Identify $X$ in the sequence, ${\rm{X}}\,\xrightarrow{{{\rm{HN}}{{\rm{O}}_{\rm{2}}}}}{{\rm{C}}_{\rm{3}}}{{\rm{H}}_{\rm{8}}}{\rm{O}}\,\xrightarrow[{{{\rm{H}}_{\rm{2}}}{\rm{S}}{{\rm{O}}_{\rm{4}}}}]{}\,{{\rm{C}}_{\rm{3}}}{{\rm{H}}_{\rm{6}}}{{\rm{O}}_{\rm{2}}}{\rm{:}}$

${\rm{C}}{{\rm{H}}_3} - {\rm{C}}{{\rm{H}}_2} - {\rm{C}}{{\rm{H}}_2} - {\rm{N}}{{\rm{H}}_2}$

${\rm{C}}{{\rm{H}}_3} - {\rm{NH}} - {\rm{C}}{{\rm{H}}_2} - {\rm{C}}{{\rm{H}}_3}$

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_3}{\rm{N}}$

$C{H_3}C{H_2}Cl\xrightarrow{{NaCN}}A\xrightarrow{{Ni/{H_2}}}B\xrightarrow[{{\rm{anhydrlde}}}]{{{\rm{acetic}} - }}C,\,C\,{\rm{is}}$

$C{H_3}\,C{H_2}\,C{H_2}\,N{H_2}$

$C{H_3}C{H_2}C{H_2}CO\,NHC{H_3}$

$C{H_3}C{H_2}C{H_2}CO\,NH\,COC{H_3}$

An aromatic amine $\left( A \right)$ was treated with alcoholic potash and another compound $\left( Y \right)$ when a foul smeling gas was formed with formula ${{\rm{C}}_6}{{\rm{H}}_5}{\rm{NC}}$. $\left( Y \right)$ was formed by reacting a compound $\left( Z \right)$ with ${\rm{C}}{{\rm{l}}_2}$ in the presence of slaked lime. Compound $\left( Z \right)$ is:

${\rm{C}}{{\rm{H}}_3}{\rm{COC}}{{\rm{H}}_3}$

${{\rm{C}}_6}{{\rm{H}}_5}{\rm{N}}{{\rm{H}}_2}{\rm{\;}}$

${\rm{C}}{{\rm{H}}_3}{\rm{OH}}$

${\rm{CHC}}{{\rm{l}}_3}{\rm{\;}}$

Back to AMINES

Your Progress

0 / 9 Answered

Correct

Incorrect

Accuracy

JEE • CHEMISTRY • AMINES

Amines practice · Hard

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →

1 Hard

1 of 9

Analyzing +4 | -1

Identify

X

in the sequence,

\mathrm{X}\,\xrightarrow{{\mathrm{HN}{\mathrm{O}_\mathrm{2}}}}{\mathrm{C}_\mathrm{3}}{\mathrm{H}_\mathrm{8}}\mathrm{O}\,\xrightarrow[{{\mathrm{H}_\mathrm{2}}\mathrm{S}{\mathrm{O}_\mathrm{4}}}]{}\,{\mathrm{C}_\mathrm{3}}{\mathrm{H}_\mathrm{6}}{\mathrm{O}_\mathrm{2}}\mathrm{:}

View answer and explanation

Correct option: B

\mathrm{C}{\mathrm{H}_3} - \mathrm{C}{\mathrm{H}_2} - \mathrm{C}{\mathrm{H}_2} - \mathrm{N}{\mathrm{H}_2}

Option B (

\mathrm{C}{\mathrm{H}_3} - \mathrm{C}{\mathrm{H}_2} - \mathrm{C}{\mathrm{H}_2} - \mathrm{N}{\mathrm{H}_2}

) is correct because it's a primary amine that reacts with

HNO_2

to form an alcohol, which then dehydrates to form an acid.

2 Hard

2 of 9

Analyzing +4 | -1

Assertion:-

{\text{H}} - \mathop {\text{C}}\limits_{\begin{array}{cccccccccccccccccccc} {||} \\ {\text{O}} \end{array}} - \mathop {\text{N}}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {{\text{C}}{{\text{H}}_{\text{3}}}} \end{array}} - {\text{C}}{{\text{H}}_{\text{3}}}

and

{\text{C}}{{\text{H}}_{\text{3}}} - \mathop {\text{C}}\limits_{\begin{array}{cccccccccccccccccccc} {||} \\ {\text{O}} \end{array}} - {\text{NH}} - {\text{C}}{{\text{H}}_{\text{3}}}

are metameres

Reason:-There is adjustment of

-\mathrm{CH}_2-

group in the molecule.

