm{N}_2}

) is correct because the reaction of a primary amine with nitrous acid produces nitrogen gas.

22 Easy

22 of 41

Remembering +4 | -1

The following turns brown on exposure to air and light

View answer and explanation

Correct option: C

Aniline

Option C (Aniline) is correct because aniline is known to turn brown upon exposure to air and light due to oxidation.

23 Easy

23 of 41

Analyzing +4 | -1

Which of the following is most basic in nature?

View answer and explanation

Correct option: C

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{NH}

Option C (

{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{NH}

) is the most basic because dialkyl amines are generally more basic than monoalkyl amines and ammonia due to the +I effect of the alkyl groups, and steric hindrance is not as significant as in trialkyl amines in aqueous solution.

24 Easy

24 of 41

Remembering +4 | -1

Mendius method of preparation of amines consists of:

View answer and explanation

Correct option: A

Catalytic reduction of alkyl cyanides

Option A (Catalytic reduction of alkyl cyanides) is correct because the Mendius method involves the reduction of alkyl cyanides to primary amines.

25 Easy

25 of 41

Understanding +4 | -1

Which one of the following methods is neither meant for the synthesis nor for separation of amines?

View answer and explanation

Correct option: B

Wurtz reaction

Option B (Wurtz reaction) is correct because the Wurtz reaction is used for the synthesis of alkanes, not amines, nor for their separation.

26 Easy

26 of 41

Analyzing +4 | -1

In the reaction of (S) 2-phenylpropamide with

\mathrm{NaBr}/{\mathrm{H}_2}\mathrm{O}

to give 1-phenylethylamine

View answer and explanation

Correct option: A

There is retention of configuration

Option B is correct because benzoic acid is more acidic than acetic acid due to resonance stabilization of the benzoate ion, and both are more acidic than phenol.

27 Easy

27 of 41

Analyzing +4 | -1

The basicity of the compounds in aqueous medium increases in the order

\mathop {C{H_3}N{H_2}}\limits_{\text{I}} ,\,\,\mathop {{{\left( {C{H_3}} \right)}_2}NH}\limits_{{\text{II}}} ,\,\,\mathop {{C_6}{H_5}N{H_2}}\limits_{{\text{III}}} ,\,\,\mathop {{{\left( {C{H_3}} \right)}_3}N}\limits_{{\text{IV}}}

View answer and explanation

Correct option: B

III

<

<

<

The correct answer is B (III < IV < I < II) because basicity in aqueous medium depends on the inductive effect and solvation effects of the alkyl groups, with steric hindrance also playing a role.

28 Easy

28 of 41

Analyzing +4 | -1

The weakest base among the following is

View answer and explanation

Correct option: B

aniline

Option B (aniline) is correct because the lone pair of electrons on the nitrogen atom in aniline is delocalized into the benzene ring, making it less available for protonation and thus a weaker base.

29 Easy

29 of 41

Application +4 | -1

A colourless, odourless and non-combustible gas is liberated when ethylamine reacts with:

View answer and explanation

Correct option: C

\mathrm{NaN}{\mathrm{O}_2} + \mathrm{HCl}

Option C (

\mathrm{NaN}{\mathrm{O}_2} + \mathrm{HCl}

) is correct because ethylamine reacts with nitrous acid (generated from

NaNO_2 + HCl

) to produce ethanol and nitrogen gas, which is colorless, odorless, and non-combustible.

30 Easy

30 of 41

Remembering +4 | -1

For carbylamine reaction. We need hot alcoholic

KOH

and

View answer and explanation

Correct option: A

Any primary amine & chloroform

Option A (Any primary amine & chloroform) is correct because the carbylamine reaction involves the reaction of a primary amine, chloroform, and a base like hot alcoholic KOH.

Revision notes and key takeaways

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Key Takeaways

✓ This set contains 41 single-correct-answer MCQs on AMINES.
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