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JEE • CHEMISTRY • 13 TH GROUP ELEMENTS (P-BLOCK)

13 th group elements (p-block) practice · Hard

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Hard

1 of 5

Analyzing +4 | -1

Assertion (A) : In aqueous solution

{AlCl}_3

forms dimer

{Al}_2 {Cl}_6

.
Reason (R) : The high enthalpy of hydration is sufficient to break the covalent dimer into

\left[M\left({H}_2 {O}\right)_6\right]^{3+}

and

{Cl}^{-}

ions.

View answer and explanation

Correct option: D

\mathbf{A}

is false but

\mathbf{R}

is true.

Option D is correct. Assertion (A) is false because

{AlCl}_3

exists as a dimer in the gaseous phase and in non-polar solvents, but it ionizes in aqueous solution. Reason (R) is true because the high enthalpy of hydration favors ionization.

2 Hard

2 of 5

Application +4 | -1

The number of neutrons present in the more abundant isotope of boron is

x.

Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is

y.

The value of

x+y

View answer and explanation

Correct option: D

Option D (9) is correct because the more abundant isotope of boron has 6 neutrons, and the oxidation state of boron in

B_2O_3

is +3, summing to 9.

3 Hard

3 of 5

Remembering +4 | -1

An alumina-silica clay, called bentonite is dropped from aeroplanes in the slurry form for:

View answer and explanation

Correct option: D

Fumigation

Option B is incorrect. Bentonite is not used for spreading water over fires. It is used for fumigation.

4 Hard

4 of 5

Understanding +4 | -1

Value of

x

in potash alum,

{\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4}\mathrm{.A}{\mathrm{I}_x}{\left( {\mathrm{S}{\mathrm{O}_4}} \right)_3}.24{\mathrm{H}_2}\mathrm{O}

View answer and explanation

Correct option: C

Option C (2) is correct because the formula for potash alum is K₂SO₄.Al₂(SO₄)₃.24H₂O, indicating x=2.

5 Hard

5 of 5

Understanding +4 | -1

The structure of diborane

\left(B_2 H_6\right)

contains '

x

' number of

2 {c}-2 {e}

bonds and '

{y}

' number of

3 c-2 e^{-}

bonds and then calculate the value of

x^2-y^3

View answer and explanation

Correct option: A

Option A (8) is correct because diborane has 4 two-center-two-electron bonds and 2 three-center-two-electron bonds, leading to x² - y³ = 4² - 2³ = 8.

Revision notes and key takeaways

Review 13 TH GROUP ELEMENTS (P-BLOCK) in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 5 single-correct-answer MCQs on 13 TH GROUP ELEMENTS (P-BLOCK).
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

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