Amines practice · Mixed difficulty

On hydrolysis of a "compound", two compounds are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollen's reagent and Fehling's solution. The "compound" is

The product formed in the reaction $n - hexanamide + \mathrm{B}{\mathrm{r}_2} + \mathrm{KOH,}$ is

Assertion (A) Gabriel phthalimide reaction can be used to prepare aryl and alkyl amines.

Reason (R) Both Aryl halides have same reactivity as alkyl halides towards nucleophilic substitution reactions.

Which can be used to distinguish ${\mathrm{C}_6}{\mathrm{H}_5}\mathrm{N}{\mathrm{H}_2}\,\mathrm{and}\,{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2}\,?$

Statement-1 : Nitrating mixture used for carrying out nitration of benzene consists of conc. ${HNO}_3+$ conc. ${H}_2 {SO}_4$.

Statement-2 : In presence of ${H}_2 {SO}_4, {HNO}_3$ acts as a base and produces ${NO}_2^{+}$ions.

The major product $P$ in the following reaction is
$C{H_3} - C{H_2}N{H_2}\xrightarrow[{0 - {5^\mathrm{o}}C}]{{NaN{o_2},\,\,HCl}}A\xrightarrow{{{H_2}O}}P(\mathrm{Major})$

Benzene diazonium chloride reacts with hypophosphor ous acid to produce

Select corerct statement(s).

Reaction of nitrous acid on $1^\circ$ aliphatic amines in cold will give:

$p -$chloro aniline and anilinium hydrogen chloride can be distinguished by

Benzyl amine cannot be prepared by

The correct order of the basic strength of methyl substituted amines in aqueous solution is:

The reaction, $\mathrm{ArN}_2^{+} \mathrm{Cl}^{-} \xrightarrow{\mathrm{Cu} / \mathrm{HCl}} \mathrm{ArCl}+\mathrm{N}_2+\mathrm{CuCl}$ is named as

Given below are two statements:

Statement I: Aniline reacts with con. $\mathrm{H}_2 \mathrm{SO}_4$, followed by heating at $453-473 \mathrm{~K}$ gives $\mathrm{p}-$ aminobenzene sulphonic acid, which gives blood red colour in the 'Lassaigne's test'.
Statement II: In Friedel-Craft's alkylation and acylation reactions, aniline forms salt with the $\mathrm{AlCl}_3$ catalyst. Due to this, nitrogen of aniline acquires a positive charge and acts as deactivating group.

In the light of the above statements, choose the correct answer from the options given below:

Statement I: In Sandmeyer reaction nucleophiles like ${Cl}^{-}, {Br}^{-}$and ${CN}^{-}$are introduced in benzene ring in the presence of ${Cu}^{+}$ ion.

Statement-II : In Gattermann rection nucleophiles are introduced in benzene ring in the presence of copper powder and $HCl.$

${\mathrm{C}_2}{\mathrm{H}_5}\mathrm{N}{\mathrm{H}_2}\mathop \to \limits^{\mathrm{HN}{\mathrm{O}_2}} A\mathop \to \limits^{\mathrm{PC}{\mathrm{I}_3}} B\mathop \to \limits^{\mathrm{N}{\mathrm{H}_3}} C$
Recognize the compound C from the following

The reaction, $\mathrm{C}{\mathrm{H}_3}\mathrm{CN} + 4\mathrm{H}\mathop \to \limits^{\mathrm{Na}/{\mathrm{C}_2}{\mathrm{H}_5}\mathrm{OH}} \mathrm{\;C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{N}{\mathrm{H}_2}$ is called:

Aliphatic amines are……basic than $\mathrm{N}{\mathrm{H}_3}$ but aromatic amines are ……basic than $\mathrm{N}{\mathrm{H}_3}$.

Arrange the following in increasing order of their basic strength?

p-nitroaniline (1); m-nitroaniline (2); 2,6-trimethylaniline(3); 3-methylanline(4).

In the reaction, $R\mathrm{N}{\mathrm{H}_2}\mathop \to \limits^{\mathrm{HN}{\mathrm{O}_2}} A + B + C \uparrow ;C$ is

When aniline is heated with benzaldehyde, the product is:

The following turns brown on exposure to air and light

Urotropine has the composition:

Which of the following is most basic in nature?

Under which of the following reaction conditions, aniline gives $p$-nitroderivative as the major product?

I. Acetyl chloride/pyridine followed by reaction with conc. $\mathrm{H}_2 \mathrm{SO}_4+$ conc. $\mathrm{HNO}_3$.

II. Acetic anhydride/pyridine followed by conc. $\mathrm{H}_2 \mathrm{SO}_4+$ conc. $\mathrm{HNO}_3$.

III. Dil. $\mathrm{HCl}$ followed by reaction with conc. $\mathrm{H}_2 \mathrm{SO}_4+$ conc. $\mathrm{HNO}_3$.

IV. Reaction with conc. $\mathrm{HNO}_3+$ conc. $\mathrm{H}_2 \mathrm{SO}_4$.

Assertion: Tert Butyl amine can be formed by Gabriel phthalimide synthesis

Reason: It follow $S_N1$ mechanism

Which one of the following does not react with Heinsberg reagent.

The discovery that shocked the vital force theory was:

Mendius method of preparation of amines consists of:

An aromatic amine $\left( A \right)$ was treated with alcoholic potash and another compound $\left( Y \right)$ when a foul smeling gas was formed with formula ${\mathrm{C}_6}{\mathrm{H}_5}\mathrm{NC}$. $\left( Y \right)$ was formed by reacting a compound $\left( Z \right)$ with $\mathrm{C}{\mathrm{l}_2}$ in the presence of slaked lime. Compound $\left( Z \right)$ is: