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JEE • CHEMISTRY • 13 TH GROUP ELEMENTS (P-BLOCK)
13 th group elements (p-block) practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 151-163 of 163 questions
151
Easy
151 of 163
Understanding
+4 | -1
Which of the following is ionic.
View answer and explanation
Correct option: A
Option A () is correct because the electronegativity difference between Al and F is large enough to form an ionic bond, while the other options have more covalent character.
152
Medium
152 of 163
Understanding
+4 | -1
Which among the following statements are correct?
(i)Carbon monoxide is neutral whereas is acidic.
(ii)Potassium oxide is basic whereas nitrous oxide is acidic.
(iii) Aluminium and zinc oxides are amphoteric.
(iv) Sulphur trioxide is acidic whereas phosphorus pentoxide is basic.
(v) Carbon dioxide is neutal whereas sulphur dioxide is amphoteric
(i)Carbon monoxide is neutral whereas is acidic.
(ii)Potassium oxide is basic whereas nitrous oxide is acidic.
(iii) Aluminium and zinc oxides are amphoteric.
(iv) Sulphur trioxide is acidic whereas phosphorus pentoxide is basic.
(v) Carbon dioxide is neutal whereas sulphur dioxide is amphoteric
View answer and explanation
Correct option: C
(i) and (iii)
Option C ((i) and (iii)) is correct because carbon monoxide is neutral, sulfur trioxide is acidic, and aluminum and zinc oxides are amphoteric.
153
Medium
153 of 163
Understanding
+4 | -1
Statement-I:Most of the is dimerised through halogen bridging,
Statement-II: complete its octet by accepting electrons from halogen in halogen bridged molecules,
Statement-II: complete its octet by accepting electrons from halogen in halogen bridged molecules,
View answer and explanation
Correct option: A
Both I and II are correct
Option A (Both I and II are correct) is correct because dimerizes to form through halogen bridging, which allows aluminum to complete its octet.
154
Medium
154 of 163
Analyzing
+4 | -1
Assertion (A): is a very strong acid.
Reason behaves as an acid in the following reaction :
Reason behaves as an acid in the following reaction :
View answer and explanation
Correct option: C
is true but is false.
Option D ( - Both cationic and anionic hydrolysis) is the wrong match because undergoes cationic hydrolysis only.
155
Medium
155 of 163
Understanding
+4 | -1
Consider the following statements
(i) Aluminium carbide on reaction with water gives methane gas.
(ii) Permanent hardness of water is easily removed by boiling
(iii) dipole moment is more than that of
(iv) Potassium impart blue colour to the flame test.
Incorrect statements among the following are
(i) Aluminium carbide on reaction with water gives methane gas.
(ii) Permanent hardness of water is easily removed by boiling
(iii) dipole moment is more than that of
(iv) Potassium impart blue colour to the flame test.
Incorrect statements among the following are
View answer and explanation
Correct option: C
(ii) and (iv) only
Option C ((ii) and (iv) only) is correct because permanent hardness cannot be easily removed by boiling, and potassium imparts a violet color to the flame test.
156
Medium
156 of 163
Remembering
+4 | -1
In alumino thermic process, Al is used as
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Correct option: A
Reducing agent
Option A (Reducing agent) is correct because Aluminum is used to reduce the metal oxide to its elemental form in the aluminothermic process.
157
Medium
157 of 163
Understanding
+4 | -1
The increasing order of atomic radii of group – 13 elements is
View answer and explanation
Correct option: A
Ga < Al < In < Tl
Option A (Ga < Al < In < Tl) is correct because the atomic radius generally increases down the group, but gallium is smaller than aluminum due to the poor shielding effect of its d-orbitals.
158
Easy
158 of 163
Understanding
+4 | -1
Which of the following elements can show covalency greater than 4
i) Be ii) P iii) S iv) B
i) Be ii) P iii) S iv) B
View answer and explanation
Correct option: B
ii & iii
Option B (ii & iii) is correct because phosphorus (P) and sulfur (S) can expand their octets due to the availability of vacant d-orbitals, allowing them to form more than four covalent bonds.
159
Easy
159 of 163
Understanding
+4 | -1
An aqueous solution of borax is
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Correct option: C
Basic
Option C (Basic) is correct because borax hydrolyzes in water to form boric acid (a weak acid) and sodium hydroxide (a strong base), resulting in a basic solution.
160
Easy
160 of 163
Application
+4 | -1
Oxidation state of boron in magnesium boride
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Correct option: A
Option A () is correct because magnesium is +2, and to balance the charge in , boron must have an oxidation state of -3.
161
Medium
161 of 163
Remembering
+4 | -1
Boric acid on heating at gives:
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Correct option: B
Option B () is correct because boric acid (H3BO3) when heated at 150°C gives tetraboric acid ().
162
Medium
162 of 163
Understanding
+4 | -1
In which one of the following molecules strongest back donation of an electron pair from halide to boron is expected?
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Correct option: B
Option B () is correct because fluorine is the smallest halide and has the highest electronegativity, leading to the strongest back donation to boron.
163
Medium
163 of 163
Analyzing
+4 | -1
Assertion (A): Aqueous solution of borax is acidic in nature.
Reason (R): Borax on reaction with aqueous hydrochloric acid gives boric acid as one of the products.
In light of the above statements, choose the correct answer.
Reason (R): Borax on reaction with aqueous hydrochloric acid gives boric acid as one of the products.
In light of the above statements, choose the correct answer.
View answer and explanation
Correct option: D
(A) is not correct but (R) is correct
Option D ((A) is not correct but (R) is correct) is correct because aqueous solutions of borax are alkaline, not acidic, and the reason correctly states that borax reacts with HCl to produce boric acid.
Revision notes and key takeaways
Review 13 TH GROUP ELEMENTS (P-BLOCK) in your textbook or class notes, then use this set to check your understanding.
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