Donate proton to form $\mathrm{H}_2 \mathrm{BO}_3^{-}$

Accept proton of form $\mathrm{H}_4 \mathrm{BO}_3^{+}$

Donate $\mathrm{OH}^{-}$to form $\mathrm{H}_2 \mathrm{BO}_2^{+}$

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JEE • CHEMISTRY • 13 TH GROUP ELEMENTS (P-BLOCK)

13 th group elements (p-block) practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-150 of 163 questions

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121 Medium

121 of 163

Understanding +4 | -1

The similarities among the trichlorides, tribromides and triiodides of all group-13 elements is/are that they are

View answer and explanation

Correct option: C

Both 1 and 2

Option C is correct. Trichlorides, tribromides, and triiodides of group-13 elements are covalent in nature and undergo hydrolysis in water.

122 Easy

122 of 163

Remembering +4 | -1

Which one is explosive?

View answer and explanation

Correct option: C

\mathrm{N}{\mathrm{H}_4}\mathrm{N}{\mathrm{O}_3} + \mathrm{Al}\;\mathrm{powder}

Option C (

\mathrm{N}{\mathrm{H}_4}\mathrm{N}{\mathrm{O}_3} + \mathrm{Al}\;\mathrm{powder}

) is correct because ammonium nitrate mixed with aluminum powder is a well-known explosive.

123 Medium

123 of 163

Remembering +4 | -1

The formula of potash alum is

View answer and explanation

Correct option: A

{\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4}\mathrm{.A}{\mathrm{l}_2}{\left( {\mathrm{S}{\mathrm{O}_4}} \right)_3}.24{\mathrm{H}_2}\mathrm{O}

Option A (

{\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4}\mathrm{.A}{\mathrm{l}_2}{\left( {\mathrm{S}{\mathrm{O}_4}} \right)_3}.24{\mathrm{H}_2}\mathrm{O}

) is correct because it represents the correct formula for potash alum, a double salt.

124 Medium

124 of 163

Remembering +4 | -1

Which compound can make fire proof clothes?

View answer and explanation

Correct option: A

Aluminium sulphate

Option A (Aluminium sulphate) is correct because aluminium sulphate is used in the treatment of fabrics to make them fire-resistant.

125 Medium

125 of 163

Remembering +4 | -1

For a good quality cement, the ratio of lime to the total of the oxides of

\mathrm{Si}, \mathrm{Al}

and

\mathrm{Fe}

should be as close as to

View answer and explanation

Correct option: C

Option C (2) is correct because the ideal ratio of lime to the total oxides of Si, Al, and Fe in good quality cement is approximately 2.

126 Medium

126 of 163

Analyzing +4 | -1

Assertion (A) :

{B}_2 {Cl}_4, {GaCl}_2, {GaS}

are diamagnetic.

Reason (R) : They show +2 oxidation state.

View answer and explanation

Correct option: B

Both

\mathbf{A}

and

\mathbf{R}

are true but

\mathbf{R}

is not the correct explanation of

\mathbf{A}

Option B (Both

\mathbf{A}

and

\mathbf{R}

are true but

\mathbf{R}

is not the correct explanation of

\mathbf{A}

) is correct because while both the assertion and reason are true, the +2 oxidation state is not the direct reason for diamagnetism.

127 Easy

127 of 163

Remembering +4 | -1

Borax is prepared by treating colemanite with:

View answer and explanation

Correct option: C

\mathrm{N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3}

Option C (

\mathrm{N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3}

) is correct because Borax is prepared by treating colemanite with sodium carbonate.

128 Easy

128 of 163

Remembering +4 | -1

Which member of group 13 is liquid at

30^\circ C

View answer and explanation

Correct option: C

Option C (Ga) is correct because Gallium (Ga) has a melting point of 29.8°C, making it liquid at 30°C.

129 Medium

129 of 163

Understanding +4 | -1

In which of the following reactions, diborane is not formed?

View answer and explanation

Correct option: D

\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7+\mathrm{HCl}+\mathrm{H}_2 \mathrm{O} \longrightarrow

Option D (

\mathrm{Na}_2 \mathrm{~B}_4 \mathrm{O}_7+\mathrm{HCl}+\mathrm{H}_2 \mathrm{O} \longrightarrow

) is correct because this reaction forms boric acid, not diborane.

