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JEE • CHEMISTRY • 13 TH GROUP ELEMENTS (P-BLOCK)

13 th group elements (p-block) practice · Mixed difficulty

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Showing 151-163 of 163 questions
151 Easy
151 of 163
Understanding +4 | -1
Which of the following is ionic.
View answer and explanation
Correct option: A
AlF3Al{F_3}
Option A (AlF3Al{F_3}) is correct because the electronegativity difference between Al and F is large enough to form an ionic bond, while the other options have more covalent character.
152 Medium
152 of 163
Understanding +4 | -1
Which among the following statements are correct?
(i)Carbon monoxide is neutral whereas SO3S{O_3} is acidic.
(ii)Potassium oxide is basic whereas nitrous oxide is acidic.
(iii) Aluminium and zinc oxides are amphoteric.
(iv) Sulphur trioxide is acidic whereas phosphorus pentoxide is basic.
(v) Carbon dioxide is neutal whereas sulphur dioxide is amphoteric
View answer and explanation
Correct option: C
(i) and (iii)
Option C ((i) and (iii)) is correct because carbon monoxide is neutral, sulfur trioxide is acidic, and aluminum and zinc oxides are amphoteric.
153 Medium
153 of 163
Understanding +4 | -1
Statement-I:Most of the AlCl3Al{Cl}_3 is dimerised through halogen bridging, Al2Cl6{Al}_2 {Cl}_6

Statement-II: AlCl3{AlCl}_3 complete its octet by accepting electrons from halogen in halogen bridged molecules, Al2Cl6{Al}_2 {Cl}_6
View answer and explanation
Correct option: A
Both I and II are correct
Option A (Both I and II are correct) is correct because AlCl3AlCl_3 dimerizes to form Al2Cl6Al_2Cl_6 through halogen bridging, which allows aluminum to complete its octet.
154 Medium
154 of 163
Analyzing +4 | -1
Assertion (A): HBF4\mathrm{HBF}_4 is a very strong acid.

Reason (R):B(OH)3(\mathbf{R}): \mathrm{B}(\mathrm{OH})_3 behaves as an acid in the following reaction :
B(OH)3+4HF⟶H3O++[BF4]−+2H2O.\mathrm{B}(\mathrm{OH})_3+4 \mathrm{HF} \longrightarrow \mathrm{H}_3 \mathrm{O}^{+}+\left[\mathrm{BF}_4 \right]^{-}+2 \mathrm{H}_2 \mathrm{O}.
View answer and explanation
Correct option: C
A\mathbf{A} is true but R\mathbf{R} is false.
Option D (NH4ClN{H_4}Cl - Both cationic and anionic hydrolysis) is the wrong match because NH4ClNH_4Cl undergoes cationic hydrolysis only.
155 Medium
155 of 163
Understanding +4 | -1
Consider the following statements

(i) Aluminium carbide on reaction with water gives methane gas.

(ii) Permanent hardness of water is easily removed by boiling

(iii) H2O2{H}_2 {O}_2 dipole moment is more than that of H2O{H}_2 {O}

(iv) Potassium impart blue colour to the flame test.

Incorrect statements among the following are
View answer and explanation
Correct option: C
(ii) and (iv) only
Option C ((ii) and (iv) only) is correct because permanent hardness cannot be easily removed by boiling, and potassium imparts a violet color to the flame test.
156 Medium
156 of 163
Remembering +4 | -1
In alumino thermic process, Al is used as
View answer and explanation
Correct option: A
Reducing agent
Option A (Reducing agent) is correct because Aluminum is used to reduce the metal oxide to its elemental form in the aluminothermic process.
157 Medium
157 of 163
Understanding +4 | -1
The increasing order of atomic radii of group – 13 elements is
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Correct option: A
Ga < Al < In < Tl
Option A (Ga < Al < In < Tl) is correct because the atomic radius generally increases down the group, but gallium is smaller than aluminum due to the poor shielding effect of its d-orbitals.
158 Easy
158 of 163
Understanding +4 | -1
Which of the following elements can show covalency greater than 4
i) Be ii) P iii) S iv) B
View answer and explanation
Correct option: B
ii & iii
Option B (ii & iii) is correct because phosphorus (P) and sulfur (S) can expand their octets due to the availability of vacant d-orbitals, allowing them to form more than four covalent bonds.
159 Easy
159 of 163
Understanding +4 | -1
An aqueous solution of borax is
View answer and explanation
Correct option: C
Basic
Option C (Basic) is correct because borax hydrolyzes in water to form boric acid (a weak acid) and sodium hydroxide (a strong base), resulting in a basic solution.
160 Easy
160 of 163
Application +4 | -1
Oxidation state of boron in magnesium boride (Mg3B2)\left( {M{g_3}{B_2}} \right)
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Correct option: A
−3- 3
Option A (−3-3) is correct because magnesium is +2, and to balance the charge in Mg3B2Mg_3B_2, boron must have an oxidation state of -3.
161 Medium
161 of 163
Remembering +4 | -1
Boric acid on heating at 150∘C150^\circ C gives:
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Correct option: B
H2B4O7{\mathrm{H}_2}{\mathrm{B}_4}{\mathrm{O}_7}
Option B (H2B4O7{\mathrm{H}_2}{\mathrm{B}_4}{\mathrm{O}_7}) is correct because boric acid (H3BO3) when heated at 150°C gives tetraboric acid (H2B4O7{\mathrm{H}_2}{\mathrm{B}_4}{\mathrm{O}_7}).
162 Medium
162 of 163
Understanding +4 | -1
In which one of the following molecules strongest back donation of an electron pair from halide to boron is expected?
View answer and explanation
Correct option: B
BF3\mathrm{B}{\mathrm{F}_\mathrm{3}}
Option B (BF3\mathrm{B}{\mathrm{F}_\mathrm{3}}) is correct because fluorine is the smallest halide and has the highest electronegativity, leading to the strongest back donation to boron.
163 Medium
163 of 163
Analyzing +4 | -1
Assertion (A): Aqueous solution of borax is acidic in nature.

Reason (R): Borax on reaction with aqueous hydrochloric acid gives boric acid as one of the products.

In light of the above statements, choose the correct answer.
View answer and explanation
Correct option: D
(A) is not correct but (R) is correct
Option D ((A) is not correct but (R) is correct) is correct because aqueous solutions of borax are alkaline, not acidic, and the reason correctly states that borax reacts with HCl to produce boric acid.
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