JEE MATHEMATICS MCQ: THEORY OF EQUATION

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The maximum number of real roots of the equation

{x^{2n}} - 1 = 0

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Correct option: A

Option A (2) is correct because the equation x⁽²ⁿ⁾ - 1 = 0 has two real roots, which are 1 and -1.

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\frac{1}{x}+\frac{1}{\sqrt{\left(1-x^2\right)}}=\frac{35}{12}

x^7+14 x^5+16 x^3+30 x-560=0

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