130 Medium

130 of 163

Remembering +4 | -1

The industrial scale production of diborane involves the reaction of

\mathrm{BF}_3

with

View answer and explanation

Correct option: B

sodium hydride

Option B (sodium hydride) is correct because the industrial production of diborane involves the reaction of BF3 with sodium hydride.

131 Medium

131 of 163

Remembering +4 | -1

Which of the following element is the most abundant metal and the third most abundant element in the earth's crust?

View answer and explanation

Correct option: A

\mathrm{Al}

Option A (

\mathrm{Al}

) is correct because aluminum is the most abundant metal and the third most abundant element in the Earth's crust.

132 Easy

132 of 163

Remembering +4 | -1

Which of the following is non-metallic?

View answer and explanation

Correct option: A

Option A (B) is correct because Boron (B) is a metalloid, which exhibits properties of both metals and non-metals, and is generally classified as a non-metal.

133 Medium

133 of 163

Analyzing +4 | -1

An inorganic compound containing

\left(3 c-2 e^{-}\right)

and

\left(2 c-2 e^{-}\right)

bonds when reacts with

\mathrm{NH}_3

, at a certain temperature, gives a compound '

X

' which is isostructural with benzene and when reacts at high temperature forms a substance

Y

'. The substance '

Y

' is

View answer and explanation

Correct option: A

\mathrm{B}_2 \mathrm{H}_6

Option B (

\mathrm{N}{\mathrm{a}_2}{\mathrm{O}_2}

) is correct because the oxygen in sodium peroxide has an oxidation state of -1, which can be both oxidized and reduced.

134 Easy

134 of 163

Remembering +4 | -1

Borax on heating with cobalt oxide forms a blue bead of:

View answer and explanation

Correct option: A

\mathrm{Co}{\left( {\mathrm{B}{\mathrm{O}_2}} \right)_2}

Option A (

\mathrm{Co}{\left( {\mathrm{B}{\mathrm{O}_2}} \right)_2}

) is correct because cobalt oxide reacts with boron trioxide to form cobalt metaborate, which has a blue color.

135 Medium

135 of 163

Understanding +4 | -1

The type of hybridisation in diborane is:

View answer and explanation

Correct option: B

s p^3

Option B (

sp^3

) is correct because in diborane, each boron atom is

sp^3

hybridized.

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136 Easy

136 of 163

Remembering +4 | -1

An acid among the following is:

View answer and explanation

Correct option: A

\mathrm{B}{\left( {\mathrm{OH}} \right)_3}

Option A (

\mathrm{B}{\left( {\mathrm{OH}} \right)_3}

) is correct because Boric acid,

\mathrm{B}{\left( {\mathrm{OH}} \right)_3}

, acts as a Lewis acid by accepting a hydroxide ion.

137 Medium

137 of 163

Remembering +4 | -1

Alum is not used:

View answer and explanation

Correct option: B

As an insecticide

Option B (As an insecticide) is correct because Alum is not used as an insecticide; it is primarily used as a mordant in dyeing, in water purification, and in leather tanning.

138 Medium

138 of 163

Analyzing +4 | -1

Assertion (A): In bivalent state, most of the halides of group 13 elements are hydrolysed in water.

Reason (R): These are covalent in nature.

View answer and explanation

Correct option: D

\mathrm{A}

is incorrect;

\mathrm{R}

is correct.

Option C (Work function of

B

1.20 \mathrm{~eV}

) is incorrect because the work function of B is calculated to be 4.2 eV based on the given conditions.

139 Medium

139 of 163

Analyzing +4 | -1

Which does not exist?

View answer and explanation

Correct option: A

{\mathrm{B}^{3 + }}

The correct answer is A (B3+) because boron's high ionization energy and small size make it extremely unlikely to form a stable B3+ ion.

140 Easy

140 of 163

Analyzing +4 | -1

Assertion: Silicon forms stable hydrides, whereas boron does not.

Reason: Boron has a lower electronegativity than silicon.

View answer and explanation

Correct option: A

Both Assertion and Reason are true and Reason is the correct explanation for Assertion

The correct answer is A because boron's lower electronegativity compared to silicon makes it difficult to form stable hydrides.

