NEET UG CHEMISTRY MCQ: 13 TH GROUP ELEMENTS (P-BLOCK)

1 Hard

1 of 1

Application +4 | -1

The number of neutrons present in the more abundant isotope of boron is

x.

Amorphous boron upon heating with air forms a product, in which the oxidation state of boron is

y.

The value of

x+y

View answer and explanation

Correct option: D

Option D (9) is correct because the more abundant isotope of boron is

^{11}B

(x=6), and boron reacts with air to form

B_2O_3

where boron's oxidation state is +3 (y=3), so x+y = 6+3 = 9.

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