JEE MATHEMATICS MCQ: THEORY OF EQUATION

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Analyzing +4 | -1

How many real solutions does the equation

x^7+14 x^5+16 x^3+30 x-560=0

have?

View answer and explanation

Correct option: A

Option A (1) is correct because the derivative of the given function is always positive, indicating that the function is strictly increasing and thus has only one real root.

More Questions from THEORY OF EQUATION

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The maximum number of real roots of the equation

{x^{2n}} - 1 = 0

is The number of roots of the equation

\frac{1}{x}+\frac{1}{\sqrt{\left(1-x^2\right)}}=\frac{35}{12}

is If

x_1, x_2, x_3, \ldots, x_n

are the roots of the equation

x^n+a x+b=0

, the value of

\left(x_1-x_2\right)\left(x_1-x_3\right)\left(x_1-x_4\right) \ldots\left(x_1-x_n\right)

is The polynomials

P(x)=k x^3+3 x^2-3

and

Q(x)=2 x^3-5 x+k

, when divided by

(x-4)

leave the same remainder, then

k

is equal to: If

{\left( {x - 1} \right)^3}

is a factor of

{x^4} + a{x^3} + b{x^2} + cx - 1,

then the other factor is The number of positive integral solutions of

x^4-y^4=3789108