View answer and explanation

Correct option: D

If both Assertion & Reason are false

Option D is correct because both the assertion and the reason are false. The given compounds are not metamers, and the reason provided is not a valid explanation of metamerism.

3 Hard

3 of 9

Application +4 | -1

C{H_3}C{H_2}Cl\xrightarrow{{NaCN}}A\xrightarrow{{Ni/{H_2}}}B\xrightarrow[{\mathrm{anhydrlde}}]{{\mathrm{acetic} - }}C,\,C\,\mathrm{is}

View answer and explanation

Correct option: C

C{H_3}C{H_2}C{H_2}\,NH\,COC{H_3}

Option C (

C{H_3}C{H_2}C{H_2}\,NH\,COC{H_3}

) is correct because it represents the product of the given reaction sequence involving nucleophilic substitution, reduction, and acylation.

4 Hard

4 of 9

Application +4 | -1

The product formed in the reaction

n - hexanamide + \mathrm{B}{\mathrm{r}_2} + \mathrm{KOH,}

View answer and explanation

Correct option: D

pentanamine

Option D (pentanamine) is correct because the reaction is a Hofmann degradation, which converts an amide to an amine with one fewer carbon atom.

5 Hard

5 of 9

Analyzing +4 | -1

Under which of the following reaction conditions, aniline gives

p

-nitroderivative as the major product?

I. Acetyl chloride/pyridine followed by reaction with conc.

\mathrm{H}_2 \mathrm{SO}_4+

conc.

\mathrm{HNO}_3

.

II. Acetic anhydride/pyridine followed by conc.

\mathrm{H}_2 \mathrm{SO}_4+

conc.

\mathrm{HNO}_3

.

III. Dil.

\mathrm{HCl}

followed by reaction with conc.

\mathrm{H}_2 \mathrm{SO}_4+

conc.

\mathrm{HNO}_3

.

IV. Reaction with conc.

\mathrm{HNO}_3+

conc.

\mathrm{H}_2 \mathrm{SO}_4

View answer and explanation

Correct option: A

I and II

Option A (I and II) is correct because acetylation protects the amino group of aniline, directing the nitration to the para position.

6 Hard

6 of 9

Analyzing +4 | -1

An aromatic amine

\left( A \right)

was treated with alcoholic potash and another compound

\left( Y \right)

when a foul smeling gas was formed with formula

{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{NC}

\left( Y \right)

was formed by reacting a compound

\left( Z \right)

with

\mathrm{C}{\mathrm{l}_2}

in the presence of slaked lime. Compound

\left( Z \right)

is:

View answer and explanation

Correct option: C

\mathrm{C}{\mathrm{H}_3}\mathrm{COC}{\mathrm{H}_3}

The correct answer is C (

\mathrm{C}{\mathrm{H}_3}\mathrm{COC}{\mathrm{H}_3}

) because it leads to the formation of chloroform, which reacts with the amine to form phenyl isocyanide.

7 Hard

7 of 9

Remembering +4 | -1

Carcinogens are the products of the reaction between:

View answer and explanation

Correct option: A

{R_2}\mathrm{NH} + \mathrm{HN}{\mathrm{O}_2}

Option A (

{R_2}\mathrm{NH} + \mathrm{HN}{\mathrm{O}_2}

) is correct because secondary amines react with nitrous acid to form nitrosoamines, which are known carcinogens.

8 Hard

8 of 9

Analyzing +4 | -1

Assertion:- Acetamide on reaction with

\mathrm{KOH}

and bromine gives acetic acid.
Reason:- Bromine catalyses hydrolysis of acetamide,

View answer and explanation

Correct option: D

If both Assertion & reason are False

Option D (If both Assertion & reason are False) is correct because acetamide reacts with KOH and bromine to give methylamine (Hoffmann bromamide degradation), not acetic acid, and bromine does not catalyze the hydrolysis of acetamide.

9 Hard

9 of 9

Understanding +4 | -1

Assertion: Hoffmann's ammonolysis can be used to prepare pure primary amines.

Reason: Ammonolysis of haloalkanes lead to multiple substitution of alkyl groups on nitrogen.

View answer and explanation

Correct option: D

Assertion is wrong, but reason is correct statement.

The correct answer is D (Assertion is wrong, but reason is correct statement) because Hoffmann's ammonolysis does not yield pure primary amines due to multiple alkylation.

Revision notes and key takeaways

Review AMINES in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 9 single-correct-answer MCQs on AMINES.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

Continue Your Practice

📚 Switch Set (HARD)

Chapter Sets

ALL 132 MCQs EASY 41 MCQs HARD 9 MCQs MEDIUM 82 MCQs

0 /9

0✓ 0✗

0% Accuracy