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JEE CHEMISTRY MCQ: AMINES
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Analyzing
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On hydrolysis of a "compound", two compounds are obtained. One of which on treatment with sodium nitrite and hydrochloric acid gives a product which does not respond to iodoform test. The second one reduces Tollen's reagent and Fehling's solution. The "compound" is
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Correct option: B
Option B (CH3CH2CH2NC) is correct because the hydrolysis of propyl isocyanide yields propylamine and formic acid. Propylamine, upon treatment with NaNO2 and HCl, gives propanol, which does not respond to the iodoform test. Formic acid reduces Tollen's reagent and Fehling's solution.
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The primary, secondary and tertiary amines can be distinguished by: Assertion: The main product of reaction of alcoholic silver nitrite and ethyl bromide is nitroethane.
Reason: Silver nitrite is predominantly covalent compound. Hofmann’s bromamide reaction is to convert Gabriel phthalamide synthesis is used for preparation of :- Elements found in explosive are:
The primary, secondary and tertiary amines can be distinguished by: Assertion: The main product of reaction of alcoholic silver nitrite and ethyl bromide is nitroethane.
Reason: Silver nitrite is predominantly covalent compound. Hofmann’s bromamide reaction is to convert Gabriel phthalamide synthesis is used for preparation of :- Elements found in explosive are: