JEE CHEMISTRY MCQ: AMINES

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Analyzing +4 | -1

The weakest base among the following is

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Correct option: B

aniline

Option B (aniline) is correct because the lone pair of electrons on the nitrogen atom in aniline is delocalized into the benzene ring, making it less available for protonation and thus a weaker base.

More Questions from AMINES

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Identify '

\mathrm{Z}

' in the sequence

{{\text{C}}_6}{{\text{H}}_5}{\text{N}}{{\text{H}}_2}\xrightarrow{{{\text{NaN}}{{\text{O}}_2} + {\text{HCl}}}}{\text{X}}\xrightarrow{{{\text{CuCN}}}}{\text{Y}}\xrightarrow{{{{\text{H}}^ + }/{{\text{H}}_2}{\text{O}}}}{\text{Z}}

The primary, secondary and tertiary amines can be distinguished by: Assertion: The main product of reaction of alcoholic silver nitrite and ethyl bromide is nitroethane.

Reason: Silver nitrite is predominantly covalent compound. Hofmann’s bromamide reaction is to convert Gabriel phthalamide synthesis is used for preparation of :- Elements found in explosive are: