JEE MATHEMATICS MCQ: THEORY OF EQUATION

1 Easy

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Application +4 | -1

The solution of the equation

2{x^3} - {x^2} - 22x - 24 = 0

when two of the roots in the ration

3:4

, is

View answer and explanation

Correct option: B

- \frac{3}{2},\; - 2,\;4

Option B (

- \frac{3}{2},\; - 2,\;4

) is correct because it satisfies the given equation and the ratio of two of its roots is 3:4.

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