141 Medium

141 of 163

Remembering +4 | -1

Aluminium reacts with caustic soda to form

View answer and explanation

Correct option: C

Sodium meta-aluminate

Option C (Sodium meta-aluminate) is correct because aluminium reacts with caustic soda (NaOH) to form sodium meta-aluminate (

NaAlO_2

) and hydrogen gas.

142 Easy

142 of 163

Analyzing +4 | -1

Which of the following is not a protonic and?

View answer and explanation

Correct option: A

\mathrm{B}(\mathrm{OH})_3

Option A is correct.

\mathrm{B(OH)_3}

is a Lewis acid, not a protonic acid. It accepts a hydroxide ion from water, releasing a proton.

143 Medium

143 of 163

Remembering +4 | -1

Nickeloy is an alloy containing:

View answer and explanation

Correct option: C

\mathrm{Ni} + \mathrm{Al} + \mathrm{Cu}

Option C (

\mathrm{Ni} + \mathrm{Al} + \mathrm{Cu}

) is correct because Nickeloy is an alloy composed of Nickel, Aluminum, and Copper.

144 Medium

144 of 163

Remembering +4 | -1

The salt used for performing bead test in qualitative inorganic analysis is:

View answer and explanation

Correct option: C

{Na}\left({NH}_4\right) {HPO}_4 \cdot 4 {H}_2 {O}

Option C (

{Na}\left({NH}_4\right) {HPO}_4 \cdot 4 {H}_2 {O}

) is correct because microcosmic salt, which is sodium ammonium hydrogen phosphate, is used in the bead test.

145 Easy

145 of 163

Understanding +4 | -1

Assertion: Boron and silicon exhibit a diagonal relationship.

Reason: Boron and silicon have similar atomic radii.

View answer and explanation

Correct option: A

Both Assertion and Reason are true and Reason is the correct explanation for Assertion

Option A is correct because both the assertion and the reason are true, and the reason correctly explains the assertion about the diagonal relationship between Boron and Silicon.

146 Hard

146 of 163

Understanding +4 | -1

The structure of diborane

\left(B_2 H_6\right)

contains '

x

' number of

2 {c}-2 {e}

bonds and '

{y}

' number of

3 c-2 e^{-}

bonds and then calculate the value of

x^2-y^3

View answer and explanation

Correct option: A

Option A (8) is correct because diborane has 4 two-center-two-electron bonds and 2 three-center-two-electron bonds, leading to x² - y³ = 4² - 2³ = 8.

147 Medium

147 of 163

Understanding +4 | -1

Orthoboric acid

View answer and explanation

Correct option: D

\mathrm{OH}^{-}

to form

\left[\mathrm{B}(\mathrm{OH})_4\right]^-

Option D (Accept

\mathrm{OH}^{-}

to form

\left[\mathrm{B}(\mathrm{OH})_4\right]^-

) is correct because orthoboric acid acts as a Lewis acid, accepting a hydroxide ion to form the tetrahydroxyborate(1-) ion.

148 Medium

148 of 163

Understanding +4 | -1

\left[{Al}\left({H}_2{O}\right)_6\right]^{3+}

ion, the hybridisation state of

{Al}

and the shape of the ion respectively are

View answer and explanation

Correct option: C

{sp}^3{d}^2

, octahedral

Option C (

{sp}^3{d}^2

, octahedral) is correct because the aluminum ion is surrounded by six water ligands, resulting in

sp^3d^2

hybridization and an octahedral geometry.

149 Medium

149 of 163

Remembering +4 | -1

Thermite is a mixture of

View answer and explanation

Correct option: B

\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} + \mathrm{Al}

Option B (

\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} + \mathrm{Al}

) is correct because thermite is a mixture of iron(III) oxide and aluminum.

150 Medium

150 of 163

Analyzing +4 | -1

\mathrm{BF}_3+\mathrm{LiAlH}_4 \stackrel{\text { Ether }}{\longrightarrow} \mathrm{X}+\mathrm{LiF}+\mathrm{AlF}_3

. Which of the following is incorrect about

\mathrm{X}

View answer and explanation

Correct option: C

Vacant orbital is not involved in bonding

The incorrect statement is C (Vacant orbital is not involved in bonding) because diborane (B2H6) has vacant orbitals involved in banana bond formation.

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